Htydjtk

I want to split a song into multiple parts, given the song duration and number of parts.

My code achieves that, but it feels a little "stupid" and I would like to learn a more sophisticated - and shorter - way. Particularly, I feel that the marker variable is a little overkill. I would welcome any suggestions.

song_duration = 20 # these two 

num_of_parts = 4   # are given



part_duration = song_duration / num_of_parts

parts = 

marker = 0



for _ in range(num_of_parts):

    part = [marker, marker + part_duration]

    marker += part_duration

    parts.append(part)



print(parts)



# parts is : [[0, 5.0], [5.0, 10.0], [10.0, 15.0], [15.0, 20.0]]

In general, building a list using a loop of the form

some_list = 

for …:

    some_list.append(…)

… would be better written using a list comprehension.

Each interval always has two elements: a start time and an end time. These two-element lists would be better represented as tuples instead of lists. (Tuples have a connotation that they have a fixed length, whereas lists can grow to arbitrary lengths.)

Finally, I'd package the code into a function.

def intervals(parts, duration):

    part_duration = duration / parts

    return [(i * part_duration, (i + 1) * part_duration) for i in range(parts)]

Firstly you should be able to see that the left value in each part is the same as the right value in the previous part. This can be implemented by using the pairwise recipe:

def pairwise(iterable):

    "s -> (s0,s1), (s1,s2), (s2, s3), ..."

    a, b = tee(iterable)

    next(b, None)

    return zip(a, b)

From this you should be able to generate all the wanted numbers using a list, or generator, comprehension:

part_duration = song_duration / num_of_parts

parts = [i * part_duration for i in range(num_of_parts + 1)]

import itertools



def pairwise(iterable):

    "s -> (s0,s1), (s1,s2), (s2, s3), ..."

    a, b = itertools.tee(iterable)

    next(b, None)

    return zip(a, b)



def song_segments(duration, segments):

    delta = duration / segments

    return pairwise([i * delta for i in range(segments + 1)])





print(list(song_segments(20, 4)))

Here are a few suggestions.

Write a function

Your code could be moved into a function on its own. It has the benefit of giving the code a clear name, a clear input, a clear output and we could go further and add documentation and tests.

def split_song(song_duration, num_of_parts):

    """Returns parts when a song of duration song_duration is split into num_of_parts parts."""

    part_duration = song_duration / num_of_parts

    parts = 

    marker = 0



    for _ in range(num_of_parts):

        part = [marker, marker + part_duration]

        marker += part_duration

        parts.append(part)

    return parts



assert split_song(20, 4) == [[0, 5.0], [5.0, 10.0], [10.0, 15.0], [15.0, 20.0]]

assert split_song(21, 4) == [[0, 5.25], [5.25, 10.5], [10.5, 15.75], [15.75, 21.0]]

Proper data structure

You are returning a list of list. In Python, there is a cultural difference in how tuple and list are used.

In our case, we know that each piece will contain 2 pieces of information: the begining and the end. It would be more relevant to use tuples here.

part = (marker, marker + part_duration)

A few things:

First, you can make use of the third parameter of range, which is the step, IF you can guarantee that part_duration is an integer (which is the case for the example you posted here):

# Integer division

part_duration = song_duration // num_of_parts

parts = 



# I rearranged this a bit too

for i in range(0, song_duration, part_duration):

    part = [i, i + part_duration]

    parts.append(part)



print(parts)

# [[0, 5], [5, 10], [10, 15], [15, 20]] # Note they're integers

Note how this is just a transformation from a range to a list though. If you're transforming one collection to a list, list comprehensions should come to mind:

# List comprehension split over two lines

parts = [[i, i + part_duration]

         for i in range(0, song_duration, part_duration)]



print(parts)

# [[0, 5], [5, 10], [10, 15], [15, 20]]

If you can't guarantee integer steps though, I'm not sure of a good way. Unfortunately, Python doesn't allow fractional steps for its range.