Selecting based on criterion on a single column
$begingroup$
I have an array that looks like M = {a, b, c, d}
, where a, b, c, d
are column vectors. I want to select rows from this array based on the elements in column c
meeting a specified condition.
For example, if I have
M = {{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"horse", 30, 1, 19},{"hippo", 99, 15,4}}
I want to take rows from this array based on the condition
c[[i]] >= 10
How could this be done? Ideally I would like to use Select
as this can retrieve the sublist.
list-manipulation filtering
$endgroup$
add a comment |
$begingroup$
I have an array that looks like M = {a, b, c, d}
, where a, b, c, d
are column vectors. I want to select rows from this array based on the elements in column c
meeting a specified condition.
For example, if I have
M = {{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"horse", 30, 1, 19},{"hippo", 99, 15,4}}
I want to take rows from this array based on the condition
c[[i]] >= 10
How could this be done? Ideally I would like to use Select
as this can retrieve the sublist.
list-manipulation filtering
$endgroup$
1
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago
add a comment |
$begingroup$
I have an array that looks like M = {a, b, c, d}
, where a, b, c, d
are column vectors. I want to select rows from this array based on the elements in column c
meeting a specified condition.
For example, if I have
M = {{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"horse", 30, 1, 19},{"hippo", 99, 15,4}}
I want to take rows from this array based on the condition
c[[i]] >= 10
How could this be done? Ideally I would like to use Select
as this can retrieve the sublist.
list-manipulation filtering
$endgroup$
I have an array that looks like M = {a, b, c, d}
, where a, b, c, d
are column vectors. I want to select rows from this array based on the elements in column c
meeting a specified condition.
For example, if I have
M = {{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"horse", 30, 1, 19},{"hippo", 99, 15,4}}
I want to take rows from this array based on the condition
c[[i]] >= 10
How could this be done? Ideally I would like to use Select
as this can retrieve the sublist.
list-manipulation filtering
list-manipulation filtering
edited 8 hours ago
m_goldberg
85.7k872196
85.7k872196
asked 8 hours ago
MKFMKF
1238
1238
1
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago
add a comment |
1
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago
1
1
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Feels like a duplicate of a bunch of questions, you could probably find by searching this forum... Some basic structures:
Select[M, #[[3]] >= 3 &]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
Cases[M,x_/;x[[3]]>=3]
{{"cat",21,10,1},{"dog",7,42,2},{"hippo",99,15,4}}
$endgroup$
add a comment |
$begingroup$
Pick[M, UnitStep[M[[All, 3]] - 10], 1]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
More general, you may use
check = # >= 10 &;
Pick[M, check /@ M[[All, 3]]]
$endgroup$
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something likeSelect[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria
$endgroup$
– MKF
8 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Feels like a duplicate of a bunch of questions, you could probably find by searching this forum... Some basic structures:
Select[M, #[[3]] >= 3 &]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
Cases[M,x_/;x[[3]]>=3]
{{"cat",21,10,1},{"dog",7,42,2},{"hippo",99,15,4}}
$endgroup$
add a comment |
$begingroup$
Feels like a duplicate of a bunch of questions, you could probably find by searching this forum... Some basic structures:
Select[M, #[[3]] >= 3 &]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
Cases[M,x_/;x[[3]]>=3]
{{"cat",21,10,1},{"dog",7,42,2},{"hippo",99,15,4}}
$endgroup$
add a comment |
$begingroup$
Feels like a duplicate of a bunch of questions, you could probably find by searching this forum... Some basic structures:
Select[M, #[[3]] >= 3 &]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
Cases[M,x_/;x[[3]]>=3]
{{"cat",21,10,1},{"dog",7,42,2},{"hippo",99,15,4}}
$endgroup$
Feels like a duplicate of a bunch of questions, you could probably find by searching this forum... Some basic structures:
Select[M, #[[3]] >= 3 &]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
Cases[M,x_/;x[[3]]>=3]
{{"cat",21,10,1},{"dog",7,42,2},{"hippo",99,15,4}}
answered 8 hours ago
Vitaliy KaurovVitaliy Kaurov
57.2k6161280
57.2k6161280
add a comment |
add a comment |
$begingroup$
Pick[M, UnitStep[M[[All, 3]] - 10], 1]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
More general, you may use
check = # >= 10 &;
Pick[M, check /@ M[[All, 3]]]
$endgroup$
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something likeSelect[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria
$endgroup$
– MKF
8 hours ago
add a comment |
$begingroup$
Pick[M, UnitStep[M[[All, 3]] - 10], 1]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
More general, you may use
check = # >= 10 &;
Pick[M, check /@ M[[All, 3]]]
$endgroup$
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something likeSelect[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria
$endgroup$
– MKF
8 hours ago
add a comment |
$begingroup$
Pick[M, UnitStep[M[[All, 3]] - 10], 1]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
More general, you may use
check = # >= 10 &;
Pick[M, check /@ M[[All, 3]]]
$endgroup$
Pick[M, UnitStep[M[[All, 3]] - 10], 1]
{{"cat", 21, 10, 1}, {"dog", 7, 42, 2}, {"hippo", 99, 15, 4}}
More general, you may use
check = # >= 10 &;
Pick[M, check /@ M[[All, 3]]]
edited 5 hours ago
answered 8 hours ago
Henrik SchumacherHenrik Schumacher
52.5k471148
52.5k471148
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something likeSelect[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria
$endgroup$
– MKF
8 hours ago
add a comment |
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something likeSelect[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria
$endgroup$
– MKF
8 hours ago
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something like
Select[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria$endgroup$
– MKF
8 hours ago
$begingroup$
Thanks Henrik; this technique wouldn't work if I exchange entries to arbitrary arrays, so is there perhaps a generalisation? I was thinking something like
Select[M, (#[[All, 3]] >=10) &]
- then (if it worked) the type of element wouldn't matter so much i.e. It could generalise to more complicated criteria$endgroup$
– MKF
8 hours ago
add a comment |
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1
$begingroup$
Essentially a duplicate of Mathematica SE question 45951 "Select record when third column matches certain criterion".
$endgroup$
– Somos
8 hours ago