my cron command doesn’t work
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 1 hour ago
dessert
24.1k670104
asked 3 hours ago
ahmadahmad
8510
add a comment |
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 1 hour ago
dessert
24.1k670104
asked 3 hours ago
ahmadahmad
8510
add a comment |
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 1 hour ago
dessert
24.1k670104
asked 3 hours ago
ahmadahmad
8510
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
command-line cron
edited 1 hour ago
dessert
24.1k670104
asked 3 hours ago
ahmadahmad
8510
edited 1 hour ago
dessert
24.1k670104
asked 3 hours ago
ahmadahmad
8510
edited 1 hour ago
dessert
24.1k670104
edited 1 hour ago
dessert
24.1k670104
edited 1 hour ago
dessert
24.1k670104
24.1k670104
asked 3 hours ago
ahmadahmad
8510
asked 3 hours ago
ahmadahmad
8510
asked 3 hours ago
ahmadahmad
8510
8510
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 3 hours ago
heemaylheemayl
67.1k9142214
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to putSHELL=/usr/bin/zshat the top of yourcrontab, and keep the command as you've written in the question.
– heemayl
2 hours ago
|
show 3 more comments
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1 Answer
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active
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1 Answer
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active
oldest
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oldest
votes
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 3 hours ago
heemaylheemayl
67.1k9142214
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to putSHELL=/usr/bin/zshat the top of yourcrontab, and keep the command as you've written in the question.
– heemayl
2 hours ago
|
show 3 more comments
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 3 hours ago
heemaylheemayl
67.1k9142214
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to putSHELL=/usr/bin/zshat the top of yourcrontab, and keep the command as you've written in the question.
– heemayl
2 hours ago
|
show 3 more comments
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 3 hours ago
heemaylheemayl
67.1k9142214
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 3 hours ago
heemaylheemayl
67.1k9142214
edited 2 hours ago
answered 3 hours ago
heemaylheemayl
67.1k9142214
answered 3 hours ago
heemaylheemayl
67.1k9142214
answered 3 hours ago
heemaylheemayl
67.1k9142214
67.1k9142214
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to putSHELL=/usr/bin/zshat the top of yourcrontab, and keep the command as you've written in the question.
– heemayl
2 hours ago
|
show 3 more comments
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to putSHELL=/usr/bin/zshat the top of yourcrontab, and keep the command as you've written in the question.
– heemayl
2 hours ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@steeldriver Fair call. Edited.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@ahmad Check my edits.
– heemayl
3 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
2 hours ago
@ahmad You're supposed to put
SHELL=/usr/bin/zsh at the top of your crontab, and keep the command as you've written in the question.– heemayl
2 hours ago
@ahmad You're supposed to put
SHELL=/usr/bin/zsh at the top of your crontab, and keep the command as you've written in the question.– heemayl
2 hours ago
|
show 3 more comments
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