Why isn't the circumferential light around the M87 black hole's event horizon symmetric?












18












$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










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$endgroup$








  • 13




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    12 hours ago








  • 1




    $begingroup$
    youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – penguin359
    5 hours ago
















18












$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










share|cite|improve this question











$endgroup$








  • 13




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    12 hours ago








  • 1




    $begingroup$
    youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – penguin359
    5 hours ago














18












18








18


3



$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










share|cite|improve this question











$endgroup$




After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here







general-relativity black-holes astronomy event-horizon accretion-disk






share|cite|improve this question















share|cite|improve this question













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share|cite|improve this question








edited 6 hours ago









Qmechanic

107k122001241




107k122001241










asked 14 hours ago









0x900x90

1,09041533




1,09041533








  • 13




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    12 hours ago








  • 1




    $begingroup$
    youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – penguin359
    5 hours ago














  • 13




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    12 hours ago








  • 1




    $begingroup$
    youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – penguin359
    5 hours ago








13




13




$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago






$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago






1




1




$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago




$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago










4 Answers
4






active

oldest

votes


















17












$begingroup$

This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



enter image description here



There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    7 hours ago





















3












$begingroup$

The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



The pictures below from the fifth event horizon telescope paper makes things clear.



Relative orientation of spin and accretion flow



The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






share|cite|improve this answer









$endgroup$





















    2












    $begingroup$

    I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



    enter image description here



    Image from BBC News and EHT Collaboration




    The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







    share|cite|improve this answer








    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$









    • 1




      $begingroup$
      I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Douglas Held
      9 hours ago










    • $begingroup$
      @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
      $endgroup$
      – StudyStudy
      9 hours ago










    • $begingroup$
      This doesn't address the reason for the asymmetry in the ring at all
      $endgroup$
      – Rob Jeffries
      7 hours ago



















    0












    $begingroup$

    I found this animated GIF to explain this really well:



    https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



    Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






    share|cite|improve this answer








    New contributor




    zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$













    • $begingroup$
      Like Doppler effect?
      $endgroup$
      – 0x90
      7 hours ago










    • $begingroup$
      No - not like doppler effect.
      $endgroup$
      – Rory Alsop
      6 hours ago










    • $begingroup$
      youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Draco18s
      1 hour ago












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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    17












    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$













    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      7 hours ago


















    17












    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$













    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      7 hours ago
















    17












    17








    17





    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$



    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited 13 hours ago

























    answered 14 hours ago









    VoidVoid

    11k11758




    11k11758












    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      7 hours ago




















    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      7 hours ago


















    $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    7 hours ago






    $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    7 hours ago













    3












    $begingroup$

    The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



    The pictures below from the fifth event horizon telescope paper makes things clear.



    Relative orientation of spin and accretion flow



    The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



    The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






    share|cite|improve this answer









    $endgroup$


















      3












      $begingroup$

      The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



      The pictures below from the fifth event horizon telescope paper makes things clear.



      Relative orientation of spin and accretion flow



      The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



      The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






      share|cite|improve this answer









      $endgroup$
















        3












        3








        3





        $begingroup$

        The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



        The pictures below from the fifth event horizon telescope paper makes things clear.



        Relative orientation of spin and accretion flow



        The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



        The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






        share|cite|improve this answer









        $endgroup$



        The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



        The pictures below from the fifth event horizon telescope paper makes things clear.



        Relative orientation of spin and accretion flow



        The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



        The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 7 hours ago









        Rob JeffriesRob Jeffries

        70.7k7145245




        70.7k7145245























            2












            $begingroup$

            I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



            enter image description here



            Image from BBC News and EHT Collaboration




            The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







            share|cite|improve this answer








            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$









            • 1




              $begingroup$
              I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Douglas Held
              9 hours ago










            • $begingroup$
              @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
              $endgroup$
              – StudyStudy
              9 hours ago










            • $begingroup$
              This doesn't address the reason for the asymmetry in the ring at all
              $endgroup$
              – Rob Jeffries
              7 hours ago
















            2












            $begingroup$

            I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



            enter image description here



            Image from BBC News and EHT Collaboration




            The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







            share|cite|improve this answer








            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$









            • 1




              $begingroup$
              I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Douglas Held
              9 hours ago










            • $begingroup$
              @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
              $endgroup$
              – StudyStudy
              9 hours ago










            • $begingroup$
              This doesn't address the reason for the asymmetry in the ring at all
              $endgroup$
              – Rob Jeffries
              7 hours ago














            2












            2








            2





            $begingroup$

            I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



            enter image description here



            Image from BBC News and EHT Collaboration




            The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







            share|cite|improve this answer








            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$



            I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



            enter image description here



            Image from BBC News and EHT Collaboration




            The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.








            share|cite|improve this answer








            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            share|cite|improve this answer



            share|cite|improve this answer






            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            answered 14 hours ago









            StudyStudyStudyStudy

            1377




            1377




            New contributor




            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            New contributor





            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.








            • 1




              $begingroup$
              I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Douglas Held
              9 hours ago










            • $begingroup$
              @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
              $endgroup$
              – StudyStudy
              9 hours ago










            • $begingroup$
              This doesn't address the reason for the asymmetry in the ring at all
              $endgroup$
              – Rob Jeffries
              7 hours ago














            • 1




              $begingroup$
              I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Douglas Held
              9 hours ago










            • $begingroup$
              @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
              $endgroup$
              – StudyStudy
              9 hours ago










            • $begingroup$
              This doesn't address the reason for the asymmetry in the ring at all
              $endgroup$
              – Rob Jeffries
              7 hours ago








            1




            1




            $begingroup$
            I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
            $endgroup$
            – Douglas Held
            9 hours ago




            $begingroup$
            I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
            $endgroup$
            – Douglas Held
            9 hours ago












            $begingroup$
            @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
            $endgroup$
            – StudyStudy
            9 hours ago




            $begingroup$
            @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
            $endgroup$
            – StudyStudy
            9 hours ago












            $begingroup$
            This doesn't address the reason for the asymmetry in the ring at all
            $endgroup$
            – Rob Jeffries
            7 hours ago




            $begingroup$
            This doesn't address the reason for the asymmetry in the ring at all
            $endgroup$
            – Rob Jeffries
            7 hours ago











            0












            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              7 hours ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              6 hours ago










            • $begingroup$
              youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Draco18s
              1 hour ago
















            0












            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              7 hours ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              6 hours ago










            • $begingroup$
              youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Draco18s
              1 hour ago














            0












            0








            0





            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$



            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.







            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            share|cite|improve this answer



            share|cite|improve this answer






            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            answered 8 hours ago









            zxbEPREFzxbEPREF

            109




            109




            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            New contributor





            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.












            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              7 hours ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              6 hours ago










            • $begingroup$
              youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Draco18s
              1 hour ago


















            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              7 hours ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              6 hours ago










            • $begingroup$
              youtube.com/watch?v=zUyH3XhpLTo
              $endgroup$
              – Draco18s
              1 hour ago
















            $begingroup$
            Like Doppler effect?
            $endgroup$
            – 0x90
            7 hours ago




            $begingroup$
            Like Doppler effect?
            $endgroup$
            – 0x90
            7 hours ago












            $begingroup$
            No - not like doppler effect.
            $endgroup$
            – Rory Alsop
            6 hours ago




            $begingroup$
            No - not like doppler effect.
            $endgroup$
            – Rory Alsop
            6 hours ago












            $begingroup$
            youtube.com/watch?v=zUyH3XhpLTo
            $endgroup$
            – Draco18s
            1 hour ago




            $begingroup$
            youtube.com/watch?v=zUyH3XhpLTo
            $endgroup$
            – Draco18s
            1 hour ago


















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