An optimized set of tikz code?
I have a question, how can have the shortest set of tikz code for this pecture 
i am tring to optimize this code:
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
La version de TikZ est : pgfversion
vfill
begin{center}
begin{tikzpicture}
%
draw (0,1) -- (1,0);
draw (1,0) -- (0,-1);
draw (0,-1) -- (-1,0);
draw (-1,0) -- (0,1);
draw (0,0) circle (1);
draw ((0,1) circle (1);
draw (0,-1) circle (1);
draw (-1,0) circle (1);
draw (1,0) circle (1);
%
draw (0,2) -- (2,0);
draw (2,0) -- (0,-2);
draw (0,-2) -- (-2,0);
draw (-2,0) -- (0,2);
draw (0,0) circle (2);
draw ((0,2) circle (2);
draw (0,-2) circle (2);
draw (-2,0) circle (2);
draw (2,0) circle (2);
end{tikzpicture}
end{center}
end{document}
tikz-pgf
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mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
I have a question, how can have the shortest set of tikz code for this pecture 
i am tring to optimize this code:
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
La version de TikZ est : pgfversion
vfill
begin{center}
begin{tikzpicture}
%
draw (0,1) -- (1,0);
draw (1,0) -- (0,-1);
draw (0,-1) -- (-1,0);
draw (-1,0) -- (0,1);
draw (0,0) circle (1);
draw ((0,1) circle (1);
draw (0,-1) circle (1);
draw (-1,0) circle (1);
draw (1,0) circle (1);
%
draw (0,2) -- (2,0);
draw (2,0) -- (0,-2);
draw (0,-2) -- (-2,0);
draw (-2,0) -- (0,2);
draw (0,0) circle (2);
draw ((0,2) circle (2);
draw (0,-2) circle (2);
draw (-2,0) circle (2);
draw (2,0) circle (2);
end{tikzpicture}
end{center}
end{document}
tikz-pgf
New contributor
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
+1 for the MWE!!
– Raaja
3 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago
add a comment |
I have a question, how can have the shortest set of tikz code for this pecture 
i am tring to optimize this code:
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
La version de TikZ est : pgfversion
vfill
begin{center}
begin{tikzpicture}
%
draw (0,1) -- (1,0);
draw (1,0) -- (0,-1);
draw (0,-1) -- (-1,0);
draw (-1,0) -- (0,1);
draw (0,0) circle (1);
draw ((0,1) circle (1);
draw (0,-1) circle (1);
draw (-1,0) circle (1);
draw (1,0) circle (1);
%
draw (0,2) -- (2,0);
draw (2,0) -- (0,-2);
draw (0,-2) -- (-2,0);
draw (-2,0) -- (0,2);
draw (0,0) circle (2);
draw ((0,2) circle (2);
draw (0,-2) circle (2);
draw (-2,0) circle (2);
draw (2,0) circle (2);
end{tikzpicture}
end{center}
end{document}
tikz-pgf
New contributor
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a question, how can have the shortest set of tikz code for this pecture 
i am tring to optimize this code:
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
begin{document}
La version de TikZ est : pgfversion
vfill
begin{center}
begin{tikzpicture}
%
draw (0,1) -- (1,0);
draw (1,0) -- (0,-1);
draw (0,-1) -- (-1,0);
draw (-1,0) -- (0,1);
draw (0,0) circle (1);
draw ((0,1) circle (1);
draw (0,-1) circle (1);
draw (-1,0) circle (1);
draw (1,0) circle (1);
%
draw (0,2) -- (2,0);
draw (2,0) -- (0,-2);
draw (0,-2) -- (-2,0);
draw (-2,0) -- (0,2);
draw (0,0) circle (2);
draw ((0,2) circle (2);
draw (0,-2) circle (2);
draw (-2,0) circle (2);
draw (2,0) circle (2);
end{tikzpicture}
end{center}
end{document}
tikz-pgf
tikz-pgf
New contributor
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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edited 17 mins ago
AndréC
8,85911447
8,85911447
New contributor
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asked 4 hours ago
mou-nadalmou-nadal
334
334
New contributor
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
mou-nadal is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
+1 for the MWE!!
– Raaja
3 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago
add a comment |
+1 for the MWE!!
– Raaja
3 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago
+1 for the MWE!!
– Raaja
3 hours ago
+1 for the MWE!!
– Raaja
3 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago
add a comment |
4 Answers
4
active
oldest
votes
Here is a solution (not the shortest):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw
circle (1) circle(2)
(0:1) --(90:1) -- (180:1) -- (270:1) -- cycle
(0:1) circle(1) (90:1) circle(1) (180:1) circle(1) (270:1) circle(1)
(0:2) --(90:2) -- (180:2) -- (270:2) -- cycle
(0:2) circle(2) (90:2) circle(2) (180:2) circle(2) (270:2) circle(2);
end{tikzpicture}
end{document}
add a comment |
Just for fun:
documentclass[tikz,margin=5mm]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) circle (1) circle (2);
foreach t/n in {0/1,90/2,180/3,270/4}{
draw (t:1)coordinate(n) circle (1) ;}
foreach t/m in {0/5,90/6,180/7,270/8}{
draw (t:2)coordinate(m) circle (2) ;}
draw (1)--(2)--(3)--(4)--cycle;
draw (5)--(6)--(7)--(8)--cycle;
end{tikzpicture}
end{document}
add a comment |
One path for everything. ;-)
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[rotate=45] foreach Y in {1,2}
{(0,0) circle[radius=Y]
({-Y/sqrt(2)},{-Y/sqrt(2)}) rectangle ({Y/sqrt(2)},{Y/sqrt(2)})
foreach X in {45,135,225,315}
{ (X:Y) circle[radius=Y]}};
end{tikzpicture}
end{document}

add a comment |
Not as much as @marmot's nicely optimised answer but a try (gives more knobs for fun though):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}[mystyle/.style={circle,draw,fill=none,minimum size=20, line width = 0.1pt}]
foreach x/y/z in {0/0/2,0/1/2,0/-1/2,-1/0/2,1/0/2,0/0/4,0/1/4,0/-1/4,-1/0/4,1/0/4}
node [mystyle, minimum size = z cm, color =black] (2) at (x, y) {};
foreach x/y in {-0.7/0.7, -1.41/1.41}
draw[rotate=45, line width = 0.1pt] (x , x ) rectangle (y, y);
end{tikzpicture}
end{document}
which gives

add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here is a solution (not the shortest):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw
circle (1) circle(2)
(0:1) --(90:1) -- (180:1) -- (270:1) -- cycle
(0:1) circle(1) (90:1) circle(1) (180:1) circle(1) (270:1) circle(1)
(0:2) --(90:2) -- (180:2) -- (270:2) -- cycle
(0:2) circle(2) (90:2) circle(2) (180:2) circle(2) (270:2) circle(2);
end{tikzpicture}
end{document}
add a comment |
Here is a solution (not the shortest):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw
circle (1) circle(2)
(0:1) --(90:1) -- (180:1) -- (270:1) -- cycle
(0:1) circle(1) (90:1) circle(1) (180:1) circle(1) (270:1) circle(1)
(0:2) --(90:2) -- (180:2) -- (270:2) -- cycle
(0:2) circle(2) (90:2) circle(2) (180:2) circle(2) (270:2) circle(2);
end{tikzpicture}
end{document}
add a comment |
Here is a solution (not the shortest):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw
circle (1) circle(2)
(0:1) --(90:1) -- (180:1) -- (270:1) -- cycle
(0:1) circle(1) (90:1) circle(1) (180:1) circle(1) (270:1) circle(1)
(0:2) --(90:2) -- (180:2) -- (270:2) -- cycle
(0:2) circle(2) (90:2) circle(2) (180:2) circle(2) (270:2) circle(2);
end{tikzpicture}
end{document}
Here is a solution (not the shortest):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw
circle (1) circle(2)
(0:1) --(90:1) -- (180:1) -- (270:1) -- cycle
(0:1) circle(1) (90:1) circle(1) (180:1) circle(1) (270:1) circle(1)
(0:2) --(90:2) -- (180:2) -- (270:2) -- cycle
(0:2) circle(2) (90:2) circle(2) (180:2) circle(2) (270:2) circle(2);
end{tikzpicture}
end{document}
answered 3 hours ago
Paul GaboritPaul Gaborit
55.2k7140226
55.2k7140226
add a comment |
add a comment |
Just for fun:
documentclass[tikz,margin=5mm]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) circle (1) circle (2);
foreach t/n in {0/1,90/2,180/3,270/4}{
draw (t:1)coordinate(n) circle (1) ;}
foreach t/m in {0/5,90/6,180/7,270/8}{
draw (t:2)coordinate(m) circle (2) ;}
draw (1)--(2)--(3)--(4)--cycle;
draw (5)--(6)--(7)--(8)--cycle;
end{tikzpicture}
end{document}
add a comment |
Just for fun:
documentclass[tikz,margin=5mm]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) circle (1) circle (2);
foreach t/n in {0/1,90/2,180/3,270/4}{
draw (t:1)coordinate(n) circle (1) ;}
foreach t/m in {0/5,90/6,180/7,270/8}{
draw (t:2)coordinate(m) circle (2) ;}
draw (1)--(2)--(3)--(4)--cycle;
draw (5)--(6)--(7)--(8)--cycle;
end{tikzpicture}
end{document}
add a comment |
Just for fun:
documentclass[tikz,margin=5mm]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) circle (1) circle (2);
foreach t/n in {0/1,90/2,180/3,270/4}{
draw (t:1)coordinate(n) circle (1) ;}
foreach t/m in {0/5,90/6,180/7,270/8}{
draw (t:2)coordinate(m) circle (2) ;}
draw (1)--(2)--(3)--(4)--cycle;
draw (5)--(6)--(7)--(8)--cycle;
end{tikzpicture}
end{document}
Just for fun:
documentclass[tikz,margin=5mm]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) circle (1) circle (2);
foreach t/n in {0/1,90/2,180/3,270/4}{
draw (t:1)coordinate(n) circle (1) ;}
foreach t/m in {0/5,90/6,180/7,270/8}{
draw (t:2)coordinate(m) circle (2) ;}
draw (1)--(2)--(3)--(4)--cycle;
draw (5)--(6)--(7)--(8)--cycle;
end{tikzpicture}
end{document}
edited 2 hours ago
answered 3 hours ago
ferahfezaferahfeza
5,76911931
5,76911931
add a comment |
add a comment |
One path for everything. ;-)
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[rotate=45] foreach Y in {1,2}
{(0,0) circle[radius=Y]
({-Y/sqrt(2)},{-Y/sqrt(2)}) rectangle ({Y/sqrt(2)},{Y/sqrt(2)})
foreach X in {45,135,225,315}
{ (X:Y) circle[radius=Y]}};
end{tikzpicture}
end{document}

add a comment |
One path for everything. ;-)
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[rotate=45] foreach Y in {1,2}
{(0,0) circle[radius=Y]
({-Y/sqrt(2)},{-Y/sqrt(2)}) rectangle ({Y/sqrt(2)},{Y/sqrt(2)})
foreach X in {45,135,225,315}
{ (X:Y) circle[radius=Y]}};
end{tikzpicture}
end{document}

add a comment |
One path for everything. ;-)
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[rotate=45] foreach Y in {1,2}
{(0,0) circle[radius=Y]
({-Y/sqrt(2)},{-Y/sqrt(2)}) rectangle ({Y/sqrt(2)},{Y/sqrt(2)})
foreach X in {45,135,225,315}
{ (X:Y) circle[radius=Y]}};
end{tikzpicture}
end{document}

One path for everything. ;-)
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[rotate=45] foreach Y in {1,2}
{(0,0) circle[radius=Y]
({-Y/sqrt(2)},{-Y/sqrt(2)}) rectangle ({Y/sqrt(2)},{Y/sqrt(2)})
foreach X in {45,135,225,315}
{ (X:Y) circle[radius=Y]}};
end{tikzpicture}
end{document}

answered 2 hours ago
marmotmarmot
98.3k4113218
98.3k4113218
add a comment |
add a comment |
Not as much as @marmot's nicely optimised answer but a try (gives more knobs for fun though):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}[mystyle/.style={circle,draw,fill=none,minimum size=20, line width = 0.1pt}]
foreach x/y/z in {0/0/2,0/1/2,0/-1/2,-1/0/2,1/0/2,0/0/4,0/1/4,0/-1/4,-1/0/4,1/0/4}
node [mystyle, minimum size = z cm, color =black] (2) at (x, y) {};
foreach x/y in {-0.7/0.7, -1.41/1.41}
draw[rotate=45, line width = 0.1pt] (x , x ) rectangle (y, y);
end{tikzpicture}
end{document}
which gives

add a comment |
Not as much as @marmot's nicely optimised answer but a try (gives more knobs for fun though):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}[mystyle/.style={circle,draw,fill=none,minimum size=20, line width = 0.1pt}]
foreach x/y/z in {0/0/2,0/1/2,0/-1/2,-1/0/2,1/0/2,0/0/4,0/1/4,0/-1/4,-1/0/4,1/0/4}
node [mystyle, minimum size = z cm, color =black] (2) at (x, y) {};
foreach x/y in {-0.7/0.7, -1.41/1.41}
draw[rotate=45, line width = 0.1pt] (x , x ) rectangle (y, y);
end{tikzpicture}
end{document}
which gives

add a comment |
Not as much as @marmot's nicely optimised answer but a try (gives more knobs for fun though):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}[mystyle/.style={circle,draw,fill=none,minimum size=20, line width = 0.1pt}]
foreach x/y/z in {0/0/2,0/1/2,0/-1/2,-1/0/2,1/0/2,0/0/4,0/1/4,0/-1/4,-1/0/4,1/0/4}
node [mystyle, minimum size = z cm, color =black] (2) at (x, y) {};
foreach x/y in {-0.7/0.7, -1.41/1.41}
draw[rotate=45, line width = 0.1pt] (x , x ) rectangle (y, y);
end{tikzpicture}
end{document}
which gives

Not as much as @marmot's nicely optimised answer but a try (gives more knobs for fun though):
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}[mystyle/.style={circle,draw,fill=none,minimum size=20, line width = 0.1pt}]
foreach x/y/z in {0/0/2,0/1/2,0/-1/2,-1/0/2,1/0/2,0/0/4,0/1/4,0/-1/4,-1/0/4,1/0/4}
node [mystyle, minimum size = z cm, color =black] (2) at (x, y) {};
foreach x/y in {-0.7/0.7, -1.41/1.41}
draw[rotate=45, line width = 0.1pt] (x , x ) rectangle (y, y);
end{tikzpicture}
end{document}
which gives

answered 2 hours ago
RaajaRaaja
3,60521037
3,60521037
add a comment |
add a comment |
mou-nadal is a new contributor. Be nice, and check out our Code of Conduct.
mou-nadal is a new contributor. Be nice, and check out our Code of Conduct.
mou-nadal is a new contributor. Be nice, and check out our Code of Conduct.
mou-nadal is a new contributor. Be nice, and check out our Code of Conduct.
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+1 for the MWE!!
– Raaja
3 hours ago
Do you mean who has the shortest execution time in processor time? Who requires the least memory?
– AndréC
2 hours ago
Some think with a loop will be a great approach, but if we consider CPU and memory we must be more careful.
– mou-nadal
2 hours ago