Gantt Chart like rectangles with log scale












5












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$








  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    6 hours ago
















5












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$








  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    6 hours ago














5












5








5





$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$




I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here







plotting charts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago







Mockup Dungeon

















asked 6 hours ago









Mockup DungeonMockup Dungeon

888613




888613








  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    6 hours ago














  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    6 hours ago








1




1




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago










3 Answers
3






active

oldest

votes


















5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data,  
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[{Labeled[#, Style[#2, White,  FontSize -> Scaled[.03]], Center]} & @@@ 
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago












  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago



















3












$begingroup$

LogLinearPlot[1, 
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]





share|improve this answer











$endgroup$













  • $begingroup$
    This is nice, was wondering how to use Rectangle. Thank you!
    $endgroup$
    – mjw
    4 hours ago



















0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];


Then we place a few rectangle's in Show.



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic} but this is not a valid argument for RegionPlot.



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.






share|improve this answer











$endgroup$













  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    5 hours ago











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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data,  
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[{Labeled[#, Style[#2, White,  FontSize -> Scaled[.03]], Center]} & @@@ 
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago












  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago
















5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data,  
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[{Labeled[#, Style[#2, White,  FontSize -> Scaled[.03]], Center]} & @@@ 
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago












  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago














5












5








5





$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data,  
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[{Labeled[#, Style[#2, White,  FontSize -> Scaled[.03]], Center]} & @@@ 
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$



SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data,  
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[{Labeled[#, Style[#2, White,  FontSize -> Scaled[.03]], Center]} & @@@ 
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century







share|improve this answer














share|improve this answer



share|improve this answer








edited 32 mins ago

























answered 4 hours ago









kglrkglr

189k10205422




189k10205422








  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago












  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago














  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago












  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago








1




1




$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
4 hours ago






$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
4 hours ago














$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago




$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago











3












$begingroup$

LogLinearPlot[1, 
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]





share|improve this answer











$endgroup$













  • $begingroup$
    This is nice, was wondering how to use Rectangle. Thank you!
    $endgroup$
    – mjw
    4 hours ago
















3












$begingroup$

LogLinearPlot[1, 
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]





share|improve this answer











$endgroup$













  • $begingroup$
    This is nice, was wondering how to use Rectangle. Thank you!
    $endgroup$
    – mjw
    4 hours ago














3












3








3





$begingroup$

LogLinearPlot[1, 
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]





share|improve this answer











$endgroup$



LogLinearPlot[1, 
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]






share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 5 hours ago









David G. StorkDavid G. Stork

24.6k22153




24.6k22153












  • $begingroup$
    This is nice, was wondering how to use Rectangle. Thank you!
    $endgroup$
    – mjw
    4 hours ago


















  • $begingroup$
    This is nice, was wondering how to use Rectangle. Thank you!
    $endgroup$
    – mjw
    4 hours ago
















$begingroup$
This is nice, was wondering how to use Rectangle. Thank you!
$endgroup$
– mjw
4 hours ago




$begingroup$
This is nice, was wondering how to use Rectangle. Thank you!
$endgroup$
– mjw
4 hours ago











0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];


Then we place a few rectangle's in Show.



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic} but this is not a valid argument for RegionPlot.



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.






share|improve this answer











$endgroup$













  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    5 hours ago
















0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];


Then we place a few rectangle's in Show.



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic} but this is not a valid argument for RegionPlot.



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.






share|improve this answer











$endgroup$













  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    5 hours ago














0












0








0





$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];


Then we place a few rectangle's in Show.



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic} but this is not a valid argument for RegionPlot.



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.






share|improve this answer











$endgroup$



Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];


Then we place a few rectangle's in Show.



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic} but this is not a valid argument for RegionPlot.



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.







share|improve this answer














share|improve this answer



share|improve this answer








edited 5 hours ago

























answered 5 hours ago









mjwmjw

5879




5879












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    5 hours ago


















  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    5 hours ago
















$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago




$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago


















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