Out of sample extension for Isomap in Sklearn












0












$begingroup$


If I'm fitting the isomap class with a certain dataset, then I transform with a different one, does that mean that Sklearn is doing out-of-sample extension ?



I.e.



isomap=sklearn.manifold.isomap()
isomap.fit(X1)

isomap.transform(X2)









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$endgroup$

















    0












    $begingroup$


    If I'm fitting the isomap class with a certain dataset, then I transform with a different one, does that mean that Sklearn is doing out-of-sample extension ?



    I.e.



    isomap=sklearn.manifold.isomap()
    isomap.fit(X1)

    isomap.transform(X2)









    share|improve this question







    New contributor




    Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      If I'm fitting the isomap class with a certain dataset, then I transform with a different one, does that mean that Sklearn is doing out-of-sample extension ?



      I.e.



      isomap=sklearn.manifold.isomap()
      isomap.fit(X1)

      isomap.transform(X2)









      share|improve this question







      New contributor




      Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      If I'm fitting the isomap class with a certain dataset, then I transform with a different one, does that mean that Sklearn is doing out-of-sample extension ?



      I.e.



      isomap=sklearn.manifold.isomap()
      isomap.fit(X1)

      isomap.transform(X2)






      python scikit-learn dimensionality-reduction






      share|improve this question







      New contributor




      Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






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      asked 14 mins ago









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