Gantt Chart like rectangles with log scale
$begingroup$
I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?
E.g.:
Min and Max values of the rectangles are the known data.
plotting charts
$endgroup$
add a comment |
$begingroup$
I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?
E.g.:
Min and Max values of the rectangles are the known data.
plotting charts
$endgroup$
1
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago
add a comment |
$begingroup$
I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?
E.g.:
Min and Max values of the rectangles are the known data.
plotting charts
$endgroup$
I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?
E.g.:
Min and Max values of the rectangles are the known data.
plotting charts
plotting charts
edited 5 hours ago
Mockup Dungeon
asked 6 hours ago
Mockup DungeonMockup Dungeon
888613
888613
1
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago
add a comment |
1
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago
1
1
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];
ListLogLinearPlot
Show[ListLogLinearPlot[data,
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]
TimeLinePlot
TimelinePlot[{Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center]} & @@@
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]
Thanks: @David G. Stork for the GeometricMean
idea to center the labels.
See also: Poets of the 19th century
$endgroup$
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.Mean
is simply incorrect. TryGeometricMean
.
$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
LogLinearPlot[1,
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]
$endgroup$
$begingroup$
This is nice, was wondering how to useRectangle
. Thank you!
$endgroup$
– mjw
4 hours ago
add a comment |
$begingroup$
Here is a start ...
A = 10^5; B = 10;
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];
Then we place a few rectangle
's in Show
.
Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]
We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic}
but this is not a valid argument for RegionPlot
.
Here is how it looks right now:
With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.
$endgroup$
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];
ListLogLinearPlot
Show[ListLogLinearPlot[data,
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]
TimeLinePlot
TimelinePlot[{Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center]} & @@@
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]
Thanks: @David G. Stork for the GeometricMean
idea to center the labels.
See also: Poets of the 19th century
$endgroup$
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.Mean
is simply incorrect. TryGeometricMean
.
$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];
ListLogLinearPlot
Show[ListLogLinearPlot[data,
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]
TimeLinePlot
TimelinePlot[{Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center]} & @@@
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]
Thanks: @David G. Stork for the GeometricMean
idea to center the labels.
See also: Poets of the 19th century
$endgroup$
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.Mean
is simply incorrect. TryGeometricMean
.
$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];
ListLogLinearPlot
Show[ListLogLinearPlot[data,
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]
TimeLinePlot
TimelinePlot[{Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center]} & @@@
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]
Thanks: @David G. Stork for the GeometricMean
idea to center the labels.
See also: Poets of the 19th century
$endgroup$
SeedRandom[1]
dates = Sort /@ RandomInteger[{10, 1000}, {5, 2}];
data = MapIndexed[Thread@{#, #2[[1]]} &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[{#, #2[[1]]}, Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];
ListLogLinearPlot
Show[ListLogLinearPlot[data,
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> {0, 6}, Frame -> True,
FrameTicks -> {{None, None}, {{50, 100, 200, 500, 1000}, Automatic}}],
ListLogLinearPlot[data2, PlotMarkers -> ""]]
TimeLinePlot
TimelinePlot[{Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center]} & @@@
Transpose[{Interval /@ (Map[N@*Log, dates, {-1}]), labels}],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> {{Automatic, Automatic},
{Transpose[{N@Log@#, #} &@{50, 100, 200, 500}], None}}]
Thanks: @David G. Stork for the GeometricMean
idea to center the labels.
See also: Poets of the 19th century
edited 32 mins ago
answered 4 hours ago
kglrkglr
189k10205422
189k10205422
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.Mean
is simply incorrect. TryGeometricMean
.
$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
add a comment |
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.Mean
is simply incorrect. TryGeometricMean
.
$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
1
1
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.
Mean
is simply incorrect. Try GeometricMean
.$endgroup$
– David G. Stork
4 hours ago
$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter.
Mean
is simply incorrect. Try GeometricMean
.$endgroup$
– David G. Stork
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
LogLinearPlot[1,
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]
$endgroup$
$begingroup$
This is nice, was wondering how to useRectangle
. Thank you!
$endgroup$
– mjw
4 hours ago
add a comment |
$begingroup$
LogLinearPlot[1,
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]
$endgroup$
$begingroup$
This is nice, was wondering how to useRectangle
. Thank you!
$endgroup$
– mjw
4 hours ago
add a comment |
$begingroup$
LogLinearPlot[1,
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]
$endgroup$
LogLinearPlot[1,
{t, .1, 100},
PlotStyle -> White,
Epilog -> {Rectangle[{Log[1], .5}, {Log[50], 1}],
Red, Rectangle[{Log[30], 1.5}, {Log[80], 2}],
Text[Style["a", White, 18], {Log[7], .75}],
Text[Style["b", White, 18], {Log[53], 1.75}]}]
edited 4 hours ago
answered 5 hours ago
David G. StorkDavid G. Stork
24.6k22153
24.6k22153
$begingroup$
This is nice, was wondering how to useRectangle
. Thank you!
$endgroup$
– mjw
4 hours ago
add a comment |
$begingroup$
This is nice, was wondering how to useRectangle
. Thank you!
$endgroup$
– mjw
4 hours ago
$begingroup$
This is nice, was wondering how to use
Rectangle
. Thank you!$endgroup$
– mjw
4 hours ago
$begingroup$
This is nice, was wondering how to use
Rectangle
. Thank you!$endgroup$
– mjw
4 hours ago
add a comment |
$begingroup$
Here is a start ...
A = 10^5; B = 10;
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];
Then we place a few rectangle
's in Show
.
Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]
We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic}
but this is not a valid argument for RegionPlot
.
Here is how it looks right now:
With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.
$endgroup$
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
add a comment |
$begingroup$
Here is a start ...
A = 10^5; B = 10;
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];
Then we place a few rectangle
's in Show
.
Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]
We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic}
but this is not a valid argument for RegionPlot
.
Here is how it looks right now:
With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.
$endgroup$
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
add a comment |
$begingroup$
Here is a start ...
A = 10^5; B = 10;
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];
Then we place a few rectangle
's in Show
.
Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]
We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic}
but this is not a valid argument for RegionPlot
.
Here is how it looks right now:
With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.
$endgroup$
Here is a start ...
A = 10^5; B = 10;
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, {x, 0, Log10[A]}, {y, 0, B}];
Then we place a few rectangle
's in Show
.
Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]
We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->{"Log10",Automatic}
but this is not a valid argument for RegionPlot
.
Here is how it looks right now:
With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_{10} x $ and not $x$ as we would like.
edited 5 hours ago
answered 5 hours ago
mjwmjw
5879
5879
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
add a comment |
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
5 hours ago
add a comment |
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1
$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
6 hours ago