A Pair of Odd (but Still Balanced) Dice












0












$begingroup$


I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.



Each die has one number on each side, that are 1 or greater.



Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)



Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.



Here are my drawings of three faces from each die:



enter image description here



(the 6 on the top drawing is actually a 6)



To solve the puzzle, all you have to do is:




Draw a complete cube net of each die.




Good luck and happy puzzling!






logical-deduction visual dice







share|improve this question











$endgroup$












  • $begingroup$
    is that a 6 or a 9? or can it be both? thanks!
    $endgroup$
    – Omega Krypton
    7 mins ago










  • $begingroup$
    @OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
    $endgroup$
    – Excited Raichu
    3 mins ago
















0












$begingroup$


I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.



Each die has one number on each side, that are 1 or greater.



Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)



Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.



Here are my drawings of three faces from each die:



enter image description here



(the 6 on the top drawing is actually a 6)



To solve the puzzle, all you have to do is:




Draw a complete cube net of each die.




Good luck and happy puzzling!






logical-deduction visual dice







share|improve this question











$endgroup$












  • $begingroup$
    is that a 6 or a 9? or can it be both? thanks!
    $endgroup$
    – Omega Krypton
    7 mins ago










  • $begingroup$
    @OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
    $endgroup$
    – Excited Raichu
    3 mins ago














0












0








0





$begingroup$


I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.



Each die has one number on each side, that are 1 or greater.



Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)



Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.



Here are my drawings of three faces from each die:



enter image description here



(the 6 on the top drawing is actually a 6)



To solve the puzzle, all you have to do is:




Draw a complete cube net of each die.




Good luck and happy puzzling!






logical-deduction visual dice







share|improve this question











$endgroup$




I have a pair of odd six-sided dice at my house... I don't quite remember where I got them.



Each die has one number on each side, that are 1 or greater.



Each pair of opposite faces sums to the same number on each individual die (but not necessarily the same across both dice)



Furthermore, the two dice, when rolled together, have the same probability of coming up a certain number as two six sided dice coming up with the same number.



Here are my drawings of three faces from each die:



enter image description here



(the 6 on the top drawing is actually a 6)



To solve the puzzle, all you have to do is:




Draw a complete cube net of each die.




Good luck and happy puzzling!






logical-deduction visual dice




logical-deduction visual dice






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 mins ago







Excited Raichu

















asked 11 mins ago









Excited RaichuExcited Raichu

6,27821065




6,27821065












  • $begingroup$
    is that a 6 or a 9? or can it be both? thanks!
    $endgroup$
    – Omega Krypton
    7 mins ago










  • $begingroup$
    @OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
    $endgroup$
    – Excited Raichu
    3 mins ago


















  • $begingroup$
    is that a 6 or a 9? or can it be both? thanks!
    $endgroup$
    – Omega Krypton
    7 mins ago










  • $begingroup$
    @OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
    $endgroup$
    – Excited Raichu
    3 mins ago
















$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
7 mins ago




$begingroup$
is that a 6 or a 9? or can it be both? thanks!
$endgroup$
– Omega Krypton
7 mins ago












$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
3 mins ago




$begingroup$
@OmegaKrypton it's a 6, I completely forgot 9 was 6 upside down, lol!
$endgroup$
– Excited Raichu
3 mins ago










1 Answer
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$begingroup$

Easy:




To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.






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    $begingroup$

    Easy:




    To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.






    share









    $endgroup$


















      0












      $begingroup$

      Easy:




      To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.






      share









      $endgroup$
















        0












        0








        0





        $begingroup$

        Easy:




        To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.






        share









        $endgroup$



        Easy:




        To get a 2 we need a 1 on the 224 die, and this must be opposite the 4, so 1,2,2,3,3,4, and we also need a 12, which must be 4+8, so the other die is 1,3,4,5,6,8.







        share











        share


        share










        answered 2 mins ago









        JonMark PerryJonMark Perry

        18.1k63787




        18.1k63787






























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