Dynamic filling of a region of a polar plot












3












$begingroup$


I would like to shade area of region as a function of angle using PolarPlot.
Here is my attempt.



With[

  {pts = 

    Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},

  Manipulate[

    Show[

      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]}, 

        Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}}, 

        PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1, 

        PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta], 

        ImageSize -> 500, AxesStyle -> Directive[Black, 18], 

        PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]], 

      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π}, 

        AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]], 

    {n, 1, Length @ pts, 1}]]


enter image description here



enter image description here



Two thing I would like to achieve:




  1. I don't want to see the yellow highlited region.

  2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


Any suggestion..






plotting filling







share|improve this question











$endgroup$

















    3












    $begingroup$


    I would like to shade area of region as a function of angle using PolarPlot.
    Here is my attempt.



    With[
    
  {pts = 
    
    Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
    
  Manipulate[
    
    Show[
    
      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]}, 
    
        Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}}, 
    
        PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1, 
    
        PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta], 
    
        ImageSize -> 500, AxesStyle -> Directive[Black, 18], 
    
        PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]], 
    
      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π}, 
    
        AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]], 
    
    {n, 1, Length @ pts, 1}]]


    enter image description here



    enter image description here



    Two thing I would like to achieve:




    1. I don't want to see the yellow highlited region.

    2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


    Any suggestion..






    plotting filling







    share|improve this question











    $endgroup$















      3












      3








      3





      $begingroup$


      I would like to shade area of region as a function of angle using PolarPlot.
      Here is my attempt.



      With[
      
  {pts = 
      
    Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
      
  Manipulate[
      
    Show[
      
      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]}, 
      
        Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}}, 
      
        PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1, 
      
        PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta], 
      
        ImageSize -> 500, AxesStyle -> Directive[Black, 18], 
      
        PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]], 
      
      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π}, 
      
        AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]], 
      
    {n, 1, Length @ pts, 1}]]


      enter image description here



      enter image description here



      Two thing I would like to achieve:




      1. I don't want to see the yellow highlited region.

      2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


      Any suggestion..






      plotting filling







      share|improve this question











      $endgroup$




      I would like to shade area of region as a function of angle using PolarPlot.
      Here is my attempt.



      With[
      
  {pts = 
      
    Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
      
  Manipulate[
      
    Show[
      
      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]}, 
      
        Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}}, 
      
        PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1, 
      
        PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta], 
      
        ImageSize -> 500, AxesStyle -> Directive[Black, 18], 
      
        PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]], 
      
      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π}, 
      
        AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]], 
      
    {n, 1, Length @ pts, 1}]]


      enter image description here



      enter image description here



      Two thing I would like to achieve:




      1. I don't want to see the yellow highlited region.

      2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


      Any suggestion..






      plotting filling




      plotting filling






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago







      Okkes Dulgerci

















      asked 3 hours ago









      Okkes DulgerciOkkes Dulgerci

      5,4641919




      5,4641919






















          1 Answer
          1






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          2












          $begingroup$

          This is what you need:



          Manipulate[ParametricPlot[
          
  r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
          
  {θ, 0, thmax},
          
  {r, 0, 1},
          
  PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
          
  PerformanceGoal -> "Quality"
          
  ], {thmax, 0.01, 2 Pi}]


          Mathematica graphics






          share|improve this answer











          $endgroup$














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            1 Answer
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            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            This is what you need:



            Manipulate[ParametricPlot[
            
  r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
            
  {θ, 0, thmax},
            
  {r, 0, 1},
            
  PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
            
  PerformanceGoal -> "Quality"
            
  ], {thmax, 0.01, 2 Pi}]


            Mathematica graphics






            share|improve this answer











            $endgroup$


















              2












              $begingroup$

              This is what you need:



              Manipulate[ParametricPlot[
              
  r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
              
  {θ, 0, thmax},
              
  {r, 0, 1},
              
  PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
              
  PerformanceGoal -> "Quality"
              
  ], {thmax, 0.01, 2 Pi}]


              Mathematica graphics






              share|improve this answer











              $endgroup$
















                2












                2








                2





                $begingroup$

                This is what you need:



                Manipulate[ParametricPlot[
                
  r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
                
  {θ, 0, thmax},
                
  {r, 0, 1},
                
  PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
                
  PerformanceGoal -> "Quality"
                
  ], {thmax, 0.01, 2 Pi}]


                Mathematica graphics






                share|improve this answer











                $endgroup$



                This is what you need:



                Manipulate[ParametricPlot[
                
  r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
                
  {θ, 0, thmax},
                
  {r, 0, 1},
                
  PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
                
  PerformanceGoal -> "Quality"
                
  ], {thmax, 0.01, 2 Pi}]


                Mathematica graphics







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 35 mins ago









                m_goldberg

                88.9k873200




                88.9k873200










                answered 56 mins ago









                C. E.C. E.

                51.2k3101207




                51.2k3101207






























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