How to grep and cut numbers from a file and sum them





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I have a log file. For every line with a specific number, I want to sum the last number of those lines. To grep and cut is no problem but I don't know how to sum the numbers. I tried some solutions from StackExchange but didn't get them to work in my case.



This is what I have so far:



grep "30201" logfile.txt | cut -f6 -d "|"


30201 are the lines I'm looking for.



I want to sum the last numbers 650, 1389 and 945



The logfile.txt



Jan 09 2016|09:15:17|30201|1|SL02|650
Jan 09 2016|09:15:18|43097|1|SL01|945
Jan 09 2016|09:15:19|28774|2|SB03|1389
Jan 09 2016|09:16:21|00788|1|SL02|650
Jan 09 2016|09:17:25|03361|3|SL01|945
Jan 09 2016|09:17:33|08385|1|SL02|650
Jan 09 2016|09:18:43|10234|1|SL01|945
Jan 09 2016|09:21:55|00788|1|SL02|650
Jan 09 2016|09:24:43|03361|3|SB03|1389
Jan 09 2016|09:26:01|30201|1|SB03|1389
Jan 09 2016|09:26:21|28774|2|SL02|650
Jan 09 2016|09:26:25|00788|1|SL02|650
Jan 09 2016|09:27:21|28774|2|SL02|650
Jan 09 2016|09:29:32|30201|1|SL01|945
Jan 09 2016|09:30:12|34032|1|SB03|1389
Jan 09 2016|09:30:15|08767|3|SL02|650









share|improve this question































    3















    I have a log file. For every line with a specific number, I want to sum the last number of those lines. To grep and cut is no problem but I don't know how to sum the numbers. I tried some solutions from StackExchange but didn't get them to work in my case.



    This is what I have so far:



    grep "30201" logfile.txt | cut -f6 -d "|"


    30201 are the lines I'm looking for.



    I want to sum the last numbers 650, 1389 and 945



    The logfile.txt



    Jan 09 2016|09:15:17|30201|1|SL02|650
    Jan 09 2016|09:15:18|43097|1|SL01|945
    Jan 09 2016|09:15:19|28774|2|SB03|1389
    Jan 09 2016|09:16:21|00788|1|SL02|650
    Jan 09 2016|09:17:25|03361|3|SL01|945
    Jan 09 2016|09:17:33|08385|1|SL02|650
    Jan 09 2016|09:18:43|10234|1|SL01|945
    Jan 09 2016|09:21:55|00788|1|SL02|650
    Jan 09 2016|09:24:43|03361|3|SB03|1389
    Jan 09 2016|09:26:01|30201|1|SB03|1389
    Jan 09 2016|09:26:21|28774|2|SL02|650
    Jan 09 2016|09:26:25|00788|1|SL02|650
    Jan 09 2016|09:27:21|28774|2|SL02|650
    Jan 09 2016|09:29:32|30201|1|SL01|945
    Jan 09 2016|09:30:12|34032|1|SB03|1389
    Jan 09 2016|09:30:15|08767|3|SL02|650









    share|improve this question



























      3












      3








      3


      2






      I have a log file. For every line with a specific number, I want to sum the last number of those lines. To grep and cut is no problem but I don't know how to sum the numbers. I tried some solutions from StackExchange but didn't get them to work in my case.



      This is what I have so far:



      grep "30201" logfile.txt | cut -f6 -d "|"


      30201 are the lines I'm looking for.



      I want to sum the last numbers 650, 1389 and 945



      The logfile.txt



      Jan 09 2016|09:15:17|30201|1|SL02|650
      Jan 09 2016|09:15:18|43097|1|SL01|945
      Jan 09 2016|09:15:19|28774|2|SB03|1389
      Jan 09 2016|09:16:21|00788|1|SL02|650
      Jan 09 2016|09:17:25|03361|3|SL01|945
      Jan 09 2016|09:17:33|08385|1|SL02|650
      Jan 09 2016|09:18:43|10234|1|SL01|945
      Jan 09 2016|09:21:55|00788|1|SL02|650
      Jan 09 2016|09:24:43|03361|3|SB03|1389
      Jan 09 2016|09:26:01|30201|1|SB03|1389
      Jan 09 2016|09:26:21|28774|2|SL02|650
      Jan 09 2016|09:26:25|00788|1|SL02|650
      Jan 09 2016|09:27:21|28774|2|SL02|650
      Jan 09 2016|09:29:32|30201|1|SL01|945
      Jan 09 2016|09:30:12|34032|1|SB03|1389
      Jan 09 2016|09:30:15|08767|3|SL02|650









      share|improve this question
















      I have a log file. For every line with a specific number, I want to sum the last number of those lines. To grep and cut is no problem but I don't know how to sum the numbers. I tried some solutions from StackExchange but didn't get them to work in my case.



      This is what I have so far:



      grep "30201" logfile.txt | cut -f6 -d "|"


      30201 are the lines I'm looking for.



      I want to sum the last numbers 650, 1389 and 945



      The logfile.txt



      Jan 09 2016|09:15:17|30201|1|SL02|650
      Jan 09 2016|09:15:18|43097|1|SL01|945
      Jan 09 2016|09:15:19|28774|2|SB03|1389
      Jan 09 2016|09:16:21|00788|1|SL02|650
      Jan 09 2016|09:17:25|03361|3|SL01|945
      Jan 09 2016|09:17:33|08385|1|SL02|650
      Jan 09 2016|09:18:43|10234|1|SL01|945
      Jan 09 2016|09:21:55|00788|1|SL02|650
      Jan 09 2016|09:24:43|03361|3|SB03|1389
      Jan 09 2016|09:26:01|30201|1|SB03|1389
      Jan 09 2016|09:26:21|28774|2|SL02|650
      Jan 09 2016|09:26:25|00788|1|SL02|650
      Jan 09 2016|09:27:21|28774|2|SL02|650
      Jan 09 2016|09:29:32|30201|1|SL01|945
      Jan 09 2016|09:30:12|34032|1|SB03|1389
      Jan 09 2016|09:30:15|08767|3|SL02|650






      text-processing grep logs cut numeric-data






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      share|improve this question













      share|improve this question




      share|improve this question








      edited 39 mins ago









      Jeff Schaller

      45k1164147




      45k1164147










      asked 12 hours ago









      YungScholarYungScholar

      233




      233






















          4 Answers
          4






          active

          oldest

          votes


















          7














          You can take help from paste to serialize the numbers in a format suitable for bc to do the addition:



          % grep "30201" logfile.txt | cut -f6 -d "|"
          650
          1389
          945

          % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+
          650+1389+945

          % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
          2984


          If you have grep with PCRE, you can do it with grep alone using postive lookbehind:



          % grep -Po '|30201|.*|Kd+' logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
          2984




          With awk alone:



          % awk -F'|' '$3 == 30201 {sum+=$NF}; END{print sum}' logfile.txt        
          2984




          • -F'|' sets the field separator as |


          • $3 == 30201 {sum+=$NF} adds up the last field's values if the third field is 30201


          • END{print sum} prints the sum at the END






          share|improve this answer


























          • Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

            – YungScholar
            12 hours ago






          • 2





            Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

            – Kusalananda
            10 hours ago





















          0














          Bash solution.



          #!/bin/bash
          pa=0 ; s=0 ;
          while read a b ; do
          if [ "$a" == "$pa" ] ; then
          s=$(($s+$b)) ;
          else
          if [ "$pa" != 0 ] ; then
          echo $pa $s ;
          fi ;
          pa=$a ; s=$b ;
          fi ;
          done < <(cat j.txt | awk -F'|' '{printf("%s %sn",$3,$6)}' | sort -n)
          echo $pa $s


          Init Previous A and SUM



          Cut down the input to fields 3 and 6 and sort them by number



          Loop as long as field 3 stays the same, add field 6 to the SUM



          if field 3 changes but the Previous A is not 0, output the Previous A and the SUM and reinit Previous A to a and SUM to last field 6 read.



          Output last Previous A and SUM.



          Output of the given input:



          00788 1950
          03361 2334
          08385 650
          08767 650
          10234 945
          28774 2689
          30201 2984
          34032 1389
          43097 945





          share|improve this answer
























          • Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

            – icarus
            4 hours ago



















          0














          There is nothing really wrong with your grep and cut command. You could make it more robust by using "|30201|" as the search pattern. The issue then is dealing with the output.



          Using bash:



          #!/bin/bash
          # get the output as a bash array and add the elements
          nums=( $(grep "|30201|" logfile.txt | cut -f6 -d "|") )
          total=0

          for i in ${!nums[@]}
          do
          total=$(($total+${nums[i]}))
          done
          echo $total





          share|improve this answer

































            0














            One little tool I keep around I call sumcol



            #!/bin/sh
            # Icarus Sparry. Free for any use.
            C=${1:?"missing required column number"}
            shift
            awk '{s+=$'"$C"'} END { print s }' "$@"


            which adds up the whitespace delimited column you provide. Whilst I would write (as @heemayl does)



            awk -F'|' '$3 == 30201 {s+=$6} END{ print s}' logfile.txt


            for the OP's problem, he could use



            grep "30201" logfile.txt | cut -f6 -d "|" | sumcol 1


            or



            grep "30201" logfile.txt | tr "| " " _" | sumcol 6





            share|improve this answer
























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              4 Answers
              4






              active

              oldest

              votes








              4 Answers
              4






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              7














              You can take help from paste to serialize the numbers in a format suitable for bc to do the addition:



              % grep "30201" logfile.txt | cut -f6 -d "|"
              650
              1389
              945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+
              650+1389+945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984


              If you have grep with PCRE, you can do it with grep alone using postive lookbehind:



              % grep -Po '|30201|.*|Kd+' logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984




              With awk alone:



              % awk -F'|' '$3 == 30201 {sum+=$NF}; END{print sum}' logfile.txt        
              2984




              • -F'|' sets the field separator as |


              • $3 == 30201 {sum+=$NF} adds up the last field's values if the third field is 30201


              • END{print sum} prints the sum at the END






              share|improve this answer


























              • Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

                – YungScholar
                12 hours ago






              • 2





                Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

                – Kusalananda
                10 hours ago


















              7














              You can take help from paste to serialize the numbers in a format suitable for bc to do the addition:



              % grep "30201" logfile.txt | cut -f6 -d "|"
              650
              1389
              945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+
              650+1389+945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984


              If you have grep with PCRE, you can do it with grep alone using postive lookbehind:



              % grep -Po '|30201|.*|Kd+' logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984




              With awk alone:



              % awk -F'|' '$3 == 30201 {sum+=$NF}; END{print sum}' logfile.txt        
              2984




              • -F'|' sets the field separator as |


              • $3 == 30201 {sum+=$NF} adds up the last field's values if the third field is 30201


              • END{print sum} prints the sum at the END






              share|improve this answer


























              • Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

                – YungScholar
                12 hours ago






              • 2





                Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

                – Kusalananda
                10 hours ago
















              7












              7








              7







              You can take help from paste to serialize the numbers in a format suitable for bc to do the addition:



              % grep "30201" logfile.txt | cut -f6 -d "|"
              650
              1389
              945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+
              650+1389+945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984


              If you have grep with PCRE, you can do it with grep alone using postive lookbehind:



              % grep -Po '|30201|.*|Kd+' logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984




              With awk alone:



              % awk -F'|' '$3 == 30201 {sum+=$NF}; END{print sum}' logfile.txt        
              2984




              • -F'|' sets the field separator as |


              • $3 == 30201 {sum+=$NF} adds up the last field's values if the third field is 30201


              • END{print sum} prints the sum at the END






              share|improve this answer















              You can take help from paste to serialize the numbers in a format suitable for bc to do the addition:



              % grep "30201" logfile.txt | cut -f6 -d "|"
              650
              1389
              945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+
              650+1389+945

              % grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984


              If you have grep with PCRE, you can do it with grep alone using postive lookbehind:



              % grep -Po '|30201|.*|Kd+' logfile.txt | cut -f6 -d "|" | paste -sd+ | bc
              2984




              With awk alone:



              % awk -F'|' '$3 == 30201 {sum+=$NF}; END{print sum}' logfile.txt        
              2984




              • -F'|' sets the field separator as |


              • $3 == 30201 {sum+=$NF} adds up the last field's values if the third field is 30201


              • END{print sum} prints the sum at the END







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 12 hours ago

























              answered 12 hours ago









              heemaylheemayl

              36.4k378108




              36.4k378108













              • Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

                – YungScholar
                12 hours ago






              • 2





                Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

                – Kusalananda
                10 hours ago





















              • Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

                – YungScholar
                12 hours ago






              • 2





                Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

                – Kusalananda
                10 hours ago



















              Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

              – YungScholar
              12 hours ago





              Thanks! grep "30201" logfile.txt | cut -f6 -d "|" | paste -sd+ dind't work for me, I got this errors (standard_in) 1: illegal character: ^M. But the solution with grep -Po '|30201|.*|Kd+' works. This is great!

              – YungScholar
              12 hours ago




              2




              2





              Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

              – Kusalananda
              10 hours ago







              Note that the grep solution does not care in what column the number is found, or whether the number is just a substring of a longer number. The awk solution is safer in this respect. The grep solution could be improved by first cutting and the matching the number at the start of the line (followed by |) with proper anchoring.

              – Kusalananda
              10 hours ago















              0














              Bash solution.



              #!/bin/bash
              pa=0 ; s=0 ;
              while read a b ; do
              if [ "$a" == "$pa" ] ; then
              s=$(($s+$b)) ;
              else
              if [ "$pa" != 0 ] ; then
              echo $pa $s ;
              fi ;
              pa=$a ; s=$b ;
              fi ;
              done < <(cat j.txt | awk -F'|' '{printf("%s %sn",$3,$6)}' | sort -n)
              echo $pa $s


              Init Previous A and SUM



              Cut down the input to fields 3 and 6 and sort them by number



              Loop as long as field 3 stays the same, add field 6 to the SUM



              if field 3 changes but the Previous A is not 0, output the Previous A and the SUM and reinit Previous A to a and SUM to last field 6 read.



              Output last Previous A and SUM.



              Output of the given input:



              00788 1950
              03361 2334
              08385 650
              08767 650
              10234 945
              28774 2689
              30201 2984
              34032 1389
              43097 945





              share|improve this answer
























              • Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

                – icarus
                4 hours ago
















              0














              Bash solution.



              #!/bin/bash
              pa=0 ; s=0 ;
              while read a b ; do
              if [ "$a" == "$pa" ] ; then
              s=$(($s+$b)) ;
              else
              if [ "$pa" != 0 ] ; then
              echo $pa $s ;
              fi ;
              pa=$a ; s=$b ;
              fi ;
              done < <(cat j.txt | awk -F'|' '{printf("%s %sn",$3,$6)}' | sort -n)
              echo $pa $s


              Init Previous A and SUM



              Cut down the input to fields 3 and 6 and sort them by number



              Loop as long as field 3 stays the same, add field 6 to the SUM



              if field 3 changes but the Previous A is not 0, output the Previous A and the SUM and reinit Previous A to a and SUM to last field 6 read.



              Output last Previous A and SUM.



              Output of the given input:



              00788 1950
              03361 2334
              08385 650
              08767 650
              10234 945
              28774 2689
              30201 2984
              34032 1389
              43097 945





              share|improve this answer
























              • Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

                – icarus
                4 hours ago














              0












              0








              0







              Bash solution.



              #!/bin/bash
              pa=0 ; s=0 ;
              while read a b ; do
              if [ "$a" == "$pa" ] ; then
              s=$(($s+$b)) ;
              else
              if [ "$pa" != 0 ] ; then
              echo $pa $s ;
              fi ;
              pa=$a ; s=$b ;
              fi ;
              done < <(cat j.txt | awk -F'|' '{printf("%s %sn",$3,$6)}' | sort -n)
              echo $pa $s


              Init Previous A and SUM



              Cut down the input to fields 3 and 6 and sort them by number



              Loop as long as field 3 stays the same, add field 6 to the SUM



              if field 3 changes but the Previous A is not 0, output the Previous A and the SUM and reinit Previous A to a and SUM to last field 6 read.



              Output last Previous A and SUM.



              Output of the given input:



              00788 1950
              03361 2334
              08385 650
              08767 650
              10234 945
              28774 2689
              30201 2984
              34032 1389
              43097 945





              share|improve this answer













              Bash solution.



              #!/bin/bash
              pa=0 ; s=0 ;
              while read a b ; do
              if [ "$a" == "$pa" ] ; then
              s=$(($s+$b)) ;
              else
              if [ "$pa" != 0 ] ; then
              echo $pa $s ;
              fi ;
              pa=$a ; s=$b ;
              fi ;
              done < <(cat j.txt | awk -F'|' '{printf("%s %sn",$3,$6)}' | sort -n)
              echo $pa $s


              Init Previous A and SUM



              Cut down the input to fields 3 and 6 and sort them by number



              Loop as long as field 3 stays the same, add field 6 to the SUM



              if field 3 changes but the Previous A is not 0, output the Previous A and the SUM and reinit Previous A to a and SUM to last field 6 read.



              Output last Previous A and SUM.



              Output of the given input:



              00788 1950
              03361 2334
              08385 650
              08767 650
              10234 945
              28774 2689
              30201 2984
              34032 1389
              43097 945






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered 11 hours ago









              JdeHaanJdeHaan

              359214




              359214













              • Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

                – icarus
                4 hours ago



















              • Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

                – icarus
                4 hours ago

















              Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

              – icarus
              4 hours ago





              Given you are using awk anyway to select the third and sixth columns, you should go the extra steps and sum things inside awk. This would give you something like awk -F'|' '{s[$3]+=$6}END{ for (i in s) { print i, s[i] }}' | sort - GNU awk has a builtin asort which could also be used rather than an external sort.

              – icarus
              4 hours ago











              0














              There is nothing really wrong with your grep and cut command. You could make it more robust by using "|30201|" as the search pattern. The issue then is dealing with the output.



              Using bash:



              #!/bin/bash
              # get the output as a bash array and add the elements
              nums=( $(grep "|30201|" logfile.txt | cut -f6 -d "|") )
              total=0

              for i in ${!nums[@]}
              do
              total=$(($total+${nums[i]}))
              done
              echo $total





              share|improve this answer






























                0














                There is nothing really wrong with your grep and cut command. You could make it more robust by using "|30201|" as the search pattern. The issue then is dealing with the output.



                Using bash:



                #!/bin/bash
                # get the output as a bash array and add the elements
                nums=( $(grep "|30201|" logfile.txt | cut -f6 -d "|") )
                total=0

                for i in ${!nums[@]}
                do
                total=$(($total+${nums[i]}))
                done
                echo $total





                share|improve this answer




























                  0












                  0








                  0







                  There is nothing really wrong with your grep and cut command. You could make it more robust by using "|30201|" as the search pattern. The issue then is dealing with the output.



                  Using bash:



                  #!/bin/bash
                  # get the output as a bash array and add the elements
                  nums=( $(grep "|30201|" logfile.txt | cut -f6 -d "|") )
                  total=0

                  for i in ${!nums[@]}
                  do
                  total=$(($total+${nums[i]}))
                  done
                  echo $total





                  share|improve this answer















                  There is nothing really wrong with your grep and cut command. You could make it more robust by using "|30201|" as the search pattern. The issue then is dealing with the output.



                  Using bash:



                  #!/bin/bash
                  # get the output as a bash array and add the elements
                  nums=( $(grep "|30201|" logfile.txt | cut -f6 -d "|") )
                  total=0

                  for i in ${!nums[@]}
                  do
                  total=$(($total+${nums[i]}))
                  done
                  echo $total






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 7 hours ago

























                  answered 7 hours ago









                  WastrelWastrel

                  11




                  11























                      0














                      One little tool I keep around I call sumcol



                      #!/bin/sh
                      # Icarus Sparry. Free for any use.
                      C=${1:?"missing required column number"}
                      shift
                      awk '{s+=$'"$C"'} END { print s }' "$@"


                      which adds up the whitespace delimited column you provide. Whilst I would write (as @heemayl does)



                      awk -F'|' '$3 == 30201 {s+=$6} END{ print s}' logfile.txt


                      for the OP's problem, he could use



                      grep "30201" logfile.txt | cut -f6 -d "|" | sumcol 1


                      or



                      grep "30201" logfile.txt | tr "| " " _" | sumcol 6





                      share|improve this answer




























                        0














                        One little tool I keep around I call sumcol



                        #!/bin/sh
                        # Icarus Sparry. Free for any use.
                        C=${1:?"missing required column number"}
                        shift
                        awk '{s+=$'"$C"'} END { print s }' "$@"


                        which adds up the whitespace delimited column you provide. Whilst I would write (as @heemayl does)



                        awk -F'|' '$3 == 30201 {s+=$6} END{ print s}' logfile.txt


                        for the OP's problem, he could use



                        grep "30201" logfile.txt | cut -f6 -d "|" | sumcol 1


                        or



                        grep "30201" logfile.txt | tr "| " " _" | sumcol 6





                        share|improve this answer


























                          0












                          0








                          0







                          One little tool I keep around I call sumcol



                          #!/bin/sh
                          # Icarus Sparry. Free for any use.
                          C=${1:?"missing required column number"}
                          shift
                          awk '{s+=$'"$C"'} END { print s }' "$@"


                          which adds up the whitespace delimited column you provide. Whilst I would write (as @heemayl does)



                          awk -F'|' '$3 == 30201 {s+=$6} END{ print s}' logfile.txt


                          for the OP's problem, he could use



                          grep "30201" logfile.txt | cut -f6 -d "|" | sumcol 1


                          or



                          grep "30201" logfile.txt | tr "| " " _" | sumcol 6





                          share|improve this answer













                          One little tool I keep around I call sumcol



                          #!/bin/sh
                          # Icarus Sparry. Free for any use.
                          C=${1:?"missing required column number"}
                          shift
                          awk '{s+=$'"$C"'} END { print s }' "$@"


                          which adds up the whitespace delimited column you provide. Whilst I would write (as @heemayl does)



                          awk -F'|' '$3 == 30201 {s+=$6} END{ print s}' logfile.txt


                          for the OP's problem, he could use



                          grep "30201" logfile.txt | cut -f6 -d "|" | sumcol 1


                          or



                          grep "30201" logfile.txt | tr "| " " _" | sumcol 6






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 4 hours ago









                          icarusicarus

                          6,21611231




                          6,21611231






























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