Sort array by month and year












6















I need help with sorting an array by month and year to display on chart respectively.



Array1: ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'....];
Desired Output : [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];


I also have another array with values for each month according to the array above respectively



Array2: ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
,'Jan19_value'....];

Array2: ['55','2','3','0','21','132'....]; //real values


Now when the monthyear array sorts i want the data in this array to move to a new position according to the monthyear position. like this:



Desired Array1: [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
Desired Array2: [....'Apr18_value','May18_value','Jun18_value','Jul18_value','Jan19_value','Mar19_value'];


So i can pick the data later like this:



var label = array[4];
var value = array2[4];


Any help will be appreciated.










share|improve this question




















  • 10





    What have you tried so far?

    – Anurag Srivastava
    yesterday
















6















I need help with sorting an array by month and year to display on chart respectively.



Array1: ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'....];
Desired Output : [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];


I also have another array with values for each month according to the array above respectively



Array2: ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
,'Jan19_value'....];

Array2: ['55','2','3','0','21','132'....]; //real values


Now when the monthyear array sorts i want the data in this array to move to a new position according to the monthyear position. like this:



Desired Array1: [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
Desired Array2: [....'Apr18_value','May18_value','Jun18_value','Jul18_value','Jan19_value','Mar19_value'];


So i can pick the data later like this:



var label = array[4];
var value = array2[4];


Any help will be appreciated.










share|improve this question




















  • 10





    What have you tried so far?

    – Anurag Srivastava
    yesterday














6












6








6


3






I need help with sorting an array by month and year to display on chart respectively.



Array1: ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'....];
Desired Output : [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];


I also have another array with values for each month according to the array above respectively



Array2: ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
,'Jan19_value'....];

Array2: ['55','2','3','0','21','132'....]; //real values


Now when the monthyear array sorts i want the data in this array to move to a new position according to the monthyear position. like this:



Desired Array1: [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
Desired Array2: [....'Apr18_value','May18_value','Jun18_value','Jul18_value','Jan19_value','Mar19_value'];


So i can pick the data later like this:



var label = array[4];
var value = array2[4];


Any help will be appreciated.










share|improve this question
















I need help with sorting an array by month and year to display on chart respectively.



Array1: ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'....];
Desired Output : [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];


I also have another array with values for each month according to the array above respectively



Array2: ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
,'Jan19_value'....];

Array2: ['55','2','3','0','21','132'....]; //real values


Now when the monthyear array sorts i want the data in this array to move to a new position according to the monthyear position. like this:



Desired Array1: [....'Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
Desired Array2: [....'Apr18_value','May18_value','Jun18_value','Jul18_value','Jan19_value','Mar19_value'];


So i can pick the data later like this:



var label = array[4];
var value = array2[4];


Any help will be appreciated.







javascript html arrays sorting






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edited yesterday









isanae

2,51711437




2,51711437










asked yesterday









Amir QureshiAmir Qureshi

222112




222112








  • 10





    What have you tried so far?

    – Anurag Srivastava
    yesterday














  • 10





    What have you tried so far?

    – Anurag Srivastava
    yesterday








10




10





What have you tried so far?

– Anurag Srivastava
yesterday





What have you tried so far?

– Anurag Srivastava
yesterday












9 Answers
9






active

oldest

votes


















5














You could get the date as sortable string and sort this sting.



For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.



The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the fuinction the string is destructed into month and year parts and replaced by its ISO 8601 representation. The callback of the replacement function takes the matched items, retuns an array with a formatted year and the month of an object with the month names and the related month numbers. Then this array is joined and returned.



The sorting takes place with a comparsion with String#localeCompare.






var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
array3 = ['55', '2', '3', '0', '21', '132'],
indices = Object
.keys(array1)
.sort(function (a, b) {
function getD(i) {
var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
s = array1[i];
return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
}
return getD(a).localeCompare(getD(b));
}),
result = [array1, array3].map(a => indices.map(i => a[i]));

result.forEach(a => console.log(...a));








share|improve this answer


























  • Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

    – prasanth
    yesterday













  • @prasanth, thank you for the hint. i thought, the number is a day.

    – Nina Scholz
    yesterday











  • if i only want to perform this with array 1 and array 3?

    – Amir Qureshi
    yesterday













  • @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

    – Nina Scholz
    yesterday













  • do you want to get new arrays?

    – Nina Scholz
    yesterday



















9














You need change the string for to new Date(dateString) format like



new Date(Month Date Year)


Updated regex Pattern for Both Array



https://regex101.com/r/h1cm1z/2/



Updated Sort Second array based on first array sorting index






var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
var arr2 =['55','2','3','0','21','132'];

function datesort(arr){
return arr.concat().sort((a,b)=>{
a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
return new Date(a) - new Date(b)
})
}

var after_arr1 =new datesort(arr1);
var after_arr2 = arr1.reduce(function(a,b,c){
var ind = after_arr1.indexOf(b);
a[ind] = arr2[c]
return a
},);


console.log(after_arr1.join(','));
console.log(after_arr2.join(','))








share|improve this answer


























  • Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

    – Amir Qureshi
    yesterday











  • i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

    – prasanth
    yesterday











  • Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

    – prasanth
    yesterday













  • i have updated the question please have a look .

    – Amir Qureshi
    yesterday






  • 1





    you need to sort array2 based on array1 sorted index position right?

    – prasanth
    yesterday



















8














To order properly you need to know the order of the months. This is not alphabetical so you can use an array with the order of the months then look them up.



const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']



Is already properly sorted and can be used in conjunction with .indexOf() to get the position of a month.






const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
,'Jan19_value'];

const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

let sortYearMonth = (a, b) => {
let monthA = monthOrder.indexOf(a.slice(0,3))
let yearA = a.slice(3,6)
let monthB = monthOrder.indexOf(b.slice(0,3))
let yearB = b.slice(3,6)
return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
}

let sortedMonths = myArr.sort(sortYearMonth)
let sortedMonths2 = myArr2.sort(sortYearMonth)

console.log(sortedMonths )
console.log(sortedMonths2 )





Update: values in same position



Updated version links the two arrays together then sorts the first while keeping the relative position to the second.



Idea: Link two arrays with a temporary Object then extract the key/value pair using Object.entries. Then sorting the array based on the first value of the pair, which is the value of array1. Then it returns the key/value pair in the right order you can extract the values into two arrays again by using .map()



I added a run with the string based example and the real values examples below




const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

const myArr3 = ['55','2','3','0','21','132'];

const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

let sortYearMonth = (a, b) => {
let monthA = monthOrder.indexOf(a.slice(0, 3))
let yearA = a.slice(3, 6)
let monthB = monthOrder.indexOf(b.slice(0, 3))
let yearB = b.slice(3, 6)
return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
}

function sortByFirst(myArr, myArr2) {
let keyValue = myArr.reduce((links, item, i) => {
links[item] = myArr2[i];
return links
}, {})
let entries = Object.entries(keyValue)
return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
}

let sortedEntries = sortByFirst(myArr, myArr2)
let sortedMonths = sortedEntries.map(i => i[0])
let sortedValues = sortedEntries.map(i => i[1])

let sortedEntries2 = sortByFirst(myArr, myArr3)
let sortedMonths2 = sortedEntries2.map(i => i[0])
let sortedValues2 = sortedEntries2.map(i => i[1])

console.log(sortedMonths)
console.log(sortedValues)

console.log(sortedMonths2)
console.log(sortedValues2)








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    8

















    const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

    //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
    //Can be done easily by using momentjs, darte-fns, but here i will do it natively

    const t = {
    Jan: 1,
    Feb: 2,
    Mar: 3,
    Apr: 4,
    May: 5,
    Jun: 6,
    Jul: 7,
    Aug: 8,
    Sep: 9,
    Oct: 10,
    Nov: 11,
    Dec: 12
    }
    const giveConcatString = (a, t) => {
    const monthPart = a.substr(0, 3)
    const yearPart = a.substr(3)
    return `${yearPart}${t[monthPart]}`
    }
    const sortedArray = input.sort((a, b) => {
    const concatString = giveConcatString(a, t)
    const concatStringB = giveConcatString(b, t)
    return concatString <= concatStringB ? -1 : 1

    })
    console.log(sortedArray)





    This may help you solve this problem. Did it natively.






    share|improve this answer

































      3














      You can try this raw snippet.






      var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
      var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
      // converting to raw date format
      for (i in MY) {
      num = MY[i].match(/d+/g);
      letr = MY[i].match(/[a-zA-Z]+/g);
      MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
      }
      // sorting logic
      var sorted = MY.sort(function(a, b) {
      a = a.split("-");
      b = b.split("-")
      return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
      });
      // converting back to original array after sorting
      res = ;
      for (i in sorted) {
      var a = sorted[i].split('-');
      res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
      }

      console.log(res);








      share|improve this answer































        2














        I used lodash for sorting and substring method to divide date into month and day parts






        const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

        const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

        const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

        console.log(sorted)

        <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>








        share|improve this answer































          2














          let mth = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];

          mth.sort((itemA, itemB)=>{
          let mthAstr = itemA.slice(0,3)+" 01 "+itemA.slice(3,5);
          let mthA = new Date(mthAstr);
          let mthBstr = itemB.slice(0,3)+" 01 "+itemB.slice(3,5);
          let mthB = new Date(mthBstr);
          if (mthA < mthB)
          return -1;
          if (mthA > mthB)
          return 1;
          return 0;
          });





          share|improve this answer































            2














            You can try something like that :



            var Array =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
            Array.sort(function(a, b) {
            a = [a.slice(0,3), ' 20', a.slice(3)].join('');
            b = [b.slice(0,3), ' 20', b.slice(3)].join('')
            return new Date() - new Date(b);
            });

            console.log(Array);





            share|improve this answer










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              0














              I would suggest that your data structure is unfortunate. Working with shared indices makes it much more difficult than a data structure that combines them, such as an array of objects, [{label: 'Mar19', value: 55}, ...].



              If your data is coming from an upstream solution you cannot control, you can still manage this in your own work, converting before you use it. (And if you really have to converting back to pass to others.)



              A common name for a function combining two arrays is zip -- think of it acting like a zipper. This version uses one that takes a function to say how the paired elements should be combined. (Elsewhere such a function might be called zipWith.)



              Here sortArraysByDate calls zip passing a function that turns 'Mar19' and 55 into {label: 'Mar19, value: 55, month: 'Mar', year: 19} using dateFields to extract the month and year from that label, then sorts these using the straightforward dateSort






              const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
              Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

              const dateFields = (d) => ({
              month: d.slice(0, 3),
              year: Number(d.slice(3))
              })

              const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
              (y1 - y2) || (months[m1] - months[m2])

              const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

              const sortArraysByDate = (a1, a2) =>
              zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
              .sort(dateSort)
              .map(({label, value}) => ({label, value}))


              const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
              const Array2 = ['55','2','3','0','21','132']; //real values

              const result = sortArraysByDate(Array1, Array2)

              console.log(result)





              The map call in sortArraysByDate is quite possibly not necessary. Without it, the resulting data includes extra year and month fields; that might not be an issue.



              If you really need those updated arrays in the original format, you can just map the result:



              const newArray1 = result.map(o => o.label)
              const newArray2 = result.map(o => o.value)


              But I would urge you not to do this unless it's absolutely necessary. This structure is really useful. The paired arrays are much less so.



              Also, if you need to combine more than two arrays, you could write a slightly more sophisticated version of zip:



              const zip = (fn, ...as) => as[0].map((_, i) => fn(...as.map(a => a[i])))


              This takes a function on n arguments, and n arrays, and yields a new array containing the result of calling that function respectively on the successive items in each of the arrays.






              share|improve this answer

























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                9 Answers
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                9 Answers
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                active

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                active

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                5














                You could get the date as sortable string and sort this sting.



                For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.



                The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the fuinction the string is destructed into month and year parts and replaced by its ISO 8601 representation. The callback of the replacement function takes the matched items, retuns an array with a formatted year and the month of an object with the month names and the related month numbers. Then this array is joined and returned.



                The sorting takes place with a comparsion with String#localeCompare.






                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));








                share|improve this answer


























                • Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                  – prasanth
                  yesterday













                • @prasanth, thank you for the hint. i thought, the number is a day.

                  – Nina Scholz
                  yesterday











                • if i only want to perform this with array 1 and array 3?

                  – Amir Qureshi
                  yesterday













                • @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                  – Nina Scholz
                  yesterday













                • do you want to get new arrays?

                  – Nina Scholz
                  yesterday
















                5














                You could get the date as sortable string and sort this sting.



                For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.



                The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the fuinction the string is destructed into month and year parts and replaced by its ISO 8601 representation. The callback of the replacement function takes the matched items, retuns an array with a formatted year and the month of an object with the month names and the related month numbers. Then this array is joined and returned.



                The sorting takes place with a comparsion with String#localeCompare.






                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));








                share|improve this answer


























                • Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                  – prasanth
                  yesterday













                • @prasanth, thank you for the hint. i thought, the number is a day.

                  – Nina Scholz
                  yesterday











                • if i only want to perform this with array 1 and array 3?

                  – Amir Qureshi
                  yesterday













                • @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                  – Nina Scholz
                  yesterday













                • do you want to get new arrays?

                  – Nina Scholz
                  yesterday














                5












                5








                5







                You could get the date as sortable string and sort this sting.



                For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.



                The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the fuinction the string is destructed into month and year parts and replaced by its ISO 8601 representation. The callback of the replacement function takes the matched items, retuns an array with a formatted year and the month of an object with the month names and the related month numbers. Then this array is joined and returned.



                The sorting takes place with a comparsion with String#localeCompare.






                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));








                share|improve this answer















                You could get the date as sortable string and sort this sting.



                For getting more than one array sorted by one signature array, you could take sorting with map, where you sort an array of indices, indicating the final sorting and then reassign all arrays with this sorting.



                The getD function returns a formatted string by taking an index of array0 for sorting. Inside of the fuinction the string is destructed into month and year parts and replaced by its ISO 8601 representation. The callback of the replacement function takes the matched items, retuns an array with a formatted year and the month of an object with the month names and the related month numbers. Then this array is joined and returned.



                The sorting takes place with a comparsion with String#localeCompare.






                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));








                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));





                var array1 = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'],
                array2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'],
                array3 = ['55', '2', '3', '0', '21', '132'],
                indices = Object
                .keys(array1)
                .sort(function (a, b) {
                function getD(i) {
                var months = { Jan: '01', Feb: '02', Mar: '03', Apr: '04', May: '05', Jun: '06', Jul: '07', Aug: '08', Sep: '09', Oct: '10', Nov: '11', Dec: '12' },
                s = array1[i];
                return s.replace(/^(...)(.+)$/, (_, m, y) => [y.padStart(4, '0'), months[m]].join('-'));
                }
                return getD(a).localeCompare(getD(b));
                }),
                result = [array1, array3].map(a => indices.map(i => a[i]));

                result.forEach(a => console.log(...a));






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited yesterday

























                answered yesterday









                Nina ScholzNina Scholz

                190k1599173




                190k1599173













                • Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                  – prasanth
                  yesterday













                • @prasanth, thank you for the hint. i thought, the number is a day.

                  – Nina Scholz
                  yesterday











                • if i only want to perform this with array 1 and array 3?

                  – Amir Qureshi
                  yesterday













                • @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                  – Nina Scholz
                  yesterday













                • do you want to get new arrays?

                  – Nina Scholz
                  yesterday



















                • Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                  – prasanth
                  yesterday













                • @prasanth, thank you for the hint. i thought, the number is a day.

                  – Nina Scholz
                  yesterday











                • if i only want to perform this with array 1 and array 3?

                  – Amir Qureshi
                  yesterday













                • @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                  – Nina Scholz
                  yesterday













                • do you want to get new arrays?

                  – Nina Scholz
                  yesterday

















                Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                – prasanth
                yesterday







                Are you sure the sorting is correct format? i think you are sorted MMDD Format its a MMYY

                – prasanth
                yesterday















                @prasanth, thank you for the hint. i thought, the number is a day.

                – Nina Scholz
                yesterday





                @prasanth, thank you for the hint. i thought, the number is a day.

                – Nina Scholz
                yesterday













                if i only want to perform this with array 1 and array 3?

                – Amir Qureshi
                yesterday







                if i only want to perform this with array 1 and array 3?

                – Amir Qureshi
                yesterday















                @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                – Nina Scholz
                yesterday







                @AmirQureshi, then you need oly the wanted array in the array for getting a new sort. please see edit.

                – Nina Scholz
                yesterday















                do you want to get new arrays?

                – Nina Scholz
                yesterday





                do you want to get new arrays?

                – Nina Scholz
                yesterday













                9














                You need change the string for to new Date(dateString) format like



                new Date(Month Date Year)


                Updated regex Pattern for Both Array



                https://regex101.com/r/h1cm1z/2/



                Updated Sort Second array based on first array sorting index






                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))








                share|improve this answer


























                • Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                  – Amir Qureshi
                  yesterday











                • i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                  – prasanth
                  yesterday











                • Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                  – prasanth
                  yesterday













                • i have updated the question please have a look .

                  – Amir Qureshi
                  yesterday






                • 1





                  you need to sort array2 based on array1 sorted index position right?

                  – prasanth
                  yesterday
















                9














                You need change the string for to new Date(dateString) format like



                new Date(Month Date Year)


                Updated regex Pattern for Both Array



                https://regex101.com/r/h1cm1z/2/



                Updated Sort Second array based on first array sorting index






                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))








                share|improve this answer


























                • Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                  – Amir Qureshi
                  yesterday











                • i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                  – prasanth
                  yesterday











                • Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                  – prasanth
                  yesterday













                • i have updated the question please have a look .

                  – Amir Qureshi
                  yesterday






                • 1





                  you need to sort array2 based on array1 sorted index position right?

                  – prasanth
                  yesterday














                9












                9








                9







                You need change the string for to new Date(dateString) format like



                new Date(Month Date Year)


                Updated regex Pattern for Both Array



                https://regex101.com/r/h1cm1z/2/



                Updated Sort Second array based on first array sorting index






                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))








                share|improve this answer















                You need change the string for to new Date(dateString) format like



                new Date(Month Date Year)


                Updated regex Pattern for Both Array



                https://regex101.com/r/h1cm1z/2/



                Updated Sort Second array based on first array sorting index






                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))








                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))





                var arr1 =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                var arr2 =['55','2','3','0','21','132'];

                function datesort(arr){
                return arr.concat().sort((a,b)=>{
                a = a.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                b = b.replace(/(d+)(.*)/g,' 1 $1'); // Month 1 YEAR
                return new Date(a) - new Date(b)
                })
                }

                var after_arr1 =new datesort(arr1);
                var after_arr2 = arr1.reduce(function(a,b,c){
                var ind = after_arr1.indexOf(b);
                a[ind] = arr2[c]
                return a
                },);


                console.log(after_arr1.join(','));
                console.log(after_arr2.join(','))






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited yesterday

























                answered yesterday









                prasanthprasanth

                13.7k21335




                13.7k21335













                • Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                  – Amir Qureshi
                  yesterday











                • i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                  – prasanth
                  yesterday











                • Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                  – prasanth
                  yesterday













                • i have updated the question please have a look .

                  – Amir Qureshi
                  yesterday






                • 1





                  you need to sort array2 based on array1 sorted index position right?

                  – prasanth
                  yesterday



















                • Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                  – Amir Qureshi
                  yesterday











                • i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                  – prasanth
                  yesterday











                • Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                  – prasanth
                  yesterday













                • i have updated the question please have a look .

                  – Amir Qureshi
                  yesterday






                • 1





                  you need to sort array2 based on array1 sorted index position right?

                  – prasanth
                  yesterday

















                Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                – Amir Qureshi
                yesterday





                Thank you , it works as required. What if i have another array with values for each month respectively according to the monthyear array. how do i sort it when the monthyear moves to a new position. do you understand what i am saying?

                – Amir Qureshi
                yesterday













                i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                – prasanth
                yesterday





                i could added the format of date .you could change your array value like this.If you have any new position .Kindly change regex pattern and reproduce the same date format.Or post your new position. i will give the matching pattern

                – prasanth
                yesterday













                Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                – prasanth
                yesterday







                Or where did you get this array? You could format array with in pattern on the place of array create.or with something added delimiters like MM_YY,YY-MM

                – prasanth
                yesterday















                i have updated the question please have a look .

                – Amir Qureshi
                yesterday





                i have updated the question please have a look .

                – Amir Qureshi
                yesterday




                1




                1





                you need to sort array2 based on array1 sorted index position right?

                – prasanth
                yesterday





                you need to sort array2 based on array1 sorted index position right?

                – prasanth
                yesterday











                8














                To order properly you need to know the order of the months. This is not alphabetical so you can use an array with the order of the months then look them up.



                const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']



                Is already properly sorted and can be used in conjunction with .indexOf() to get the position of a month.






                const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                ,'Jan19_value'];

                const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                let sortYearMonth = (a, b) => {
                let monthA = monthOrder.indexOf(a.slice(0,3))
                let yearA = a.slice(3,6)
                let monthB = monthOrder.indexOf(b.slice(0,3))
                let yearB = b.slice(3,6)
                return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                }

                let sortedMonths = myArr.sort(sortYearMonth)
                let sortedMonths2 = myArr2.sort(sortYearMonth)

                console.log(sortedMonths )
                console.log(sortedMonths2 )





                Update: values in same position



                Updated version links the two arrays together then sorts the first while keeping the relative position to the second.



                Idea: Link two arrays with a temporary Object then extract the key/value pair using Object.entries. Then sorting the array based on the first value of the pair, which is the value of array1. Then it returns the key/value pair in the right order you can extract the values into two arrays again by using .map()



                I added a run with the string based example and the real values examples below




                const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                const myArr3 = ['55','2','3','0','21','132'];

                const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                let sortYearMonth = (a, b) => {
                let monthA = monthOrder.indexOf(a.slice(0, 3))
                let yearA = a.slice(3, 6)
                let monthB = monthOrder.indexOf(b.slice(0, 3))
                let yearB = b.slice(3, 6)
                return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                }

                function sortByFirst(myArr, myArr2) {
                let keyValue = myArr.reduce((links, item, i) => {
                links[item] = myArr2[i];
                return links
                }, {})
                let entries = Object.entries(keyValue)
                return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                }

                let sortedEntries = sortByFirst(myArr, myArr2)
                let sortedMonths = sortedEntries.map(i => i[0])
                let sortedValues = sortedEntries.map(i => i[1])

                let sortedEntries2 = sortByFirst(myArr, myArr3)
                let sortedMonths2 = sortedEntries2.map(i => i[0])
                let sortedValues2 = sortedEntries2.map(i => i[1])

                console.log(sortedMonths)
                console.log(sortedValues)

                console.log(sortedMonths2)
                console.log(sortedValues2)








                share|improve this answer






























                  8














                  To order properly you need to know the order of the months. This is not alphabetical so you can use an array with the order of the months then look them up.



                  const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']



                  Is already properly sorted and can be used in conjunction with .indexOf() to get the position of a month.






                  const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                  const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                  ,'Jan19_value'];

                  const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                  let sortYearMonth = (a, b) => {
                  let monthA = monthOrder.indexOf(a.slice(0,3))
                  let yearA = a.slice(3,6)
                  let monthB = monthOrder.indexOf(b.slice(0,3))
                  let yearB = b.slice(3,6)
                  return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                  }

                  let sortedMonths = myArr.sort(sortYearMonth)
                  let sortedMonths2 = myArr2.sort(sortYearMonth)

                  console.log(sortedMonths )
                  console.log(sortedMonths2 )





                  Update: values in same position



                  Updated version links the two arrays together then sorts the first while keeping the relative position to the second.



                  Idea: Link two arrays with a temporary Object then extract the key/value pair using Object.entries. Then sorting the array based on the first value of the pair, which is the value of array1. Then it returns the key/value pair in the right order you can extract the values into two arrays again by using .map()



                  I added a run with the string based example and the real values examples below




                  const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                  const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                  const myArr3 = ['55','2','3','0','21','132'];

                  const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                  let sortYearMonth = (a, b) => {
                  let monthA = monthOrder.indexOf(a.slice(0, 3))
                  let yearA = a.slice(3, 6)
                  let monthB = monthOrder.indexOf(b.slice(0, 3))
                  let yearB = b.slice(3, 6)
                  return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                  }

                  function sortByFirst(myArr, myArr2) {
                  let keyValue = myArr.reduce((links, item, i) => {
                  links[item] = myArr2[i];
                  return links
                  }, {})
                  let entries = Object.entries(keyValue)
                  return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                  }

                  let sortedEntries = sortByFirst(myArr, myArr2)
                  let sortedMonths = sortedEntries.map(i => i[0])
                  let sortedValues = sortedEntries.map(i => i[1])

                  let sortedEntries2 = sortByFirst(myArr, myArr3)
                  let sortedMonths2 = sortedEntries2.map(i => i[0])
                  let sortedValues2 = sortedEntries2.map(i => i[1])

                  console.log(sortedMonths)
                  console.log(sortedValues)

                  console.log(sortedMonths2)
                  console.log(sortedValues2)








                  share|improve this answer




























                    8












                    8








                    8







                    To order properly you need to know the order of the months. This is not alphabetical so you can use an array with the order of the months then look them up.



                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']



                    Is already properly sorted and can be used in conjunction with .indexOf() to get the position of a month.






                    const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                    const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                    ,'Jan19_value'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0,3))
                    let yearA = a.slice(3,6)
                    let monthB = monthOrder.indexOf(b.slice(0,3))
                    let yearB = b.slice(3,6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    let sortedMonths = myArr.sort(sortYearMonth)
                    let sortedMonths2 = myArr2.sort(sortYearMonth)

                    console.log(sortedMonths )
                    console.log(sortedMonths2 )





                    Update: values in same position



                    Updated version links the two arrays together then sorts the first while keeping the relative position to the second.



                    Idea: Link two arrays with a temporary Object then extract the key/value pair using Object.entries. Then sorting the array based on the first value of the pair, which is the value of array1. Then it returns the key/value pair in the right order you can extract the values into two arrays again by using .map()



                    I added a run with the string based example and the real values examples below




                    const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                    const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                    const myArr3 = ['55','2','3','0','21','132'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0, 3))
                    let yearA = a.slice(3, 6)
                    let monthB = monthOrder.indexOf(b.slice(0, 3))
                    let yearB = b.slice(3, 6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    function sortByFirst(myArr, myArr2) {
                    let keyValue = myArr.reduce((links, item, i) => {
                    links[item] = myArr2[i];
                    return links
                    }, {})
                    let entries = Object.entries(keyValue)
                    return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                    }

                    let sortedEntries = sortByFirst(myArr, myArr2)
                    let sortedMonths = sortedEntries.map(i => i[0])
                    let sortedValues = sortedEntries.map(i => i[1])

                    let sortedEntries2 = sortByFirst(myArr, myArr3)
                    let sortedMonths2 = sortedEntries2.map(i => i[0])
                    let sortedValues2 = sortedEntries2.map(i => i[1])

                    console.log(sortedMonths)
                    console.log(sortedValues)

                    console.log(sortedMonths2)
                    console.log(sortedValues2)








                    share|improve this answer















                    To order properly you need to know the order of the months. This is not alphabetical so you can use an array with the order of the months then look them up.



                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']



                    Is already properly sorted and can be used in conjunction with .indexOf() to get the position of a month.






                    const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                    const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                    ,'Jan19_value'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0,3))
                    let yearA = a.slice(3,6)
                    let monthB = monthOrder.indexOf(b.slice(0,3))
                    let yearB = b.slice(3,6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    let sortedMonths = myArr.sort(sortYearMonth)
                    let sortedMonths2 = myArr2.sort(sortYearMonth)

                    console.log(sortedMonths )
                    console.log(sortedMonths2 )





                    Update: values in same position



                    Updated version links the two arrays together then sorts the first while keeping the relative position to the second.



                    Idea: Link two arrays with a temporary Object then extract the key/value pair using Object.entries. Then sorting the array based on the first value of the pair, which is the value of array1. Then it returns the key/value pair in the right order you can extract the values into two arrays again by using .map()



                    I added a run with the string based example and the real values examples below




                    const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                    const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                    const myArr3 = ['55','2','3','0','21','132'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0, 3))
                    let yearA = a.slice(3, 6)
                    let monthB = monthOrder.indexOf(b.slice(0, 3))
                    let yearB = b.slice(3, 6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    function sortByFirst(myArr, myArr2) {
                    let keyValue = myArr.reduce((links, item, i) => {
                    links[item] = myArr2[i];
                    return links
                    }, {})
                    let entries = Object.entries(keyValue)
                    return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                    }

                    let sortedEntries = sortByFirst(myArr, myArr2)
                    let sortedMonths = sortedEntries.map(i => i[0])
                    let sortedValues = sortedEntries.map(i => i[1])

                    let sortedEntries2 = sortByFirst(myArr, myArr3)
                    let sortedMonths2 = sortedEntries2.map(i => i[0])
                    let sortedValues2 = sortedEntries2.map(i => i[1])

                    console.log(sortedMonths)
                    console.log(sortedValues)

                    console.log(sortedMonths2)
                    console.log(sortedValues2)








                    const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                    const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                    ,'Jan19_value'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0,3))
                    let yearA = a.slice(3,6)
                    let monthB = monthOrder.indexOf(b.slice(0,3))
                    let yearB = b.slice(3,6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    let sortedMonths = myArr.sort(sortYearMonth)
                    let sortedMonths2 = myArr2.sort(sortYearMonth)

                    console.log(sortedMonths )
                    console.log(sortedMonths2 )





                    const myArr =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                    const myArr2 = ['Mar19_value','Apr18_value','Jun18_value','Jul18_value','May18_value'
                    ,'Jan19_value'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0,3))
                    let yearA = a.slice(3,6)
                    let monthB = monthOrder.indexOf(b.slice(0,3))
                    let yearB = b.slice(3,6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    let sortedMonths = myArr.sort(sortYearMonth)
                    let sortedMonths2 = myArr2.sort(sortYearMonth)

                    console.log(sortedMonths )
                    console.log(sortedMonths2 )





                    const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                    const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                    const myArr3 = ['55','2','3','0','21','132'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0, 3))
                    let yearA = a.slice(3, 6)
                    let monthB = monthOrder.indexOf(b.slice(0, 3))
                    let yearB = b.slice(3, 6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    function sortByFirst(myArr, myArr2) {
                    let keyValue = myArr.reduce((links, item, i) => {
                    links[item] = myArr2[i];
                    return links
                    }, {})
                    let entries = Object.entries(keyValue)
                    return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                    }

                    let sortedEntries = sortByFirst(myArr, myArr2)
                    let sortedMonths = sortedEntries.map(i => i[0])
                    let sortedValues = sortedEntries.map(i => i[1])

                    let sortedEntries2 = sortByFirst(myArr, myArr3)
                    let sortedMonths2 = sortedEntries2.map(i => i[0])
                    let sortedValues2 = sortedEntries2.map(i => i[1])

                    console.log(sortedMonths)
                    console.log(sortedValues)

                    console.log(sortedMonths2)
                    console.log(sortedValues2)





                    const myArr = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                    const myArr2 = ['Mar19_value', 'Apr18_value', 'Jun18_value', 'Jul18_value', 'May18_value', 'Jan19_value'];

                    const myArr3 = ['55','2','3','0','21','132'];

                    const monthOrder = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']

                    let sortYearMonth = (a, b) => {
                    let monthA = monthOrder.indexOf(a.slice(0, 3))
                    let yearA = a.slice(3, 6)
                    let monthB = monthOrder.indexOf(b.slice(0, 3))
                    let yearB = b.slice(3, 6)
                    return (`${yearA}-${monthA}` < `${yearB}-${monthB}`) ? -1 : (`${yearA}-${monthA}` > `${yearB}-${monthB}`) ? 1 : 0
                    }

                    function sortByFirst(myArr, myArr2) {
                    let keyValue = myArr.reduce((links, item, i) => {
                    links[item] = myArr2[i];
                    return links
                    }, {})
                    let entries = Object.entries(keyValue)
                    return entries.sort((a, b) => sortYearMonth(a[0], b[0]))
                    }

                    let sortedEntries = sortByFirst(myArr, myArr2)
                    let sortedMonths = sortedEntries.map(i => i[0])
                    let sortedValues = sortedEntries.map(i => i[1])

                    let sortedEntries2 = sortByFirst(myArr, myArr3)
                    let sortedMonths2 = sortedEntries2.map(i => i[0])
                    let sortedValues2 = sortedEntries2.map(i => i[1])

                    console.log(sortedMonths)
                    console.log(sortedValues)

                    console.log(sortedMonths2)
                    console.log(sortedValues2)






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited yesterday

























                    answered yesterday









                    Jordan MaduroJordan Maduro

                    47827




                    47827























                        8

















                        const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                        //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                        //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                        const t = {
                        Jan: 1,
                        Feb: 2,
                        Mar: 3,
                        Apr: 4,
                        May: 5,
                        Jun: 6,
                        Jul: 7,
                        Aug: 8,
                        Sep: 9,
                        Oct: 10,
                        Nov: 11,
                        Dec: 12
                        }
                        const giveConcatString = (a, t) => {
                        const monthPart = a.substr(0, 3)
                        const yearPart = a.substr(3)
                        return `${yearPart}${t[monthPart]}`
                        }
                        const sortedArray = input.sort((a, b) => {
                        const concatString = giveConcatString(a, t)
                        const concatStringB = giveConcatString(b, t)
                        return concatString <= concatStringB ? -1 : 1

                        })
                        console.log(sortedArray)





                        This may help you solve this problem. Did it natively.






                        share|improve this answer






























                          8

















                          const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                          //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                          //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                          const t = {
                          Jan: 1,
                          Feb: 2,
                          Mar: 3,
                          Apr: 4,
                          May: 5,
                          Jun: 6,
                          Jul: 7,
                          Aug: 8,
                          Sep: 9,
                          Oct: 10,
                          Nov: 11,
                          Dec: 12
                          }
                          const giveConcatString = (a, t) => {
                          const monthPart = a.substr(0, 3)
                          const yearPart = a.substr(3)
                          return `${yearPart}${t[monthPart]}`
                          }
                          const sortedArray = input.sort((a, b) => {
                          const concatString = giveConcatString(a, t)
                          const concatStringB = giveConcatString(b, t)
                          return concatString <= concatStringB ? -1 : 1

                          })
                          console.log(sortedArray)





                          This may help you solve this problem. Did it natively.






                          share|improve this answer




























                            8












                            8








                            8










                            const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                            //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                            //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                            const t = {
                            Jan: 1,
                            Feb: 2,
                            Mar: 3,
                            Apr: 4,
                            May: 5,
                            Jun: 6,
                            Jul: 7,
                            Aug: 8,
                            Sep: 9,
                            Oct: 10,
                            Nov: 11,
                            Dec: 12
                            }
                            const giveConcatString = (a, t) => {
                            const monthPart = a.substr(0, 3)
                            const yearPart = a.substr(3)
                            return `${yearPart}${t[monthPart]}`
                            }
                            const sortedArray = input.sort((a, b) => {
                            const concatString = giveConcatString(a, t)
                            const concatStringB = giveConcatString(b, t)
                            return concatString <= concatStringB ? -1 : 1

                            })
                            console.log(sortedArray)





                            This may help you solve this problem. Did it natively.






                            share|improve this answer


















                            const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                            //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                            //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                            const t = {
                            Jan: 1,
                            Feb: 2,
                            Mar: 3,
                            Apr: 4,
                            May: 5,
                            Jun: 6,
                            Jul: 7,
                            Aug: 8,
                            Sep: 9,
                            Oct: 10,
                            Nov: 11,
                            Dec: 12
                            }
                            const giveConcatString = (a, t) => {
                            const monthPart = a.substr(0, 3)
                            const yearPart = a.substr(3)
                            return `${yearPart}${t[monthPart]}`
                            }
                            const sortedArray = input.sort((a, b) => {
                            const concatString = giveConcatString(a, t)
                            const concatStringB = giveConcatString(b, t)
                            return concatString <= concatStringB ? -1 : 1

                            })
                            console.log(sortedArray)





                            This may help you solve this problem. Did it natively.






                            const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                            //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                            //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                            const t = {
                            Jan: 1,
                            Feb: 2,
                            Mar: 3,
                            Apr: 4,
                            May: 5,
                            Jun: 6,
                            Jul: 7,
                            Aug: 8,
                            Sep: 9,
                            Oct: 10,
                            Nov: 11,
                            Dec: 12
                            }
                            const giveConcatString = (a, t) => {
                            const monthPart = a.substr(0, 3)
                            const yearPart = a.substr(3)
                            return `${yearPart}${t[monthPart]}`
                            }
                            const sortedArray = input.sort((a, b) => {
                            const concatString = giveConcatString(a, t)
                            const concatStringB = giveConcatString(b, t)
                            return concatString <= concatStringB ? -1 : 1

                            })
                            console.log(sortedArray)





                            const input = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];

                            //const output : ['Apr18','May18','Jun18','Jul18','Jan19','Mar19'];
                            //Can be done easily by using momentjs, darte-fns, but here i will do it natively

                            const t = {
                            Jan: 1,
                            Feb: 2,
                            Mar: 3,
                            Apr: 4,
                            May: 5,
                            Jun: 6,
                            Jul: 7,
                            Aug: 8,
                            Sep: 9,
                            Oct: 10,
                            Nov: 11,
                            Dec: 12
                            }
                            const giveConcatString = (a, t) => {
                            const monthPart = a.substr(0, 3)
                            const yearPart = a.substr(3)
                            return `${yearPart}${t[monthPart]}`
                            }
                            const sortedArray = input.sort((a, b) => {
                            const concatString = giveConcatString(a, t)
                            const concatStringB = giveConcatString(b, t)
                            return concatString <= concatStringB ? -1 : 1

                            })
                            console.log(sortedArray)






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited yesterday

























                            answered yesterday









                            simbathesailorsimbathesailor

                            2,23411018




                            2,23411018























                                3














                                You can try this raw snippet.






                                var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                // converting to raw date format
                                for (i in MY) {
                                num = MY[i].match(/d+/g);
                                letr = MY[i].match(/[a-zA-Z]+/g);
                                MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                }
                                // sorting logic
                                var sorted = MY.sort(function(a, b) {
                                a = a.split("-");
                                b = b.split("-")
                                return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                });
                                // converting back to original array after sorting
                                res = ;
                                for (i in sorted) {
                                var a = sorted[i].split('-');
                                res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                }

                                console.log(res);








                                share|improve this answer




























                                  3














                                  You can try this raw snippet.






                                  var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                  var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                  // converting to raw date format
                                  for (i in MY) {
                                  num = MY[i].match(/d+/g);
                                  letr = MY[i].match(/[a-zA-Z]+/g);
                                  MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                  }
                                  // sorting logic
                                  var sorted = MY.sort(function(a, b) {
                                  a = a.split("-");
                                  b = b.split("-")
                                  return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                  });
                                  // converting back to original array after sorting
                                  res = ;
                                  for (i in sorted) {
                                  var a = sorted[i].split('-');
                                  res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                  }

                                  console.log(res);








                                  share|improve this answer


























                                    3












                                    3








                                    3







                                    You can try this raw snippet.






                                    var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                    var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                    // converting to raw date format
                                    for (i in MY) {
                                    num = MY[i].match(/d+/g);
                                    letr = MY[i].match(/[a-zA-Z]+/g);
                                    MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                    }
                                    // sorting logic
                                    var sorted = MY.sort(function(a, b) {
                                    a = a.split("-");
                                    b = b.split("-")
                                    return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                    });
                                    // converting back to original array after sorting
                                    res = ;
                                    for (i in sorted) {
                                    var a = sorted[i].split('-');
                                    res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                    }

                                    console.log(res);








                                    share|improve this answer













                                    You can try this raw snippet.






                                    var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                    var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                    // converting to raw date format
                                    for (i in MY) {
                                    num = MY[i].match(/d+/g);
                                    letr = MY[i].match(/[a-zA-Z]+/g);
                                    MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                    }
                                    // sorting logic
                                    var sorted = MY.sort(function(a, b) {
                                    a = a.split("-");
                                    b = b.split("-")
                                    return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                    });
                                    // converting back to original array after sorting
                                    res = ;
                                    for (i in sorted) {
                                    var a = sorted[i].split('-');
                                    res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                    }

                                    console.log(res);








                                    var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                    var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                    // converting to raw date format
                                    for (i in MY) {
                                    num = MY[i].match(/d+/g);
                                    letr = MY[i].match(/[a-zA-Z]+/g);
                                    MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                    }
                                    // sorting logic
                                    var sorted = MY.sort(function(a, b) {
                                    a = a.split("-");
                                    b = b.split("-")
                                    return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                    });
                                    // converting back to original array after sorting
                                    res = ;
                                    for (i in sorted) {
                                    var a = sorted[i].split('-');
                                    res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                    }

                                    console.log(res);





                                    var MY = ['Mar19', 'Apr18', 'Jun18', 'Jul18', 'May18', 'Jan19'];
                                    var s = "JanFebMarAprMayJunJulAugSepOctNovDec";
                                    // converting to raw date format
                                    for (i in MY) {
                                    num = MY[i].match(/d+/g);
                                    letr = MY[i].match(/[a-zA-Z]+/g);
                                    MY[i] = (s.indexOf(letr) / 3 + 1) + '-' + '20' + num;
                                    }
                                    // sorting logic
                                    var sorted = MY.sort(function(a, b) {
                                    a = a.split("-");
                                    b = b.split("-")
                                    return new Date(a[1], a[0], 1) - new Date(b[1], b[0], 1)
                                    });
                                    // converting back to original array after sorting
                                    res = ;
                                    for (i in sorted) {
                                    var a = sorted[i].split('-');
                                    res[i] = (s.substr((parseInt(a[0]) - 1) * 3, 3)) + '-' + a[1].substr(2, 2);
                                    }

                                    console.log(res);






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered yesterday









                                    Rahul MeshramRahul Meshram

                                    7,32041942




                                    7,32041942























                                        2














                                        I used lodash for sorting and substring method to divide date into month and day parts






                                        const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                        const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                        const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                        console.log(sorted)

                                        <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>








                                        share|improve this answer




























                                          2














                                          I used lodash for sorting and substring method to divide date into month and day parts






                                          const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                          const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                          const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                          console.log(sorted)

                                          <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>








                                          share|improve this answer


























                                            2












                                            2








                                            2







                                            I used lodash for sorting and substring method to divide date into month and day parts






                                            const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                            const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                            const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                            console.log(sorted)

                                            <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>








                                            share|improve this answer













                                            I used lodash for sorting and substring method to divide date into month and day parts






                                            const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                            const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                            const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                            console.log(sorted)

                                            <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>








                                            const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                            const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                            const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                            console.log(sorted)

                                            <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>





                                            const data = ['Mar20','Mar21', 'Mar01', 'Mar19','Apr18','Jun18','Jul18','May18','Jan19']

                                            const monthMap = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"];

                                            const sorted = _.sortBy(data, date => monthMap.indexOf(date.substring(0,3)), date => date.substring(3,5))

                                            console.log(sorted)

                                            <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>






                                            share|improve this answer












                                            share|improve this answer



                                            share|improve this answer










                                            answered yesterday









                                            Krzysztof KrzeszewskiKrzysztof Krzeszewski

                                            7641110




                                            7641110























                                                2














                                                let mth = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];

                                                mth.sort((itemA, itemB)=>{
                                                let mthAstr = itemA.slice(0,3)+" 01 "+itemA.slice(3,5);
                                                let mthA = new Date(mthAstr);
                                                let mthBstr = itemB.slice(0,3)+" 01 "+itemB.slice(3,5);
                                                let mthB = new Date(mthBstr);
                                                if (mthA < mthB)
                                                return -1;
                                                if (mthA > mthB)
                                                return 1;
                                                return 0;
                                                });





                                                share|improve this answer




























                                                  2














                                                  let mth = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];

                                                  mth.sort((itemA, itemB)=>{
                                                  let mthAstr = itemA.slice(0,3)+" 01 "+itemA.slice(3,5);
                                                  let mthA = new Date(mthAstr);
                                                  let mthBstr = itemB.slice(0,3)+" 01 "+itemB.slice(3,5);
                                                  let mthB = new Date(mthBstr);
                                                  if (mthA < mthB)
                                                  return -1;
                                                  if (mthA > mthB)
                                                  return 1;
                                                  return 0;
                                                  });





                                                  share|improve this answer


























                                                    2












                                                    2








                                                    2







                                                    let mth = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];

                                                    mth.sort((itemA, itemB)=>{
                                                    let mthAstr = itemA.slice(0,3)+" 01 "+itemA.slice(3,5);
                                                    let mthA = new Date(mthAstr);
                                                    let mthBstr = itemB.slice(0,3)+" 01 "+itemB.slice(3,5);
                                                    let mthB = new Date(mthBstr);
                                                    if (mthA < mthB)
                                                    return -1;
                                                    if (mthA > mthB)
                                                    return 1;
                                                    return 0;
                                                    });





                                                    share|improve this answer













                                                    let mth = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];

                                                    mth.sort((itemA, itemB)=>{
                                                    let mthAstr = itemA.slice(0,3)+" 01 "+itemA.slice(3,5);
                                                    let mthA = new Date(mthAstr);
                                                    let mthBstr = itemB.slice(0,3)+" 01 "+itemB.slice(3,5);
                                                    let mthB = new Date(mthBstr);
                                                    if (mthA < mthB)
                                                    return -1;
                                                    if (mthA > mthB)
                                                    return 1;
                                                    return 0;
                                                    });






                                                    share|improve this answer












                                                    share|improve this answer



                                                    share|improve this answer










                                                    answered yesterday









                                                    EdperEdper

                                                    7,21711842




                                                    7,21711842























                                                        2














                                                        You can try something like that :



                                                        var Array =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                        Array.sort(function(a, b) {
                                                        a = [a.slice(0,3), ' 20', a.slice(3)].join('');
                                                        b = [b.slice(0,3), ' 20', b.slice(3)].join('')
                                                        return new Date() - new Date(b);
                                                        });

                                                        console.log(Array);





                                                        share|improve this answer










                                                        New contributor




                                                        KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                        Check out our Code of Conduct.

























                                                          2














                                                          You can try something like that :



                                                          var Array =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                          Array.sort(function(a, b) {
                                                          a = [a.slice(0,3), ' 20', a.slice(3)].join('');
                                                          b = [b.slice(0,3), ' 20', b.slice(3)].join('')
                                                          return new Date() - new Date(b);
                                                          });

                                                          console.log(Array);





                                                          share|improve this answer










                                                          New contributor




                                                          KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                          Check out our Code of Conduct.























                                                            2












                                                            2








                                                            2







                                                            You can try something like that :



                                                            var Array =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                            Array.sort(function(a, b) {
                                                            a = [a.slice(0,3), ' 20', a.slice(3)].join('');
                                                            b = [b.slice(0,3), ' 20', b.slice(3)].join('')
                                                            return new Date() - new Date(b);
                                                            });

                                                            console.log(Array);





                                                            share|improve this answer










                                                            New contributor




                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.










                                                            You can try something like that :



                                                            var Array =  ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                            Array.sort(function(a, b) {
                                                            a = [a.slice(0,3), ' 20', a.slice(3)].join('');
                                                            b = [b.slice(0,3), ' 20', b.slice(3)].join('')
                                                            return new Date() - new Date(b);
                                                            });

                                                            console.log(Array);






                                                            share|improve this answer










                                                            New contributor




                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.









                                                            share|improve this answer



                                                            share|improve this answer








                                                            edited yesterday









                                                            Enzo BLANCHON

                                                            653216




                                                            653216






                                                            New contributor




                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.









                                                            answered yesterday









                                                            KAMLESH NEHRAKAMLESH NEHRA

                                                            212




                                                            212




                                                            New contributor




                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.





                                                            New contributor





                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.






                                                            KAMLESH NEHRA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                            Check out our Code of Conduct.























                                                                0














                                                                I would suggest that your data structure is unfortunate. Working with shared indices makes it much more difficult than a data structure that combines them, such as an array of objects, [{label: 'Mar19', value: 55}, ...].



                                                                If your data is coming from an upstream solution you cannot control, you can still manage this in your own work, converting before you use it. (And if you really have to converting back to pass to others.)



                                                                A common name for a function combining two arrays is zip -- think of it acting like a zipper. This version uses one that takes a function to say how the paired elements should be combined. (Elsewhere such a function might be called zipWith.)



                                                                Here sortArraysByDate calls zip passing a function that turns 'Mar19' and 55 into {label: 'Mar19, value: 55, month: 'Mar', year: 19} using dateFields to extract the month and year from that label, then sorts these using the straightforward dateSort






                                                                const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                const dateFields = (d) => ({
                                                                month: d.slice(0, 3),
                                                                year: Number(d.slice(3))
                                                                })

                                                                const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                (y1 - y2) || (months[m1] - months[m2])

                                                                const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                const sortArraysByDate = (a1, a2) =>
                                                                zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                .sort(dateSort)
                                                                .map(({label, value}) => ({label, value}))


                                                                const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                const Array2 = ['55','2','3','0','21','132']; //real values

                                                                const result = sortArraysByDate(Array1, Array2)

                                                                console.log(result)





                                                                The map call in sortArraysByDate is quite possibly not necessary. Without it, the resulting data includes extra year and month fields; that might not be an issue.



                                                                If you really need those updated arrays in the original format, you can just map the result:



                                                                const newArray1 = result.map(o => o.label)
                                                                const newArray2 = result.map(o => o.value)


                                                                But I would urge you not to do this unless it's absolutely necessary. This structure is really useful. The paired arrays are much less so.



                                                                Also, if you need to combine more than two arrays, you could write a slightly more sophisticated version of zip:



                                                                const zip = (fn, ...as) => as[0].map((_, i) => fn(...as.map(a => a[i])))


                                                                This takes a function on n arguments, and n arrays, and yields a new array containing the result of calling that function respectively on the successive items in each of the arrays.






                                                                share|improve this answer






























                                                                  0














                                                                  I would suggest that your data structure is unfortunate. Working with shared indices makes it much more difficult than a data structure that combines them, such as an array of objects, [{label: 'Mar19', value: 55}, ...].



                                                                  If your data is coming from an upstream solution you cannot control, you can still manage this in your own work, converting before you use it. (And if you really have to converting back to pass to others.)



                                                                  A common name for a function combining two arrays is zip -- think of it acting like a zipper. This version uses one that takes a function to say how the paired elements should be combined. (Elsewhere such a function might be called zipWith.)



                                                                  Here sortArraysByDate calls zip passing a function that turns 'Mar19' and 55 into {label: 'Mar19, value: 55, month: 'Mar', year: 19} using dateFields to extract the month and year from that label, then sorts these using the straightforward dateSort






                                                                  const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                  Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                  const dateFields = (d) => ({
                                                                  month: d.slice(0, 3),
                                                                  year: Number(d.slice(3))
                                                                  })

                                                                  const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                  (y1 - y2) || (months[m1] - months[m2])

                                                                  const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                  const sortArraysByDate = (a1, a2) =>
                                                                  zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                  .sort(dateSort)
                                                                  .map(({label, value}) => ({label, value}))


                                                                  const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                  const Array2 = ['55','2','3','0','21','132']; //real values

                                                                  const result = sortArraysByDate(Array1, Array2)

                                                                  console.log(result)





                                                                  The map call in sortArraysByDate is quite possibly not necessary. Without it, the resulting data includes extra year and month fields; that might not be an issue.



                                                                  If you really need those updated arrays in the original format, you can just map the result:



                                                                  const newArray1 = result.map(o => o.label)
                                                                  const newArray2 = result.map(o => o.value)


                                                                  But I would urge you not to do this unless it's absolutely necessary. This structure is really useful. The paired arrays are much less so.



                                                                  Also, if you need to combine more than two arrays, you could write a slightly more sophisticated version of zip:



                                                                  const zip = (fn, ...as) => as[0].map((_, i) => fn(...as.map(a => a[i])))


                                                                  This takes a function on n arguments, and n arrays, and yields a new array containing the result of calling that function respectively on the successive items in each of the arrays.






                                                                  share|improve this answer




























                                                                    0












                                                                    0








                                                                    0







                                                                    I would suggest that your data structure is unfortunate. Working with shared indices makes it much more difficult than a data structure that combines them, such as an array of objects, [{label: 'Mar19', value: 55}, ...].



                                                                    If your data is coming from an upstream solution you cannot control, you can still manage this in your own work, converting before you use it. (And if you really have to converting back to pass to others.)



                                                                    A common name for a function combining two arrays is zip -- think of it acting like a zipper. This version uses one that takes a function to say how the paired elements should be combined. (Elsewhere such a function might be called zipWith.)



                                                                    Here sortArraysByDate calls zip passing a function that turns 'Mar19' and 55 into {label: 'Mar19, value: 55, month: 'Mar', year: 19} using dateFields to extract the month and year from that label, then sorts these using the straightforward dateSort






                                                                    const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                    Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                    const dateFields = (d) => ({
                                                                    month: d.slice(0, 3),
                                                                    year: Number(d.slice(3))
                                                                    })

                                                                    const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                    (y1 - y2) || (months[m1] - months[m2])

                                                                    const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                    const sortArraysByDate = (a1, a2) =>
                                                                    zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                    .sort(dateSort)
                                                                    .map(({label, value}) => ({label, value}))


                                                                    const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                    const Array2 = ['55','2','3','0','21','132']; //real values

                                                                    const result = sortArraysByDate(Array1, Array2)

                                                                    console.log(result)





                                                                    The map call in sortArraysByDate is quite possibly not necessary. Without it, the resulting data includes extra year and month fields; that might not be an issue.



                                                                    If you really need those updated arrays in the original format, you can just map the result:



                                                                    const newArray1 = result.map(o => o.label)
                                                                    const newArray2 = result.map(o => o.value)


                                                                    But I would urge you not to do this unless it's absolutely necessary. This structure is really useful. The paired arrays are much less so.



                                                                    Also, if you need to combine more than two arrays, you could write a slightly more sophisticated version of zip:



                                                                    const zip = (fn, ...as) => as[0].map((_, i) => fn(...as.map(a => a[i])))


                                                                    This takes a function on n arguments, and n arrays, and yields a new array containing the result of calling that function respectively on the successive items in each of the arrays.






                                                                    share|improve this answer















                                                                    I would suggest that your data structure is unfortunate. Working with shared indices makes it much more difficult than a data structure that combines them, such as an array of objects, [{label: 'Mar19', value: 55}, ...].



                                                                    If your data is coming from an upstream solution you cannot control, you can still manage this in your own work, converting before you use it. (And if you really have to converting back to pass to others.)



                                                                    A common name for a function combining two arrays is zip -- think of it acting like a zipper. This version uses one that takes a function to say how the paired elements should be combined. (Elsewhere such a function might be called zipWith.)



                                                                    Here sortArraysByDate calls zip passing a function that turns 'Mar19' and 55 into {label: 'Mar19, value: 55, month: 'Mar', year: 19} using dateFields to extract the month and year from that label, then sorts these using the straightforward dateSort






                                                                    const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                    Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                    const dateFields = (d) => ({
                                                                    month: d.slice(0, 3),
                                                                    year: Number(d.slice(3))
                                                                    })

                                                                    const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                    (y1 - y2) || (months[m1] - months[m2])

                                                                    const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                    const sortArraysByDate = (a1, a2) =>
                                                                    zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                    .sort(dateSort)
                                                                    .map(({label, value}) => ({label, value}))


                                                                    const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                    const Array2 = ['55','2','3','0','21','132']; //real values

                                                                    const result = sortArraysByDate(Array1, Array2)

                                                                    console.log(result)





                                                                    The map call in sortArraysByDate is quite possibly not necessary. Without it, the resulting data includes extra year and month fields; that might not be an issue.



                                                                    If you really need those updated arrays in the original format, you can just map the result:



                                                                    const newArray1 = result.map(o => o.label)
                                                                    const newArray2 = result.map(o => o.value)


                                                                    But I would urge you not to do this unless it's absolutely necessary. This structure is really useful. The paired arrays are much less so.



                                                                    Also, if you need to combine more than two arrays, you could write a slightly more sophisticated version of zip:



                                                                    const zip = (fn, ...as) => as[0].map((_, i) => fn(...as.map(a => a[i])))


                                                                    This takes a function on n arguments, and n arrays, and yields a new array containing the result of calling that function respectively on the successive items in each of the arrays.






                                                                    const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                    Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                    const dateFields = (d) => ({
                                                                    month: d.slice(0, 3),
                                                                    year: Number(d.slice(3))
                                                                    })

                                                                    const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                    (y1 - y2) || (months[m1] - months[m2])

                                                                    const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                    const sortArraysByDate = (a1, a2) =>
                                                                    zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                    .sort(dateSort)
                                                                    .map(({label, value}) => ({label, value}))


                                                                    const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                    const Array2 = ['55','2','3','0','21','132']; //real values

                                                                    const result = sortArraysByDate(Array1, Array2)

                                                                    console.log(result)





                                                                    const months = {Jan: 1, Feb: 2, Mar: 3, Apr: 4,  May: 5,  Jun: 6,
                                                                    Jul: 7, Aug: 8, Sep: 9, Oct: 10, Nov: 11, Dec: 12}

                                                                    const dateFields = (d) => ({
                                                                    month: d.slice(0, 3),
                                                                    year: Number(d.slice(3))
                                                                    })

                                                                    const dateSort = ({month: m1, year: y1}, {month: m2, year: y2}) =>
                                                                    (y1 - y2) || (months[m1] - months[m2])

                                                                    const zip = (fn, a1, a2) => a1.map((a, i) => fn(a, a2[i]))

                                                                    const sortArraysByDate = (a1, a2) =>
                                                                    zip((label, value) => ({label, value, ...dateFields(label)}), a1, a2)
                                                                    .sort(dateSort)
                                                                    .map(({label, value}) => ({label, value}))


                                                                    const Array1 = ['Mar19','Apr18','Jun18','Jul18','May18','Jan19'];
                                                                    const Array2 = ['55','2','3','0','21','132']; //real values

                                                                    const result = sortArraysByDate(Array1, Array2)

                                                                    console.log(result)






                                                                    share|improve this answer














                                                                    share|improve this answer



                                                                    share|improve this answer








                                                                    edited yesterday

























                                                                    answered yesterday









                                                                    Scott SauyetScott Sauyet

                                                                    20.8k22757




                                                                    20.8k22757






























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                                                                        To learn more, see our tips on writing great answers.




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