Is every open circuit a capacitor?












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I think that even open ended wires can let ac current flow through them, just with low capacitance. I also think an antenna could be a capacitor and open ended. Am I thinking correctly?










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  • 11




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    Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
    $endgroup$
    – Solomon Slow
    yesterday












  • $begingroup$
    Possibly useful: physics.stackexchange.com/a/301027/44126
    $endgroup$
    – rob
    yesterday






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    Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
    $endgroup$
    – Dmitry Grigoryev
    21 hours ago










  • $begingroup$
    "I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
    $endgroup$
    – rexkogitans
    18 hours ago
















23












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I think that even open ended wires can let ac current flow through them, just with low capacitance. I also think an antenna could be a capacitor and open ended. Am I thinking correctly?










share|cite|improve this question











$endgroup$








  • 11




    $begingroup$
    Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
    $endgroup$
    – Solomon Slow
    yesterday












  • $begingroup$
    Possibly useful: physics.stackexchange.com/a/301027/44126
    $endgroup$
    – rob
    yesterday






  • 1




    $begingroup$
    Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
    $endgroup$
    – Dmitry Grigoryev
    21 hours ago










  • $begingroup$
    "I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
    $endgroup$
    – rexkogitans
    18 hours ago














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I think that even open ended wires can let ac current flow through them, just with low capacitance. I also think an antenna could be a capacitor and open ended. Am I thinking correctly?










share|cite|improve this question











$endgroup$




I think that even open ended wires can let ac current flow through them, just with low capacitance. I also think an antenna could be a capacitor and open ended. Am I thinking correctly?







electric-circuits electric-current capacitance antennas






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edited yesterday









Aaron Stevens

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asked yesterday









Bálint TataiBálint Tatai

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19517








  • 11




    $begingroup$
    Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
    $endgroup$
    – Solomon Slow
    yesterday












  • $begingroup$
    Possibly useful: physics.stackexchange.com/a/301027/44126
    $endgroup$
    – rob
    yesterday






  • 1




    $begingroup$
    Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
    $endgroup$
    – Dmitry Grigoryev
    21 hours ago










  • $begingroup$
    "I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
    $endgroup$
    – rexkogitans
    18 hours ago














  • 11




    $begingroup$
    Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
    $endgroup$
    – Solomon Slow
    yesterday












  • $begingroup$
    Possibly useful: physics.stackexchange.com/a/301027/44126
    $endgroup$
    – rob
    yesterday






  • 1




    $begingroup$
    Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
    $endgroup$
    – Dmitry Grigoryev
    21 hours ago










  • $begingroup$
    "I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
    $endgroup$
    – rexkogitans
    18 hours ago








11




11




$begingroup$
Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
$endgroup$
– Solomon Slow
yesterday






$begingroup$
Depends whether you are talking about a real, physical circuit, or a lumped element model of a circuit. In the physical world, yes, capacitance is distributed everywhere between conductors. In the model, we pretend that the distributed capacitance doesn't exist in order to make the math more tractable. In cases where the actual, distributed capacitance can't be ignored, we often can solve the problem by adding another "lump" to the model and calling it "parasitic capacitance."
$endgroup$
– Solomon Slow
yesterday














$begingroup$
Possibly useful: physics.stackexchange.com/a/301027/44126
$endgroup$
– rob
yesterday




$begingroup$
Possibly useful: physics.stackexchange.com/a/301027/44126
$endgroup$
– rob
yesterday




1




1




$begingroup$
Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
$endgroup$
– Dmitry Grigoryev
21 hours ago




$begingroup$
Capacitance is not an intrinsic characteristic of capacitors, it's a common property of all circuits, just like resistance or mass. Everything is a capacitor given a high enough frequency.
$endgroup$
– Dmitry Grigoryev
21 hours ago












$begingroup$
"I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
$endgroup$
– rexkogitans
18 hours ago




$begingroup$
"I also think an antenna could be a capacitor and open ended" A marconi antenna is the perfect example for a wire whose ends are the poles of a capacitor, and in between is a coil with only one straightend loop: A complete LC circuit.
$endgroup$
– rexkogitans
18 hours ago










9 Answers
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You are right, every circuit possesses some unintended capacitance, which is called "stray" capacitance. Whether or not it affects the operation of the circuit depends on the frequencies that the circuit is intended to operate at. The amount of stray capacitance that a circuit has is typically tiny, but at high enough frequencies even a very tiny amount of capacitance will couple parts of the circuit together and make it malfunction.



For example, the circuit inside a plug that connects together computer routers and switches in a big router farm has to operate at ultrahigh frequencies, at which two adjacent traces on a circuit board can present enough stray capacitance to stop the device from functioning.



And the capacitance between a long piece of wire strung between two trees as a shortwave transmitting antenna and the ground beneath it is enough to alter the resonant frequency of the antenna, which must be taken into account when designing and building the antenna.






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  • $begingroup$
    This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
    $endgroup$
    – DanielSank
    yesterday










  • $begingroup$
    @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
    $endgroup$
    – niels nielsen
    yesterday






  • 2




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    Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
    $endgroup$
    – Jim Garrison
    yesterday






  • 8




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    @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
    $endgroup$
    – hyportnex
    yesterday






  • 2




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    @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
    $endgroup$
    – BurnsBA
    yesterday



















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Yes, this is correct.



However, you should also keep in mind $-$ particularly when you're describing any type of antenna $-$ that any such residual capacitance may very well be competing with the inductance of the circuit, coming from nonzero interactions between the different currents in different parts of the circuit.



For an actual antenna, where you're radiating significant amounts of power, all of this needs to be supplemented with radiation resistance, which represents that loss of power from your current source into the far-field electromagnetic field.






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    If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
    $endgroup$
    – hyportnex
    yesterday










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    @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
    $endgroup$
    – Emilio Pisanty
    yesterday










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    In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
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    – hyportnex
    yesterday





















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A slight deviation from the actual question -- focus on antennas. Antennas can be capacitive or reactive in how they respond to RF energy either by feeding the antenna used for transmitting or from electromagnetic waves in receiving.



A purely resonant "ideal" antenna to a single frequency is neither capacitive nor inductive as one definition of resonance is when the antenna reactance (Imaginary) is zero. Thus pure resistance (Real) made up (hopefully) of mostly radiation resistance with smaller losses in thermal resistance.



The mobile "screwdriver" antenna that I had on the back of my pickup truck for my mobile HF transceiver had a center-loaded coil (Inductance) to offset the usually capacitive antenna. Short antennas (shorter than resonant length for the frequency) are capacitive. Long antennas are inductive.



However, to make the antenna efficient for lower frequencies it is useful to make use of capacitance on the top of the antenna. This results in increased current along the upper radiating portion of the antenna (above the center loaded coil). Increasing the capacitance is done by adding conductors to the top of the antenna, usually radiating out up to 12 inches or so. This is called a "capacity hat" for the antenna. In the case of my mobile screwdriver antenna, adding the capacity had would give me 20 to 30 dB increased received signal strength.



I thought adding a few photos would help in this description. This first photo shows the antenna and the inductor is there in the center. You can't easily see the top section (above the coil) as it is a whip antenna about 3 1/2 feet long. The coil is tunable with motorized screw drive controllable from the inside of the truck (yes, while I am driving).



enter image description here



To achieve a good match at the feed point at the base of the antenna for the lower frequencies (80 and 40 meter bands) I use a shunt coil. I create the coil merely by experimentation and not design to achieve a good match (low SWR on impedance match). It us usually about 2 microHenries or less at operating frequencies. For the lower bands (20, 17, 15, 12, and 10) it looks like an open circuit rather than a shunt.



enter image description here






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    That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
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    – uhoh
    yesterday





















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It is more useful to talk about capacitance rather than capacitors, because capacitance is a tendency of the distribution of charge to affect current flow, while a capacitor is any device designed to have capacitance. All conductors have free charges, and thus any conductors that are in proximity to one-another will affect each other electrically. Their charges will 'feel' an electric force, and will therefore rearrange, and the way this happens is described by the phenomenon of capacitance. Particularly, this describes mutual capacitance, as opposed to self-capacitance, which is the tendency of a body to store charge.



Capacitance as a concept relates a potential (or potential difference) of a body to the amount of charge stored on that body. In a vacuum, a body's capacitance depends only on its geometry and material properties. When another body is introduced nearby, they interact as described above, and therefore the capacitance of either body will change. In this case it makes the most sense to talk about conductors which are allowed to exchange charge (e.g. conductors connected to +V and ground) without being shorted together (separated electrically by a dielectric), and then we define their mutual capacitance as the ratio of charge to potential difference.



So when these requirements are met (two electrically separate conductors which are part of the same circuit), there exists mutual capacitance, which is what people mean when they say "capacitance".



Keep in mind, however, that modelling of circuit behavior with lumped elements is not appropriate when signals (voltage, current) change rapidly. If the wavelength of a sinusoidal signal is nearly of the scale of a component, or smaller, use a distributed model of components. As well, most circuit analysis neglects radiation loss, but when considering antennas you cannot. Treating radiation loss mathematically can make a couple of straight open circuit wires with incredibly small capacitance between them look like big capacitors with shunt inductances, but it's only the way radiation is modeled for circuit analysis. Radiation, in general, is a complicated phenomenon, and requires very detailed analysis. That doesn't mean you can't analyze an antenna though. Just know that if radiation is involved, circuit assumptions may need to be revised to understand the models.






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    Technically, yes... Practically, no...



    A capacitor is nothing more than an anode (wire on one side), a cathode (wire on the other side), and a dielectric in the middle (something reasonably non-conducting). So, yes, if you expose a length of wire in your house and cut it with wire cutters (please trip the breaker first...), what you'll have is a capacitor.



    But it stinks.



    Capacitance has a great deal to do with (a) the amount of conductive surface between the anode and cathode, (b) the nature of the dielectric between those conductors, and (c) the distance between the conductors.



    (a) wants to be large. Many commercial capacitors use very long lengths of foil rolled up into a tube to get substantial surface area.



    (b) wants to permit charge — but NOT permit an arc. Air will work as a dielectric (and is sometimes used), but it's not very good. I remodeled an old hospital once that had a barrel-sized capacitor (about 20 gallons in size) used with the ancient (circa 1980) X-ray machine. Two enormous lengths of foil wrapped a bazzillion times and submersed with a dielectric oil. For reasons I'll never understand, it was installed in the attic. I couldn't tip it to drain the oil. It's still there.



    (c) wants to be small (there's a lot of math here). It's not uncommon for the distance between the plates (the foil strips) to be fractions of a millimeter.



    So, yes, there's a minute and usually insignificant amount of capacitance in any open circuit. But it's not worth much.






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      $begingroup$

      You are correct that between any two conductors separated by a dielectric (solid, liquid or gas) or even by a vacuum, there is capacitance. This capacitance exists, whether or not by design. The capacitance between conductors that is not by design is sometimes referred to as "stray capacitance" (unintended and unwanted capacitance). It is usually extremely small and does not have an effect on a circuit except for the possibility of adversely affecting circuits involving very high frequencies. This is because any unwanted capacitive currents are proportional to both the magnitude of the capacitance and the rate of change in voltage between the conductors, or



      $$i(t)=Cfrac{dV(t)}{dt}$$



      When stray capacitance has an unwanted effect on a circuit, it is sometimes referred to as “parasitic” capacitance.



      I believe others have adequately covered the topic of antennas and capacitance.



      Hope this, together with the other good answers, helps.






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        $begingroup$

        Every object in a circuit has resistance, capacitance, and inductance, but these quantities are often small enough that they can be treated as being zero. When these quantities are large enough that they need to be considered, they are often separated out in circuit diagrams as "separate" objects to make the analysis easier. For instance, a battery might be represented in a circuit diagram with a symbol for DC voltage source and a symbol for a resistor, as if the voltage and resistance of the battery were being produced by separate objects. In reality, of course, a battery exhibits resistance distributed throughout its length, but for most purposes this resistance can be treated as being concentrated in one location.



        Similarly, while an ideal wire has no capacitance, in reality actual wires will have some. So will batteries, resistors, etc. If we need to consider the effect of these capacitances on the circuit, we will usually put one capacitor symbol in the circuit diagram to represent the total effective capacitance of all of them together (although in more complicated circuits we may need to represent the effect of their capacitances with multiple symbols). In a circuit with actual capacitors, the capacitances of other parts of the circuits are generally so low in comparison that they can be ignored.






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          If one were somehow able to try to draw current from any point while feeding current to any other point without involving anything else in the universe, the points would behave as though there was some capacitance between them. A network of three points, however, may behave as though there is capacitance between the first and second, and between the second and third, without behaving as though there is any meaningful capacitance between the first and third. This subject came up in a recent youtube video https://youtu.be/uGXQc-zanWg on the Mr. Carlson's Lab channel.



          As explained by that video, if a half-wave rectified signal is fed into a 50uF cap to ground, and from there passes through a 10K resistor and into another 50uF cap to ground, the second cap could easily have orders of magnitude less ripple than the first. Although it would appear that there is a 25uF connection (two 50uF caps in series) between the two sides of the 10K resistor, the ground connection between the two caps may prevent unwanted coupling of any ground-referenced signal through that capacitance. If the two caps were disconnected from ground but remained connected to each other, however, then that 25uF capacitance would come into play. If that happened but one tried to fix the circuit by adding 50uF caps in parallel with the locations where the originals should have been, that 25uF capacitance would cause the second cap to have about 1/3 as much ripple as the first.






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            Yes. If two non-insulators (in the Universe) are connected to any emf source, current will flow between them regardless of the source frequency (eg. 60Hz or 60GHz). At DC, the leakage current flow depends on the circuit conductance. At AC, the leakage current flow depends on the circuit admittance. Of course, the current may be insignificant (especially if one non-insulator is on Mars and the other is on Earth) and/or irrelevant.



            An antenna is designed to radiate with an AC emf. It depends how it is connected, as to whether it acts as a capacitance or inductance at some frequency, if it is not resonating at its fundamental or a harmonic frequency.






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            J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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              9 Answers
              9






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              9 Answers
              9






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              active

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              29












              $begingroup$

              You are right, every circuit possesses some unintended capacitance, which is called "stray" capacitance. Whether or not it affects the operation of the circuit depends on the frequencies that the circuit is intended to operate at. The amount of stray capacitance that a circuit has is typically tiny, but at high enough frequencies even a very tiny amount of capacitance will couple parts of the circuit together and make it malfunction.



              For example, the circuit inside a plug that connects together computer routers and switches in a big router farm has to operate at ultrahigh frequencies, at which two adjacent traces on a circuit board can present enough stray capacitance to stop the device from functioning.



              And the capacitance between a long piece of wire strung between two trees as a shortwave transmitting antenna and the ground beneath it is enough to alter the resonant frequency of the antenna, which must be taken into account when designing and building the antenna.






              share|cite|improve this answer









              $endgroup$













              • $begingroup$
                This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
                $endgroup$
                – DanielSank
                yesterday










              • $begingroup$
                @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
                $endgroup$
                – niels nielsen
                yesterday






              • 2




                $begingroup$
                Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
                $endgroup$
                – Jim Garrison
                yesterday






              • 8




                $begingroup$
                @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
                $endgroup$
                – hyportnex
                yesterday






              • 2




                $begingroup$
                @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
                $endgroup$
                – BurnsBA
                yesterday
















              29












              $begingroup$

              You are right, every circuit possesses some unintended capacitance, which is called "stray" capacitance. Whether or not it affects the operation of the circuit depends on the frequencies that the circuit is intended to operate at. The amount of stray capacitance that a circuit has is typically tiny, but at high enough frequencies even a very tiny amount of capacitance will couple parts of the circuit together and make it malfunction.



              For example, the circuit inside a plug that connects together computer routers and switches in a big router farm has to operate at ultrahigh frequencies, at which two adjacent traces on a circuit board can present enough stray capacitance to stop the device from functioning.



              And the capacitance between a long piece of wire strung between two trees as a shortwave transmitting antenna and the ground beneath it is enough to alter the resonant frequency of the antenna, which must be taken into account when designing and building the antenna.






              share|cite|improve this answer









              $endgroup$













              • $begingroup$
                This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
                $endgroup$
                – DanielSank
                yesterday










              • $begingroup$
                @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
                $endgroup$
                – niels nielsen
                yesterday






              • 2




                $begingroup$
                Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
                $endgroup$
                – Jim Garrison
                yesterday






              • 8




                $begingroup$
                @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
                $endgroup$
                – hyportnex
                yesterday






              • 2




                $begingroup$
                @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
                $endgroup$
                – BurnsBA
                yesterday














              29












              29








              29





              $begingroup$

              You are right, every circuit possesses some unintended capacitance, which is called "stray" capacitance. Whether or not it affects the operation of the circuit depends on the frequencies that the circuit is intended to operate at. The amount of stray capacitance that a circuit has is typically tiny, but at high enough frequencies even a very tiny amount of capacitance will couple parts of the circuit together and make it malfunction.



              For example, the circuit inside a plug that connects together computer routers and switches in a big router farm has to operate at ultrahigh frequencies, at which two adjacent traces on a circuit board can present enough stray capacitance to stop the device from functioning.



              And the capacitance between a long piece of wire strung between two trees as a shortwave transmitting antenna and the ground beneath it is enough to alter the resonant frequency of the antenna, which must be taken into account when designing and building the antenna.






              share|cite|improve this answer









              $endgroup$



              You are right, every circuit possesses some unintended capacitance, which is called "stray" capacitance. Whether or not it affects the operation of the circuit depends on the frequencies that the circuit is intended to operate at. The amount of stray capacitance that a circuit has is typically tiny, but at high enough frequencies even a very tiny amount of capacitance will couple parts of the circuit together and make it malfunction.



              For example, the circuit inside a plug that connects together computer routers and switches in a big router farm has to operate at ultrahigh frequencies, at which two adjacent traces on a circuit board can present enough stray capacitance to stop the device from functioning.



              And the capacitance between a long piece of wire strung between two trees as a shortwave transmitting antenna and the ground beneath it is enough to alter the resonant frequency of the antenna, which must be taken into account when designing and building the antenna.







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered yesterday









              niels nielsenniels nielsen

              20.2k53061




              20.2k53061












              • $begingroup$
                This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
                $endgroup$
                – DanielSank
                yesterday










              • $begingroup$
                @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
                $endgroup$
                – niels nielsen
                yesterday






              • 2




                $begingroup$
                Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
                $endgroup$
                – Jim Garrison
                yesterday






              • 8




                $begingroup$
                @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
                $endgroup$
                – hyportnex
                yesterday






              • 2




                $begingroup$
                @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
                $endgroup$
                – BurnsBA
                yesterday


















              • $begingroup$
                This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
                $endgroup$
                – DanielSank
                yesterday










              • $begingroup$
                @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
                $endgroup$
                – niels nielsen
                yesterday






              • 2




                $begingroup$
                Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
                $endgroup$
                – Jim Garrison
                yesterday






              • 8




                $begingroup$
                @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
                $endgroup$
                – hyportnex
                yesterday






              • 2




                $begingroup$
                @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
                $endgroup$
                – BurnsBA
                yesterday
















              $begingroup$
              This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
              $endgroup$
              – DanielSank
              yesterday




              $begingroup$
              This is a good answer but "ultrahigh" might be a bit of a misleading term. What frequency range do those router interconnects work at?
              $endgroup$
              – DanielSank
              yesterday












              $begingroup$
              @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
              $endgroup$
              – niels nielsen
              yesterday




              $begingroup$
              @DanielSank, a common frequency is of order 450megahertz (this would be the bit rate on a single data line in a parallel bus)
              $endgroup$
              – niels nielsen
              yesterday




              2




              2




              $begingroup$
              Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
              $endgroup$
              – Jim Garrison
              yesterday




              $begingroup$
              Is the fact that a small USB2 Bluetooth dongle won’t work reliably in a USB3 socket due to stray capacitance acting like an antenna and radiating in the 2.4GHz band?
              $endgroup$
              – Jim Garrison
              yesterday




              8




              8




              $begingroup$
              @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
              $endgroup$
              – hyportnex
              yesterday




              $begingroup$
              @DanielSank UHF (ultrahigh frequency) is standard RF nomenclature for 300MHz to 3GHz.
              $endgroup$
              – hyportnex
              yesterday




              2




              2




              $begingroup$
              @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
              $endgroup$
              – BurnsBA
              yesterday




              $begingroup$
              @DanielSank Router interconnects typically work in the 1-3 GHZ range, which is the ultrahigh frequency range. e.g., doi.org/10.1109/IEDM.2017.8268426 or people.ece.umn.edu/~sachin/conf/islped11.pdf . See en.wikipedia.org/wiki/UHF and en.wikipedia.org/wiki/Radio_spectrum for definitions.
              $endgroup$
              – BurnsBA
              yesterday











              7












              $begingroup$

              Yes, this is correct.



              However, you should also keep in mind $-$ particularly when you're describing any type of antenna $-$ that any such residual capacitance may very well be competing with the inductance of the circuit, coming from nonzero interactions between the different currents in different parts of the circuit.



              For an actual antenna, where you're radiating significant amounts of power, all of this needs to be supplemented with radiation resistance, which represents that loss of power from your current source into the far-field electromagnetic field.






              share|cite|improve this answer









              $endgroup$









              • 1




                $begingroup$
                If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
                $endgroup$
                – hyportnex
                yesterday










              • $begingroup$
                @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
                $endgroup$
                – Emilio Pisanty
                yesterday










              • $begingroup$
                In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
                $endgroup$
                – hyportnex
                yesterday


















              7












              $begingroup$

              Yes, this is correct.



              However, you should also keep in mind $-$ particularly when you're describing any type of antenna $-$ that any such residual capacitance may very well be competing with the inductance of the circuit, coming from nonzero interactions between the different currents in different parts of the circuit.



              For an actual antenna, where you're radiating significant amounts of power, all of this needs to be supplemented with radiation resistance, which represents that loss of power from your current source into the far-field electromagnetic field.






              share|cite|improve this answer









              $endgroup$









              • 1




                $begingroup$
                If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
                $endgroup$
                – hyportnex
                yesterday










              • $begingroup$
                @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
                $endgroup$
                – Emilio Pisanty
                yesterday










              • $begingroup$
                In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
                $endgroup$
                – hyportnex
                yesterday
















              7












              7








              7





              $begingroup$

              Yes, this is correct.



              However, you should also keep in mind $-$ particularly when you're describing any type of antenna $-$ that any such residual capacitance may very well be competing with the inductance of the circuit, coming from nonzero interactions between the different currents in different parts of the circuit.



              For an actual antenna, where you're radiating significant amounts of power, all of this needs to be supplemented with radiation resistance, which represents that loss of power from your current source into the far-field electromagnetic field.






              share|cite|improve this answer









              $endgroup$



              Yes, this is correct.



              However, you should also keep in mind $-$ particularly when you're describing any type of antenna $-$ that any such residual capacitance may very well be competing with the inductance of the circuit, coming from nonzero interactions between the different currents in different parts of the circuit.



              For an actual antenna, where you're radiating significant amounts of power, all of this needs to be supplemented with radiation resistance, which represents that loss of power from your current source into the far-field electromagnetic field.







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered yesterday









              Emilio PisantyEmilio Pisanty

              84.6k22209427




              84.6k22209427








              • 1




                $begingroup$
                If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
                $endgroup$
                – hyportnex
                yesterday










              • $begingroup$
                @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
                $endgroup$
                – Emilio Pisanty
                yesterday










              • $begingroup$
                In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
                $endgroup$
                – hyportnex
                yesterday
















              • 1




                $begingroup$
                If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
                $endgroup$
                – hyportnex
                yesterday










              • $begingroup$
                @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
                $endgroup$
                – Emilio Pisanty
                yesterday










              • $begingroup$
                In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
                $endgroup$
                – hyportnex
                yesterday










              1




              1




              $begingroup$
              If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
              $endgroup$
              – hyportnex
              yesterday




              $begingroup$
              If instead of referring to radiation resistance you are talking about radiation impedance then you will have also included any other reactance be it capacitive or inductive that may load the generator and transmission line connecting to the antenna.
              $endgroup$
              – hyportnex
              yesterday












              $begingroup$
              @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
              $endgroup$
              – Emilio Pisanty
              yesterday




              $begingroup$
              @hyportnex Probably. And you'll also have buried OP in enough opaque terminology that the answer becomes inscrutable. But I look forward to your answer explaining the concept.
              $endgroup$
              – Emilio Pisanty
              yesterday












              $begingroup$
              In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
              $endgroup$
              – hyportnex
              yesterday






              $begingroup$
              In that you maybe right but this is not the question that would need an 8th variation on a theme; next time.
              $endgroup$
              – hyportnex
              yesterday













              5












              $begingroup$

              A slight deviation from the actual question -- focus on antennas. Antennas can be capacitive or reactive in how they respond to RF energy either by feeding the antenna used for transmitting or from electromagnetic waves in receiving.



              A purely resonant "ideal" antenna to a single frequency is neither capacitive nor inductive as one definition of resonance is when the antenna reactance (Imaginary) is zero. Thus pure resistance (Real) made up (hopefully) of mostly radiation resistance with smaller losses in thermal resistance.



              The mobile "screwdriver" antenna that I had on the back of my pickup truck for my mobile HF transceiver had a center-loaded coil (Inductance) to offset the usually capacitive antenna. Short antennas (shorter than resonant length for the frequency) are capacitive. Long antennas are inductive.



              However, to make the antenna efficient for lower frequencies it is useful to make use of capacitance on the top of the antenna. This results in increased current along the upper radiating portion of the antenna (above the center loaded coil). Increasing the capacitance is done by adding conductors to the top of the antenna, usually radiating out up to 12 inches or so. This is called a "capacity hat" for the antenna. In the case of my mobile screwdriver antenna, adding the capacity had would give me 20 to 30 dB increased received signal strength.



              I thought adding a few photos would help in this description. This first photo shows the antenna and the inductor is there in the center. You can't easily see the top section (above the coil) as it is a whip antenna about 3 1/2 feet long. The coil is tunable with motorized screw drive controllable from the inside of the truck (yes, while I am driving).



              enter image description here



              To achieve a good match at the feed point at the base of the antenna for the lower frequencies (80 and 40 meter bands) I use a shunt coil. I create the coil merely by experimentation and not design to achieve a good match (low SWR on impedance match). It us usually about 2 microHenries or less at operating frequencies. For the lower bands (20, 17, 15, 12, and 10) it looks like an open circuit rather than a shunt.



              enter image description here






              share|cite|improve this answer











              $endgroup$













              • $begingroup$
                That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
                $endgroup$
                – uhoh
                yesterday


















              5












              $begingroup$

              A slight deviation from the actual question -- focus on antennas. Antennas can be capacitive or reactive in how they respond to RF energy either by feeding the antenna used for transmitting or from electromagnetic waves in receiving.



              A purely resonant "ideal" antenna to a single frequency is neither capacitive nor inductive as one definition of resonance is when the antenna reactance (Imaginary) is zero. Thus pure resistance (Real) made up (hopefully) of mostly radiation resistance with smaller losses in thermal resistance.



              The mobile "screwdriver" antenna that I had on the back of my pickup truck for my mobile HF transceiver had a center-loaded coil (Inductance) to offset the usually capacitive antenna. Short antennas (shorter than resonant length for the frequency) are capacitive. Long antennas are inductive.



              However, to make the antenna efficient for lower frequencies it is useful to make use of capacitance on the top of the antenna. This results in increased current along the upper radiating portion of the antenna (above the center loaded coil). Increasing the capacitance is done by adding conductors to the top of the antenna, usually radiating out up to 12 inches or so. This is called a "capacity hat" for the antenna. In the case of my mobile screwdriver antenna, adding the capacity had would give me 20 to 30 dB increased received signal strength.



              I thought adding a few photos would help in this description. This first photo shows the antenna and the inductor is there in the center. You can't easily see the top section (above the coil) as it is a whip antenna about 3 1/2 feet long. The coil is tunable with motorized screw drive controllable from the inside of the truck (yes, while I am driving).



              enter image description here



              To achieve a good match at the feed point at the base of the antenna for the lower frequencies (80 and 40 meter bands) I use a shunt coil. I create the coil merely by experimentation and not design to achieve a good match (low SWR on impedance match). It us usually about 2 microHenries or less at operating frequencies. For the lower bands (20, 17, 15, 12, and 10) it looks like an open circuit rather than a shunt.



              enter image description here






              share|cite|improve this answer











              $endgroup$













              • $begingroup$
                That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
                $endgroup$
                – uhoh
                yesterday
















              5












              5








              5





              $begingroup$

              A slight deviation from the actual question -- focus on antennas. Antennas can be capacitive or reactive in how they respond to RF energy either by feeding the antenna used for transmitting or from electromagnetic waves in receiving.



              A purely resonant "ideal" antenna to a single frequency is neither capacitive nor inductive as one definition of resonance is when the antenna reactance (Imaginary) is zero. Thus pure resistance (Real) made up (hopefully) of mostly radiation resistance with smaller losses in thermal resistance.



              The mobile "screwdriver" antenna that I had on the back of my pickup truck for my mobile HF transceiver had a center-loaded coil (Inductance) to offset the usually capacitive antenna. Short antennas (shorter than resonant length for the frequency) are capacitive. Long antennas are inductive.



              However, to make the antenna efficient for lower frequencies it is useful to make use of capacitance on the top of the antenna. This results in increased current along the upper radiating portion of the antenna (above the center loaded coil). Increasing the capacitance is done by adding conductors to the top of the antenna, usually radiating out up to 12 inches or so. This is called a "capacity hat" for the antenna. In the case of my mobile screwdriver antenna, adding the capacity had would give me 20 to 30 dB increased received signal strength.



              I thought adding a few photos would help in this description. This first photo shows the antenna and the inductor is there in the center. You can't easily see the top section (above the coil) as it is a whip antenna about 3 1/2 feet long. The coil is tunable with motorized screw drive controllable from the inside of the truck (yes, while I am driving).



              enter image description here



              To achieve a good match at the feed point at the base of the antenna for the lower frequencies (80 and 40 meter bands) I use a shunt coil. I create the coil merely by experimentation and not design to achieve a good match (low SWR on impedance match). It us usually about 2 microHenries or less at operating frequencies. For the lower bands (20, 17, 15, 12, and 10) it looks like an open circuit rather than a shunt.



              enter image description here






              share|cite|improve this answer











              $endgroup$



              A slight deviation from the actual question -- focus on antennas. Antennas can be capacitive or reactive in how they respond to RF energy either by feeding the antenna used for transmitting or from electromagnetic waves in receiving.



              A purely resonant "ideal" antenna to a single frequency is neither capacitive nor inductive as one definition of resonance is when the antenna reactance (Imaginary) is zero. Thus pure resistance (Real) made up (hopefully) of mostly radiation resistance with smaller losses in thermal resistance.



              The mobile "screwdriver" antenna that I had on the back of my pickup truck for my mobile HF transceiver had a center-loaded coil (Inductance) to offset the usually capacitive antenna. Short antennas (shorter than resonant length for the frequency) are capacitive. Long antennas are inductive.



              However, to make the antenna efficient for lower frequencies it is useful to make use of capacitance on the top of the antenna. This results in increased current along the upper radiating portion of the antenna (above the center loaded coil). Increasing the capacitance is done by adding conductors to the top of the antenna, usually radiating out up to 12 inches or so. This is called a "capacity hat" for the antenna. In the case of my mobile screwdriver antenna, adding the capacity had would give me 20 to 30 dB increased received signal strength.



              I thought adding a few photos would help in this description. This first photo shows the antenna and the inductor is there in the center. You can't easily see the top section (above the coil) as it is a whip antenna about 3 1/2 feet long. The coil is tunable with motorized screw drive controllable from the inside of the truck (yes, while I am driving).



              enter image description here



              To achieve a good match at the feed point at the base of the antenna for the lower frequencies (80 and 40 meter bands) I use a shunt coil. I create the coil merely by experimentation and not design to achieve a good match (low SWR on impedance match). It us usually about 2 microHenries or less at operating frequencies. For the lower bands (20, 17, 15, 12, and 10) it looks like an open circuit rather than a shunt.



              enter image description here







              share|cite|improve this answer














              share|cite|improve this answer



              share|cite|improve this answer








              edited yesterday

























              answered yesterday









              K7PEHK7PEH

              1,025914




              1,025914












              • $begingroup$
                That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
                $endgroup$
                – uhoh
                yesterday




















              • $begingroup$
                That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
                $endgroup$
                – uhoh
                yesterday


















              $begingroup$
              That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
              $endgroup$
              – uhoh
              yesterday






              $begingroup$
              That's much nicer looking than i.stack.imgur.com/Dbjau.jpg (from here from here)
              $endgroup$
              – uhoh
              yesterday













              3












              $begingroup$

              It is more useful to talk about capacitance rather than capacitors, because capacitance is a tendency of the distribution of charge to affect current flow, while a capacitor is any device designed to have capacitance. All conductors have free charges, and thus any conductors that are in proximity to one-another will affect each other electrically. Their charges will 'feel' an electric force, and will therefore rearrange, and the way this happens is described by the phenomenon of capacitance. Particularly, this describes mutual capacitance, as opposed to self-capacitance, which is the tendency of a body to store charge.



              Capacitance as a concept relates a potential (or potential difference) of a body to the amount of charge stored on that body. In a vacuum, a body's capacitance depends only on its geometry and material properties. When another body is introduced nearby, they interact as described above, and therefore the capacitance of either body will change. In this case it makes the most sense to talk about conductors which are allowed to exchange charge (e.g. conductors connected to +V and ground) without being shorted together (separated electrically by a dielectric), and then we define their mutual capacitance as the ratio of charge to potential difference.



              So when these requirements are met (two electrically separate conductors which are part of the same circuit), there exists mutual capacitance, which is what people mean when they say "capacitance".



              Keep in mind, however, that modelling of circuit behavior with lumped elements is not appropriate when signals (voltage, current) change rapidly. If the wavelength of a sinusoidal signal is nearly of the scale of a component, or smaller, use a distributed model of components. As well, most circuit analysis neglects radiation loss, but when considering antennas you cannot. Treating radiation loss mathematically can make a couple of straight open circuit wires with incredibly small capacitance between them look like big capacitors with shunt inductances, but it's only the way radiation is modeled for circuit analysis. Radiation, in general, is a complicated phenomenon, and requires very detailed analysis. That doesn't mean you can't analyze an antenna though. Just know that if radiation is involved, circuit assumptions may need to be revised to understand the models.






              share|cite|improve this answer









              $endgroup$


















                3












                $begingroup$

                It is more useful to talk about capacitance rather than capacitors, because capacitance is a tendency of the distribution of charge to affect current flow, while a capacitor is any device designed to have capacitance. All conductors have free charges, and thus any conductors that are in proximity to one-another will affect each other electrically. Their charges will 'feel' an electric force, and will therefore rearrange, and the way this happens is described by the phenomenon of capacitance. Particularly, this describes mutual capacitance, as opposed to self-capacitance, which is the tendency of a body to store charge.



                Capacitance as a concept relates a potential (or potential difference) of a body to the amount of charge stored on that body. In a vacuum, a body's capacitance depends only on its geometry and material properties. When another body is introduced nearby, they interact as described above, and therefore the capacitance of either body will change. In this case it makes the most sense to talk about conductors which are allowed to exchange charge (e.g. conductors connected to +V and ground) without being shorted together (separated electrically by a dielectric), and then we define their mutual capacitance as the ratio of charge to potential difference.



                So when these requirements are met (two electrically separate conductors which are part of the same circuit), there exists mutual capacitance, which is what people mean when they say "capacitance".



                Keep in mind, however, that modelling of circuit behavior with lumped elements is not appropriate when signals (voltage, current) change rapidly. If the wavelength of a sinusoidal signal is nearly of the scale of a component, or smaller, use a distributed model of components. As well, most circuit analysis neglects radiation loss, but when considering antennas you cannot. Treating radiation loss mathematically can make a couple of straight open circuit wires with incredibly small capacitance between them look like big capacitors with shunt inductances, but it's only the way radiation is modeled for circuit analysis. Radiation, in general, is a complicated phenomenon, and requires very detailed analysis. That doesn't mean you can't analyze an antenna though. Just know that if radiation is involved, circuit assumptions may need to be revised to understand the models.






                share|cite|improve this answer









                $endgroup$
















                  3












                  3








                  3





                  $begingroup$

                  It is more useful to talk about capacitance rather than capacitors, because capacitance is a tendency of the distribution of charge to affect current flow, while a capacitor is any device designed to have capacitance. All conductors have free charges, and thus any conductors that are in proximity to one-another will affect each other electrically. Their charges will 'feel' an electric force, and will therefore rearrange, and the way this happens is described by the phenomenon of capacitance. Particularly, this describes mutual capacitance, as opposed to self-capacitance, which is the tendency of a body to store charge.



                  Capacitance as a concept relates a potential (or potential difference) of a body to the amount of charge stored on that body. In a vacuum, a body's capacitance depends only on its geometry and material properties. When another body is introduced nearby, they interact as described above, and therefore the capacitance of either body will change. In this case it makes the most sense to talk about conductors which are allowed to exchange charge (e.g. conductors connected to +V and ground) without being shorted together (separated electrically by a dielectric), and then we define their mutual capacitance as the ratio of charge to potential difference.



                  So when these requirements are met (two electrically separate conductors which are part of the same circuit), there exists mutual capacitance, which is what people mean when they say "capacitance".



                  Keep in mind, however, that modelling of circuit behavior with lumped elements is not appropriate when signals (voltage, current) change rapidly. If the wavelength of a sinusoidal signal is nearly of the scale of a component, or smaller, use a distributed model of components. As well, most circuit analysis neglects radiation loss, but when considering antennas you cannot. Treating radiation loss mathematically can make a couple of straight open circuit wires with incredibly small capacitance between them look like big capacitors with shunt inductances, but it's only the way radiation is modeled for circuit analysis. Radiation, in general, is a complicated phenomenon, and requires very detailed analysis. That doesn't mean you can't analyze an antenna though. Just know that if radiation is involved, circuit assumptions may need to be revised to understand the models.






                  share|cite|improve this answer









                  $endgroup$



                  It is more useful to talk about capacitance rather than capacitors, because capacitance is a tendency of the distribution of charge to affect current flow, while a capacitor is any device designed to have capacitance. All conductors have free charges, and thus any conductors that are in proximity to one-another will affect each other electrically. Their charges will 'feel' an electric force, and will therefore rearrange, and the way this happens is described by the phenomenon of capacitance. Particularly, this describes mutual capacitance, as opposed to self-capacitance, which is the tendency of a body to store charge.



                  Capacitance as a concept relates a potential (or potential difference) of a body to the amount of charge stored on that body. In a vacuum, a body's capacitance depends only on its geometry and material properties. When another body is introduced nearby, they interact as described above, and therefore the capacitance of either body will change. In this case it makes the most sense to talk about conductors which are allowed to exchange charge (e.g. conductors connected to +V and ground) without being shorted together (separated electrically by a dielectric), and then we define their mutual capacitance as the ratio of charge to potential difference.



                  So when these requirements are met (two electrically separate conductors which are part of the same circuit), there exists mutual capacitance, which is what people mean when they say "capacitance".



                  Keep in mind, however, that modelling of circuit behavior with lumped elements is not appropriate when signals (voltage, current) change rapidly. If the wavelength of a sinusoidal signal is nearly of the scale of a component, or smaller, use a distributed model of components. As well, most circuit analysis neglects radiation loss, but when considering antennas you cannot. Treating radiation loss mathematically can make a couple of straight open circuit wires with incredibly small capacitance between them look like big capacitors with shunt inductances, but it's only the way radiation is modeled for circuit analysis. Radiation, in general, is a complicated phenomenon, and requires very detailed analysis. That doesn't mean you can't analyze an antenna though. Just know that if radiation is involved, circuit assumptions may need to be revised to understand the models.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered yesterday









                  Sam GallagherSam Gallagher

                  353210




                  353210























                      2












                      $begingroup$

                      Technically, yes... Practically, no...



                      A capacitor is nothing more than an anode (wire on one side), a cathode (wire on the other side), and a dielectric in the middle (something reasonably non-conducting). So, yes, if you expose a length of wire in your house and cut it with wire cutters (please trip the breaker first...), what you'll have is a capacitor.



                      But it stinks.



                      Capacitance has a great deal to do with (a) the amount of conductive surface between the anode and cathode, (b) the nature of the dielectric between those conductors, and (c) the distance between the conductors.



                      (a) wants to be large. Many commercial capacitors use very long lengths of foil rolled up into a tube to get substantial surface area.



                      (b) wants to permit charge — but NOT permit an arc. Air will work as a dielectric (and is sometimes used), but it's not very good. I remodeled an old hospital once that had a barrel-sized capacitor (about 20 gallons in size) used with the ancient (circa 1980) X-ray machine. Two enormous lengths of foil wrapped a bazzillion times and submersed with a dielectric oil. For reasons I'll never understand, it was installed in the attic. I couldn't tip it to drain the oil. It's still there.



                      (c) wants to be small (there's a lot of math here). It's not uncommon for the distance between the plates (the foil strips) to be fractions of a millimeter.



                      So, yes, there's a minute and usually insignificant amount of capacitance in any open circuit. But it's not worth much.






                      share|cite|improve this answer









                      $endgroup$


















                        2












                        $begingroup$

                        Technically, yes... Practically, no...



                        A capacitor is nothing more than an anode (wire on one side), a cathode (wire on the other side), and a dielectric in the middle (something reasonably non-conducting). So, yes, if you expose a length of wire in your house and cut it with wire cutters (please trip the breaker first...), what you'll have is a capacitor.



                        But it stinks.



                        Capacitance has a great deal to do with (a) the amount of conductive surface between the anode and cathode, (b) the nature of the dielectric between those conductors, and (c) the distance between the conductors.



                        (a) wants to be large. Many commercial capacitors use very long lengths of foil rolled up into a tube to get substantial surface area.



                        (b) wants to permit charge — but NOT permit an arc. Air will work as a dielectric (and is sometimes used), but it's not very good. I remodeled an old hospital once that had a barrel-sized capacitor (about 20 gallons in size) used with the ancient (circa 1980) X-ray machine. Two enormous lengths of foil wrapped a bazzillion times and submersed with a dielectric oil. For reasons I'll never understand, it was installed in the attic. I couldn't tip it to drain the oil. It's still there.



                        (c) wants to be small (there's a lot of math here). It's not uncommon for the distance between the plates (the foil strips) to be fractions of a millimeter.



                        So, yes, there's a minute and usually insignificant amount of capacitance in any open circuit. But it's not worth much.






                        share|cite|improve this answer









                        $endgroup$
















                          2












                          2








                          2





                          $begingroup$

                          Technically, yes... Practically, no...



                          A capacitor is nothing more than an anode (wire on one side), a cathode (wire on the other side), and a dielectric in the middle (something reasonably non-conducting). So, yes, if you expose a length of wire in your house and cut it with wire cutters (please trip the breaker first...), what you'll have is a capacitor.



                          But it stinks.



                          Capacitance has a great deal to do with (a) the amount of conductive surface between the anode and cathode, (b) the nature of the dielectric between those conductors, and (c) the distance between the conductors.



                          (a) wants to be large. Many commercial capacitors use very long lengths of foil rolled up into a tube to get substantial surface area.



                          (b) wants to permit charge — but NOT permit an arc. Air will work as a dielectric (and is sometimes used), but it's not very good. I remodeled an old hospital once that had a barrel-sized capacitor (about 20 gallons in size) used with the ancient (circa 1980) X-ray machine. Two enormous lengths of foil wrapped a bazzillion times and submersed with a dielectric oil. For reasons I'll never understand, it was installed in the attic. I couldn't tip it to drain the oil. It's still there.



                          (c) wants to be small (there's a lot of math here). It's not uncommon for the distance between the plates (the foil strips) to be fractions of a millimeter.



                          So, yes, there's a minute and usually insignificant amount of capacitance in any open circuit. But it's not worth much.






                          share|cite|improve this answer









                          $endgroup$



                          Technically, yes... Practically, no...



                          A capacitor is nothing more than an anode (wire on one side), a cathode (wire on the other side), and a dielectric in the middle (something reasonably non-conducting). So, yes, if you expose a length of wire in your house and cut it with wire cutters (please trip the breaker first...), what you'll have is a capacitor.



                          But it stinks.



                          Capacitance has a great deal to do with (a) the amount of conductive surface between the anode and cathode, (b) the nature of the dielectric between those conductors, and (c) the distance between the conductors.



                          (a) wants to be large. Many commercial capacitors use very long lengths of foil rolled up into a tube to get substantial surface area.



                          (b) wants to permit charge — but NOT permit an arc. Air will work as a dielectric (and is sometimes used), but it's not very good. I remodeled an old hospital once that had a barrel-sized capacitor (about 20 gallons in size) used with the ancient (circa 1980) X-ray machine. Two enormous lengths of foil wrapped a bazzillion times and submersed with a dielectric oil. For reasons I'll never understand, it was installed in the attic. I couldn't tip it to drain the oil. It's still there.



                          (c) wants to be small (there's a lot of math here). It's not uncommon for the distance between the plates (the foil strips) to be fractions of a millimeter.



                          So, yes, there's a minute and usually insignificant amount of capacitance in any open circuit. But it's not worth much.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 21 hours ago









                          JBHJBH

                          1268




                          1268























                              1












                              $begingroup$

                              You are correct that between any two conductors separated by a dielectric (solid, liquid or gas) or even by a vacuum, there is capacitance. This capacitance exists, whether or not by design. The capacitance between conductors that is not by design is sometimes referred to as "stray capacitance" (unintended and unwanted capacitance). It is usually extremely small and does not have an effect on a circuit except for the possibility of adversely affecting circuits involving very high frequencies. This is because any unwanted capacitive currents are proportional to both the magnitude of the capacitance and the rate of change in voltage between the conductors, or



                              $$i(t)=Cfrac{dV(t)}{dt}$$



                              When stray capacitance has an unwanted effect on a circuit, it is sometimes referred to as “parasitic” capacitance.



                              I believe others have adequately covered the topic of antennas and capacitance.



                              Hope this, together with the other good answers, helps.






                              share|cite|improve this answer









                              $endgroup$


















                                1












                                $begingroup$

                                You are correct that between any two conductors separated by a dielectric (solid, liquid or gas) or even by a vacuum, there is capacitance. This capacitance exists, whether or not by design. The capacitance between conductors that is not by design is sometimes referred to as "stray capacitance" (unintended and unwanted capacitance). It is usually extremely small and does not have an effect on a circuit except for the possibility of adversely affecting circuits involving very high frequencies. This is because any unwanted capacitive currents are proportional to both the magnitude of the capacitance and the rate of change in voltage between the conductors, or



                                $$i(t)=Cfrac{dV(t)}{dt}$$



                                When stray capacitance has an unwanted effect on a circuit, it is sometimes referred to as “parasitic” capacitance.



                                I believe others have adequately covered the topic of antennas and capacitance.



                                Hope this, together with the other good answers, helps.






                                share|cite|improve this answer









                                $endgroup$
















                                  1












                                  1








                                  1





                                  $begingroup$

                                  You are correct that between any two conductors separated by a dielectric (solid, liquid or gas) or even by a vacuum, there is capacitance. This capacitance exists, whether or not by design. The capacitance between conductors that is not by design is sometimes referred to as "stray capacitance" (unintended and unwanted capacitance). It is usually extremely small and does not have an effect on a circuit except for the possibility of adversely affecting circuits involving very high frequencies. This is because any unwanted capacitive currents are proportional to both the magnitude of the capacitance and the rate of change in voltage between the conductors, or



                                  $$i(t)=Cfrac{dV(t)}{dt}$$



                                  When stray capacitance has an unwanted effect on a circuit, it is sometimes referred to as “parasitic” capacitance.



                                  I believe others have adequately covered the topic of antennas and capacitance.



                                  Hope this, together with the other good answers, helps.






                                  share|cite|improve this answer









                                  $endgroup$



                                  You are correct that between any two conductors separated by a dielectric (solid, liquid or gas) or even by a vacuum, there is capacitance. This capacitance exists, whether or not by design. The capacitance between conductors that is not by design is sometimes referred to as "stray capacitance" (unintended and unwanted capacitance). It is usually extremely small and does not have an effect on a circuit except for the possibility of adversely affecting circuits involving very high frequencies. This is because any unwanted capacitive currents are proportional to both the magnitude of the capacitance and the rate of change in voltage between the conductors, or



                                  $$i(t)=Cfrac{dV(t)}{dt}$$



                                  When stray capacitance has an unwanted effect on a circuit, it is sometimes referred to as “parasitic” capacitance.



                                  I believe others have adequately covered the topic of antennas and capacitance.



                                  Hope this, together with the other good answers, helps.







                                  share|cite|improve this answer












                                  share|cite|improve this answer



                                  share|cite|improve this answer










                                  answered yesterday









                                  Bob DBob D

                                  3,6582316




                                  3,6582316























                                      1












                                      $begingroup$

                                      Every object in a circuit has resistance, capacitance, and inductance, but these quantities are often small enough that they can be treated as being zero. When these quantities are large enough that they need to be considered, they are often separated out in circuit diagrams as "separate" objects to make the analysis easier. For instance, a battery might be represented in a circuit diagram with a symbol for DC voltage source and a symbol for a resistor, as if the voltage and resistance of the battery were being produced by separate objects. In reality, of course, a battery exhibits resistance distributed throughout its length, but for most purposes this resistance can be treated as being concentrated in one location.



                                      Similarly, while an ideal wire has no capacitance, in reality actual wires will have some. So will batteries, resistors, etc. If we need to consider the effect of these capacitances on the circuit, we will usually put one capacitor symbol in the circuit diagram to represent the total effective capacitance of all of them together (although in more complicated circuits we may need to represent the effect of their capacitances with multiple symbols). In a circuit with actual capacitors, the capacitances of other parts of the circuits are generally so low in comparison that they can be ignored.






                                      share|cite|improve this answer









                                      $endgroup$


















                                        1












                                        $begingroup$

                                        Every object in a circuit has resistance, capacitance, and inductance, but these quantities are often small enough that they can be treated as being zero. When these quantities are large enough that they need to be considered, they are often separated out in circuit diagrams as "separate" objects to make the analysis easier. For instance, a battery might be represented in a circuit diagram with a symbol for DC voltage source and a symbol for a resistor, as if the voltage and resistance of the battery were being produced by separate objects. In reality, of course, a battery exhibits resistance distributed throughout its length, but for most purposes this resistance can be treated as being concentrated in one location.



                                        Similarly, while an ideal wire has no capacitance, in reality actual wires will have some. So will batteries, resistors, etc. If we need to consider the effect of these capacitances on the circuit, we will usually put one capacitor symbol in the circuit diagram to represent the total effective capacitance of all of them together (although in more complicated circuits we may need to represent the effect of their capacitances with multiple symbols). In a circuit with actual capacitors, the capacitances of other parts of the circuits are generally so low in comparison that they can be ignored.






                                        share|cite|improve this answer









                                        $endgroup$
















                                          1












                                          1








                                          1





                                          $begingroup$

                                          Every object in a circuit has resistance, capacitance, and inductance, but these quantities are often small enough that they can be treated as being zero. When these quantities are large enough that they need to be considered, they are often separated out in circuit diagrams as "separate" objects to make the analysis easier. For instance, a battery might be represented in a circuit diagram with a symbol for DC voltage source and a symbol for a resistor, as if the voltage and resistance of the battery were being produced by separate objects. In reality, of course, a battery exhibits resistance distributed throughout its length, but for most purposes this resistance can be treated as being concentrated in one location.



                                          Similarly, while an ideal wire has no capacitance, in reality actual wires will have some. So will batteries, resistors, etc. If we need to consider the effect of these capacitances on the circuit, we will usually put one capacitor symbol in the circuit diagram to represent the total effective capacitance of all of them together (although in more complicated circuits we may need to represent the effect of their capacitances with multiple symbols). In a circuit with actual capacitors, the capacitances of other parts of the circuits are generally so low in comparison that they can be ignored.






                                          share|cite|improve this answer









                                          $endgroup$



                                          Every object in a circuit has resistance, capacitance, and inductance, but these quantities are often small enough that they can be treated as being zero. When these quantities are large enough that they need to be considered, they are often separated out in circuit diagrams as "separate" objects to make the analysis easier. For instance, a battery might be represented in a circuit diagram with a symbol for DC voltage source and a symbol for a resistor, as if the voltage and resistance of the battery were being produced by separate objects. In reality, of course, a battery exhibits resistance distributed throughout its length, but for most purposes this resistance can be treated as being concentrated in one location.



                                          Similarly, while an ideal wire has no capacitance, in reality actual wires will have some. So will batteries, resistors, etc. If we need to consider the effect of these capacitances on the circuit, we will usually put one capacitor symbol in the circuit diagram to represent the total effective capacitance of all of them together (although in more complicated circuits we may need to represent the effect of their capacitances with multiple symbols). In a circuit with actual capacitors, the capacitances of other parts of the circuits are generally so low in comparison that they can be ignored.







                                          share|cite|improve this answer












                                          share|cite|improve this answer



                                          share|cite|improve this answer










                                          answered yesterday









                                          AcccumulationAcccumulation

                                          2,666312




                                          2,666312























                                              1












                                              $begingroup$

                                              If one were somehow able to try to draw current from any point while feeding current to any other point without involving anything else in the universe, the points would behave as though there was some capacitance between them. A network of three points, however, may behave as though there is capacitance between the first and second, and between the second and third, without behaving as though there is any meaningful capacitance between the first and third. This subject came up in a recent youtube video https://youtu.be/uGXQc-zanWg on the Mr. Carlson's Lab channel.



                                              As explained by that video, if a half-wave rectified signal is fed into a 50uF cap to ground, and from there passes through a 10K resistor and into another 50uF cap to ground, the second cap could easily have orders of magnitude less ripple than the first. Although it would appear that there is a 25uF connection (two 50uF caps in series) between the two sides of the 10K resistor, the ground connection between the two caps may prevent unwanted coupling of any ground-referenced signal through that capacitance. If the two caps were disconnected from ground but remained connected to each other, however, then that 25uF capacitance would come into play. If that happened but one tried to fix the circuit by adding 50uF caps in parallel with the locations where the originals should have been, that 25uF capacitance would cause the second cap to have about 1/3 as much ripple as the first.






                                              share|cite|improve this answer









                                              $endgroup$


















                                                1












                                                $begingroup$

                                                If one were somehow able to try to draw current from any point while feeding current to any other point without involving anything else in the universe, the points would behave as though there was some capacitance between them. A network of three points, however, may behave as though there is capacitance between the first and second, and between the second and third, without behaving as though there is any meaningful capacitance between the first and third. This subject came up in a recent youtube video https://youtu.be/uGXQc-zanWg on the Mr. Carlson's Lab channel.



                                                As explained by that video, if a half-wave rectified signal is fed into a 50uF cap to ground, and from there passes through a 10K resistor and into another 50uF cap to ground, the second cap could easily have orders of magnitude less ripple than the first. Although it would appear that there is a 25uF connection (two 50uF caps in series) between the two sides of the 10K resistor, the ground connection between the two caps may prevent unwanted coupling of any ground-referenced signal through that capacitance. If the two caps were disconnected from ground but remained connected to each other, however, then that 25uF capacitance would come into play. If that happened but one tried to fix the circuit by adding 50uF caps in parallel with the locations where the originals should have been, that 25uF capacitance would cause the second cap to have about 1/3 as much ripple as the first.






                                                share|cite|improve this answer









                                                $endgroup$
















                                                  1












                                                  1








                                                  1





                                                  $begingroup$

                                                  If one were somehow able to try to draw current from any point while feeding current to any other point without involving anything else in the universe, the points would behave as though there was some capacitance between them. A network of three points, however, may behave as though there is capacitance between the first and second, and between the second and third, without behaving as though there is any meaningful capacitance between the first and third. This subject came up in a recent youtube video https://youtu.be/uGXQc-zanWg on the Mr. Carlson's Lab channel.



                                                  As explained by that video, if a half-wave rectified signal is fed into a 50uF cap to ground, and from there passes through a 10K resistor and into another 50uF cap to ground, the second cap could easily have orders of magnitude less ripple than the first. Although it would appear that there is a 25uF connection (two 50uF caps in series) between the two sides of the 10K resistor, the ground connection between the two caps may prevent unwanted coupling of any ground-referenced signal through that capacitance. If the two caps were disconnected from ground but remained connected to each other, however, then that 25uF capacitance would come into play. If that happened but one tried to fix the circuit by adding 50uF caps in parallel with the locations where the originals should have been, that 25uF capacitance would cause the second cap to have about 1/3 as much ripple as the first.






                                                  share|cite|improve this answer









                                                  $endgroup$



                                                  If one were somehow able to try to draw current from any point while feeding current to any other point without involving anything else in the universe, the points would behave as though there was some capacitance between them. A network of three points, however, may behave as though there is capacitance between the first and second, and between the second and third, without behaving as though there is any meaningful capacitance between the first and third. This subject came up in a recent youtube video https://youtu.be/uGXQc-zanWg on the Mr. Carlson's Lab channel.



                                                  As explained by that video, if a half-wave rectified signal is fed into a 50uF cap to ground, and from there passes through a 10K resistor and into another 50uF cap to ground, the second cap could easily have orders of magnitude less ripple than the first. Although it would appear that there is a 25uF connection (two 50uF caps in series) between the two sides of the 10K resistor, the ground connection between the two caps may prevent unwanted coupling of any ground-referenced signal through that capacitance. If the two caps were disconnected from ground but remained connected to each other, however, then that 25uF capacitance would come into play. If that happened but one tried to fix the circuit by adding 50uF caps in parallel with the locations where the originals should have been, that 25uF capacitance would cause the second cap to have about 1/3 as much ripple as the first.







                                                  share|cite|improve this answer












                                                  share|cite|improve this answer



                                                  share|cite|improve this answer










                                                  answered yesterday









                                                  supercatsupercat

                                                  55438




                                                  55438























                                                      0












                                                      $begingroup$

                                                      Yes. If two non-insulators (in the Universe) are connected to any emf source, current will flow between them regardless of the source frequency (eg. 60Hz or 60GHz). At DC, the leakage current flow depends on the circuit conductance. At AC, the leakage current flow depends on the circuit admittance. Of course, the current may be insignificant (especially if one non-insulator is on Mars and the other is on Earth) and/or irrelevant.



                                                      An antenna is designed to radiate with an AC emf. It depends how it is connected, as to whether it acts as a capacitance or inductance at some frequency, if it is not resonating at its fundamental or a harmonic frequency.






                                                      share|cite|improve this answer








                                                      New contributor




                                                      J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                      Check out our Code of Conduct.






                                                      $endgroup$


















                                                        0












                                                        $begingroup$

                                                        Yes. If two non-insulators (in the Universe) are connected to any emf source, current will flow between them regardless of the source frequency (eg. 60Hz or 60GHz). At DC, the leakage current flow depends on the circuit conductance. At AC, the leakage current flow depends on the circuit admittance. Of course, the current may be insignificant (especially if one non-insulator is on Mars and the other is on Earth) and/or irrelevant.



                                                        An antenna is designed to radiate with an AC emf. It depends how it is connected, as to whether it acts as a capacitance or inductance at some frequency, if it is not resonating at its fundamental or a harmonic frequency.






                                                        share|cite|improve this answer








                                                        New contributor




                                                        J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                        Check out our Code of Conduct.






                                                        $endgroup$
















                                                          0












                                                          0








                                                          0





                                                          $begingroup$

                                                          Yes. If two non-insulators (in the Universe) are connected to any emf source, current will flow between them regardless of the source frequency (eg. 60Hz or 60GHz). At DC, the leakage current flow depends on the circuit conductance. At AC, the leakage current flow depends on the circuit admittance. Of course, the current may be insignificant (especially if one non-insulator is on Mars and the other is on Earth) and/or irrelevant.



                                                          An antenna is designed to radiate with an AC emf. It depends how it is connected, as to whether it acts as a capacitance or inductance at some frequency, if it is not resonating at its fundamental or a harmonic frequency.






                                                          share|cite|improve this answer








                                                          New contributor




                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.






                                                          $endgroup$



                                                          Yes. If two non-insulators (in the Universe) are connected to any emf source, current will flow between them regardless of the source frequency (eg. 60Hz or 60GHz). At DC, the leakage current flow depends on the circuit conductance. At AC, the leakage current flow depends on the circuit admittance. Of course, the current may be insignificant (especially if one non-insulator is on Mars and the other is on Earth) and/or irrelevant.



                                                          An antenna is designed to radiate with an AC emf. It depends how it is connected, as to whether it acts as a capacitance or inductance at some frequency, if it is not resonating at its fundamental or a harmonic frequency.







                                                          share|cite|improve this answer








                                                          New contributor




                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.









                                                          share|cite|improve this answer



                                                          share|cite|improve this answer






                                                          New contributor




                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.









                                                          answered 11 hours ago









                                                          J. PhillipsJ. Phillips

                                                          1




                                                          1




                                                          New contributor




                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.





                                                          New contributor





                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.






                                                          J. Phillips is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.






























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