Missing is what in picture
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Source:
http://gpuzzles.com/mind-teasers/pattern-series-picture-puzzle/?source=stack
What is missing in the picture?

logical-deduction pattern
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add a comment |
$begingroup$
Source:
http://gpuzzles.com/mind-teasers/pattern-series-picture-puzzle/?source=stack
What is missing in the picture?

logical-deduction pattern
$endgroup$
$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
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– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15
add a comment |
$begingroup$
Source:
http://gpuzzles.com/mind-teasers/pattern-series-picture-puzzle/?source=stack
What is missing in the picture?

logical-deduction pattern
$endgroup$
Source:
http://gpuzzles.com/mind-teasers/pattern-series-picture-puzzle/?source=stack
What is missing in the picture?

logical-deduction pattern
logical-deduction pattern
edited 7 hours ago
generalcrispy
4,67922844
4,67922844
asked Feb 28 '15 at 6:22
user9857
$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
$endgroup$
– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15
add a comment |
$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
$endgroup$
– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15
$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
$endgroup$
– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
$endgroup$
– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Correct answer is 
The reason is not because
it's left of
, because as you can see in the second row
it's also left of
.
This is the order of elements: 







The matrix puzzle starts with the first element, then adds each element once, and also resets the pattern to repeat itself.
And this is the result:




































If you line this list in 6x6 matrix, it will look like the original puzzle.
This puzzle does not use it's full enigmatic potential though. For example, it could have been much more interesting and challenging if it could have looked like this:

$endgroup$
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
add a comment |
$begingroup$
I found there are 1,2,3,4,4,6,7,8 of each suite and the number increases black,red, black, red, black, red so the second 4 should have been 5 of a black suit. The two 4's were hearts and upside down clubs. So - upside down club.
$endgroup$
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Correct answer is 
The reason is not because
it's left of
, because as you can see in the second row
it's also left of
.
This is the order of elements: 







The matrix puzzle starts with the first element, then adds each element once, and also resets the pattern to repeat itself.
And this is the result:




































If you line this list in 6x6 matrix, it will look like the original puzzle.
This puzzle does not use it's full enigmatic potential though. For example, it could have been much more interesting and challenging if it could have looked like this:

$endgroup$
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
add a comment |
$begingroup$
Correct answer is 
The reason is not because
it's left of
, because as you can see in the second row
it's also left of
.
This is the order of elements: 







The matrix puzzle starts with the first element, then adds each element once, and also resets the pattern to repeat itself.
And this is the result:




































If you line this list in 6x6 matrix, it will look like the original puzzle.
This puzzle does not use it's full enigmatic potential though. For example, it could have been much more interesting and challenging if it could have looked like this:

$endgroup$
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
add a comment |
$begingroup$
Correct answer is 
The reason is not because
it's left of
, because as you can see in the second row
it's also left of
.
This is the order of elements: 







The matrix puzzle starts with the first element, then adds each element once, and also resets the pattern to repeat itself.
And this is the result:




































If you line this list in 6x6 matrix, it will look like the original puzzle.
This puzzle does not use it's full enigmatic potential though. For example, it could have been much more interesting and challenging if it could have looked like this:

$endgroup$
Correct answer is 
The reason is not because
it's left of
, because as you can see in the second row
it's also left of
.
This is the order of elements: 







The matrix puzzle starts with the first element, then adds each element once, and also resets the pattern to repeat itself.
And this is the result:




































If you line this list in 6x6 matrix, it will look like the original puzzle.
This puzzle does not use it's full enigmatic potential though. For example, it could have been much more interesting and challenging if it could have looked like this:

edited 12 hours ago
answered Feb 28 '15 at 14:44
greggreg
1913
1913
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
add a comment |
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
1
1
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
$begingroup$
Even simpler: the sequence starts with a <> and the square is filled with 1, 2, 3, ... symbols from the sequence.
$endgroup$
– Florian F
Mar 1 '15 at 5:55
1
1
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
$begingroup$
Diamond is 1, Right side up club is 2, etc. 1, 12, 123, 1234, etc. Same idea, without the awkward "static dynamic reset" thingy.
$endgroup$
– Tibos
Mar 1 '15 at 7:13
add a comment |
$begingroup$
I found there are 1,2,3,4,4,6,7,8 of each suite and the number increases black,red, black, red, black, red so the second 4 should have been 5 of a black suit. The two 4's were hearts and upside down clubs. So - upside down club.
$endgroup$
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
add a comment |
$begingroup$
I found there are 1,2,3,4,4,6,7,8 of each suite and the number increases black,red, black, red, black, red so the second 4 should have been 5 of a black suit. The two 4's were hearts and upside down clubs. So - upside down club.
$endgroup$
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
add a comment |
$begingroup$
I found there are 1,2,3,4,4,6,7,8 of each suite and the number increases black,red, black, red, black, red so the second 4 should have been 5 of a black suit. The two 4's were hearts and upside down clubs. So - upside down club.
$endgroup$
I found there are 1,2,3,4,4,6,7,8 of each suite and the number increases black,red, black, red, black, red so the second 4 should have been 5 of a black suit. The two 4's were hearts and upside down clubs. So - upside down club.
answered May 14 '16 at 21:42
Christine DobsonChristine Dobson
1
1
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
add a comment |
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
2
2
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
$begingroup$
This answer is correct, but the observed pattern is a consequence of the pattern mentioned in the other answer.
$endgroup$
– f''
May 14 '16 at 21:46
add a comment |
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$begingroup$
Is Genc Kelmendi's answer correct? Is it going to be accepted?
$endgroup$
– Rand al'Thor
Mar 11 '15 at 15:02
$begingroup$
Probably and no.
$endgroup$
– Anthony Pham
Mar 11 '15 at 23:15