Add number in the string after each letter
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D
to A3B1C7D1
.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D
to A3B1C7D1
.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D
to A3B1C7D1
.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D
to A3B1C7D1
.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
r regex string
edited 16 hours ago
markus
13.1k1234
13.1k1234
asked 16 hours ago
DongDong
1586
1586
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1
in this case.
add a comment |
Find all (uppercase) letters ([A-Z]
) that is not followed by a number and replace it with that string + 1
:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep
all positions that do not end with a number, and paste a 1
to them.
9
Almost. Check the second element it should be"A3B1C3"
– markus
16 hours ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1
in this case.
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1
in this case.
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1
in this case.
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1
in this case.
edited 15 hours ago
answered 15 hours ago
arg0nautarg0naut
4,2191316
4,2191316
add a comment |
add a comment |
Find all (uppercase) letters ([A-Z]
) that is not followed by a number and replace it with that string + 1
:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
add a comment |
Find all (uppercase) letters ([A-Z]
) that is not followed by a number and replace it with that string + 1
:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
add a comment |
Find all (uppercase) letters ([A-Z]
) that is not followed by a number and replace it with that string + 1
:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
Find all (uppercase) letters ([A-Z]
) that is not followed by a number and replace it with that string + 1
:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
edited 13 hours ago
answered 14 hours ago
sindri_baldursindri_baldur
7,8141032
7,8141032
add a comment |
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep
all positions that do not end with a number, and paste a 1
to them.
9
Almost. Check the second element it should be"A3B1C3"
– markus
16 hours ago
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep
all positions that do not end with a number, and paste a 1
to them.
9
Almost. Check the second element it should be"A3B1C3"
– markus
16 hours ago
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep
all positions that do not end with a number, and paste a 1
to them.
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep
all positions that do not end with a number, and paste a 1
to them.
answered 16 hours ago
boskiboski
500210
500210
9
Almost. Check the second element it should be"A3B1C3"
– markus
16 hours ago
add a comment |
9
Almost. Check the second element it should be"A3B1C3"
– markus
16 hours ago
9
9
Almost. Check the second element it should be
"A3B1C3"
– markus
16 hours ago
Almost. Check the second element it should be
"A3B1C3"
– markus
16 hours ago
add a comment |
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