Why don't the fuse connections in programmable ROM cause the whole matrix to be shorted together?
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If the rationale of using diodes in ROM (rather than simple wires) is to prevent the matrix being shorted together, then why does shorting not occur for programmable ROM - which has blowable fuse connections?
Apologies if should not be starting a new thread for this; please note that the question is inspired by an answer here What is the rationale of using diode matrix in ROM , but I don't have sufficient 'rep' to comment my question there.
rom
asked 17 hours ago
dmacdmac
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$begingroup$
If the rationale of using diodes in ROM (rather than simple wires) is to prevent the matrix being shorted together, then why does shorting not occur for programmable ROM - which has blowable fuse connections?
Apologies if should not be starting a new thread for this; please note that the question is inspired by an answer here What is the rationale of using diode matrix in ROM , but I don't have sufficient 'rep' to comment my question there.
rom
asked 17 hours ago
dmacdmac
686
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dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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4
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Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
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– Transistor
16 hours ago
add a comment |
$begingroup$
If the rationale of using diodes in ROM (rather than simple wires) is to prevent the matrix being shorted together, then why does shorting not occur for programmable ROM - which has blowable fuse connections?
Apologies if should not be starting a new thread for this; please note that the question is inspired by an answer here What is the rationale of using diode matrix in ROM , but I don't have sufficient 'rep' to comment my question there.
rom
asked 17 hours ago
dmacdmac
686
New contributor
dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
If the rationale of using diodes in ROM (rather than simple wires) is to prevent the matrix being shorted together, then why does shorting not occur for programmable ROM - which has blowable fuse connections?
Apologies if should not be starting a new thread for this; please note that the question is inspired by an answer here What is the rationale of using diode matrix in ROM , but I don't have sufficient 'rep' to comment my question there.
rom
rom
asked 17 hours ago
dmacdmac
686
New contributor
dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 17 hours ago
dmacdmac
686
New contributor
dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 17 hours ago
dmacdmac
686
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dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 17 hours ago
dmacdmac
686
asked 17 hours ago
dmacdmac
686
686
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dmac is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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4
$begingroup$
Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
$endgroup$
– Transistor
16 hours ago
add a comment |
4
$begingroup$
Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
$endgroup$
– Transistor
16 hours ago
4
4
$begingroup$
Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
$endgroup$
– Transistor
16 hours ago
$begingroup$
Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
$endgroup$
– Transistor
16 hours ago
add a comment |
1 Answer
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$begingroup$
Fuse-programmable ROM is not a simple wired XY matrix, with fuses at each intersection. That wouldn't work, for the reasons you give.
Typically, transistors are used at each intersection, like this.
Image from here, worth visiting if you're interested in other types of ROM.
Conceptually, something as simple as a diode in series with each fuse would serve to both allow reading, and selection of the appropriate fuse to blow. However, there's a lot of development and technology between the basic idea, and a commercial product. Interestingly, many fuse ROMS use 'anti-fuses'. In the right process, high voltage can punch through the dielectric layer of a capacitor and make it fail short more reliably and cheaply than high current can open a fuse.
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
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1 Answer
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$begingroup$
Fuse-programmable ROM is not a simple wired XY matrix, with fuses at each intersection. That wouldn't work, for the reasons you give.
Typically, transistors are used at each intersection, like this.
Image from here, worth visiting if you're interested in other types of ROM.
Conceptually, something as simple as a diode in series with each fuse would serve to both allow reading, and selection of the appropriate fuse to blow. However, there's a lot of development and technology between the basic idea, and a commercial product. Interestingly, many fuse ROMS use 'anti-fuses'. In the right process, high voltage can punch through the dielectric layer of a capacitor and make it fail short more reliably and cheaply than high current can open a fuse.
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
$endgroup$
add a comment |
$begingroup$
Fuse-programmable ROM is not a simple wired XY matrix, with fuses at each intersection. That wouldn't work, for the reasons you give.
Typically, transistors are used at each intersection, like this.
Image from here, worth visiting if you're interested in other types of ROM.
Conceptually, something as simple as a diode in series with each fuse would serve to both allow reading, and selection of the appropriate fuse to blow. However, there's a lot of development and technology between the basic idea, and a commercial product. Interestingly, many fuse ROMS use 'anti-fuses'. In the right process, high voltage can punch through the dielectric layer of a capacitor and make it fail short more reliably and cheaply than high current can open a fuse.
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
$endgroup$
add a comment |
$begingroup$
Fuse-programmable ROM is not a simple wired XY matrix, with fuses at each intersection. That wouldn't work, for the reasons you give.
Typically, transistors are used at each intersection, like this.
Image from here, worth visiting if you're interested in other types of ROM.
Conceptually, something as simple as a diode in series with each fuse would serve to both allow reading, and selection of the appropriate fuse to blow. However, there's a lot of development and technology between the basic idea, and a commercial product. Interestingly, many fuse ROMS use 'anti-fuses'. In the right process, high voltage can punch through the dielectric layer of a capacitor and make it fail short more reliably and cheaply than high current can open a fuse.
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
$endgroup$
Fuse-programmable ROM is not a simple wired XY matrix, with fuses at each intersection. That wouldn't work, for the reasons you give.
Typically, transistors are used at each intersection, like this.
Image from here, worth visiting if you're interested in other types of ROM.
Conceptually, something as simple as a diode in series with each fuse would serve to both allow reading, and selection of the appropriate fuse to blow. However, there's a lot of development and technology between the basic idea, and a commercial product. Interestingly, many fuse ROMS use 'anti-fuses'. In the right process, high voltage can punch through the dielectric layer of a capacitor and make it fail short more reliably and cheaply than high current can open a fuse.
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
edited 7 hours ago
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
answered 15 hours ago
Neil_UKNeil_UK
76.4k282172
76.4k282172
add a comment |
add a comment |
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$begingroup$
Asking a new question and cross-referencing to the old one is the correct procedure on this site. +1.
$endgroup$
– Transistor
16 hours ago