Bracket schedule












4












$begingroup$


my friends and I are doing beer Olympics. There are 12 teams with 6 games. Each game has its own “bracket”. Essentially there will be 6 winners, 1 from each bracket or game. Those teams will then compete in the playoffs. Yes I know a bracket with 12 teams doesn’t come out evenly, I have it figured out. My question to you is, how can schedule where each team plays one game for each game in the first round without playing another team twice. ALSO while having them go in a rotation.



To make this more clear, each “session” every team will he participating in 1 game. After all games finish, I would to be able to rotate these teams to a game they haven’t played yet, but also against a team they haven’t played yet as well. Ive tried trial and error but I’m currently having a problem with it. Can someone help me out?



Too add onto this, all 12 teams are playing simultaneously (6 games, 2 teams per). Once all the single games end, teams must rotate to another game all while playing a different team.



See if this helps.. First game of Event 1: T1 vs T2, 1st game of event 2: T3 vs T4, 1st game of event 3: T5 vs T6, 1st game of event 4: T7 vs T8, first game of event 5: T9 vs T10, first game of event 6: T11 vs T12. Now all the first games of each event are competed. Now for the 2nd games of each event. 2nd game of E1: T1 vs T12, 2nd game of E2: T2 vs T3, 2nd game of E3: T4 vs T5, 2nd game of E4: T6 vs T7, 2nd game of E5: T8 vs T9, 2nd game of E6: T10 vs T11. I need games 3-6 for each event to go in a rotation where each team plays a different game against a different team.










share|improve this question









New contributor




Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$












  • $begingroup$
    How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
    $endgroup$
    – Dr Xorile
    1 hour ago










  • $begingroup$
    I commented below and went more in depth...
    $endgroup$
    – Eric
    1 hour ago










  • $begingroup$
    Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
    $endgroup$
    – PiIsNot3
    1 hour ago










  • $begingroup$
    I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
    $endgroup$
    – Brandon_J
    1 hour ago






  • 1




    $begingroup$
    @PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
    $endgroup$
    – Brandon_J
    1 hour ago
















4












$begingroup$


my friends and I are doing beer Olympics. There are 12 teams with 6 games. Each game has its own “bracket”. Essentially there will be 6 winners, 1 from each bracket or game. Those teams will then compete in the playoffs. Yes I know a bracket with 12 teams doesn’t come out evenly, I have it figured out. My question to you is, how can schedule where each team plays one game for each game in the first round without playing another team twice. ALSO while having them go in a rotation.



To make this more clear, each “session” every team will he participating in 1 game. After all games finish, I would to be able to rotate these teams to a game they haven’t played yet, but also against a team they haven’t played yet as well. Ive tried trial and error but I’m currently having a problem with it. Can someone help me out?



Too add onto this, all 12 teams are playing simultaneously (6 games, 2 teams per). Once all the single games end, teams must rotate to another game all while playing a different team.



See if this helps.. First game of Event 1: T1 vs T2, 1st game of event 2: T3 vs T4, 1st game of event 3: T5 vs T6, 1st game of event 4: T7 vs T8, first game of event 5: T9 vs T10, first game of event 6: T11 vs T12. Now all the first games of each event are competed. Now for the 2nd games of each event. 2nd game of E1: T1 vs T12, 2nd game of E2: T2 vs T3, 2nd game of E3: T4 vs T5, 2nd game of E4: T6 vs T7, 2nd game of E5: T8 vs T9, 2nd game of E6: T10 vs T11. I need games 3-6 for each event to go in a rotation where each team plays a different game against a different team.










share|improve this question









New contributor




Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
    $endgroup$
    – Dr Xorile
    1 hour ago










  • $begingroup$
    I commented below and went more in depth...
    $endgroup$
    – Eric
    1 hour ago










  • $begingroup$
    Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
    $endgroup$
    – PiIsNot3
    1 hour ago










  • $begingroup$
    I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
    $endgroup$
    – Brandon_J
    1 hour ago






  • 1




    $begingroup$
    @PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
    $endgroup$
    – Brandon_J
    1 hour ago














4












4








4





$begingroup$


my friends and I are doing beer Olympics. There are 12 teams with 6 games. Each game has its own “bracket”. Essentially there will be 6 winners, 1 from each bracket or game. Those teams will then compete in the playoffs. Yes I know a bracket with 12 teams doesn’t come out evenly, I have it figured out. My question to you is, how can schedule where each team plays one game for each game in the first round without playing another team twice. ALSO while having them go in a rotation.



To make this more clear, each “session” every team will he participating in 1 game. After all games finish, I would to be able to rotate these teams to a game they haven’t played yet, but also against a team they haven’t played yet as well. Ive tried trial and error but I’m currently having a problem with it. Can someone help me out?



Too add onto this, all 12 teams are playing simultaneously (6 games, 2 teams per). Once all the single games end, teams must rotate to another game all while playing a different team.



See if this helps.. First game of Event 1: T1 vs T2, 1st game of event 2: T3 vs T4, 1st game of event 3: T5 vs T6, 1st game of event 4: T7 vs T8, first game of event 5: T9 vs T10, first game of event 6: T11 vs T12. Now all the first games of each event are competed. Now for the 2nd games of each event. 2nd game of E1: T1 vs T12, 2nd game of E2: T2 vs T3, 2nd game of E3: T4 vs T5, 2nd game of E4: T6 vs T7, 2nd game of E5: T8 vs T9, 2nd game of E6: T10 vs T11. I need games 3-6 for each event to go in a rotation where each team plays a different game against a different team.










share|improve this question









New contributor




Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




my friends and I are doing beer Olympics. There are 12 teams with 6 games. Each game has its own “bracket”. Essentially there will be 6 winners, 1 from each bracket or game. Those teams will then compete in the playoffs. Yes I know a bracket with 12 teams doesn’t come out evenly, I have it figured out. My question to you is, how can schedule where each team plays one game for each game in the first round without playing another team twice. ALSO while having them go in a rotation.



To make this more clear, each “session” every team will he participating in 1 game. After all games finish, I would to be able to rotate these teams to a game they haven’t played yet, but also against a team they haven’t played yet as well. Ive tried trial and error but I’m currently having a problem with it. Can someone help me out?



Too add onto this, all 12 teams are playing simultaneously (6 games, 2 teams per). Once all the single games end, teams must rotate to another game all while playing a different team.



See if this helps.. First game of Event 1: T1 vs T2, 1st game of event 2: T3 vs T4, 1st game of event 3: T5 vs T6, 1st game of event 4: T7 vs T8, first game of event 5: T9 vs T10, first game of event 6: T11 vs T12. Now all the first games of each event are competed. Now for the 2nd games of each event. 2nd game of E1: T1 vs T12, 2nd game of E2: T2 vs T3, 2nd game of E3: T4 vs T5, 2nd game of E4: T6 vs T7, 2nd game of E5: T8 vs T9, 2nd game of E6: T10 vs T11. I need games 3-6 for each event to go in a rotation where each team plays a different game against a different team.







mathematics sports






share|improve this question









New contributor




Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|improve this question









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share|improve this question




share|improve this question








edited 36 mins ago







Eric













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asked 1 hour ago









EricEric

212




212




New contributor




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New contributor





Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Eric is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
    $endgroup$
    – Dr Xorile
    1 hour ago










  • $begingroup$
    I commented below and went more in depth...
    $endgroup$
    – Eric
    1 hour ago










  • $begingroup$
    Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
    $endgroup$
    – PiIsNot3
    1 hour ago










  • $begingroup$
    I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
    $endgroup$
    – Brandon_J
    1 hour ago






  • 1




    $begingroup$
    @PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
    $endgroup$
    – Brandon_J
    1 hour ago


















  • $begingroup$
    How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
    $endgroup$
    – Dr Xorile
    1 hour ago










  • $begingroup$
    I commented below and went more in depth...
    $endgroup$
    – Eric
    1 hour ago










  • $begingroup$
    Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
    $endgroup$
    – PiIsNot3
    1 hour ago










  • $begingroup$
    I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
    $endgroup$
    – Brandon_J
    1 hour ago






  • 1




    $begingroup$
    @PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
    $endgroup$
    – Brandon_J
    1 hour ago
















$begingroup$
How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
$endgroup$
– Dr Xorile
1 hour ago




$begingroup$
How many players are there in a game? Are they all two player games? Are you trying to do a round robin in each bracket or a direct elimination or what?
$endgroup$
– Dr Xorile
1 hour ago












$begingroup$
I commented below and went more in depth...
$endgroup$
– Eric
1 hour ago




$begingroup$
I commented below and went more in depth...
$endgroup$
– Eric
1 hour ago












$begingroup$
Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
$endgroup$
– PiIsNot3
1 hour ago




$begingroup$
Hi @Eric, welcome to Puzzling Stack Exchange! (Take the tour if you haven’t already!) This sounds more like a math problem than a puzzle. In general, math textbook style problems are considered off-topic here and may be better off posted elsewhere such as in MSE. Thanks!
$endgroup$
– PiIsNot3
1 hour ago












$begingroup$
I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
$endgroup$
– Brandon_J
1 hour ago




$begingroup$
I think I see the problem that's confusing everyone - you not only want a tournament, but you have different contests in the tournament, and don't want a single time to participate in any single contest more than once. I.e. if a team has already played and won beer pong, then they have to play beer chess or beer soccer (no, I'm not a drinker; how'd you tell?).
$endgroup$
– Brandon_J
1 hour ago




1




1




$begingroup$
@PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
$endgroup$
– Brandon_J
1 hour ago




$begingroup$
@PiIsNot3 math puzzles are OK, and I don't think that this is a textbook-style problem. Not sure though; just my initial reaction.
$endgroup$
– Brandon_J
1 hour ago










2 Answers
2






active

oldest

votes


















1












$begingroup$

So maybe you have to change the separation. I think this is one sample that works:



1v2 3v4 5v6 7v8 9v10 11v12



1v3 2v4 5v7 6v8 9v11 10v12



1v4 2v5 3v6 7v10 8v11 9v12



1v5 2v9 3v10 4v11 6v7 8v12



1v6 2v7 3v8 4v9 5v12 10v11



1v7 2v8 3v9 4v10 5v11 6v12






share|improve this answer









$endgroup$





















    0












    $begingroup$

    I'm not totally sure I've got your question right. But a standard way to run a round robin is to make a dot for each player. One in the centre and the others spaced around a circle. (if there's an odd number of players add one extra to make it even and anyone playing that extra one gets a bye).



    Then draw a line from the center out to one of the edge dots and join the rest of them in pairs perpendicular to the first line.



    This structure can then be rotated to get all the arrangements.



    Here's a literal back-of-the-envelope:



    round robin method



    In your case (if I understand you), you're essentially running a round robin, so you'll have to rotate the games through the lines while you rotate the lines around to make the match ups.






    share|improve this answer











    $endgroup$













    • $begingroup$
      okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
      $endgroup$
      – Eric
      1 hour ago












    • $begingroup$
      A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
      $endgroup$
      – Eric
      1 hour ago










    • $begingroup$
      Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
      $endgroup$
      – Dr Xorile
      16 mins ago










    • $begingroup$
      At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
      $endgroup$
      – Dr Xorile
      9 mins ago












    Your Answer





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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    So maybe you have to change the separation. I think this is one sample that works:



    1v2 3v4 5v6 7v8 9v10 11v12



    1v3 2v4 5v7 6v8 9v11 10v12



    1v4 2v5 3v6 7v10 8v11 9v12



    1v5 2v9 3v10 4v11 6v7 8v12



    1v6 2v7 3v8 4v9 5v12 10v11



    1v7 2v8 3v9 4v10 5v11 6v12






    share|improve this answer









    $endgroup$


















      1












      $begingroup$

      So maybe you have to change the separation. I think this is one sample that works:



      1v2 3v4 5v6 7v8 9v10 11v12



      1v3 2v4 5v7 6v8 9v11 10v12



      1v4 2v5 3v6 7v10 8v11 9v12



      1v5 2v9 3v10 4v11 6v7 8v12



      1v6 2v7 3v8 4v9 5v12 10v11



      1v7 2v8 3v9 4v10 5v11 6v12






      share|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        So maybe you have to change the separation. I think this is one sample that works:



        1v2 3v4 5v6 7v8 9v10 11v12



        1v3 2v4 5v7 6v8 9v11 10v12



        1v4 2v5 3v6 7v10 8v11 9v12



        1v5 2v9 3v10 4v11 6v7 8v12



        1v6 2v7 3v8 4v9 5v12 10v11



        1v7 2v8 3v9 4v10 5v11 6v12






        share|improve this answer









        $endgroup$



        So maybe you have to change the separation. I think this is one sample that works:



        1v2 3v4 5v6 7v8 9v10 11v12



        1v3 2v4 5v7 6v8 9v11 10v12



        1v4 2v5 3v6 7v10 8v11 9v12



        1v5 2v9 3v10 4v11 6v7 8v12



        1v6 2v7 3v8 4v9 5v12 10v11



        1v7 2v8 3v9 4v10 5v11 6v12







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 29 mins ago









        El-GuestEl-Guest

        21.7k35092




        21.7k35092























            0












            $begingroup$

            I'm not totally sure I've got your question right. But a standard way to run a round robin is to make a dot for each player. One in the centre and the others spaced around a circle. (if there's an odd number of players add one extra to make it even and anyone playing that extra one gets a bye).



            Then draw a line from the center out to one of the edge dots and join the rest of them in pairs perpendicular to the first line.



            This structure can then be rotated to get all the arrangements.



            Here's a literal back-of-the-envelope:



            round robin method



            In your case (if I understand you), you're essentially running a round robin, so you'll have to rotate the games through the lines while you rotate the lines around to make the match ups.






            share|improve this answer











            $endgroup$













            • $begingroup$
              okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
              $endgroup$
              – Eric
              1 hour ago












            • $begingroup$
              A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
              $endgroup$
              – Eric
              1 hour ago










            • $begingroup$
              Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
              $endgroup$
              – Dr Xorile
              16 mins ago










            • $begingroup$
              At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
              $endgroup$
              – Dr Xorile
              9 mins ago
















            0












            $begingroup$

            I'm not totally sure I've got your question right. But a standard way to run a round robin is to make a dot for each player. One in the centre and the others spaced around a circle. (if there's an odd number of players add one extra to make it even and anyone playing that extra one gets a bye).



            Then draw a line from the center out to one of the edge dots and join the rest of them in pairs perpendicular to the first line.



            This structure can then be rotated to get all the arrangements.



            Here's a literal back-of-the-envelope:



            round robin method



            In your case (if I understand you), you're essentially running a round robin, so you'll have to rotate the games through the lines while you rotate the lines around to make the match ups.






            share|improve this answer











            $endgroup$













            • $begingroup$
              okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
              $endgroup$
              – Eric
              1 hour ago












            • $begingroup$
              A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
              $endgroup$
              – Eric
              1 hour ago










            • $begingroup$
              Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
              $endgroup$
              – Dr Xorile
              16 mins ago










            • $begingroup$
              At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
              $endgroup$
              – Dr Xorile
              9 mins ago














            0












            0








            0





            $begingroup$

            I'm not totally sure I've got your question right. But a standard way to run a round robin is to make a dot for each player. One in the centre and the others spaced around a circle. (if there's an odd number of players add one extra to make it even and anyone playing that extra one gets a bye).



            Then draw a line from the center out to one of the edge dots and join the rest of them in pairs perpendicular to the first line.



            This structure can then be rotated to get all the arrangements.



            Here's a literal back-of-the-envelope:



            round robin method



            In your case (if I understand you), you're essentially running a round robin, so you'll have to rotate the games through the lines while you rotate the lines around to make the match ups.






            share|improve this answer











            $endgroup$



            I'm not totally sure I've got your question right. But a standard way to run a round robin is to make a dot for each player. One in the centre and the others spaced around a circle. (if there's an odd number of players add one extra to make it even and anyone playing that extra one gets a bye).



            Then draw a line from the center out to one of the edge dots and join the rest of them in pairs perpendicular to the first line.



            This structure can then be rotated to get all the arrangements.



            Here's a literal back-of-the-envelope:



            round robin method



            In your case (if I understand you), you're essentially running a round robin, so you'll have to rotate the games through the lines while you rotate the lines around to make the match ups.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 1 hour ago

























            answered 1 hour ago









            Dr XorileDr Xorile

            14.1k33083




            14.1k33083












            • $begingroup$
              okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
              $endgroup$
              – Eric
              1 hour ago












            • $begingroup$
              A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
              $endgroup$
              – Eric
              1 hour ago










            • $begingroup$
              Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
              $endgroup$
              – Dr Xorile
              16 mins ago










            • $begingroup$
              At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
              $endgroup$
              – Dr Xorile
              9 mins ago


















            • $begingroup$
              okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
              $endgroup$
              – Eric
              1 hour ago












            • $begingroup$
              A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
              $endgroup$
              – Eric
              1 hour ago










            • $begingroup$
              Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
              $endgroup$
              – Dr Xorile
              16 mins ago










            • $begingroup$
              At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
              $endgroup$
              – Dr Xorile
              9 mins ago
















            $begingroup$
            okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
            $endgroup$
            – Eric
            1 hour ago






            $begingroup$
            okay let me try to explain more... so if you’ve ever seen a bracket, such as the March madness bracket. The first round or “round of 64” has 32 mini brackets or two lines joined together to represent the teams that are playing each other. For mine, I only have 12 teams, so the first round of “round of 12” has 6 mini brackets or 6 two lined objects joined together (it eventually minimizes to 6 teams then 3). There 6 individual brackets, 1 for each game. I need for every team to play the game once in the round of 12 and never play a team twice in that round of 12. BUTalso while having a rotation
            $endgroup$
            – Eric
            1 hour ago














            $begingroup$
            A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
            $endgroup$
            – Eric
            1 hour ago




            $begingroup$
            A rotation so I can be able to call out each team and tell them where there next game is without having any problems. Is this making sense?
            $endgroup$
            – Eric
            1 hour ago












            $begingroup$
            Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
            $endgroup$
            – Dr Xorile
            16 mins ago




            $begingroup$
            Okay. Then my answer will work. I'll try to make it clearer later but if you work through it it will give you the answer you're looking for
            $endgroup$
            – Dr Xorile
            16 mins ago












            $begingroup$
            At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
            $endgroup$
            – Dr Xorile
            9 mins ago




            $begingroup$
            At least roughly. It's not possible to do it exactly. You'll have 11 rounds until everyone has met everyone else, so not quite enough for everyone to play every game twice
            $endgroup$
            – Dr Xorile
            9 mins ago










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