Rearrange c++ const and reference specifiers
1
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
1
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
1
1
1
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
asked 5 hours ago
Jay MuellerJay Mueller
82
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
3
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 5 hours ago
RalfRalf
3,1551317
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "599"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fvi.stackexchange.com%2fquestions%2f19354%2frearrange-c-const-and-reference-specifiers%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 5 hours ago
RalfRalf
3,1551317
add a comment |
3
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 5 hours ago
RalfRalf
3,1551317
add a comment |
3
3
3
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 5 hours ago
RalfRalf
3,1551317
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 5 hours ago
RalfRalf
3,1551317
answered 5 hours ago
RalfRalf
3,1551317
answered 5 hours ago
RalfRalf
3,1551317
answered 5 hours ago
RalfRalf
3,1551317
3,1551317
add a comment |
add a comment |
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Vi and Vim Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fvi.stackexchange.com%2fquestions%2f19354%2frearrange-c-const-and-reference-specifiers%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
