How to remove specific numbers from a txt file with SED or AWK?
I work on a company that will not let me install any software on my computers and I run awful windows there.
I need to clean a lot of texts I copy from the intranet and save as a txt file. So I have to use sed
and/or awk
online live editors, like this or this
These texts are like this
01
010010-26.2010.501.0026 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
fdfsadf adsf adsf asdf asdfas fadsf asdfa
02
0011-15.2016.501.0012 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
asdfasd fasd asasdff
asdfasd fasd asasdff
0011-125.2013.501.0012
asdfasd fasd asasdff
See the numbers like 0011-15.2016.501.0012
this is what I want. I do not care for the rest but I want to create a new clean text with all these numbers, one per line. In the previous example, I need a text with
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
the .501.
is always present, in all numbers, as the 4th group.
I have tried this command on the sed online editor
's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*)/1/'
Not working.
text-processing awk sed
add a comment |
I work on a company that will not let me install any software on my computers and I run awful windows there.
I need to clean a lot of texts I copy from the intranet and save as a txt file. So I have to use sed
and/or awk
online live editors, like this or this
These texts are like this
01
010010-26.2010.501.0026 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
fdfsadf adsf adsf asdf asdfas fadsf asdfa
02
0011-15.2016.501.0012 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
asdfasd fasd asasdff
asdfasd fasd asasdff
0011-125.2013.501.0012
asdfasd fasd asasdff
See the numbers like 0011-15.2016.501.0012
this is what I want. I do not care for the rest but I want to create a new clean text with all these numbers, one per line. In the previous example, I need a text with
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
the .501.
is always present, in all numbers, as the 4th group.
I have tried this command on the sed online editor
's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*)/1/'
Not working.
text-processing awk sed
I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago
add a comment |
I work on a company that will not let me install any software on my computers and I run awful windows there.
I need to clean a lot of texts I copy from the intranet and save as a txt file. So I have to use sed
and/or awk
online live editors, like this or this
These texts are like this
01
010010-26.2010.501.0026 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
fdfsadf adsf adsf asdf asdfas fadsf asdfa
02
0011-15.2016.501.0012 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
asdfasd fasd asasdff
asdfasd fasd asasdff
0011-125.2013.501.0012
asdfasd fasd asasdff
See the numbers like 0011-15.2016.501.0012
this is what I want. I do not care for the rest but I want to create a new clean text with all these numbers, one per line. In the previous example, I need a text with
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
the .501.
is always present, in all numbers, as the 4th group.
I have tried this command on the sed online editor
's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*)/1/'
Not working.
text-processing awk sed
I work on a company that will not let me install any software on my computers and I run awful windows there.
I need to clean a lot of texts I copy from the intranet and save as a txt file. So I have to use sed
and/or awk
online live editors, like this or this
These texts are like this
01
010010-26.2010.501.0026 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
fdfsadf adsf adsf asdf asdfas fadsf asdfa
02
0011-15.2016.501.0012 fafas fasdf asdf asdfsadf asdfasd fasd asasdff
asdfasd fasd asasdff
asdfasd fasd asasdff
0011-125.2013.501.0012
asdfasd fasd asasdff
See the numbers like 0011-15.2016.501.0012
this is what I want. I do not care for the rest but I want to create a new clean text with all these numbers, one per line. In the previous example, I need a text with
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
the .501.
is always present, in all numbers, as the 4th group.
I have tried this command on the sed online editor
's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*)/1/'
Not working.
text-processing awk sed
text-processing awk sed
edited 8 hours ago
jimmij
31.6k872108
31.6k872108
asked 9 hours ago
SpaceDogSpaceDog
1,741123153
1,741123153
I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago
add a comment |
I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago
I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago
add a comment |
2 Answers
2
active
oldest
votes
It does work, but you don't change anything, or rather change it to what it was. But with very small modification of this code you can get what you want:
sed -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Notice three things:
-n
switch, it means to not print anything by default
.*
at the end of the group selected with(...)
p
as a last command means print this line
Result:
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
BTW, you can simplify a little by adding -E
and using extended regular expression, i.e. get rid of backslashes in front of capturing groups:
sed -E -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Both ways work on mentioned webpage.
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping-
? But I've just upvoted your question as it is very good in most part.
– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the-
but it is working without the escape. So, thanks.
– SpaceDog
8 hours ago
1
@Bananguin Backslash in front of a-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but-
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.
– jimmij
8 hours ago
|
show 2 more comments
It is fairly straight forward with AWK, b/c usually AWK doesn't do anything, so we just need to tell it when to do things, i.e. print the ID at the beginning of the line, if it's there
/^[0-9]+-[0-9]+.[0-9]+.501.[0-9]+/{
print $1
}
With sed it's a little different, b/c by default sed will print everything. (At least that's how these tools have been working for me.) First, we need to invoke sed
as sed -n
, to change its default behaviour to not do anything. Then we can
s/^([0-9]+-[0-9]+.[0-9]+.501.[0-9]+).*$/1/p
We need the p
at the end to tell sed to print the result, if we had a matching pattern. Your particular sed expression is a NOOP because it replaces every match with itself and prints everything else as it was.
thanks for your answer!!!
– SpaceDog
5 hours ago
add a comment |
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2 Answers
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2 Answers
2
active
oldest
votes
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oldest
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oldest
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It does work, but you don't change anything, or rather change it to what it was. But with very small modification of this code you can get what you want:
sed -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Notice three things:
-n
switch, it means to not print anything by default
.*
at the end of the group selected with(...)
p
as a last command means print this line
Result:
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
BTW, you can simplify a little by adding -E
and using extended regular expression, i.e. get rid of backslashes in front of capturing groups:
sed -E -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Both ways work on mentioned webpage.
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping-
? But I've just upvoted your question as it is very good in most part.
– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the-
but it is working without the escape. So, thanks.
– SpaceDog
8 hours ago
1
@Bananguin Backslash in front of a-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but-
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.
– jimmij
8 hours ago
|
show 2 more comments
It does work, but you don't change anything, or rather change it to what it was. But with very small modification of this code you can get what you want:
sed -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Notice three things:
-n
switch, it means to not print anything by default
.*
at the end of the group selected with(...)
p
as a last command means print this line
Result:
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
BTW, you can simplify a little by adding -E
and using extended regular expression, i.e. get rid of backslashes in front of capturing groups:
sed -E -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Both ways work on mentioned webpage.
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping-
? But I've just upvoted your question as it is very good in most part.
– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the-
but it is working without the escape. So, thanks.
– SpaceDog
8 hours ago
1
@Bananguin Backslash in front of a-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but-
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.
– jimmij
8 hours ago
|
show 2 more comments
It does work, but you don't change anything, or rather change it to what it was. But with very small modification of this code you can get what you want:
sed -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Notice three things:
-n
switch, it means to not print anything by default
.*
at the end of the group selected with(...)
p
as a last command means print this line
Result:
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
BTW, you can simplify a little by adding -E
and using extended regular expression, i.e. get rid of backslashes in front of capturing groups:
sed -E -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Both ways work on mentioned webpage.
It does work, but you don't change anything, or rather change it to what it was. But with very small modification of this code you can get what you want:
sed -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Notice three things:
-n
switch, it means to not print anything by default
.*
at the end of the group selected with(...)
p
as a last command means print this line
Result:
010010-26.2010.501.0026
0011-15.2016.501.0012
0011-125.2013.501.0012
BTW, you can simplify a little by adding -E
and using extended regular expression, i.e. get rid of backslashes in front of capturing groups:
sed -E -n 's/([0-9]*-[0-9]*.[0-9]*.501.[0-9]*).*/1/p'
Both ways work on mentioned webpage.
edited 8 hours ago
answered 8 hours ago
jimmijjimmij
31.6k872108
31.6k872108
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping-
? But I've just upvoted your question as it is very good in most part.
– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the-
but it is working without the escape. So, thanks.
– SpaceDog
8 hours ago
1
@Bananguin Backslash in front of a-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but-
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.
– jimmij
8 hours ago
|
show 2 more comments
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping-
? But I've just upvoted your question as it is very good in most part.
– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the-
but it is working without the escape. So, thanks.
– SpaceDog
8 hours ago
1
@Bananguin Backslash in front of a-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but-
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.
– jimmij
8 hours ago
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
yeah, i hate this. you post your answer 12 seconds LATER and get all the credit. i will take this to meta one day ...
– Bananguin
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping
-
? But I've just upvoted your question as it is very good in most part.– jimmij
8 hours ago
@Bananguin Yeah, I see, perhaps because of not corrected (imho) statement about escaping
-
? But I've just upvoted your question as it is very good in most part.– jimmij
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
thanks :D. In your oppinion not correct? But you still modified your answer and removed the escaping ``. The hyphen is no special character. Why would it need escaping? I didn't care much for the web-implementation, I just guessed that it might have tripped over that, if the statement was "not working". Turns out on my commandline I can "escape" the hyphen. So it's more a stuff character than an escape sequence. Why not ... I guess.
– Bananguin
8 hours ago
I would ask about escaping the
-
but it is working without the escape. So, thanks.– SpaceDog
8 hours ago
I would ask about escaping the
-
but it is working without the escape. So, thanks.– SpaceDog
8 hours ago
1
1
@Bananguin Backslash in front of a
-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but -
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.– jimmij
8 hours ago
@Bananguin Backslash in front of a
-
is not necessary, but at the same time doesn't do any harm. It only says to treat character that follows literally, but -
is treated like that anyway (in this context). So in my "minimal" modified example I left it, but when it comes to simplification I removed it together with other backslashes. It is working either way.– jimmij
8 hours ago
|
show 2 more comments
It is fairly straight forward with AWK, b/c usually AWK doesn't do anything, so we just need to tell it when to do things, i.e. print the ID at the beginning of the line, if it's there
/^[0-9]+-[0-9]+.[0-9]+.501.[0-9]+/{
print $1
}
With sed it's a little different, b/c by default sed will print everything. (At least that's how these tools have been working for me.) First, we need to invoke sed
as sed -n
, to change its default behaviour to not do anything. Then we can
s/^([0-9]+-[0-9]+.[0-9]+.501.[0-9]+).*$/1/p
We need the p
at the end to tell sed to print the result, if we had a matching pattern. Your particular sed expression is a NOOP because it replaces every match with itself and prints everything else as it was.
thanks for your answer!!!
– SpaceDog
5 hours ago
add a comment |
It is fairly straight forward with AWK, b/c usually AWK doesn't do anything, so we just need to tell it when to do things, i.e. print the ID at the beginning of the line, if it's there
/^[0-9]+-[0-9]+.[0-9]+.501.[0-9]+/{
print $1
}
With sed it's a little different, b/c by default sed will print everything. (At least that's how these tools have been working for me.) First, we need to invoke sed
as sed -n
, to change its default behaviour to not do anything. Then we can
s/^([0-9]+-[0-9]+.[0-9]+.501.[0-9]+).*$/1/p
We need the p
at the end to tell sed to print the result, if we had a matching pattern. Your particular sed expression is a NOOP because it replaces every match with itself and prints everything else as it was.
thanks for your answer!!!
– SpaceDog
5 hours ago
add a comment |
It is fairly straight forward with AWK, b/c usually AWK doesn't do anything, so we just need to tell it when to do things, i.e. print the ID at the beginning of the line, if it's there
/^[0-9]+-[0-9]+.[0-9]+.501.[0-9]+/{
print $1
}
With sed it's a little different, b/c by default sed will print everything. (At least that's how these tools have been working for me.) First, we need to invoke sed
as sed -n
, to change its default behaviour to not do anything. Then we can
s/^([0-9]+-[0-9]+.[0-9]+.501.[0-9]+).*$/1/p
We need the p
at the end to tell sed to print the result, if we had a matching pattern. Your particular sed expression is a NOOP because it replaces every match with itself and prints everything else as it was.
It is fairly straight forward with AWK, b/c usually AWK doesn't do anything, so we just need to tell it when to do things, i.e. print the ID at the beginning of the line, if it's there
/^[0-9]+-[0-9]+.[0-9]+.501.[0-9]+/{
print $1
}
With sed it's a little different, b/c by default sed will print everything. (At least that's how these tools have been working for me.) First, we need to invoke sed
as sed -n
, to change its default behaviour to not do anything. Then we can
s/^([0-9]+-[0-9]+.[0-9]+.501.[0-9]+).*$/1/p
We need the p
at the end to tell sed to print the result, if we had a matching pattern. Your particular sed expression is a NOOP because it replaces every match with itself and prints everything else as it was.
edited 5 hours ago
answered 8 hours ago
BananguinBananguin
5,3701338
5,3701338
thanks for your answer!!!
– SpaceDog
5 hours ago
add a comment |
thanks for your answer!!!
– SpaceDog
5 hours ago
thanks for your answer!!!
– SpaceDog
5 hours ago
thanks for your answer!!!
– SpaceDog
5 hours ago
add a comment |
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I am using this online tool... sed.js.org this is the tool I will have to use, so the command has to work there.
– SpaceDog
8 hours ago
I have mentioned in my question.
– SpaceDog
8 hours ago
This is not an answer for your original question (that's already solved), but you might want to check if you can use Powershell. On newer windows machines it's installed by default (I think), so if it's on your machine, you might be able to use it. It has regular expression support, exactly what you need here. In case you're forced to use one MS product anyway, you could just go all in. ;)
– Nyos
6 hours ago