♦ Series - Getting a free donut












12












$begingroup$


Introduction



There is a way to get a free donut at a coffee shop near the Stack Exchange offices.



However, you are required to solve a phrase and convert it into a single number.





Codes



You watch as a cashier says:




Do not use the toilets here. We're washing them.




And then the person replies:




$38$.




They get a free donut.



Next, another person walks in and you listen again. The cashier says:




Donuts by the dozen are $3.




The person replies:




$20$.




Once again, the cashier gives the person a free donut.





You go back the following day and watch as more people get their own free donuts.



The cashier says:




Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.




The person replies:




$20$.




Once again, they get a free donut.



The cashier says to another customer:




Your donuts aren't considered free yet.




The customer replies:




$50$.




This is also correct, and the cashier gives them free donuts.





You go up to the counter and the cashier says:




No donuts right now. We're making some more.




You come up with a random number:




Hmm... $44$?




She replies:




Sorry, but I do not know what you are talking about.




(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)





You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)





Hints




  • Hint 1:



Donut ignore the pun in this hint.





  • Hint 2:



Do you nut see a tasty treat hidden in this?





  • Hint 3:



Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."





  • Hint 4:



$6+2+7+2+8+2+9+2+10+2 = 50$.











share|improve this question











$endgroup$








  • 1




    $begingroup$
    It's re-misspelled in the latest edit. Accidental?
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 1:58






  • 1




    $begingroup$
    It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 2:01






  • 6




    $begingroup$
    Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
    $endgroup$
    – user1717828
    Jul 4 '16 at 12:40






  • 1




    $begingroup$
    If you're really that hungry, why not just pay for the donut? :P
    $endgroup$
    – Ian MacDonald
    Jul 4 '16 at 13:25






  • 2




    $begingroup$
    @Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
    $endgroup$
    – M Oehm
    Jul 5 '16 at 5:19
















12












$begingroup$


Introduction



There is a way to get a free donut at a coffee shop near the Stack Exchange offices.



However, you are required to solve a phrase and convert it into a single number.





Codes



You watch as a cashier says:




Do not use the toilets here. We're washing them.




And then the person replies:




$38$.




They get a free donut.



Next, another person walks in and you listen again. The cashier says:




Donuts by the dozen are $3.




The person replies:




$20$.




Once again, the cashier gives the person a free donut.





You go back the following day and watch as more people get their own free donuts.



The cashier says:




Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.




The person replies:




$20$.




Once again, they get a free donut.



The cashier says to another customer:




Your donuts aren't considered free yet.




The customer replies:




$50$.




This is also correct, and the cashier gives them free donuts.





You go up to the counter and the cashier says:




No donuts right now. We're making some more.




You come up with a random number:




Hmm... $44$?




She replies:




Sorry, but I do not know what you are talking about.




(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)





You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)





Hints




  • Hint 1:



Donut ignore the pun in this hint.





  • Hint 2:



Do you nut see a tasty treat hidden in this?





  • Hint 3:



Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."





  • Hint 4:



$6+2+7+2+8+2+9+2+10+2 = 50$.











share|improve this question











$endgroup$








  • 1




    $begingroup$
    It's re-misspelled in the latest edit. Accidental?
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 1:58






  • 1




    $begingroup$
    It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 2:01






  • 6




    $begingroup$
    Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
    $endgroup$
    – user1717828
    Jul 4 '16 at 12:40






  • 1




    $begingroup$
    If you're really that hungry, why not just pay for the donut? :P
    $endgroup$
    – Ian MacDonald
    Jul 4 '16 at 13:25






  • 2




    $begingroup$
    @Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
    $endgroup$
    – M Oehm
    Jul 5 '16 at 5:19














12












12








12


3



$begingroup$


Introduction



There is a way to get a free donut at a coffee shop near the Stack Exchange offices.



However, you are required to solve a phrase and convert it into a single number.





Codes



You watch as a cashier says:




Do not use the toilets here. We're washing them.




And then the person replies:




$38$.




They get a free donut.



Next, another person walks in and you listen again. The cashier says:




Donuts by the dozen are $3.




The person replies:




$20$.




Once again, the cashier gives the person a free donut.





You go back the following day and watch as more people get their own free donuts.



The cashier says:




Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.




The person replies:




$20$.




Once again, they get a free donut.



The cashier says to another customer:




Your donuts aren't considered free yet.




The customer replies:




$50$.




This is also correct, and the cashier gives them free donuts.





You go up to the counter and the cashier says:




No donuts right now. We're making some more.




You come up with a random number:




Hmm... $44$?




She replies:




Sorry, but I do not know what you are talking about.




(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)





You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)





Hints




  • Hint 1:



Donut ignore the pun in this hint.





  • Hint 2:



Do you nut see a tasty treat hidden in this?





  • Hint 3:



Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."





  • Hint 4:



$6+2+7+2+8+2+9+2+10+2 = 50$.











share|improve this question











$endgroup$




Introduction



There is a way to get a free donut at a coffee shop near the Stack Exchange offices.



However, you are required to solve a phrase and convert it into a single number.





Codes



You watch as a cashier says:




Do not use the toilets here. We're washing them.




And then the person replies:




$38$.




They get a free donut.



Next, another person walks in and you listen again. The cashier says:




Donuts by the dozen are $3.




The person replies:




$20$.




Once again, the cashier gives the person a free donut.





You go back the following day and watch as more people get their own free donuts.



The cashier says:




Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.




The person replies:




$20$.




Once again, they get a free donut.



The cashier says to another customer:




Your donuts aren't considered free yet.




The customer replies:




$50$.




This is also correct, and the cashier gives them free donuts.





You go up to the counter and the cashier says:




No donuts right now. We're making some more.




You come up with a random number:




Hmm... $44$?




She replies:




Sorry, but I do not know what you are talking about.




(You saw some donuts being handed to a paying person later, so you know she wasn't telling the truth when she said there were no donuts)





You are really hungry and want to get a free donut. What number should you say when you come back? You have promised her you will come back with the correct number (although she just shrugs)





Hints




  • Hint 1:



Donut ignore the pun in this hint.





  • Hint 2:



Do you nut see a tasty treat hidden in this?





  • Hint 3:



Why do you nut take what the cashier said literally? "Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question."





  • Hint 4:



$6+2+7+2+8+2+9+2+10+2 = 50$.








story password steganography






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 39 mins ago







haykam

















asked Jul 3 '16 at 2:52









haykamhaykam

904323




904323








  • 1




    $begingroup$
    It's re-misspelled in the latest edit. Accidental?
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 1:58






  • 1




    $begingroup$
    It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 2:01






  • 6




    $begingroup$
    Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
    $endgroup$
    – user1717828
    Jul 4 '16 at 12:40






  • 1




    $begingroup$
    If you're really that hungry, why not just pay for the donut? :P
    $endgroup$
    – Ian MacDonald
    Jul 4 '16 at 13:25






  • 2




    $begingroup$
    @Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
    $endgroup$
    – M Oehm
    Jul 5 '16 at 5:19














  • 1




    $begingroup$
    It's re-misspelled in the latest edit. Accidental?
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 1:58






  • 1




    $begingroup$
    It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
    $endgroup$
    – Dan Russell
    Jul 4 '16 at 2:01






  • 6




    $begingroup$
    Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
    $endgroup$
    – user1717828
    Jul 4 '16 at 12:40






  • 1




    $begingroup$
    If you're really that hungry, why not just pay for the donut? :P
    $endgroup$
    – Ian MacDonald
    Jul 4 '16 at 13:25






  • 2




    $begingroup$
    @Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
    $endgroup$
    – M Oehm
    Jul 5 '16 at 5:19








1




1




$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58




$begingroup$
It's re-misspelled in the latest edit. Accidental?
$endgroup$
– Dan Russell
Jul 4 '16 at 1:58




1




1




$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01




$begingroup$
It isn't accidental, or it isn't misspelled? (Because it is misspelled, o instead of a.)
$endgroup$
– Dan Russell
Jul 4 '16 at 2:01




6




6




$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40




$begingroup$
Unfortunately, this question seems to be of the "Guess what I'm thinking" type. OP has now shot down two answers that fit all the clues with Sorry not what I had in mind.
$endgroup$
– user1717828
Jul 4 '16 at 12:40




1




1




$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25




$begingroup$
If you're really that hungry, why not just pay for the donut? :P
$endgroup$
– Ian MacDonald
Jul 4 '16 at 13:25




2




2




$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
$endgroup$
– M Oehm
Jul 5 '16 at 5:19




$begingroup$
@Peanut: When they were really hungry when the question was first asked, they must be starved by now. :)
$endgroup$
– M Oehm
Jul 5 '16 at 5:19










7 Answers
7






active

oldest

votes


















18












$begingroup$

You should have answered




40




to begin with, but now you can answer




149




to get a free donut.




The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.








Do not use the toilets here. We're washing them. 

D = First word, first character = 1, 1

O = First word, second character = 1, 2

N = Second word, fourth character (including spaces!) = 2, 4

U = Third word, eighth character = 3, 8

T = Fourth word, twelfth character = 4, 12
 1 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38 







Donuts by the dozen are $3.

D = 1, 1

O = 1, 2

N = 1, 3

U = 1, 4

T = 1, 5
 1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.  

D = 1, 1

O = 1, 2

N = 1, 3

U = 1, 4

T = 1, 5
 1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







Your donuts aren't considered free yet.  

D = 2, 6

O = 2, 7

N = 2, 8

U = 2, 9

T = 2, 10
 2 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50 







No donuts right now. We're making some more.  

D = 2, 4

O = 2, 5

N = 2, 6

U = 2, 7

T = 2, 8
 2 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40 






So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:


Sorry, but I do not know what you are talking about.

D = 4, 14

O = 4, 15

N = 5, 17

U = 8, 33

T = 10, 39
4 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149 






So now, you may answer with 149 to get your free donut.






Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:





I can see a hint, but donut ignore that I still see steganogrophy-related in the text.  

D = 7, 23

O = 7, 24

N = 7, 25

U = 7, 26

T = 7, 27
 7 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160 






share|improve this answer











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  • 1




    $begingroup$
    I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
    $endgroup$
    – Arth
    Aug 3 '16 at 16:34






  • 2




    $begingroup$
    @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
    $endgroup$
    – Morgan G
    Aug 3 '16 at 17:10






  • 5




    $begingroup$
    Oh my goodness thank you, @MorganG, for putting this one to rest.
    $endgroup$
    – Dan Russell
    Aug 3 '16 at 17:13






  • 1




    $begingroup$
    Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
    $endgroup$
    – haykam
    Aug 3 '16 at 17:17






  • 1




    $begingroup$
    @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
    $endgroup$
    – Morgan G
    Aug 3 '16 at 17:20





















18












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For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals




the number of letters in the cashier's utterance, plus one




with the proviso that




you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".




In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say




either 34 or 40 (if I've counted right).







share|improve this answer











$endgroup$













  • $begingroup$
    This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
    $endgroup$
    – haykam
    Jul 4 '16 at 1:39












  • $begingroup$
    @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
    $endgroup$
    – f''
    Jul 4 '16 at 2:16










  • $begingroup$
    @f", the rule has stayed the same this whole time.
    $endgroup$
    – haykam
    Jul 4 '16 at 2:24






  • 4




    $begingroup$
    @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
    $endgroup$
    – f''
    Jul 4 '16 at 2:30












  • $begingroup$
    I hereby confirm that f'' has understood me correctly.
    $endgroup$
    – Gareth McCaughan
    Jul 4 '16 at 10:10



















14












$begingroup$

My answer is




38




Reasoning




I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.

The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".

The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.




Do not use the toilets here. We're washing them.




The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.

The cashier utters two distinct sentences and 8 is the genus two shape.




Donuts by the dozen are $3.




The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.

The cashier utters one sentence which corresponds to the simple genus one donut 0.




Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.




The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.

The cashier utters one sentence which corresponds to the simple genus one donut 0.




Your donuts aren't considered free yet.




The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.

The cashier utters one sentence which corresponds to the simple genus one donut 0.




No donuts right now. We're making some more.




The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.

The cashier utters two sentences which corresponds to the genus two donut 8.




Also,




This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.







share|improve this answer









$endgroup$





















    7












    $begingroup$

    Seems like the question was edited since I posted my answer. So I've adjusted.



    Re: What number should you say when you come back?




    35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.







    share|improve this answer











    $endgroup$













    • $begingroup$
      The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
      $endgroup$
      – haykam
      Jul 4 '16 at 1:40






    • 1




      $begingroup$
      I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
      $endgroup$
      – HardScale
      Jul 4 '16 at 3:47










    • $begingroup$
      To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
      $endgroup$
      – mestackoverflow
      Jul 4 '16 at 8:09










    • $begingroup$
      The resulting number of that message, @ericm301, would be 160.
      $endgroup$
      – haykam
      Jul 5 '16 at 2:19



















    6












    $begingroup$

    The answer is:




    20.




    Explanation:




    Any answer with "donuts" in it is 20







    share|improve this answer











    $endgroup$













    • $begingroup$
      This is not the answer I was looking for, nor is it a complete answer.
      $endgroup$
      – haykam
      Jul 4 '16 at 1:44






    • 1




      $begingroup$
      I knew it was too simple, why doesn't 20 work?
      $endgroup$
      – Areeb
      Jul 4 '16 at 1:53










    • $begingroup$
      I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
      $endgroup$
      – haykam
      Jul 4 '16 at 2:01






    • 3




      $begingroup$
      This fits all the current clues.
      $endgroup$
      – Dan Russell
      Jul 4 '16 at 2:02






    • 2




      $begingroup$
      @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
      $endgroup$
      – Dan Russell
      Jul 4 '16 at 2:05



















    2












    $begingroup$

    Possibly a partial:




    It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.




    'No donuts right now. We're making some more.':




    You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.




    'Sorry, but I do not know what you are talking about.'




    For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.




    Not solved:




    The first digit.




    Crazy guess:




    The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).




    Additional from comment on @flu's answer:



    'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160




    There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.




    --




    The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.







    share|improve this answer











    $endgroup$





















      1












      $begingroup$


      58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.







      share|improve this answer











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        7 Answers
        7






        active

        oldest

        votes








        7 Answers
        7






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        18












        $begingroup$

        You should have answered




        40




        to begin with, but now you can answer




        149




        to get a free donut.




        The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.








        Do not use the toilets here. We're washing them. 

        D = First word, first character = 1, 1

        O = First word, second character = 1, 2

        N = Second word, fourth character (including spaces!) = 2, 4

        U = Third word, eighth character = 3, 8

        T = Fourth word, twelfth character = 4, 12
         1 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38 







        Donuts by the dozen are $3.

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.  

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Your donuts aren't considered free yet.  

        D = 2, 6

        O = 2, 7

        N = 2, 8

        U = 2, 9

        T = 2, 10
         2 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50 







        No donuts right now. We're making some more.  

        D = 2, 4

        O = 2, 5

        N = 2, 6

        U = 2, 7

        T = 2, 8
         2 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40 






        So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:


        Sorry, but I do not know what you are talking about.

        D = 4, 14

        O = 4, 15

        N = 5, 17

        U = 8, 33

        T = 10, 39
        4 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149 






        So now, you may answer with 149 to get your free donut.






        Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:





        I can see a hint, but donut ignore that I still see steganogrophy-related in the text.  

        D = 7, 23

        O = 7, 24

        N = 7, 25

        U = 7, 26

        T = 7, 27
         7 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160 






        share|improve this answer











        $endgroup$









        • 1




          $begingroup$
          I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
          $endgroup$
          – Arth
          Aug 3 '16 at 16:34






        • 2




          $begingroup$
          @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:10






        • 5




          $begingroup$
          Oh my goodness thank you, @MorganG, for putting this one to rest.
          $endgroup$
          – Dan Russell
          Aug 3 '16 at 17:13






        • 1




          $begingroup$
          Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
          $endgroup$
          – haykam
          Aug 3 '16 at 17:17






        • 1




          $begingroup$
          @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:20


















        18












        $begingroup$

        You should have answered




        40




        to begin with, but now you can answer




        149




        to get a free donut.




        The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.








        Do not use the toilets here. We're washing them. 

        D = First word, first character = 1, 1

        O = First word, second character = 1, 2

        N = Second word, fourth character (including spaces!) = 2, 4

        U = Third word, eighth character = 3, 8

        T = Fourth word, twelfth character = 4, 12
         1 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38 







        Donuts by the dozen are $3.

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.  

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Your donuts aren't considered free yet.  

        D = 2, 6

        O = 2, 7

        N = 2, 8

        U = 2, 9

        T = 2, 10
         2 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50 







        No donuts right now. We're making some more.  

        D = 2, 4

        O = 2, 5

        N = 2, 6

        U = 2, 7

        T = 2, 8
         2 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40 






        So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:


        Sorry, but I do not know what you are talking about.

        D = 4, 14

        O = 4, 15

        N = 5, 17

        U = 8, 33

        T = 10, 39
        4 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149 






        So now, you may answer with 149 to get your free donut.






        Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:





        I can see a hint, but donut ignore that I still see steganogrophy-related in the text.  

        D = 7, 23

        O = 7, 24

        N = 7, 25

        U = 7, 26

        T = 7, 27
         7 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160 






        share|improve this answer











        $endgroup$









        • 1




          $begingroup$
          I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
          $endgroup$
          – Arth
          Aug 3 '16 at 16:34






        • 2




          $begingroup$
          @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:10






        • 5




          $begingroup$
          Oh my goodness thank you, @MorganG, for putting this one to rest.
          $endgroup$
          – Dan Russell
          Aug 3 '16 at 17:13






        • 1




          $begingroup$
          Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
          $endgroup$
          – haykam
          Aug 3 '16 at 17:17






        • 1




          $begingroup$
          @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:20
















        18












        18








        18





        $begingroup$

        You should have answered




        40




        to begin with, but now you can answer




        149




        to get a free donut.




        The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.








        Do not use the toilets here. We're washing them. 

        D = First word, first character = 1, 1

        O = First word, second character = 1, 2

        N = Second word, fourth character (including spaces!) = 2, 4

        U = Third word, eighth character = 3, 8

        T = Fourth word, twelfth character = 4, 12
         1 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38 







        Donuts by the dozen are $3.

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.  

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Your donuts aren't considered free yet.  

        D = 2, 6

        O = 2, 7

        N = 2, 8

        U = 2, 9

        T = 2, 10
         2 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50 







        No donuts right now. We're making some more.  

        D = 2, 4

        O = 2, 5

        N = 2, 6

        U = 2, 7

        T = 2, 8
         2 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40 






        So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:


        Sorry, but I do not know what you are talking about.

        D = 4, 14

        O = 4, 15

        N = 5, 17

        U = 8, 33

        T = 10, 39
        4 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149 






        So now, you may answer with 149 to get your free donut.






        Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:





        I can see a hint, but donut ignore that I still see steganogrophy-related in the text.  

        D = 7, 23

        O = 7, 24

        N = 7, 25

        U = 7, 26

        T = 7, 27
         7 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160 






        share|improve this answer











        $endgroup$



        You should have answered




        40




        to begin with, but now you can answer




        149




        to get a free donut.




        The pattern is as follows. You need to spell the word "donut" using the letters the cashier used, in order. Then, add up the word positions and absolute character positions. Donut must be spelled in order, using the order of the characters that the cashier uses.








        Do not use the toilets here. We're washing them. 

        D = First word, first character = 1, 1

        O = First word, second character = 1, 2

        N = Second word, fourth character (including spaces!) = 2, 4

        U = Third word, eighth character = 3, 8

        T = Fourth word, twelfth character = 4, 12
         1 + 1 + 1 + 2 + 2 + 4 + 3 + 8 + 4 + 12 = 38 







        Donuts by the dozen are $3.

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Donuts are mentioned somehow as a secret here, and thus, this is a steganography-related question.  

        D = 1, 1

        O = 1, 2

        N = 1, 3

        U = 1, 4

        T = 1, 5
         1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 = 20 







        Your donuts aren't considered free yet.  

        D = 2, 6

        O = 2, 7

        N = 2, 8

        U = 2, 9

        T = 2, 10
         2 + 6 + 2 + 7 + 2 + 8 + 2 + 9 + 2 + 10 = 50 







        No donuts right now. We're making some more.  

        D = 2, 4

        O = 2, 5

        N = 2, 6

        U = 2, 7

        T = 2, 8
         2 + 4 + 2 + 5 + 2 + 6 + 2 + 7 + 2 + 8 = 40 






        So, you should have answered 40 to begin with. Now, the cashier has said another sentence which we can apply the rule to:


        Sorry, but I do not know what you are talking about.

        D = 4, 14

        O = 4, 15

        N = 5, 17

        U = 8, 33

        T = 10, 39
        4 + 14 + 4 + 15 + 5 + 17 + 8 + 33 + 10 + 39 = 149 






        So now, you may answer with 149 to get your free donut.






        Bonus confirmation pointed out by Arth, shown in a comment on flu's answer:





        I can see a hint, but donut ignore that I still see steganogrophy-related in the text.  

        D = 7, 23

        O = 7, 24

        N = 7, 25

        U = 7, 26

        T = 7, 27
         7 + 23 + 7 + 24 + 7 + 25 + 7 + 26 + 7 + 27 = 160 







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Aug 4 '16 at 19:03

























        answered Aug 3 '16 at 16:25









        Morgan GMorgan G

        1,811527




        1,811527








        • 1




          $begingroup$
          I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
          $endgroup$
          – Arth
          Aug 3 '16 at 16:34






        • 2




          $begingroup$
          @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:10






        • 5




          $begingroup$
          Oh my goodness thank you, @MorganG, for putting this one to rest.
          $endgroup$
          – Dan Russell
          Aug 3 '16 at 17:13






        • 1




          $begingroup$
          Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
          $endgroup$
          – haykam
          Aug 3 '16 at 17:17






        • 1




          $begingroup$
          @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:20
















        • 1




          $begingroup$
          I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
          $endgroup$
          – Arth
          Aug 3 '16 at 16:34






        • 2




          $begingroup$
          @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:10






        • 5




          $begingroup$
          Oh my goodness thank you, @MorganG, for putting this one to rest.
          $endgroup$
          – Dan Russell
          Aug 3 '16 at 17:13






        • 1




          $begingroup$
          Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
          $endgroup$
          – haykam
          Aug 3 '16 at 17:17






        • 1




          $begingroup$
          @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
          $endgroup$
          – Morgan G
          Aug 3 '16 at 17:20










        1




        1




        $begingroup$
        I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
        $endgroup$
        – Arth
        Aug 3 '16 at 16:34




        $begingroup$
        I was just about to start writing out something close to this answer, glad I saw the update before I did! Looks good and is also backed up by the comment answer 'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - 160 (23+7+24+7+25+7+26+7+27+7)
        $endgroup$
        – Arth
        Aug 3 '16 at 16:34




        2




        2




        $begingroup$
        @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
        $endgroup$
        – Morgan G
        Aug 3 '16 at 17:10




        $begingroup$
        @Arth I was taking them way too literally at first, trying to find the number of "donuts" (letters with holes) in each sentence.
        $endgroup$
        – Morgan G
        Aug 3 '16 at 17:10




        5




        5




        $begingroup$
        Oh my goodness thank you, @MorganG, for putting this one to rest.
        $endgroup$
        – Dan Russell
        Aug 3 '16 at 17:13




        $begingroup$
        Oh my goodness thank you, @MorganG, for putting this one to rest.
        $endgroup$
        – Dan Russell
        Aug 3 '16 at 17:13




        1




        1




        $begingroup$
        Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
        $endgroup$
        – haykam
        Aug 3 '16 at 17:17




        $begingroup$
        Congratulations, you finished this puzzle! Just wondering, but did you use any of the hints?
        $endgroup$
        – haykam
        Aug 3 '16 at 17:17




        1




        1




        $begingroup$
        @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
        $endgroup$
        – Morgan G
        Aug 3 '16 at 17:20






        $begingroup$
        @Peanut, Yes. I've been obsessing over this for a week or so but had nothing solid until the hint you posted last night. The first three hints didn't really give me any additional information though.
        $endgroup$
        – Morgan G
        Aug 3 '16 at 17:20













        18












        $begingroup$

        For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals




        the number of letters in the cashier's utterance, plus one




        with the proviso that




        you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".




        In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say




        either 34 or 40 (if I've counted right).







        share|improve this answer











        $endgroup$













        • $begingroup$
          This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
          $endgroup$
          – haykam
          Jul 4 '16 at 1:39












        • $begingroup$
          @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
          $endgroup$
          – f''
          Jul 4 '16 at 2:16










        • $begingroup$
          @f", the rule has stayed the same this whole time.
          $endgroup$
          – haykam
          Jul 4 '16 at 2:24






        • 4




          $begingroup$
          @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
          $endgroup$
          – f''
          Jul 4 '16 at 2:30












        • $begingroup$
          I hereby confirm that f'' has understood me correctly.
          $endgroup$
          – Gareth McCaughan
          Jul 4 '16 at 10:10
















        18












        $begingroup$

        For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals




        the number of letters in the cashier's utterance, plus one




        with the proviso that




        you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".




        In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say




        either 34 or 40 (if I've counted right).







        share|improve this answer











        $endgroup$













        • $begingroup$
          This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
          $endgroup$
          – haykam
          Jul 4 '16 at 1:39












        • $begingroup$
          @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
          $endgroup$
          – f''
          Jul 4 '16 at 2:16










        • $begingroup$
          @f", the rule has stayed the same this whole time.
          $endgroup$
          – haykam
          Jul 4 '16 at 2:24






        • 4




          $begingroup$
          @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
          $endgroup$
          – f''
          Jul 4 '16 at 2:30












        • $begingroup$
          I hereby confirm that f'' has understood me correctly.
          $endgroup$
          – Gareth McCaughan
          Jul 4 '16 at 10:10














        18












        18








        18





        $begingroup$

        For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals




        the number of letters in the cashier's utterance, plus one




        with the proviso that




        you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".




        In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say




        either 34 or 40 (if I've counted right).







        share|improve this answer











        $endgroup$



        For the known-good answers we have so far [EDITED to add: ... but more answers have since been added to the question], the number equals




        the number of letters in the cashier's utterance, plus one




        with the proviso that




        you somehow need to know that "$3" is a symbol and a digit rather than, say, "t-h-r-e-e b-u-c-k-s".




        In that case, depending on whether we take the cashier's last utterance as a "prompt" or an "error message", it seems like you need to say




        either 34 or 40 (if I've counted right).








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Jul 4 '16 at 10:10

























        answered Jul 3 '16 at 3:04









        Gareth McCaughanGareth McCaughan

        63.5k3163248




        63.5k3163248












        • $begingroup$
          This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
          $endgroup$
          – haykam
          Jul 4 '16 at 1:39












        • $begingroup$
          @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
          $endgroup$
          – f''
          Jul 4 '16 at 2:16










        • $begingroup$
          @f", the rule has stayed the same this whole time.
          $endgroup$
          – haykam
          Jul 4 '16 at 2:24






        • 4




          $begingroup$
          @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
          $endgroup$
          – f''
          Jul 4 '16 at 2:30












        • $begingroup$
          I hereby confirm that f'' has understood me correctly.
          $endgroup$
          – Gareth McCaughan
          Jul 4 '16 at 10:10


















        • $begingroup$
          This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
          $endgroup$
          – haykam
          Jul 4 '16 at 1:39












        • $begingroup$
          @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
          $endgroup$
          – f''
          Jul 4 '16 at 2:16










        • $begingroup$
          @f", the rule has stayed the same this whole time.
          $endgroup$
          – haykam
          Jul 4 '16 at 2:24






        • 4




          $begingroup$
          @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
          $endgroup$
          – f''
          Jul 4 '16 at 2:30












        • $begingroup$
          I hereby confirm that f'' has understood me correctly.
          $endgroup$
          – Gareth McCaughan
          Jul 4 '16 at 10:10
















        $begingroup$
        This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
        $endgroup$
        – haykam
        Jul 4 '16 at 1:39






        $begingroup$
        This is not the answer I'm looking for. However, why are the resulting numbers different depending on if the cashier's last utterance was taken as a prompt virus an error message? Also, I've added a hint.
        $endgroup$
        – haykam
        Jul 4 '16 at 1:39














        $begingroup$
        @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
        $endgroup$
        – f''
        Jul 4 '16 at 2:16




        $begingroup$
        @Peanut It's different depending on whether you're supposed to respond to the original prompt or the new utterance.
        $endgroup$
        – f''
        Jul 4 '16 at 2:16












        $begingroup$
        @f", the rule has stayed the same this whole time.
        $endgroup$
        – haykam
        Jul 4 '16 at 2:24




        $begingroup$
        @f", the rule has stayed the same this whole time.
        $endgroup$
        – haykam
        Jul 4 '16 at 2:24




        4




        4




        $begingroup$
        @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
        $endgroup$
        – f''
        Jul 4 '16 at 2:30






        $begingroup$
        @Peanut The rule in this answer is the same, but the different numbers are because one is applying the rule to the original message ("No donuts right now..."), while the other one comes from applying the rule to the new response ("Sorry, but I do not know...").
        $endgroup$
        – f''
        Jul 4 '16 at 2:30














        $begingroup$
        I hereby confirm that f'' has understood me correctly.
        $endgroup$
        – Gareth McCaughan
        Jul 4 '16 at 10:10




        $begingroup$
        I hereby confirm that f'' has understood me correctly.
        $endgroup$
        – Gareth McCaughan
        Jul 4 '16 at 10:10











        14












        $begingroup$

        My answer is




        38




        Reasoning




        I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.

        The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".

        The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.




        Do not use the toilets here. We're washing them.




        The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.

        The cashier utters two distinct sentences and 8 is the genus two shape.




        Donuts by the dozen are $3.




        The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.

        The cashier utters one sentence which corresponds to the simple genus one donut 0.




        Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.




        The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.

        The cashier utters one sentence which corresponds to the simple genus one donut 0.




        Your donuts aren't considered free yet.




        The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.

        The cashier utters one sentence which corresponds to the simple genus one donut 0.




        No donuts right now. We're making some more.




        The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.

        The cashier utters two sentences which corresponds to the genus two donut 8.




        Also,




        This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.







        share|improve this answer









        $endgroup$


















          14












          $begingroup$

          My answer is




          38




          Reasoning




          I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.

          The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".

          The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.




          Do not use the toilets here. We're washing them.




          The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.

          The cashier utters two distinct sentences and 8 is the genus two shape.




          Donuts by the dozen are $3.




          The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.

          The cashier utters one sentence which corresponds to the simple genus one donut 0.




          Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.




          The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.

          The cashier utters one sentence which corresponds to the simple genus one donut 0.




          Your donuts aren't considered free yet.




          The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.

          The cashier utters one sentence which corresponds to the simple genus one donut 0.




          No donuts right now. We're making some more.




          The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.

          The cashier utters two sentences which corresponds to the genus two donut 8.




          Also,




          This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.







          share|improve this answer









          $endgroup$
















            14












            14








            14





            $begingroup$

            My answer is




            38




            Reasoning




            I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.

            The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".

            The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.




            Do not use the toilets here. We're washing them.




            The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.

            The cashier utters two distinct sentences and 8 is the genus two shape.




            Donuts by the dozen are $3.




            The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.




            The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            Your donuts aren't considered free yet.




            The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            No donuts right now. We're making some more.




            The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.

            The cashier utters two sentences which corresponds to the genus two donut 8.




            Also,




            This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.







            share|improve this answer









            $endgroup$



            My answer is




            38




            Reasoning




            I think each digit of the answer represents a different aspect of the phrase uttered by the cashier.

            The first digit gives the position of the first word in the phrase which shares less than two letters with the word "donut".

            The second digit is not a digit but rather a representation of a generalised donut whose genus (number of holes) is given by the number of sentences uttered by the cashier.




            Do not use the toilets here. We're washing them.




            The first word in the sentence which shares less than 2 letters with "donut" is use which is at position 3.

            The cashier utters two distinct sentences and 8 is the genus two shape.




            Donuts by the dozen are $3.




            The first word in the sentence which shares less than 2 letters with "donut" is by which is at position 2.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            Donuts are mentioned somehow as a secret here, and thus, this is a steganogrophy-related question.




            The first word in the sentence which shares less than 2 letters with "donut" is are which is at position 2.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            Your donuts aren't considered free yet.




            The first word in the sentence which shares less than 2 letters with "donut" is free which is at position 5.

            The cashier utters one sentence which corresponds to the simple genus one donut 0.




            No donuts right now. We're making some more.




            The first word in the sentence which shares less than 2 letters with "donut" is right which is at position 3.

            The cashier utters two sentences which corresponds to the genus two donut 8.




            Also,




            This explains the cashier's confusion as 4 is not a legitimate answer for the second digit.








            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Jul 6 '16 at 10:46









            hexominohexomino

            41.7k3125198




            41.7k3125198























                7












                $begingroup$

                Seems like the question was edited since I posted my answer. So I've adjusted.



                Re: What number should you say when you come back?




                35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.







                share|improve this answer











                $endgroup$













                • $begingroup$
                  The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:40






                • 1




                  $begingroup$
                  I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                  $endgroup$
                  – HardScale
                  Jul 4 '16 at 3:47










                • $begingroup$
                  To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                  $endgroup$
                  – mestackoverflow
                  Jul 4 '16 at 8:09










                • $begingroup$
                  The resulting number of that message, @ericm301, would be 160.
                  $endgroup$
                  – haykam
                  Jul 5 '16 at 2:19
















                7












                $begingroup$

                Seems like the question was edited since I posted my answer. So I've adjusted.



                Re: What number should you say when you come back?




                35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.







                share|improve this answer











                $endgroup$













                • $begingroup$
                  The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:40






                • 1




                  $begingroup$
                  I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                  $endgroup$
                  – HardScale
                  Jul 4 '16 at 3:47










                • $begingroup$
                  To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                  $endgroup$
                  – mestackoverflow
                  Jul 4 '16 at 8:09










                • $begingroup$
                  The resulting number of that message, @ericm301, would be 160.
                  $endgroup$
                  – haykam
                  Jul 5 '16 at 2:19














                7












                7








                7





                $begingroup$

                Seems like the question was edited since I posted my answer. So I've adjusted.



                Re: What number should you say when you come back?




                35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.







                share|improve this answer











                $endgroup$



                Seems like the question was edited since I posted my answer. So I've adjusted.



                Re: What number should you say when you come back?




                35. Which is the count of letters and numbers modulus 60. But not including symbols, spaces or punctuation. So "we're" would count as 5, after being expanded to "we are". And "$3" would simply count as 1. The misspelling of steganography is assumed as well, and counted as 12 letters.








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Jul 3 '16 at 22:18

























                answered Jul 3 '16 at 17:12









                fluflu

                32115




                32115












                • $begingroup$
                  The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:40






                • 1




                  $begingroup$
                  I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                  $endgroup$
                  – HardScale
                  Jul 4 '16 at 3:47










                • $begingroup$
                  To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                  $endgroup$
                  – mestackoverflow
                  Jul 4 '16 at 8:09










                • $begingroup$
                  The resulting number of that message, @ericm301, would be 160.
                  $endgroup$
                  – haykam
                  Jul 5 '16 at 2:19


















                • $begingroup$
                  The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:40






                • 1




                  $begingroup$
                  I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                  $endgroup$
                  – HardScale
                  Jul 4 '16 at 3:47










                • $begingroup$
                  To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                  $endgroup$
                  – mestackoverflow
                  Jul 4 '16 at 8:09










                • $begingroup$
                  The resulting number of that message, @ericm301, would be 160.
                  $endgroup$
                  – haykam
                  Jul 5 '16 at 2:19
















                $begingroup$
                The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                $endgroup$
                – haykam
                Jul 4 '16 at 1:40




                $begingroup$
                The misspelling of steganography was a mistake on my part. I've since updated the post and fixed that error, along with adding a hint.
                $endgroup$
                – haykam
                Jul 4 '16 at 1:40




                1




                1




                $begingroup$
                I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                $endgroup$
                – HardScale
                Jul 4 '16 at 3:47




                $begingroup$
                I can see a hint, but donut ignore that I still see steganogrophy-related in the text.
                $endgroup$
                – HardScale
                Jul 4 '16 at 3:47












                $begingroup$
                To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                $endgroup$
                – mestackoverflow
                Jul 4 '16 at 8:09




                $begingroup$
                To include the hint in any answers that use counting the letters, maybe "donuts" becomes "do not", so 5 letters instead of 6.
                $endgroup$
                – mestackoverflow
                Jul 4 '16 at 8:09












                $begingroup$
                The resulting number of that message, @ericm301, would be 160.
                $endgroup$
                – haykam
                Jul 5 '16 at 2:19




                $begingroup$
                The resulting number of that message, @ericm301, would be 160.
                $endgroup$
                – haykam
                Jul 5 '16 at 2:19











                6












                $begingroup$

                The answer is:




                20.




                Explanation:




                Any answer with "donuts" in it is 20







                share|improve this answer











                $endgroup$













                • $begingroup$
                  This is not the answer I was looking for, nor is it a complete answer.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:44






                • 1




                  $begingroup$
                  I knew it was too simple, why doesn't 20 work?
                  $endgroup$
                  – Areeb
                  Jul 4 '16 at 1:53










                • $begingroup$
                  I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 2:01






                • 3




                  $begingroup$
                  This fits all the current clues.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:02






                • 2




                  $begingroup$
                  @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:05
















                6












                $begingroup$

                The answer is:




                20.




                Explanation:




                Any answer with "donuts" in it is 20







                share|improve this answer











                $endgroup$













                • $begingroup$
                  This is not the answer I was looking for, nor is it a complete answer.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:44






                • 1




                  $begingroup$
                  I knew it was too simple, why doesn't 20 work?
                  $endgroup$
                  – Areeb
                  Jul 4 '16 at 1:53










                • $begingroup$
                  I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 2:01






                • 3




                  $begingroup$
                  This fits all the current clues.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:02






                • 2




                  $begingroup$
                  @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:05














                6












                6








                6





                $begingroup$

                The answer is:




                20.




                Explanation:




                Any answer with "donuts" in it is 20







                share|improve this answer











                $endgroup$



                The answer is:




                20.




                Explanation:




                Any answer with "donuts" in it is 20








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Jul 4 '16 at 1:51









                haykam

                904323




                904323










                answered Jul 4 '16 at 1:41









                AreebAreeb

                1,3781726




                1,3781726












                • $begingroup$
                  This is not the answer I was looking for, nor is it a complete answer.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:44






                • 1




                  $begingroup$
                  I knew it was too simple, why doesn't 20 work?
                  $endgroup$
                  – Areeb
                  Jul 4 '16 at 1:53










                • $begingroup$
                  I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 2:01






                • 3




                  $begingroup$
                  This fits all the current clues.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:02






                • 2




                  $begingroup$
                  @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:05


















                • $begingroup$
                  This is not the answer I was looking for, nor is it a complete answer.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 1:44






                • 1




                  $begingroup$
                  I knew it was too simple, why doesn't 20 work?
                  $endgroup$
                  – Areeb
                  Jul 4 '16 at 1:53










                • $begingroup$
                  I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                  $endgroup$
                  – haykam
                  Jul 4 '16 at 2:01






                • 3




                  $begingroup$
                  This fits all the current clues.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:02






                • 2




                  $begingroup$
                  @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                  $endgroup$
                  – Dan Russell
                  Jul 4 '16 at 2:05
















                $begingroup$
                This is not the answer I was looking for, nor is it a complete answer.
                $endgroup$
                – haykam
                Jul 4 '16 at 1:44




                $begingroup$
                This is not the answer I was looking for, nor is it a complete answer.
                $endgroup$
                – haykam
                Jul 4 '16 at 1:44




                1




                1




                $begingroup$
                I knew it was too simple, why doesn't 20 work?
                $endgroup$
                – Areeb
                Jul 4 '16 at 1:53




                $begingroup$
                I knew it was too simple, why doesn't 20 work?
                $endgroup$
                – Areeb
                Jul 4 '16 at 1:53












                $begingroup$
                I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                $endgroup$
                – haykam
                Jul 4 '16 at 2:01




                $begingroup$
                I'd have to reveal the correct answer to you to explain that. Your reasoning is wrong; 20 can be right or wrong.
                $endgroup$
                – haykam
                Jul 4 '16 at 2:01




                3




                3




                $begingroup$
                This fits all the current clues.
                $endgroup$
                – Dan Russell
                Jul 4 '16 at 2:02




                $begingroup$
                This fits all the current clues.
                $endgroup$
                – Dan Russell
                Jul 4 '16 at 2:02




                2




                2




                $begingroup$
                @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                $endgroup$
                – Dan Russell
                Jul 4 '16 at 2:05




                $begingroup$
                @Peanut Yep, just saying that it's consistent and thus is a reasonable guess.
                $endgroup$
                – Dan Russell
                Jul 4 '16 at 2:05











                2












                $begingroup$

                Possibly a partial:




                It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.




                'No donuts right now. We're making some more.':




                You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.




                'Sorry, but I do not know what you are talking about.'




                For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.




                Not solved:




                The first digit.




                Crazy guess:




                The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).




                Additional from comment on @flu's answer:



                'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160




                There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.




                --




                The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.







                share|improve this answer











                $endgroup$


















                  2












                  $begingroup$

                  Possibly a partial:




                  It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.




                  'No donuts right now. We're making some more.':




                  You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.




                  'Sorry, but I do not know what you are talking about.'




                  For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.




                  Not solved:




                  The first digit.




                  Crazy guess:




                  The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).




                  Additional from comment on @flu's answer:



                  'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160




                  There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.




                  --




                  The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.







                  share|improve this answer











                  $endgroup$
















                    2












                    2








                    2





                    $begingroup$

                    Possibly a partial:




                    It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.




                    'No donuts right now. We're making some more.':




                    You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.




                    'Sorry, but I do not know what you are talking about.'




                    For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.




                    Not solved:




                    The first digit.




                    Crazy guess:




                    The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).




                    Additional from comment on @flu's answer:



                    'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160




                    There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.




                    --




                    The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.







                    share|improve this answer











                    $endgroup$



                    Possibly a partial:




                    It appears that when the cashier says 'Donut(s)' the answer ends in a 0, which at least one of my Maths teachers referred to jokingly as a donut. And when the cashier says 'Do not' it ends with an 8 at least from the one sample. This could be seen as a 0 with a line through it in calculator font.




                    'No donuts right now. We're making some more.':




                    You could answer x0 as 'donuts' is mentioned, possibly 50 as this response earned free donuts not a singular donut and I'm greedy.




                    'Sorry, but I do not know what you are talking about.'




                    For the second statement I'd guess x8, as 'do not' is mentioned, possibly 38 as this answer was rewarded before.




                    Not solved:




                    The first digit.




                    Crazy guess:




                    The first digit comes from the first digit of an HTTP response code, 2 for status ok, 3 for a redirect 4 for not found and 5 for an error code. This would make sense for 38 (redirected to the toilets), two 20s (info about donuts), 50 (error for donuts not free). The correct responses could be 40 (no donuts found) and 58 or 48 (don't know what you are talking about).




                    Additional from comment on @flu's answer:



                    'I can see a hint, but donut ignore that I still see steganogrophy-related in the text.' - Correct response 160




                    There are 16 letters before the 'o' in 'donut' and there are 5 letters before the 'o' in 'donuts' in the statement with the answer 50 and beginning 'Your donuts...'. This suggests in the case of 'donut(s)' the answer is 10 times the number of letters before the 'o' in 'donut(s)'. Unfortunately there is only 1 character before the 'o' in 'donuts' in the two 20 statements.




                    --




                    The answer for 'No donuts right now. We're making some more' could then be 30 or 40 depending on which method you follow as there are 3 letters before the 'o'; this sheds no light on why the first answer is 38 however.








                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Jul 6 '16 at 14:53

























                    answered Jul 6 '16 at 12:25









                    ArthArth

                    3,1901331




                    3,1901331























                        1












                        $begingroup$


                        58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.







                        share|improve this answer











                        $endgroup$


















                          1












                          $begingroup$


                          58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.







                          share|improve this answer











                          $endgroup$
















                            1












                            1








                            1





                            $begingroup$


                            58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.







                            share|improve this answer











                            $endgroup$




                            58. You take the number of the vowel with the largest amount as they are the same for the whole two or one sentences for the first number, then take the number of a matching consonants plus vowels plus 1 as the second, for example, in "Do not use the toilets here. We're washing them." it is the number of each letter matching, because there are three "o"s and "e"s.








                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Aug 2 '16 at 1:37

























                            answered Aug 2 '16 at 1:28









                            Ray WuRay Wu

                            697




                            697






























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