What does it mean to be “stable to deformation”?












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In the context of image classification, what does it mean to be stable to deformation? Say I were trying to classify digits, what would the difference be between an operation that is stable vs unstable to deformation?










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    Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
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    – Pedro Henrique Monforte
    yesterday
















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$begingroup$


In the context of image classification, what does it mean to be stable to deformation? Say I were trying to classify digits, what would the difference be between an operation that is stable vs unstable to deformation?










share|improve this question









$endgroup$












  • $begingroup$
    Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
    $endgroup$
    – Pedro Henrique Monforte
    yesterday














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$begingroup$


In the context of image classification, what does it mean to be stable to deformation? Say I were trying to classify digits, what would the difference be between an operation that is stable vs unstable to deformation?










share|improve this question









$endgroup$




In the context of image classification, what does it mean to be stable to deformation? Say I were trying to classify digits, what would the difference be between an operation that is stable vs unstable to deformation?







neural-network image-classification






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asked yesterday









IzzoIzzo

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  • $begingroup$
    Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
    $endgroup$
    – Pedro Henrique Monforte
    yesterday


















  • $begingroup$
    Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
    $endgroup$
    – Pedro Henrique Monforte
    yesterday
















$begingroup$
Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
$endgroup$
– Pedro Henrique Monforte
yesterday




$begingroup$
Could you provide some context? I think you are talking about afine transformations and models that are robust to such transformations, but I can't be sure. Where did you see this?
$endgroup$
– Pedro Henrique Monforte
yesterday










1 Answer
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Images are susceptible to deformations, i.e. afine or arbitrary deformations, such as "melting" effects.



In computer vision algorithms for non-constrained environments it may be desirable for a predictive model to be "stable", i.e. robust, ideally invariant, to arbitrary transformations that are common in that problem. E.g. a digit classifier would benefit from been stable to common paper deformations such as those caused by wrapping and unwrapping a long letter.



It is said that pooling layers insert certain stability to these deformations, this is analysed by Ruderman on his paper Learned Deformation Stability in Convolutional Neural Networks and in Pooling is neither necessary nor sufficient for
appropriate deformation stability in CNNs.



Some features, such as SIFT, BRISK and HoG try to deal with the most common deformations in image (Scale and Rotation). Most of convolution-dependent methods are already invariant to shifting as that is a feature of convolutional filtering itself.






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    $begingroup$

    Images are susceptible to deformations, i.e. afine or arbitrary deformations, such as "melting" effects.



    In computer vision algorithms for non-constrained environments it may be desirable for a predictive model to be "stable", i.e. robust, ideally invariant, to arbitrary transformations that are common in that problem. E.g. a digit classifier would benefit from been stable to common paper deformations such as those caused by wrapping and unwrapping a long letter.



    It is said that pooling layers insert certain stability to these deformations, this is analysed by Ruderman on his paper Learned Deformation Stability in Convolutional Neural Networks and in Pooling is neither necessary nor sufficient for
    appropriate deformation stability in CNNs.



    Some features, such as SIFT, BRISK and HoG try to deal with the most common deformations in image (Scale and Rotation). Most of convolution-dependent methods are already invariant to shifting as that is a feature of convolutional filtering itself.






    share|improve this answer









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      $begingroup$

      Images are susceptible to deformations, i.e. afine or arbitrary deformations, such as "melting" effects.



      In computer vision algorithms for non-constrained environments it may be desirable for a predictive model to be "stable", i.e. robust, ideally invariant, to arbitrary transformations that are common in that problem. E.g. a digit classifier would benefit from been stable to common paper deformations such as those caused by wrapping and unwrapping a long letter.



      It is said that pooling layers insert certain stability to these deformations, this is analysed by Ruderman on his paper Learned Deformation Stability in Convolutional Neural Networks and in Pooling is neither necessary nor sufficient for
      appropriate deformation stability in CNNs.



      Some features, such as SIFT, BRISK and HoG try to deal with the most common deformations in image (Scale and Rotation). Most of convolution-dependent methods are already invariant to shifting as that is a feature of convolutional filtering itself.






      share|improve this answer









      $endgroup$
















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        $begingroup$

        Images are susceptible to deformations, i.e. afine or arbitrary deformations, such as "melting" effects.



        In computer vision algorithms for non-constrained environments it may be desirable for a predictive model to be "stable", i.e. robust, ideally invariant, to arbitrary transformations that are common in that problem. E.g. a digit classifier would benefit from been stable to common paper deformations such as those caused by wrapping and unwrapping a long letter.



        It is said that pooling layers insert certain stability to these deformations, this is analysed by Ruderman on his paper Learned Deformation Stability in Convolutional Neural Networks and in Pooling is neither necessary nor sufficient for
        appropriate deformation stability in CNNs.



        Some features, such as SIFT, BRISK and HoG try to deal with the most common deformations in image (Scale and Rotation). Most of convolution-dependent methods are already invariant to shifting as that is a feature of convolutional filtering itself.






        share|improve this answer









        $endgroup$



        Images are susceptible to deformations, i.e. afine or arbitrary deformations, such as "melting" effects.



        In computer vision algorithms for non-constrained environments it may be desirable for a predictive model to be "stable", i.e. robust, ideally invariant, to arbitrary transformations that are common in that problem. E.g. a digit classifier would benefit from been stable to common paper deformations such as those caused by wrapping and unwrapping a long letter.



        It is said that pooling layers insert certain stability to these deformations, this is analysed by Ruderman on his paper Learned Deformation Stability in Convolutional Neural Networks and in Pooling is neither necessary nor sufficient for
        appropriate deformation stability in CNNs.



        Some features, such as SIFT, BRISK and HoG try to deal with the most common deformations in image (Scale and Rotation). Most of convolution-dependent methods are already invariant to shifting as that is a feature of convolutional filtering itself.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        Pedro Henrique MonfortePedro Henrique Monforte

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