What's the next image 2?
$begingroup$
Can you help me with this one:
It is from a local IQ test from the schools in Vratsa, Bulgaria.
Thanks,
Todor
visual
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
$endgroup$
add a comment |
$begingroup$
Can you help me with this one:
It is from a local IQ test from the schools in Vratsa, Bulgaria.
Thanks,
Todor
visual
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
$endgroup$
$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
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might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
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@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago
add a comment |
$begingroup$
Can you help me with this one:
It is from a local IQ test from the schools in Vratsa, Bulgaria.
Thanks,
Todor
visual
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
$endgroup$
Can you help me with this one:
It is from a local IQ test from the schools in Vratsa, Bulgaria.
Thanks,
Todor
visual
visual
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
asked Aug 18 '18 at 18:51
Todor BonchevTodor Bonchev
363
363
$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
$begingroup$
might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
$begingroup$
@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago
add a comment |
$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
$begingroup$
might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
$begingroup$
@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago
$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
$begingroup$
might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
$begingroup$
might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
$begingroup$
@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago
$begingroup$
@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
SPOILER ALERT -- scroll down to my answer:
Answer I get is "C". The logic: Considering only the sides that have dots count the number of unique sides for each example (consider both number and position of dots). Example 1 has 3 unique sides. Example 2 has 2 unique sides. Example 3 has 2 unique sides. Example 4 has 3 unique sides. Example 5 has no dots. Now the number of different or unique patterns on TOP of each example will be the same as the number of unique sides for each example.
answered 8 mins ago
Bob BixlerBob Bixler
17519
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add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
SPOILER ALERT -- scroll down to my answer:
Answer I get is "C". The logic: Considering only the sides that have dots count the number of unique sides for each example (consider both number and position of dots). Example 1 has 3 unique sides. Example 2 has 2 unique sides. Example 3 has 2 unique sides. Example 4 has 3 unique sides. Example 5 has no dots. Now the number of different or unique patterns on TOP of each example will be the same as the number of unique sides for each example.
answered 8 mins ago
Bob BixlerBob Bixler
17519
$endgroup$
add a comment |
$begingroup$
SPOILER ALERT -- scroll down to my answer:
Answer I get is "C". The logic: Considering only the sides that have dots count the number of unique sides for each example (consider both number and position of dots). Example 1 has 3 unique sides. Example 2 has 2 unique sides. Example 3 has 2 unique sides. Example 4 has 3 unique sides. Example 5 has no dots. Now the number of different or unique patterns on TOP of each example will be the same as the number of unique sides for each example.
answered 8 mins ago
Bob BixlerBob Bixler
17519
$endgroup$
add a comment |
$begingroup$
SPOILER ALERT -- scroll down to my answer:
Answer I get is "C". The logic: Considering only the sides that have dots count the number of unique sides for each example (consider both number and position of dots). Example 1 has 3 unique sides. Example 2 has 2 unique sides. Example 3 has 2 unique sides. Example 4 has 3 unique sides. Example 5 has no dots. Now the number of different or unique patterns on TOP of each example will be the same as the number of unique sides for each example.
answered 8 mins ago
Bob BixlerBob Bixler
17519
$endgroup$
SPOILER ALERT -- scroll down to my answer:
Answer I get is "C". The logic: Considering only the sides that have dots count the number of unique sides for each example (consider both number and position of dots). Example 1 has 3 unique sides. Example 2 has 2 unique sides. Example 3 has 2 unique sides. Example 4 has 3 unique sides. Example 5 has no dots. Now the number of different or unique patterns on TOP of each example will be the same as the number of unique sides for each example.
answered 8 mins ago
Bob BixlerBob Bixler
17519
edited 1 min ago
answered 8 mins ago
Bob BixlerBob Bixler
17519
answered 8 mins ago
Bob BixlerBob Bixler
17519
answered 8 mins ago
Bob BixlerBob Bixler
17519
17519
add a comment |
add a comment |
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$begingroup$
this is what happens when you ask 999 monkeys to make an IQ test!
$endgroup$
– JonMark Perry
Aug 18 '18 at 19:03
$begingroup$
might be C (it looking like mixing of all)
$endgroup$
– CR241
Aug 22 '18 at 23:44
$begingroup$
@BobBixler this is an answer instead of a comment. please post this as an answer and spoiler it for the sake of other users. thanks!
$endgroup$
– Omega Krypton
5 hours ago