Does a code with length 6, size 32 and distance 2 exist?
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The problem is to prove or disprove the existence of $C$, s.t., $|c| = 6,forall cin C$; $|C| = 32$; $d(c_i,c_j)geq2,1leq i<jleq32$. ($d$ stands for hamming distance)
I tried to construct a satisfying code. The best I can get is to let $C = C'times C'$, a concatenation of $C' = {000,011,110,101}$, which is of size 16. 32 happens to be the theoretical upper bound of the size, now I don't know what to do next so as to solve the problem.
information-theory coding-theory encoding-scheme
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add a comment |
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The problem is to prove or disprove the existence of $C$, s.t., $|c| = 6,forall cin C$; $|C| = 32$; $d(c_i,c_j)geq2,1leq i<jleq32$. ($d$ stands for hamming distance)
I tried to construct a satisfying code. The best I can get is to let $C = C'times C'$, a concatenation of $C' = {000,011,110,101}$, which is of size 16. 32 happens to be the theoretical upper bound of the size, now I don't know what to do next so as to solve the problem.
information-theory coding-theory encoding-scheme
$endgroup$
add a comment |
$begingroup$
The problem is to prove or disprove the existence of $C$, s.t., $|c| = 6,forall cin C$; $|C| = 32$; $d(c_i,c_j)geq2,1leq i<jleq32$. ($d$ stands for hamming distance)
I tried to construct a satisfying code. The best I can get is to let $C = C'times C'$, a concatenation of $C' = {000,011,110,101}$, which is of size 16. 32 happens to be the theoretical upper bound of the size, now I don't know what to do next so as to solve the problem.
information-theory coding-theory encoding-scheme
$endgroup$
The problem is to prove or disprove the existence of $C$, s.t., $|c| = 6,forall cin C$; $|C| = 32$; $d(c_i,c_j)geq2,1leq i<jleq32$. ($d$ stands for hamming distance)
I tried to construct a satisfying code. The best I can get is to let $C = C'times C'$, a concatenation of $C' = {000,011,110,101}$, which is of size 16. 32 happens to be the theoretical upper bound of the size, now I don't know what to do next so as to solve the problem.
information-theory coding-theory encoding-scheme
information-theory coding-theory encoding-scheme
asked 21 hours ago
MianguMiangu
865
865
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2 Answers
2
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oldest
votes
$begingroup$
Yes, there is such a set. You are actually on the right track to find the following example.
Let $C = {c : |c|=6 text{ and there are even number of 1's in c}}$. You can check the following.
$|C|=32$.
$d(u,v)geq2$ for all $u,vin C$, $unot=v$. (In fact, $d(u,v)=2$ or 4 or 6.)
Here are four related exercise, listed in the order of increasing difficulty. As in the question, only binary code is concerned.
Exercise 1. Give another example of a set of 32 words of length 6 and pairwise distance at least 2.
Exercise 2. Show that there are only two such sets, as given in the answer and in the exercise 1.
Exercise 3. Generalize the above to words of any given length and pairwise distance at least 2. (Hint, $32=2^{6-1}$.)
Exercise 4. (further generalization stated in Yuval's answer) If $A(n,d)$ is the maximum size of a code of length $n$ and minimum pairwise distance $d$, then $A(d,2d)=A(n-1,2d-1)$.
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1
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I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
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– siegi
14 hours ago
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@siegi, thanks. Updated.
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– Apass.Jack
11 hours ago
add a comment |
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All words of even parity from a linear code with $2^{n-1}$ codewords and minimum distance $2$.
More generally, if $A_2(n,d)$ is the maximum size of a code of length $n$ and minimum distance $d$, then $A_2(n,2d) = A_2(n-1,2d-1)$.
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1
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Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
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– Apass.Jack
19 hours ago
1
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The subscript signifies the field $mathbb{F}_2$.
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– Yuval Filmus
19 hours ago
add a comment |
Your Answer
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2 Answers
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2 Answers
2
active
oldest
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active
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$begingroup$
Yes, there is such a set. You are actually on the right track to find the following example.
Let $C = {c : |c|=6 text{ and there are even number of 1's in c}}$. You can check the following.
$|C|=32$.
$d(u,v)geq2$ for all $u,vin C$, $unot=v$. (In fact, $d(u,v)=2$ or 4 or 6.)
Here are four related exercise, listed in the order of increasing difficulty. As in the question, only binary code is concerned.
Exercise 1. Give another example of a set of 32 words of length 6 and pairwise distance at least 2.
Exercise 2. Show that there are only two such sets, as given in the answer and in the exercise 1.
Exercise 3. Generalize the above to words of any given length and pairwise distance at least 2. (Hint, $32=2^{6-1}$.)
Exercise 4. (further generalization stated in Yuval's answer) If $A(n,d)$ is the maximum size of a code of length $n$ and minimum pairwise distance $d$, then $A(d,2d)=A(n-1,2d-1)$.
$endgroup$
1
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
add a comment |
$begingroup$
Yes, there is such a set. You are actually on the right track to find the following example.
Let $C = {c : |c|=6 text{ and there are even number of 1's in c}}$. You can check the following.
$|C|=32$.
$d(u,v)geq2$ for all $u,vin C$, $unot=v$. (In fact, $d(u,v)=2$ or 4 or 6.)
Here are four related exercise, listed in the order of increasing difficulty. As in the question, only binary code is concerned.
Exercise 1. Give another example of a set of 32 words of length 6 and pairwise distance at least 2.
Exercise 2. Show that there are only two such sets, as given in the answer and in the exercise 1.
Exercise 3. Generalize the above to words of any given length and pairwise distance at least 2. (Hint, $32=2^{6-1}$.)
Exercise 4. (further generalization stated in Yuval's answer) If $A(n,d)$ is the maximum size of a code of length $n$ and minimum pairwise distance $d$, then $A(d,2d)=A(n-1,2d-1)$.
$endgroup$
1
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
add a comment |
$begingroup$
Yes, there is such a set. You are actually on the right track to find the following example.
Let $C = {c : |c|=6 text{ and there are even number of 1's in c}}$. You can check the following.
$|C|=32$.
$d(u,v)geq2$ for all $u,vin C$, $unot=v$. (In fact, $d(u,v)=2$ or 4 or 6.)
Here are four related exercise, listed in the order of increasing difficulty. As in the question, only binary code is concerned.
Exercise 1. Give another example of a set of 32 words of length 6 and pairwise distance at least 2.
Exercise 2. Show that there are only two such sets, as given in the answer and in the exercise 1.
Exercise 3. Generalize the above to words of any given length and pairwise distance at least 2. (Hint, $32=2^{6-1}$.)
Exercise 4. (further generalization stated in Yuval's answer) If $A(n,d)$ is the maximum size of a code of length $n$ and minimum pairwise distance $d$, then $A(d,2d)=A(n-1,2d-1)$.
$endgroup$
Yes, there is such a set. You are actually on the right track to find the following example.
Let $C = {c : |c|=6 text{ and there are even number of 1's in c}}$. You can check the following.
$|C|=32$.
$d(u,v)geq2$ for all $u,vin C$, $unot=v$. (In fact, $d(u,v)=2$ or 4 or 6.)
Here are four related exercise, listed in the order of increasing difficulty. As in the question, only binary code is concerned.
Exercise 1. Give another example of a set of 32 words of length 6 and pairwise distance at least 2.
Exercise 2. Show that there are only two such sets, as given in the answer and in the exercise 1.
Exercise 3. Generalize the above to words of any given length and pairwise distance at least 2. (Hint, $32=2^{6-1}$.)
Exercise 4. (further generalization stated in Yuval's answer) If $A(n,d)$ is the maximum size of a code of length $n$ and minimum pairwise distance $d$, then $A(d,2d)=A(n-1,2d-1)$.
edited 11 hours ago
answered 20 hours ago
Apass.JackApass.Jack
11.1k1939
11.1k1939
1
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
add a comment |
1
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
1
1
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
I think $d(u,v)$ may also be 6, specifically for $u=000000$ and $v=111111$, as both $uin C$ and $vin C$ because both have even number of 1's. Or am I missing something?
$endgroup$
– siegi
14 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
$begingroup$
@siegi, thanks. Updated.
$endgroup$
– Apass.Jack
11 hours ago
add a comment |
$begingroup$
All words of even parity from a linear code with $2^{n-1}$ codewords and minimum distance $2$.
More generally, if $A_2(n,d)$ is the maximum size of a code of length $n$ and minimum distance $d$, then $A_2(n,2d) = A_2(n-1,2d-1)$.
$endgroup$
1
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
1
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
add a comment |
$begingroup$
All words of even parity from a linear code with $2^{n-1}$ codewords and minimum distance $2$.
More generally, if $A_2(n,d)$ is the maximum size of a code of length $n$ and minimum distance $d$, then $A_2(n,2d) = A_2(n-1,2d-1)$.
$endgroup$
1
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
1
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
add a comment |
$begingroup$
All words of even parity from a linear code with $2^{n-1}$ codewords and minimum distance $2$.
More generally, if $A_2(n,d)$ is the maximum size of a code of length $n$ and minimum distance $d$, then $A_2(n,2d) = A_2(n-1,2d-1)$.
$endgroup$
All words of even parity from a linear code with $2^{n-1}$ codewords and minimum distance $2$.
More generally, if $A_2(n,d)$ is the maximum size of a code of length $n$ and minimum distance $d$, then $A_2(n,2d) = A_2(n-1,2d-1)$.
answered 20 hours ago
Yuval FilmusYuval Filmus
193k14180345
193k14180345
1
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
1
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
add a comment |
1
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
1
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
1
1
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
$begingroup$
Nice fact, upvoted. By the way, why not just $A(n,d)$ instead of $A_2(n,d)$? Oh, two letters.
$endgroup$
– Apass.Jack
19 hours ago
1
1
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
$begingroup$
The subscript signifies the field $mathbb{F}_2$.
$endgroup$
– Yuval Filmus
19 hours ago
add a comment |
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