can entangled photons produce an interference pattern?












1












$begingroup$


Suppose you have a laser that emits entangled photons in opposite directions towards a double-slit screen setup as shown below.



enter image description here



The photons are entangled such that if a photon on the left travels through slit A, then its entangled photon goes through slit D. If we do not record any which path information on either side, would we get an interference or clump pattern recorded on the screens beyond the double-slits?






quantum-mechanics quantum-entanglement double-slit-experiment interference coherence







share|cite|improve this question











$endgroup$












  • $begingroup$
    Which degree of freedom is entangled?
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    The degree of freedom that is entangled is path.
    $endgroup$
    – kishdude
    11 hours ago








  • 1




    $begingroup$
    A photon is a wave. It doesn't have a path.
    $endgroup$
    – safesphere
    8 hours ago
















1












$begingroup$


Suppose you have a laser that emits entangled photons in opposite directions towards a double-slit screen setup as shown below.



enter image description here



The photons are entangled such that if a photon on the left travels through slit A, then its entangled photon goes through slit D. If we do not record any which path information on either side, would we get an interference or clump pattern recorded on the screens beyond the double-slits?






quantum-mechanics quantum-entanglement double-slit-experiment interference coherence







share|cite|improve this question











$endgroup$












  • $begingroup$
    Which degree of freedom is entangled?
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    The degree of freedom that is entangled is path.
    $endgroup$
    – kishdude
    11 hours ago








  • 1




    $begingroup$
    A photon is a wave. It doesn't have a path.
    $endgroup$
    – safesphere
    8 hours ago














1












1








1


1



$begingroup$


Suppose you have a laser that emits entangled photons in opposite directions towards a double-slit screen setup as shown below.



enter image description here



The photons are entangled such that if a photon on the left travels through slit A, then its entangled photon goes through slit D. If we do not record any which path information on either side, would we get an interference or clump pattern recorded on the screens beyond the double-slits?






quantum-mechanics quantum-entanglement double-slit-experiment interference coherence







share|cite|improve this question











$endgroup$




Suppose you have a laser that emits entangled photons in opposite directions towards a double-slit screen setup as shown below.



enter image description here



The photons are entangled such that if a photon on the left travels through slit A, then its entangled photon goes through slit D. If we do not record any which path information on either side, would we get an interference or clump pattern recorded on the screens beyond the double-slits?






quantum-mechanics quantum-entanglement double-slit-experiment interference coherence




quantum-mechanics quantum-entanglement double-slit-experiment interference coherence






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 11 hours ago









Norbert Schuch

8,76722438




8,76722438










asked 12 hours ago









kishdudekishdude

171




171












  • $begingroup$
    Which degree of freedom is entangled?
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    The degree of freedom that is entangled is path.
    $endgroup$
    – kishdude
    11 hours ago








  • 1




    $begingroup$
    A photon is a wave. It doesn't have a path.
    $endgroup$
    – safesphere
    8 hours ago


















  • $begingroup$
    Which degree of freedom is entangled?
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    The degree of freedom that is entangled is path.
    $endgroup$
    – kishdude
    11 hours ago








  • 1




    $begingroup$
    A photon is a wave. It doesn't have a path.
    $endgroup$
    – safesphere
    8 hours ago
















$begingroup$
Which degree of freedom is entangled?
$endgroup$
– Norbert Schuch
11 hours ago




$begingroup$
Which degree of freedom is entangled?
$endgroup$
– Norbert Schuch
11 hours ago












$begingroup$
The degree of freedom that is entangled is path.
$endgroup$
– kishdude
11 hours ago






$begingroup$
The degree of freedom that is entangled is path.
$endgroup$
– kishdude
11 hours ago






1




1




$begingroup$
A photon is a wave. It doesn't have a path.
$endgroup$
– safesphere
8 hours ago




$begingroup$
A photon is a wave. It doesn't have a path.
$endgroup$
– safesphere
8 hours ago










1 Answer
1






active

oldest

votes


















2












$begingroup$

You can infer what happens by looking at one of the screens only (say, the left one). In that case, instead of entangled photons, you can as well just look at the left photons. If some of their degrees of freedom (DoF) are entangled with the right photons, it means that the left photons don't have a well-defined value for that DoF (i.e. it is in a mixed state). So the question is whether you still see an interference pattern if some degree of freedom has some randomness.



First, note that every photon just interferes with itself. Thus, the distribution of each individual photon on the screen will follow an interference pattern.



Now if the entangled DoF is the polarization, each photon will follow the same interference pattern, and you will see an interference pattern.



On the other hand, if the entangled DoF is the frequency, the spacing of the pattern will be different for each photon, and thus, you will see the average of interference patterns over the spread of the frequency. For a large enough spread, this will destroy the interference pattern (the spacing is proportional to the wavelength). If you want to know how this changes with the spreading of the frequency, this is a nice exercise problem!






share|cite|improve this answer









$endgroup$













  • $begingroup$
    If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
    $endgroup$
    – Norbert Schuch
    8 hours ago











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "151"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f455287%2fcan-entangled-photons-produce-an-interference-pattern%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

You can infer what happens by looking at one of the screens only (say, the left one). In that case, instead of entangled photons, you can as well just look at the left photons. If some of their degrees of freedom (DoF) are entangled with the right photons, it means that the left photons don't have a well-defined value for that DoF (i.e. it is in a mixed state). So the question is whether you still see an interference pattern if some degree of freedom has some randomness.



First, note that every photon just interferes with itself. Thus, the distribution of each individual photon on the screen will follow an interference pattern.



Now if the entangled DoF is the polarization, each photon will follow the same interference pattern, and you will see an interference pattern.



On the other hand, if the entangled DoF is the frequency, the spacing of the pattern will be different for each photon, and thus, you will see the average of interference patterns over the spread of the frequency. For a large enough spread, this will destroy the interference pattern (the spacing is proportional to the wavelength). If you want to know how this changes with the spreading of the frequency, this is a nice exercise problem!






share|cite|improve this answer









$endgroup$













  • $begingroup$
    If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
    $endgroup$
    – Norbert Schuch
    8 hours ago
















2












$begingroup$

You can infer what happens by looking at one of the screens only (say, the left one). In that case, instead of entangled photons, you can as well just look at the left photons. If some of their degrees of freedom (DoF) are entangled with the right photons, it means that the left photons don't have a well-defined value for that DoF (i.e. it is in a mixed state). So the question is whether you still see an interference pattern if some degree of freedom has some randomness.



First, note that every photon just interferes with itself. Thus, the distribution of each individual photon on the screen will follow an interference pattern.



Now if the entangled DoF is the polarization, each photon will follow the same interference pattern, and you will see an interference pattern.



On the other hand, if the entangled DoF is the frequency, the spacing of the pattern will be different for each photon, and thus, you will see the average of interference patterns over the spread of the frequency. For a large enough spread, this will destroy the interference pattern (the spacing is proportional to the wavelength). If you want to know how this changes with the spreading of the frequency, this is a nice exercise problem!






share|cite|improve this answer









$endgroup$













  • $begingroup$
    If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
    $endgroup$
    – Norbert Schuch
    8 hours ago














2












2








2





$begingroup$

You can infer what happens by looking at one of the screens only (say, the left one). In that case, instead of entangled photons, you can as well just look at the left photons. If some of their degrees of freedom (DoF) are entangled with the right photons, it means that the left photons don't have a well-defined value for that DoF (i.e. it is in a mixed state). So the question is whether you still see an interference pattern if some degree of freedom has some randomness.



First, note that every photon just interferes with itself. Thus, the distribution of each individual photon on the screen will follow an interference pattern.



Now if the entangled DoF is the polarization, each photon will follow the same interference pattern, and you will see an interference pattern.



On the other hand, if the entangled DoF is the frequency, the spacing of the pattern will be different for each photon, and thus, you will see the average of interference patterns over the spread of the frequency. For a large enough spread, this will destroy the interference pattern (the spacing is proportional to the wavelength). If you want to know how this changes with the spreading of the frequency, this is a nice exercise problem!






share|cite|improve this answer









$endgroup$



You can infer what happens by looking at one of the screens only (say, the left one). In that case, instead of entangled photons, you can as well just look at the left photons. If some of their degrees of freedom (DoF) are entangled with the right photons, it means that the left photons don't have a well-defined value for that DoF (i.e. it is in a mixed state). So the question is whether you still see an interference pattern if some degree of freedom has some randomness.



First, note that every photon just interferes with itself. Thus, the distribution of each individual photon on the screen will follow an interference pattern.



Now if the entangled DoF is the polarization, each photon will follow the same interference pattern, and you will see an interference pattern.



On the other hand, if the entangled DoF is the frequency, the spacing of the pattern will be different for each photon, and thus, you will see the average of interference patterns over the spread of the frequency. For a large enough spread, this will destroy the interference pattern (the spacing is proportional to the wavelength). If you want to know how this changes with the spreading of the frequency, this is a nice exercise problem!







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered 11 hours ago









Norbert SchuchNorbert Schuch

8,76722438




8,76722438












  • $begingroup$
    If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
    $endgroup$
    – Norbert Schuch
    8 hours ago


















  • $begingroup$
    If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
    $endgroup$
    – Norbert Schuch
    11 hours ago










  • $begingroup$
    So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
    $endgroup$
    – kishdude
    11 hours ago










  • $begingroup$
    @kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
    $endgroup$
    – Norbert Schuch
    8 hours ago
















$begingroup$
If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
$endgroup$
– kishdude
11 hours ago




$begingroup$
If the DoF is polarization can we still expect that for every photon going through slit A that its entangled pair has to through slit D?
$endgroup$
– kishdude
11 hours ago












$begingroup$
@kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
$endgroup$
– Norbert Schuch
11 hours ago




$begingroup$
@kishdude It doesn't matter. If these are really screens, then you will see an averaged pattern over many photons, so in the end you can treat the two screens completely independently. It only becomes different once you try to correlate the measurements on the two screens.
$endgroup$
– Norbert Schuch
11 hours ago












$begingroup$
So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
$endgroup$
– kishdude
11 hours ago




$begingroup$
So en essence what you are saying is that you will see an interference pattern on both screens since this is what would happen if we take each side independently.
$endgroup$
– kishdude
11 hours ago












$begingroup$
@kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
$endgroup$
– Norbert Schuch
8 hours ago




$begingroup$
@kishdude ... unless the photons are frequency-entangled, with a too big frequency spread. Though even then, I'd guess it still looks different from a single peak distribution.
$endgroup$
– Norbert Schuch
8 hours ago


















draft saved

draft discarded




















































Thanks for contributing an answer to Physics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f455287%2fcan-entangled-photons-produce-an-interference-pattern%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

How to label and detect the document text images

Image
1 $begingroup$ This is what I mean as document text image: I want to label the texts in image as separate blocks and my model should detect these labels as classes. NOTE: This is how the end result should be like: The labels like Block 1, Block 2, Block 3,.. should be Logo, Title, Date,.. Others, etc. Work done: First approach : I tried to implement this method via Object Detection, it didn't work. It didn't even detect any text. Second approach : Then I tried it using PixelLink. As this model is build for scene text detection, it detected each and every text in the image. But this method can detect multiple lines of text if the threshold values are increased. But I have no idea how do I add labels to the text blocks. PIXEL_CLS_WEIGHT_all_ones = 'PIXEL_CLS_WEIGHT_all_ones' PIXEL_C
Read more

Vallis Paradisi

Image
Coordinata: .mw-parser-output .geo-default,.mw-parser-output .geo-dms,.mw-parser-output .geo-dec{display:inline}.mw-parser-output .geo-nondefault,.mw-parser-output .geo-multi-punct{display:none}.mw-parser-output .longitude,.mw-parser-output .latitude{white-space:nowrap} 33°03′S 71°37′W  /  33.05°S 71.617°W  / -33.05; -71.617 Vallis Paradisi Res apud Vicidata repertae: Civitas : Chilia Numerus incolarum : 296 655 Zona horaria : UTC-4 Situs interretialis Nomen officiale : Valparaíso Gubernium Consilium : municipal council of Valparaíso Geographia Superficies : 401 600 000 Metrum quadratum Coniunctiones urbium Urbes gemellae : Ovetum , Badalona , Santa Fe , Ora longa , Sciamhaevum , Quantunia , Callao , Bat Yam , Melaka , Novorossiysk , Busan , Corduba , Odessa , Rosario , Malacca , Barcino , Soteropolis , Franciscopolis (California) , Guanajuato, Silao Tabula aut despectus Despectus in portum sinumque et urbem Vallis Paradisi Vallis Para
Read more

Tabula Rosettana

Image
Tabula multilinguis Rosettana in Museo Britannico ostenditur. Tabula Rosettana, [1] etiam titulo OGIS 90 agnita, est stela decreto de rebus sacris in Aegypto anno 196 a.C.n. lato inscripta. Tabula iuxta Rosettam Aegypti, urbem in delta Nili et ad oram maris Mediterranei iacentem, anno 1799 a milite Francico reperta est. Inventio stelae, linguis duabus scripturisque tribus inscriptae, eruditis Instituti Aegypti statim nuntiata est; ibi enim iussu imperatoris Napoleonis eruditi omnium scientiarum (sub aegide Commissionis Scientiarum et Artium) properaverant cum expeditione Francica. Qua a Britannis mox debellata, tabula Rosettana Londinium missa hodie apud Museum Britannicum iacet. Textus Graecus cito lectus interpretationi textuum Aegyptiorum (in formis hieroglyphica et demotica expressorum) gradatim adiuvit. Denique textum plene interpretatus est Ioannes Franciscus Champollion. Ab opere eruditorum cumulativo coepit hodiernus scripturae hieroglyphicae linguaeque Aegyptiae a
Read more