How to count words in a line
I have a text file called "shoplist.txt" which one have:
drinks water cola fanta
fruit banana orange
And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?
My actually code is:
fileLine=`cat file.txt`
#Here I get each line saving it to fileLine
for line in $fileLine; do
echo
((aux++))
done
But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)
How can I get the first line and then count the words on that line?
bash shell-script
add a comment |
I have a text file called "shoplist.txt" which one have:
drinks water cola fanta
fruit banana orange
And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?
My actually code is:
fileLine=`cat file.txt`
#Here I get each line saving it to fileLine
for line in $fileLine; do
echo
((aux++))
done
But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)
How can I get the first line and then count the words on that line?
bash shell-script
wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
Is the output of theawk
script in the answer what you want to have? If not, what exactly do you want to get?
– Bodo
2 hours ago
add a comment |
I have a text file called "shoplist.txt" which one have:
drinks water cola fanta
fruit banana orange
And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?
My actually code is:
fileLine=`cat file.txt`
#Here I get each line saving it to fileLine
for line in $fileLine; do
echo
((aux++))
done
But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)
How can I get the first line and then count the words on that line?
bash shell-script
I have a text file called "shoplist.txt" which one have:
drinks water cola fanta
fruit banana orange
And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?
My actually code is:
fileLine=`cat file.txt`
#Here I get each line saving it to fileLine
for line in $fileLine; do
echo
((aux++))
done
But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)
How can I get the first line and then count the words on that line?
bash shell-script
bash shell-script
edited 19 hours ago
Rui F Ribeiro
41k1479137
41k1479137
asked 19 hours ago
Multi17Multi17
182
182
wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
Is the output of theawk
script in the answer what you want to have? If not, what exactly do you want to get?
– Bodo
2 hours ago
add a comment |
wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
Is the output of theawk
script in the answer what you want to have? If not, what exactly do you want to get?
– Bodo
2 hours ago
wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
Is the output of the
awk
script in the answer what you want to have? If not, what exactly do you want to get?– Bodo
2 hours ago
Is the output of the
awk
script in the answer what you want to have? If not, what exactly do you want to get?– Bodo
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
If you can use awk
, NF
is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).
Use
awk '{ print NF, $0 }' inputfile
With your sample input, this will print
4 drinks water cola fanta
3 fruit banana orange
The more crypticawk '$0=NF" "$0' inputfile
is a shorter solution.
– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
add a comment |
In Bash and wc
:
IFS=$'n'
while read line; do
wc -w <<< "$line"
done < file.txt
wc
counts lines, words, bytes in files. With a shell loop you can make it count words in a line.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you can use awk
, NF
is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).
Use
awk '{ print NF, $0 }' inputfile
With your sample input, this will print
4 drinks water cola fanta
3 fruit banana orange
The more crypticawk '$0=NF" "$0' inputfile
is a shorter solution.
– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
add a comment |
If you can use awk
, NF
is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).
Use
awk '{ print NF, $0 }' inputfile
With your sample input, this will print
4 drinks water cola fanta
3 fruit banana orange
The more crypticawk '$0=NF" "$0' inputfile
is a shorter solution.
– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
add a comment |
If you can use awk
, NF
is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).
Use
awk '{ print NF, $0 }' inputfile
With your sample input, this will print
4 drinks water cola fanta
3 fruit banana orange
If you can use awk
, NF
is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).
Use
awk '{ print NF, $0 }' inputfile
With your sample input, this will print
4 drinks water cola fanta
3 fruit banana orange
edited 15 hours ago
Kusalananda
134k17254418
134k17254418
answered 19 hours ago
BodoBodo
2,033316
2,033316
The more crypticawk '$0=NF" "$0' inputfile
is a shorter solution.
– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
add a comment |
The more crypticawk '$0=NF" "$0' inputfile
is a shorter solution.
– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
The more cryptic
awk '$0=NF" "$0' inputfile
is a shorter solution.– Isaac
9 hours ago
The more cryptic
awk '$0=NF" "$0' inputfile
is a shorter solution.– Isaac
9 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
@Isaac: Really ? Is shorter better ? In this specific case Bodo's answer is just the answer to OP, ... and [s]he beat us all to it. :-[
– Cbhihe
2 hours ago
add a comment |
In Bash and wc
:
IFS=$'n'
while read line; do
wc -w <<< "$line"
done < file.txt
wc
counts lines, words, bytes in files. With a shell loop you can make it count words in a line.
add a comment |
In Bash and wc
:
IFS=$'n'
while read line; do
wc -w <<< "$line"
done < file.txt
wc
counts lines, words, bytes in files. With a shell loop you can make it count words in a line.
add a comment |
In Bash and wc
:
IFS=$'n'
while read line; do
wc -w <<< "$line"
done < file.txt
wc
counts lines, words, bytes in files. With a shell loop you can make it count words in a line.
In Bash and wc
:
IFS=$'n'
while read line; do
wc -w <<< "$line"
done < file.txt
wc
counts lines, words, bytes in files. With a shell loop you can make it count words in a line.
edited 15 hours ago
answered 18 hours ago
sborskysborsky
789511
789511
add a comment |
add a comment |
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wc would do the necessary job in a loop.
– Puspharaj Selvaraj
8 hours ago
Is the output of the
awk
script in the answer what you want to have? If not, what exactly do you want to get?– Bodo
2 hours ago