What is the domain in a tikz parametric plot?
I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=40, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t)*.5+.5});
end{scope}
end{tikzpicture}
end{document}
tikz-pgf plot domain
asked 5 hours ago
argentum2fargentum2f
1336
add a comment |
I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=40, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t)*.5+.5});
end{scope}
end{tikzpicture}
end{document}
tikz-pgf plot domain
asked 5 hours ago
argentum2fargentum2f
1336
add a comment |
I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=40, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t)*.5+.5});
end{scope}
end{tikzpicture}
end{document}
tikz-pgf plot domain
asked 5 hours ago
argentum2fargentum2f
1336
I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=40, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t)*.5+.5});
end{scope}
end{tikzpicture}
end{document}
tikz-pgf plot domain
tikz-pgf plot domain
asked 5 hours ago
argentum2fargentum2f
1336
asked 5 hours ago
argentum2fargentum2f
1336
asked 5 hours ago
argentum2fargentum2f
1336
asked 5 hours ago
argentum2fargentum2f
1336
asked 5 hours ago
argentum2fargentum2f
1336
1336
add a comment |
add a comment |
1 Answer
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You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.
You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):
documentclass{article}
usepackage{tikz}
usetikzlibrary{fpu}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=400, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t r)*.5+.5});
end{scope}% ^
end{tikzpicture}
end{document}
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
1
withsamples=400,smoothit looks better, but this is not the question ;)
– Kpym
5 hours ago
@Kpym Certainly! I just removed thesmoothto show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have asinfunction for argument radians andsindfunction for argument in degrees. Anyhow, Till must have had his reasons :)
– Phelype Oleinik
3 hours ago
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
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oldest
votes
You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.
You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):
documentclass{article}
usepackage{tikz}
usetikzlibrary{fpu}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=400, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t r)*.5+.5});
end{scope}% ^
end{tikzpicture}
end{document}
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
1
withsamples=400,smoothit looks better, but this is not the question ;)
– Kpym
5 hours ago
@Kpym Certainly! I just removed thesmoothto show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have asinfunction for argument radians andsindfunction for argument in degrees. Anyhow, Till must have had his reasons :)
– Phelype Oleinik
3 hours ago
add a comment |
You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.
You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):
documentclass{article}
usepackage{tikz}
usetikzlibrary{fpu}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=400, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t r)*.5+.5});
end{scope}% ^
end{tikzpicture}
end{document}
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
1
withsamples=400,smoothit looks better, but this is not the question ;)
– Kpym
5 hours ago
@Kpym Certainly! I just removed thesmoothto show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have asinfunction for argument radians andsindfunction for argument in degrees. Anyhow, Till must have had his reasons :)
– Phelype Oleinik
3 hours ago
add a comment |
You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.
You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):
documentclass{article}
usepackage{tikz}
usetikzlibrary{fpu}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=400, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t r)*.5+.5});
end{scope}% ^
end{tikzpicture}
end{document}
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.
You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):
documentclass{article}
usepackage{tikz}
usetikzlibrary{fpu}
begin{document}
begin{tikzpicture}
begin{scope}[x=.6textwidth,y=.6textwidth]
pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}
draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);
draw [ thick, domain=0:100, samples=400, smooth, variable=t]
plot ({t/100}, {sin(2*pi*t r)*.5+.5});
end{scope}% ^
end{tikzpicture}
end{document}
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
edited 4 hours ago
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
answered 5 hours ago
Phelype OleinikPhelype Oleinik
24.2k54688
24.2k54688
1
withsamples=400,smoothit looks better, but this is not the question ;)
– Kpym
5 hours ago
@Kpym Certainly! I just removed thesmoothto show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have asinfunction for argument radians andsindfunction for argument in degrees. Anyhow, Till must have had his reasons :)
– Phelype Oleinik
3 hours ago
add a comment |
1
withsamples=400,smoothit looks better, but this is not the question ;)
– Kpym
5 hours ago
@Kpym Certainly! I just removed thesmoothto show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have asinfunction for argument radians andsindfunction for argument in degrees. Anyhow, Till must have had his reasons :)
– Phelype Oleinik
3 hours ago
1
1
with
samples=400,smooth it looks better, but this is not the question ;)– Kpym
5 hours ago
with
samples=400,smooth it looks better, but this is not the question ;)– Kpym
5 hours ago
@Kpym Certainly! I just removed the
smooth to show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)– Phelype Oleinik
5 hours ago
@Kpym Certainly! I just removed the
smooth to show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)– Phelype Oleinik
5 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
– argentum2f
4 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have a
sin function for argument radians and sind function for argument in degrees. Anyhow, Till must have had his reasons :)– Phelype Oleinik
3 hours ago
@argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have a
sin function for argument radians and sind function for argument in degrees. Anyhow, Till must have had his reasons :)– Phelype Oleinik
3 hours ago
add a comment |
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