Independently Tidelocked Moon?












4












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Simple question that might seem odd. Not going to get too specific but I am curious, more or less, as to what it would look like for a planet that had a moon (A habital one) which was in essence tidally-locked to the star of the system. In addition, just how probable/possible is that, really?



It orbits its planet as any satellite does but isn't tidally locked to it. Instead its spin in relation to its own orbit around the planet (and its own orbit of the sun) causes it to always have the same side facing the sun. I assume this would cause for habitual, essentially daily eclipses for the side in eternal day (Almost equating to its own equivalent of a "night") but I can't find what else that might entail.






gravity orbital-mechanics solar-system tides







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4












$begingroup$


Simple question that might seem odd. Not going to get too specific but I am curious, more or less, as to what it would look like for a planet that had a moon (A habital one) which was in essence tidally-locked to the star of the system. In addition, just how probable/possible is that, really?



It orbits its planet as any satellite does but isn't tidally locked to it. Instead its spin in relation to its own orbit around the planet (and its own orbit of the sun) causes it to always have the same side facing the sun. I assume this would cause for habitual, essentially daily eclipses for the side in eternal day (Almost equating to its own equivalent of a "night") but I can't find what else that might entail.






gravity orbital-mechanics solar-system tides







share|improve this question







New contributor




Magilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    Welcome to worldbuilding, please take the tour and visit the help center to make yourself familiar with our community.
    $endgroup$
    – L.Dutch♦
    4 hours ago














4












4








4





$begingroup$


Simple question that might seem odd. Not going to get too specific but I am curious, more or less, as to what it would look like for a planet that had a moon (A habital one) which was in essence tidally-locked to the star of the system. In addition, just how probable/possible is that, really?



It orbits its planet as any satellite does but isn't tidally locked to it. Instead its spin in relation to its own orbit around the planet (and its own orbit of the sun) causes it to always have the same side facing the sun. I assume this would cause for habitual, essentially daily eclipses for the side in eternal day (Almost equating to its own equivalent of a "night") but I can't find what else that might entail.






gravity orbital-mechanics solar-system tides







share|improve this question







New contributor




Magilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Simple question that might seem odd. Not going to get too specific but I am curious, more or less, as to what it would look like for a planet that had a moon (A habital one) which was in essence tidally-locked to the star of the system. In addition, just how probable/possible is that, really?



It orbits its planet as any satellite does but isn't tidally locked to it. Instead its spin in relation to its own orbit around the planet (and its own orbit of the sun) causes it to always have the same side facing the sun. I assume this would cause for habitual, essentially daily eclipses for the side in eternal day (Almost equating to its own equivalent of a "night") but I can't find what else that might entail.






gravity orbital-mechanics solar-system tides




gravity orbital-mechanics solar-system tides






share|improve this question







New contributor




Magilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Magilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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share|improve this question






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asked 5 hours ago









MagillaMagilla

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Magilla is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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Check out our Code of Conduct.












  • $begingroup$
    Welcome to worldbuilding, please take the tour and visit the help center to make yourself familiar with our community.
    $endgroup$
    – L.Dutch♦
    4 hours ago


















  • $begingroup$
    Welcome to worldbuilding, please take the tour and visit the help center to make yourself familiar with our community.
    $endgroup$
    – L.Dutch♦
    4 hours ago
















$begingroup$
Welcome to worldbuilding, please take the tour and visit the help center to make yourself familiar with our community.
$endgroup$
– L.Dutch♦
4 hours ago




$begingroup$
Welcome to worldbuilding, please take the tour and visit the help center to make yourself familiar with our community.
$endgroup$
– L.Dutch♦
4 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

Tidal lock happens when the tidal forces, exerting a momentum on a body, synchronize its rotation around its axis with the revolution around the main body.



Since for a moon-planet-star system the forces exerted by the planet will always be greater than those exerted by the star, there is no way for the moon to be tidally locked with the star and not with the planet.



The only case in which the tidal forces generated by the star are stronger than those generated by the planet implies that the moon is orbiting the star and not the planet.






share|improve this answer









$endgroup$













  • $begingroup$
    So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
    $endgroup$
    – Magilla
    1 hour ago










  • $begingroup$
    @Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
    $endgroup$
    – Tim B♦
    1 hour ago



















0












$begingroup$

For this to happen, the moon would have to be tide locked to the planet while the planet itself is tide locked to the star.



Notice that surface exposed to the star will vary slightly throughout the year due to axial tilts and also a movement called libration.






share|improve this answer











$endgroup$













  • $begingroup$
    This still wouldn't work, the moon has to orbit the planet in order not to crash into it
    $endgroup$
    – Tim B♦
    1 hour ago










  • $begingroup$
    @TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
    $endgroup$
    – Renan
    25 mins ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Tidal lock happens when the tidal forces, exerting a momentum on a body, synchronize its rotation around its axis with the revolution around the main body.



Since for a moon-planet-star system the forces exerted by the planet will always be greater than those exerted by the star, there is no way for the moon to be tidally locked with the star and not with the planet.



The only case in which the tidal forces generated by the star are stronger than those generated by the planet implies that the moon is orbiting the star and not the planet.






share|improve this answer









$endgroup$













  • $begingroup$
    So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
    $endgroup$
    – Magilla
    1 hour ago










  • $begingroup$
    @Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
    $endgroup$
    – Tim B♦
    1 hour ago
















3












$begingroup$

Tidal lock happens when the tidal forces, exerting a momentum on a body, synchronize its rotation around its axis with the revolution around the main body.



Since for a moon-planet-star system the forces exerted by the planet will always be greater than those exerted by the star, there is no way for the moon to be tidally locked with the star and not with the planet.



The only case in which the tidal forces generated by the star are stronger than those generated by the planet implies that the moon is orbiting the star and not the planet.






share|improve this answer









$endgroup$













  • $begingroup$
    So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
    $endgroup$
    – Magilla
    1 hour ago










  • $begingroup$
    @Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
    $endgroup$
    – Tim B♦
    1 hour ago














3












3








3





$begingroup$

Tidal lock happens when the tidal forces, exerting a momentum on a body, synchronize its rotation around its axis with the revolution around the main body.



Since for a moon-planet-star system the forces exerted by the planet will always be greater than those exerted by the star, there is no way for the moon to be tidally locked with the star and not with the planet.



The only case in which the tidal forces generated by the star are stronger than those generated by the planet implies that the moon is orbiting the star and not the planet.






share|improve this answer









$endgroup$



Tidal lock happens when the tidal forces, exerting a momentum on a body, synchronize its rotation around its axis with the revolution around the main body.



Since for a moon-planet-star system the forces exerted by the planet will always be greater than those exerted by the star, there is no way for the moon to be tidally locked with the star and not with the planet.



The only case in which the tidal forces generated by the star are stronger than those generated by the planet implies that the moon is orbiting the star and not the planet.







share|improve this answer












share|improve this answer



share|improve this answer










answered 4 hours ago









L.Dutch♦L.Dutch

80.4k26192391




80.4k26192391












  • $begingroup$
    So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
    $endgroup$
    – Magilla
    1 hour ago










  • $begingroup$
    @Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
    $endgroup$
    – Tim B♦
    1 hour ago


















  • $begingroup$
    So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
    $endgroup$
    – Magilla
    1 hour ago










  • $begingroup$
    @Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
    $endgroup$
    – Tim B♦
    1 hour ago
















$begingroup$
So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
$endgroup$
– Magilla
1 hour ago




$begingroup$
So does a moon have to be tidally locked to its planet? Is it not actually feasible a moon's own rotation could not sync like that with a star?
$endgroup$
– Magilla
1 hour ago












$begingroup$
@Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
$endgroup$
– Tim B♦
1 hour ago




$begingroup$
@Magilla It would be a short term (in astronomical terms) and temporary coincidence if it was.
$endgroup$
– Tim B♦
1 hour ago











0












$begingroup$

For this to happen, the moon would have to be tide locked to the planet while the planet itself is tide locked to the star.



Notice that surface exposed to the star will vary slightly throughout the year due to axial tilts and also a movement called libration.






share|improve this answer











$endgroup$













  • $begingroup$
    This still wouldn't work, the moon has to orbit the planet in order not to crash into it
    $endgroup$
    – Tim B♦
    1 hour ago










  • $begingroup$
    @TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
    $endgroup$
    – Renan
    25 mins ago
















0












$begingroup$

For this to happen, the moon would have to be tide locked to the planet while the planet itself is tide locked to the star.



Notice that surface exposed to the star will vary slightly throughout the year due to axial tilts and also a movement called libration.






share|improve this answer











$endgroup$













  • $begingroup$
    This still wouldn't work, the moon has to orbit the planet in order not to crash into it
    $endgroup$
    – Tim B♦
    1 hour ago










  • $begingroup$
    @TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
    $endgroup$
    – Renan
    25 mins ago














0












0








0





$begingroup$

For this to happen, the moon would have to be tide locked to the planet while the planet itself is tide locked to the star.



Notice that surface exposed to the star will vary slightly throughout the year due to axial tilts and also a movement called libration.






share|improve this answer











$endgroup$



For this to happen, the moon would have to be tide locked to the planet while the planet itself is tide locked to the star.



Notice that surface exposed to the star will vary slightly throughout the year due to axial tilts and also a movement called libration.







share|improve this answer














share|improve this answer



share|improve this answer








edited 26 mins ago

























answered 1 hour ago









RenanRenan

46.2k11109234




46.2k11109234












  • $begingroup$
    This still wouldn't work, the moon has to orbit the planet in order not to crash into it
    $endgroup$
    – Tim B♦
    1 hour ago










  • $begingroup$
    @TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
    $endgroup$
    – Renan
    25 mins ago


















  • $begingroup$
    This still wouldn't work, the moon has to orbit the planet in order not to crash into it
    $endgroup$
    – Tim B♦
    1 hour ago










  • $begingroup$
    @TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
    $endgroup$
    – Renan
    25 mins ago
















$begingroup$
This still wouldn't work, the moon has to orbit the planet in order not to crash into it
$endgroup$
– Tim B♦
1 hour ago




$begingroup$
This still wouldn't work, the moon has to orbit the planet in order not to crash into it
$endgroup$
– Tim B♦
1 hour ago












$begingroup$
@TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
$endgroup$
– Renan
25 mins ago




$begingroup$
@TimB I am suggesting a Moon that is tifslly locked to a planet, thus it is in orbit around the planet.
$endgroup$
– Renan
25 mins ago










Magilla is a new contributor. Be nice, and check out our Code of Conduct.










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