Logitic Regression cost function - what if ln(0)?
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I am building logistic regression from scrap.
The simplified cost function I am using is (from machine learning course on coursera):
in specific case during learning,
one observation in training set y is 0 - but the specific choice of betas in:
makes g(z) = h(x) = 1 , because e.g. z > 50.
in this case my right side od J is (1 - 0) * log(1 - 1) what is -inf (I am doing my calculations in python)
I understand that in this case value of cost function should be high because the probability of y = 1 is very big while the truth is that it actually is 0.
Is the problem approximation of g(50) being 1 instead of something like: 0.999999? Or there is some more fundametal error with my logic?
because this specific example the summation of cost of all observations is nan (not a number) in my code.
logistic-regression cost-function
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add a comment |
$begingroup$
I am building logistic regression from scrap.
The simplified cost function I am using is (from machine learning course on coursera):
in specific case during learning,
one observation in training set y is 0 - but the specific choice of betas in:
makes g(z) = h(x) = 1 , because e.g. z > 50.
in this case my right side od J is (1 - 0) * log(1 - 1) what is -inf (I am doing my calculations in python)
I understand that in this case value of cost function should be high because the probability of y = 1 is very big while the truth is that it actually is 0.
Is the problem approximation of g(50) being 1 instead of something like: 0.999999? Or there is some more fundametal error with my logic?
because this specific example the summation of cost of all observations is nan (not a number) in my code.
logistic-regression cost-function
$endgroup$
add a comment |
$begingroup$
I am building logistic regression from scrap.
The simplified cost function I am using is (from machine learning course on coursera):
in specific case during learning,
one observation in training set y is 0 - but the specific choice of betas in:
makes g(z) = h(x) = 1 , because e.g. z > 50.
in this case my right side od J is (1 - 0) * log(1 - 1) what is -inf (I am doing my calculations in python)
I understand that in this case value of cost function should be high because the probability of y = 1 is very big while the truth is that it actually is 0.
Is the problem approximation of g(50) being 1 instead of something like: 0.999999? Or there is some more fundametal error with my logic?
because this specific example the summation of cost of all observations is nan (not a number) in my code.
logistic-regression cost-function
$endgroup$
I am building logistic regression from scrap.
The simplified cost function I am using is (from machine learning course on coursera):
in specific case during learning,
one observation in training set y is 0 - but the specific choice of betas in:
makes g(z) = h(x) = 1 , because e.g. z > 50.
in this case my right side od J is (1 - 0) * log(1 - 1) what is -inf (I am doing my calculations in python)
I understand that in this case value of cost function should be high because the probability of y = 1 is very big while the truth is that it actually is 0.
Is the problem approximation of g(50) being 1 instead of something like: 0.999999? Or there is some more fundametal error with my logic?
because this specific example the summation of cost of all observations is nan (not a number) in my code.
logistic-regression cost-function
logistic-regression cost-function
asked yesterday
Mateusz KonopelskiMateusz Konopelski
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In practice, an offset is used to avoid log explosion due to values close to zero. For example $hat{text{log}}(x)=text{log}(x + text{1e-6})$.
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1
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Ha. Didn't think about it. Thanks!
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– Mateusz Konopelski
yesterday
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1 Answer
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1 Answer
1
active
oldest
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active
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active
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votes
$begingroup$
In practice, an offset is used to avoid log explosion due to values close to zero. For example $hat{text{log}}(x)=text{log}(x + text{1e-6})$.
$endgroup$
1
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
add a comment |
$begingroup$
In practice, an offset is used to avoid log explosion due to values close to zero. For example $hat{text{log}}(x)=text{log}(x + text{1e-6})$.
$endgroup$
1
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
add a comment |
$begingroup$
In practice, an offset is used to avoid log explosion due to values close to zero. For example $hat{text{log}}(x)=text{log}(x + text{1e-6})$.
$endgroup$
In practice, an offset is used to avoid log explosion due to values close to zero. For example $hat{text{log}}(x)=text{log}(x + text{1e-6})$.
answered yesterday
EsmailianEsmailian
1,536113
1,536113
1
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
add a comment |
1
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
1
1
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
$begingroup$
Ha. Didn't think about it. Thanks!
$endgroup$
– Mateusz Konopelski
yesterday
add a comment |
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