How to Partition rest rows by the first row?












3












$begingroup$


Given a list



lst = {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},

        { "A","B","C","D","E","F","G","H","I"},

        { "9","8","7","6","5","4","3","2","1"}};


How to get this by Partition.



res =  {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},

        {{"A","B","C"},{"D","E"},{"F","G","H","I"}},

        {{"9","8","7"},{"6","5"},{"4","3","2","1"}}};


Thanks!






list-manipulation partitions







share|improve this question









$endgroup$

















    3












    $begingroup$


    Given a list



    lst = {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
    
        { "A","B","C","D","E","F","G","H","I"},
    
        { "9","8","7","6","5","4","3","2","1"}};


    How to get this by Partition.



    res =  {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
    
        {{"A","B","C"},{"D","E"},{"F","G","H","I"}},
    
        {{"9","8","7"},{"6","5"},{"4","3","2","1"}}};


    Thanks!






    list-manipulation partitions







    share|improve this question









    $endgroup$















      3












      3








      3





      $begingroup$


      Given a list



      lst = {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
      
        { "A","B","C","D","E","F","G","H","I"},
      
        { "9","8","7","6","5","4","3","2","1"}};


      How to get this by Partition.



      res =  {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
      
        {{"A","B","C"},{"D","E"},{"F","G","H","I"}},
      
        {{"9","8","7"},{"6","5"},{"4","3","2","1"}}};


      Thanks!






      list-manipulation partitions







      share|improve this question









      $endgroup$




      Given a list



      lst = {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
      
        { "A","B","C","D","E","F","G","H","I"},
      
        { "9","8","7","6","5","4","3","2","1"}};


      How to get this by Partition.



      res =  {{{"1","2","3"},{"4","5"},{"6","7","8","9"}},
      
        {{"A","B","C"},{"D","E"},{"F","G","H","I"}},
      
        {{"9","8","7"},{"6","5"},{"4","3","2","1"}}};


      Thanks!






      list-manipulation partitions




      list-manipulation partitions






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 9 hours ago









      JerryJerry

      1,043112




      1,043112






















          3 Answers
          3






          active

          oldest

          votes


















          6












          $begingroup$

          lst2 = lst;
          
lst2[[2 ;;]] = TakeList[Flatten @ #, Length /@ lst[[1]]] & /@ lst[[2 ;;]];
          
lst2



          {{{"1", "2", "3"}, {"4", "5"}, {"6", "7", "8", "9"}},

          {{"A", "B",
          "C"}, {"D", "E"}, {"F", "G", "H", "I"}},

          {{"9", "8", "7"}, {"6",
          "5"}, {"4", "3", "2", "1"}}}




          Also:



          lst3 = lst; 
          
lst3[[2 ;;]] = Function[x, Module[{k = 0}, Map[x[[k++]] &, lst[[1]], {-1}]]] /@ Rest[lst3];
          
lst3



          same result




          MapAt[TakeList[Flatten @ #, Length /@ lst[[1]]] &, lst, {{2}, {3}}]



          same result







          share|improve this answer











          $endgroup$













          • $begingroup$
            Thanks! Master who is energetic and always online.;)
            $endgroup$
            – Jerry
            8 hours ago



















          3












          $begingroup$

          p = Length /@ First[lst];
          

          
res = Prepend[
          
  Internal`PartitionRagged[#, p] & /@ Rest[lst],
          
  First[lst]]
          




          {{{1, 2, 3}, {4, 5}, {6, 7, 8, 9}},
          
 {{A, B, C}, {D, E}, {F, G, H, I}},
          
 {{9, 8, 7}, {6, 5}, {4, 3, 2, 1}}}






          share|improve this answer









          $endgroup$





















            2












            $begingroup$

            The following also works. I removed the brackets 



            Prepend[Table[FoldPairList[TakeDrop, lst[[i]], Length /@ lst[[1]]], {i, 2, Length[lst]}], lst[[1]]]


            Also, many thanks to kglr for correcting my code.



            FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst]





            share|improve this answer











            $endgroup$









            • 1




              $begingroup$
              Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
              $endgroup$
              – kglr
              4 hours ago










            • $begingroup$
              @kglr thank you very much! I do not handle pure functions well.
              $endgroup$
              – Titus
              4 hours ago











            Your Answer





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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6












            $begingroup$

            lst2 = lst;
            
lst2[[2 ;;]] = TakeList[Flatten @ #, Length /@ lst[[1]]] & /@ lst[[2 ;;]];
            
lst2



            {{{"1", "2", "3"}, {"4", "5"}, {"6", "7", "8", "9"}},

            {{"A", "B",
            "C"}, {"D", "E"}, {"F", "G", "H", "I"}},

            {{"9", "8", "7"}, {"6",
            "5"}, {"4", "3", "2", "1"}}}




            Also:



            lst3 = lst; 
            
lst3[[2 ;;]] = Function[x, Module[{k = 0}, Map[x[[k++]] &, lst[[1]], {-1}]]] /@ Rest[lst3];
            
lst3



            same result




            MapAt[TakeList[Flatten @ #, Length /@ lst[[1]]] &, lst, {{2}, {3}}]



            same result







            share|improve this answer











            $endgroup$













            • $begingroup$
              Thanks! Master who is energetic and always online.;)
              $endgroup$
              – Jerry
              8 hours ago
















            6












            $begingroup$

            lst2 = lst;
            
lst2[[2 ;;]] = TakeList[Flatten @ #, Length /@ lst[[1]]] & /@ lst[[2 ;;]];
            
lst2



            {{{"1", "2", "3"}, {"4", "5"}, {"6", "7", "8", "9"}},

            {{"A", "B",
            "C"}, {"D", "E"}, {"F", "G", "H", "I"}},

            {{"9", "8", "7"}, {"6",
            "5"}, {"4", "3", "2", "1"}}}




            Also:



            lst3 = lst; 
            
lst3[[2 ;;]] = Function[x, Module[{k = 0}, Map[x[[k++]] &, lst[[1]], {-1}]]] /@ Rest[lst3];
            
lst3



            same result




            MapAt[TakeList[Flatten @ #, Length /@ lst[[1]]] &, lst, {{2}, {3}}]



            same result







            share|improve this answer











            $endgroup$













            • $begingroup$
              Thanks! Master who is energetic and always online.;)
              $endgroup$
              – Jerry
              8 hours ago














            6












            6








            6





            $begingroup$

            lst2 = lst;
            
lst2[[2 ;;]] = TakeList[Flatten @ #, Length /@ lst[[1]]] & /@ lst[[2 ;;]];
            
lst2



            {{{"1", "2", "3"}, {"4", "5"}, {"6", "7", "8", "9"}},

            {{"A", "B",
            "C"}, {"D", "E"}, {"F", "G", "H", "I"}},

            {{"9", "8", "7"}, {"6",
            "5"}, {"4", "3", "2", "1"}}}




            Also:



            lst3 = lst; 
            
lst3[[2 ;;]] = Function[x, Module[{k = 0}, Map[x[[k++]] &, lst[[1]], {-1}]]] /@ Rest[lst3];
            
lst3



            same result




            MapAt[TakeList[Flatten @ #, Length /@ lst[[1]]] &, lst, {{2}, {3}}]



            same result







            share|improve this answer











            $endgroup$



            lst2 = lst;
            
lst2[[2 ;;]] = TakeList[Flatten @ #, Length /@ lst[[1]]] & /@ lst[[2 ;;]];
            
lst2



            {{{"1", "2", "3"}, {"4", "5"}, {"6", "7", "8", "9"}},

            {{"A", "B",
            "C"}, {"D", "E"}, {"F", "G", "H", "I"}},

            {{"9", "8", "7"}, {"6",
            "5"}, {"4", "3", "2", "1"}}}




            Also:



            lst3 = lst; 
            
lst3[[2 ;;]] = Function[x, Module[{k = 0}, Map[x[[k++]] &, lst[[1]], {-1}]]] /@ Rest[lst3];
            
lst3



            same result




            MapAt[TakeList[Flatten @ #, Length /@ lst[[1]]] &, lst, {{2}, {3}}]



            same result








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 1 hour ago

























            answered 9 hours ago









            kglrkglr

            179k9199410




            179k9199410












            • $begingroup$
              Thanks! Master who is energetic and always online.;)
              $endgroup$
              – Jerry
              8 hours ago


















            • $begingroup$
              Thanks! Master who is energetic and always online.;)
              $endgroup$
              – Jerry
              8 hours ago
















            $begingroup$
            Thanks! Master who is energetic and always online.;)
            $endgroup$
            – Jerry
            8 hours ago




            $begingroup$
            Thanks! Master who is energetic and always online.;)
            $endgroup$
            – Jerry
            8 hours ago











            3












            $begingroup$

            p = Length /@ First[lst];
            

            
res = Prepend[
            
  Internal`PartitionRagged[#, p] & /@ Rest[lst],
            
  First[lst]]
            




            {{{1, 2, 3}, {4, 5}, {6, 7, 8, 9}},
            
 {{A, B, C}, {D, E}, {F, G, H, I}},
            
 {{9, 8, 7}, {6, 5}, {4, 3, 2, 1}}}






            share|improve this answer









            $endgroup$


















              3












              $begingroup$

              p = Length /@ First[lst];
              

              
res = Prepend[
              
  Internal`PartitionRagged[#, p] & /@ Rest[lst],
              
  First[lst]]
              




              {{{1, 2, 3}, {4, 5}, {6, 7, 8, 9}},
              
 {{A, B, C}, {D, E}, {F, G, H, I}},
              
 {{9, 8, 7}, {6, 5}, {4, 3, 2, 1}}}






              share|improve this answer









              $endgroup$
















                3












                3








                3





                $begingroup$

                p = Length /@ First[lst];
                

                
res = Prepend[
                
  Internal`PartitionRagged[#, p] & /@ Rest[lst],
                
  First[lst]]
                




                {{{1, 2, 3}, {4, 5}, {6, 7, 8, 9}},
                
 {{A, B, C}, {D, E}, {F, G, H, I}},
                
 {{9, 8, 7}, {6, 5}, {4, 3, 2, 1}}}






                share|improve this answer









                $endgroup$



                p = Length /@ First[lst];
                

                
res = Prepend[
                
  Internal`PartitionRagged[#, p] & /@ Rest[lst],
                
  First[lst]]
                




                {{{1, 2, 3}, {4, 5}, {6, 7, 8, 9}},
                
 {{A, B, C}, {D, E}, {F, G, H, I}},
                
 {{9, 8, 7}, {6, 5}, {4, 3, 2, 1}}}







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 5 hours ago









                Chris DegnenChris Degnen

                21.9k23585




                21.9k23585























                    2












                    $begingroup$

                    The following also works. I removed the brackets 



                    Prepend[Table[FoldPairList[TakeDrop, lst[[i]], Length /@ lst[[1]]], {i, 2, Length[lst]}], lst[[1]]]


                    Also, many thanks to kglr for correcting my code.



                    FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst]





                    share|improve this answer











                    $endgroup$









                    • 1




                      $begingroup$
                      Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                      $endgroup$
                      – kglr
                      4 hours ago










                    • $begingroup$
                      @kglr thank you very much! I do not handle pure functions well.
                      $endgroup$
                      – Titus
                      4 hours ago
















                    2












                    $begingroup$

                    The following also works. I removed the brackets 



                    Prepend[Table[FoldPairList[TakeDrop, lst[[i]], Length /@ lst[[1]]], {i, 2, Length[lst]}], lst[[1]]]


                    Also, many thanks to kglr for correcting my code.



                    FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst]





                    share|improve this answer











                    $endgroup$









                    • 1




                      $begingroup$
                      Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                      $endgroup$
                      – kglr
                      4 hours ago










                    • $begingroup$
                      @kglr thank you very much! I do not handle pure functions well.
                      $endgroup$
                      – Titus
                      4 hours ago














                    2












                    2








                    2





                    $begingroup$

                    The following also works. I removed the brackets 



                    Prepend[Table[FoldPairList[TakeDrop, lst[[i]], Length /@ lst[[1]]], {i, 2, Length[lst]}], lst[[1]]]


                    Also, many thanks to kglr for correcting my code.



                    FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst]





                    share|improve this answer











                    $endgroup$



                    The following also works. I removed the brackets 



                    Prepend[Table[FoldPairList[TakeDrop, lst[[i]], Length /@ lst[[1]]], {i, 2, Length[lst]}], lst[[1]]]


                    Also, many thanks to kglr for correcting my code.



                    FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst]






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 3 hours ago

























                    answered 4 hours ago









                    TitusTitus

                    645417




                    645417








                    • 1




                      $begingroup$
                      Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                      $endgroup$
                      – kglr
                      4 hours ago










                    • $begingroup$
                      @kglr thank you very much! I do not handle pure functions well.
                      $endgroup$
                      – Titus
                      4 hours ago














                    • 1




                      $begingroup$
                      Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                      $endgroup$
                      – kglr
                      4 hours ago










                    • $begingroup$
                      @kglr thank you very much! I do not handle pure functions well.
                      $endgroup$
                      – Titus
                      4 hours ago








                    1




                    1




                    $begingroup$
                    Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                    $endgroup$
                    – kglr
                    4 hours ago




                    $begingroup$
                    Titus, re "Unfortunately, ..." , just move & outside FoldPairList[...], that is, use FoldPairList[TakeDrop, #, Length /@ lst[[1]]] & /@ Rest[lst].
                    $endgroup$
                    – kglr
                    4 hours ago












                    $begingroup$
                    @kglr thank you very much! I do not handle pure functions well.
                    $endgroup$
                    – Titus
                    4 hours ago




                    $begingroup$
                    @kglr thank you very much! I do not handle pure functions well.
                    $endgroup$
                    – Titus
                    4 hours ago


















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