Convert dataframe into dictionary
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
{20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]}
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = {20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]}
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dictionary
New contributor
add a comment |
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
{20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]}
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = {20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]}
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dictionary
New contributor
1
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
2
drop=False
inset_index
is what you need
– Sreeram TP
17 hours ago
add a comment |
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
{20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]}
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = {20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]}
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dictionary
New contributor
I have a dataframe and i want it to select a few columns and convert it into Dictionary in the a certain manner
Dataframe:
and here's the output I want
{20: [4.6, 4.3, 4.3, 20],
21: [4.6, 4.3, 4.3, 21],
22: [6.0, 5.6, 9.0, 22],
23: [8.75, 5.6, 6.6, 23]}
I have tried this
items_dic = data[["Length","Width","Height","Pid" ]].set_index('Pid').T.to_dict('list')
items_dic = {20: [4.6, 4.3, 4.3],
21: [4.6, 4.3, 4.3],
22: [6.0, 5.6, 9.0],
23: [8.75, 5.6, 6.6]}
but this does not include Pid in the list of values
Can someone explain why ?
python python-3.x pandas dictionary
python python-3.x pandas dictionary
New contributor
New contributor
edited 17 hours ago
jezrael
346k25301374
346k25301374
New contributor
asked 17 hours ago
Rahul SharmaRahul Sharma
957
957
New contributor
New contributor
1
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
2
drop=False
inset_index
is what you need
– Sreeram TP
17 hours ago
add a comment |
1
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
2
drop=False
inset_index
is what you need
– Sreeram TP
17 hours ago
1
1
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
2
2
drop=False
in set_index
is what you need– Sreeram TP
17 hours ago
drop=False
in set_index
is what you need– Sreeram TP
17 hours ago
add a comment |
2 Answers
2
active
oldest
votes
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
{20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]}
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
{20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]}
>>>
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
{20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]}
add a comment |
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
{20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]}
add a comment |
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
{20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]}
Set parameter drop=False
in DataFrame.set_index
, because default parameter drop=False
move column to index:
cols = ["Length","Width","Height","Pid"]
items_dic = data[cols].set_index('Pid', drop=False).T.to_dict('list')
print (items_dic)
{20: [4.6, 4.3, 4.3, 20.0],
21: [4.6, 4.3, 4.3, 21.0],
22: [6.0, 5.6, 9.0, 22.0],
23: [8.75, 5.6, 6.6, 23.0]}
edited 17 hours ago
answered 17 hours ago
jezraeljezrael
346k25301374
346k25301374
add a comment |
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
{20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]}
>>>
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
{20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]}
>>>
add a comment |
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
{20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]}
>>>
Or use dict(zip(...))
:
>>> cols = ["Length","Width","Height","Pid"]
>>> items_dic = dict(zip(df['Pid'],df[cols].values.tolist()))
>>> items_dic
{20: [4.8, 4.3, 4.3, 20.0], 21: [4.8, 4.3, 4.3, 21.0], 22: [6.0, 5.6, 9.0, 22.0], 23: [8.75, 5.6, 6.6, 23.0], 24: [6.0, 5.16, 6.6, 24.0]}
>>>
edited 15 hours ago
Mudits
6641928
6641928
answered 17 hours ago
U9-ForwardU9-Forward
16.5k51543
16.5k51543
add a comment |
add a comment |
Rahul Sharma is a new contributor. Be nice, and check out our Code of Conduct.
Rahul Sharma is a new contributor. Be nice, and check out our Code of Conduct.
Rahul Sharma is a new contributor. Be nice, and check out our Code of Conduct.
Rahul Sharma is a new contributor. Be nice, and check out our Code of Conduct.
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1
Please, write the dataframe in proper format, not in picture.
– pistol2myhead
17 hours ago
I am sorry but I am fairly new to SO and I don't know how to do that
– Rahul Sharma
17 hours ago
2
drop=False
inset_index
is what you need– Sreeram TP
17 hours ago