How to understand the return values of scipy.interpolate.splrep
$begingroup$
Background
Continuation of Spline interpolation - why cube with 2nd derivative
as following Cubic Spline Interpolation in youtube. The example in the youtube is below.
Implemented using scipy.interpolate.splrep and try to understand what the returns of the splrep function are.
Given the set of data points (x[i], y[i]) determine a smooth spline approximation of degree k on the interval xb <= x <= xe.
Returns
tck : tuple
A tuple
(t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
import numpy as np
from pylab import plt, mpl
plt.style.use('seaborn')
mpl.rcParams['font.family'] = 'serif'
%matplotlib inline
def create_plot(x, y, styles, labels, axlabels):
plt.figure(figsize=(10, 6))
for i in range(len(x)):
plt.plot(x[i], y[i], styles[i], label=labels[i])
plt.xlabel(axlabels[0])
plt.ylabel(axlabels[1])
plt.legend(loc=0)
x = np.array([3.0, 4.5, 7.0, 9.0])
y = np.array([2.5, 1.0, 2.5, 0.5])
create_plot([x], [y], ['b'], ['y'], ['x', 'y'])
import scipy.interpolate as spi
interpolation = spi.splrep(x, y, k=3)
IX = np.linspace(3, 9, 100)
IY = spi.splev(IX, interpolation)
create_plot(
[x, IX],
[y, IY],
['b', 'ro'],
['x', 'IY:interpolation'],
['x', 'y']
)
Questions
How to interpret and understand the return values and which resources to look into to understand?
A tuple (t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
The return value on Knots
interpolation[0]
array([3., 3., 3., 3., 9., 9., 9., 9.])
I thought the first tuple element would be the knots which would be the x, but not. What are these 3., 3. ... values?
The return values on B-spline co-efficient
interpolation[1]
array([ 2.5 , -2.21111111, 6.18888889, 0.5 , 0. , 0. , 0. , 0. ])
Please help or suggest where I should look into and what to understand about "B-spline coefficient" to be able to interpret these values?
The solution of the first interval is (0.186566, 1.6667, 0.24689), hence I thought these values would be in the 2nd element, but not. How the solution values would relate to the return values?
scipy interpolation
$endgroup$
add a comment |
$begingroup$
Background
Continuation of Spline interpolation - why cube with 2nd derivative
as following Cubic Spline Interpolation in youtube. The example in the youtube is below.
Implemented using scipy.interpolate.splrep and try to understand what the returns of the splrep function are.
Given the set of data points (x[i], y[i]) determine a smooth spline approximation of degree k on the interval xb <= x <= xe.
Returns
tck : tuple
A tuple
(t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
import numpy as np
from pylab import plt, mpl
plt.style.use('seaborn')
mpl.rcParams['font.family'] = 'serif'
%matplotlib inline
def create_plot(x, y, styles, labels, axlabels):
plt.figure(figsize=(10, 6))
for i in range(len(x)):
plt.plot(x[i], y[i], styles[i], label=labels[i])
plt.xlabel(axlabels[0])
plt.ylabel(axlabels[1])
plt.legend(loc=0)
x = np.array([3.0, 4.5, 7.0, 9.0])
y = np.array([2.5, 1.0, 2.5, 0.5])
create_plot([x], [y], ['b'], ['y'], ['x', 'y'])
import scipy.interpolate as spi
interpolation = spi.splrep(x, y, k=3)
IX = np.linspace(3, 9, 100)
IY = spi.splev(IX, interpolation)
create_plot(
[x, IX],
[y, IY],
['b', 'ro'],
['x', 'IY:interpolation'],
['x', 'y']
)
Questions
How to interpret and understand the return values and which resources to look into to understand?
A tuple (t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
The return value on Knots
interpolation[0]
array([3., 3., 3., 3., 9., 9., 9., 9.])
I thought the first tuple element would be the knots which would be the x, but not. What are these 3., 3. ... values?
The return values on B-spline co-efficient
interpolation[1]
array([ 2.5 , -2.21111111, 6.18888889, 0.5 , 0. , 0. , 0. , 0. ])
Please help or suggest where I should look into and what to understand about "B-spline coefficient" to be able to interpret these values?
The solution of the first interval is (0.186566, 1.6667, 0.24689), hence I thought these values would be in the 2nd element, but not. How the solution values would relate to the return values?
scipy interpolation
$endgroup$
add a comment |
$begingroup$
Background
Continuation of Spline interpolation - why cube with 2nd derivative
as following Cubic Spline Interpolation in youtube. The example in the youtube is below.
Implemented using scipy.interpolate.splrep and try to understand what the returns of the splrep function are.
Given the set of data points (x[i], y[i]) determine a smooth spline approximation of degree k on the interval xb <= x <= xe.
Returns
tck : tuple
A tuple
(t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
import numpy as np
from pylab import plt, mpl
plt.style.use('seaborn')
mpl.rcParams['font.family'] = 'serif'
%matplotlib inline
def create_plot(x, y, styles, labels, axlabels):
plt.figure(figsize=(10, 6))
for i in range(len(x)):
plt.plot(x[i], y[i], styles[i], label=labels[i])
plt.xlabel(axlabels[0])
plt.ylabel(axlabels[1])
plt.legend(loc=0)
x = np.array([3.0, 4.5, 7.0, 9.0])
y = np.array([2.5, 1.0, 2.5, 0.5])
create_plot([x], [y], ['b'], ['y'], ['x', 'y'])
import scipy.interpolate as spi
interpolation = spi.splrep(x, y, k=3)
IX = np.linspace(3, 9, 100)
IY = spi.splev(IX, interpolation)
create_plot(
[x, IX],
[y, IY],
['b', 'ro'],
['x', 'IY:interpolation'],
['x', 'y']
)
Questions
How to interpret and understand the return values and which resources to look into to understand?
A tuple (t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
The return value on Knots
interpolation[0]
array([3., 3., 3., 3., 9., 9., 9., 9.])
I thought the first tuple element would be the knots which would be the x, but not. What are these 3., 3. ... values?
The return values on B-spline co-efficient
interpolation[1]
array([ 2.5 , -2.21111111, 6.18888889, 0.5 , 0. , 0. , 0. , 0. ])
Please help or suggest where I should look into and what to understand about "B-spline coefficient" to be able to interpret these values?
The solution of the first interval is (0.186566, 1.6667, 0.24689), hence I thought these values would be in the 2nd element, but not. How the solution values would relate to the return values?
scipy interpolation
$endgroup$
Background
Continuation of Spline interpolation - why cube with 2nd derivative
as following Cubic Spline Interpolation in youtube. The example in the youtube is below.
Implemented using scipy.interpolate.splrep and try to understand what the returns of the splrep function are.
Given the set of data points (x[i], y[i]) determine a smooth spline approximation of degree k on the interval xb <= x <= xe.
Returns
tck : tuple
A tuple
(t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
import numpy as np
from pylab import plt, mpl
plt.style.use('seaborn')
mpl.rcParams['font.family'] = 'serif'
%matplotlib inline
def create_plot(x, y, styles, labels, axlabels):
plt.figure(figsize=(10, 6))
for i in range(len(x)):
plt.plot(x[i], y[i], styles[i], label=labels[i])
plt.xlabel(axlabels[0])
plt.ylabel(axlabels[1])
plt.legend(loc=0)
x = np.array([3.0, 4.5, 7.0, 9.0])
y = np.array([2.5, 1.0, 2.5, 0.5])
create_plot([x], [y], ['b'], ['y'], ['x', 'y'])
import scipy.interpolate as spi
interpolation = spi.splrep(x, y, k=3)
IX = np.linspace(3, 9, 100)
IY = spi.splev(IX, interpolation)
create_plot(
[x, IX],
[y, IY],
['b', 'ro'],
['x', 'IY:interpolation'],
['x', 'y']
)
Questions
How to interpret and understand the return values and which resources to look into to understand?
A tuple (t,c,k) containing the vector of knots, the B-spline coefficients, and the degree of the spline.
The return value on Knots
interpolation[0]
array([3., 3., 3., 3., 9., 9., 9., 9.])
I thought the first tuple element would be the knots which would be the x, but not. What are these 3., 3. ... values?
The return values on B-spline co-efficient
interpolation[1]
array([ 2.5 , -2.21111111, 6.18888889, 0.5 , 0. , 0. , 0. , 0. ])
Please help or suggest where I should look into and what to understand about "B-spline coefficient" to be able to interpret these values?
The solution of the first interval is (0.186566, 1.6667, 0.24689), hence I thought these values would be in the 2nd element, but not. How the solution values would relate to the return values?
scipy interpolation
scipy interpolation
asked 20 hours ago
monmon
1073
1073
add a comment |
add a comment |
1 Answer
1
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$begingroup$
This documentation may work:
BSpline
Univariate spline in the B-spline basis.
$S(x) = sum_{j=0}^{n-1} c_jB_{j,k;t}(x)$
where $B_{j,k;t}$ are B-spline basis functions of degree k and knots t.
New contributor
$endgroup$
add a comment |
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1 Answer
1
active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This documentation may work:
BSpline
Univariate spline in the B-spline basis.
$S(x) = sum_{j=0}^{n-1} c_jB_{j,k;t}(x)$
where $B_{j,k;t}$ are B-spline basis functions of degree k and knots t.
New contributor
$endgroup$
add a comment |
$begingroup$
This documentation may work:
BSpline
Univariate spline in the B-spline basis.
$S(x) = sum_{j=0}^{n-1} c_jB_{j,k;t}(x)$
where $B_{j,k;t}$ are B-spline basis functions of degree k and knots t.
New contributor
$endgroup$
add a comment |
$begingroup$
This documentation may work:
BSpline
Univariate spline in the B-spline basis.
$S(x) = sum_{j=0}^{n-1} c_jB_{j,k;t}(x)$
where $B_{j,k;t}$ are B-spline basis functions of degree k and knots t.
New contributor
$endgroup$
This documentation may work:
BSpline
Univariate spline in the B-spline basis.
$S(x) = sum_{j=0}^{n-1} c_jB_{j,k;t}(x)$
where $B_{j,k;t}$ are B-spline basis functions of degree k and knots t.
New contributor
New contributor
answered 19 hours ago
Juan Esteban de la CalleJuan Esteban de la Calle
938
938
New contributor
New contributor
add a comment |
add a comment |
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