Specific list manipulation












2












$begingroup$


Suppose I have two lists each of different size, e.g toy case ListX = {x1,x2,x3} and ListY = {y1,y2} and all possible combinations of elements give rise to an element in another list ListZ = {z1,z2,z3,z4,z5,z6} of dimension dim(ListX) x dim(ListY), i.e the tuple (x1,y1) is associated with z1, say.



How to merge all three lists such that I obtain the following combined list?



{{{x1,y1},z1}, {{x1,y2},z2}, {{x2,y1},z3}, {{x2,y2},z4}, {{x3,y1},z5},{{x3,y2},z6}}



I've tried nested tables but I always generate additional items that I don't want. The actual lists I'm dealing with are of dimension O(50) such that the equivalent of ListZ is of dimension O(2500).






list-manipulation







share|improve this question











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    2












    $begingroup$


    Suppose I have two lists each of different size, e.g toy case ListX = {x1,x2,x3} and ListY = {y1,y2} and all possible combinations of elements give rise to an element in another list ListZ = {z1,z2,z3,z4,z5,z6} of dimension dim(ListX) x dim(ListY), i.e the tuple (x1,y1) is associated with z1, say.



    How to merge all three lists such that I obtain the following combined list?



    {{{x1,y1},z1}, {{x1,y2},z2}, {{x2,y1},z3}, {{x2,y2},z4}, {{x3,y1},z5},{{x3,y2},z6}}



    I've tried nested tables but I always generate additional items that I don't want. The actual lists I'm dealing with are of dimension O(50) such that the equivalent of ListZ is of dimension O(2500).






    list-manipulation







    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      Suppose I have two lists each of different size, e.g toy case ListX = {x1,x2,x3} and ListY = {y1,y2} and all possible combinations of elements give rise to an element in another list ListZ = {z1,z2,z3,z4,z5,z6} of dimension dim(ListX) x dim(ListY), i.e the tuple (x1,y1) is associated with z1, say.



      How to merge all three lists such that I obtain the following combined list?



      {{{x1,y1},z1}, {{x1,y2},z2}, {{x2,y1},z3}, {{x2,y2},z4}, {{x3,y1},z5},{{x3,y2},z6}}



      I've tried nested tables but I always generate additional items that I don't want. The actual lists I'm dealing with are of dimension O(50) such that the equivalent of ListZ is of dimension O(2500).






      list-manipulation







      share|improve this question











      $endgroup$




      Suppose I have two lists each of different size, e.g toy case ListX = {x1,x2,x3} and ListY = {y1,y2} and all possible combinations of elements give rise to an element in another list ListZ = {z1,z2,z3,z4,z5,z6} of dimension dim(ListX) x dim(ListY), i.e the tuple (x1,y1) is associated with z1, say.



      How to merge all three lists such that I obtain the following combined list?



      {{{x1,y1},z1}, {{x1,y2},z2}, {{x2,y1},z3}, {{x2,y2},z4}, {{x3,y1},z5},{{x3,y2},z6}}



      I've tried nested tables but I always generate additional items that I don't want. The actual lists I'm dealing with are of dimension O(50) such that the equivalent of ListZ is of dimension O(2500).






      list-manipulation




      list-manipulation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 11 mins ago









      J. M. is computer-less♦

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      asked 8 hours ago









      CAFCAF

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      255110






















          2 Answers
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          $begingroup$

          This seems to do what you are looking for:



          ListX = {x1, x2, x3};
          
ListY = {y1, y2};
          
ListZ = {z1, z2, z3, z4, z5, z6};
          
Partition[Riffle[Flatten[Outer[List, ListX, ListY], 1], ListZ], 2]


          The Outer product gives all the pairs, but they are nested funny so you need to Flatten. Riffle does the interleaving of the Outer product with ListZ, and again it's not quite got your desired structure, but Partition fixes that.






          share|improve this answer









          $endgroup$





















            7












            $begingroup$

            Transpose@{Tuples@{ListX, ListY}, ListZ}





            share|improve this answer








            New contributor




            ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$









            • 1




              $begingroup$
              Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
              $endgroup$
              – rmw
              7 hours ago










            • $begingroup$
              Yes. Thanks for reminding me that.
              $endgroup$
              – ukar
              4 hours ago











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            2 Answers
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            2 Answers
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            $begingroup$

            This seems to do what you are looking for:



            ListX = {x1, x2, x3};
            
ListY = {y1, y2};
            
ListZ = {z1, z2, z3, z4, z5, z6};
            
Partition[Riffle[Flatten[Outer[List, ListX, ListY], 1], ListZ], 2]


            The Outer product gives all the pairs, but they are nested funny so you need to Flatten. Riffle does the interleaving of the Outer product with ListZ, and again it's not quite got your desired structure, but Partition fixes that.






            share|improve this answer









            $endgroup$


















              2












              $begingroup$

              This seems to do what you are looking for:



              ListX = {x1, x2, x3};
              
ListY = {y1, y2};
              
ListZ = {z1, z2, z3, z4, z5, z6};
              
Partition[Riffle[Flatten[Outer[List, ListX, ListY], 1], ListZ], 2]


              The Outer product gives all the pairs, but they are nested funny so you need to Flatten. Riffle does the interleaving of the Outer product with ListZ, and again it's not quite got your desired structure, but Partition fixes that.






              share|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                This seems to do what you are looking for:



                ListX = {x1, x2, x3};
                
ListY = {y1, y2};
                
ListZ = {z1, z2, z3, z4, z5, z6};
                
Partition[Riffle[Flatten[Outer[List, ListX, ListY], 1], ListZ], 2]


                The Outer product gives all the pairs, but they are nested funny so you need to Flatten. Riffle does the interleaving of the Outer product with ListZ, and again it's not quite got your desired structure, but Partition fixes that.






                share|improve this answer









                $endgroup$



                This seems to do what you are looking for:



                ListX = {x1, x2, x3};
                
ListY = {y1, y2};
                
ListZ = {z1, z2, z3, z4, z5, z6};
                
Partition[Riffle[Flatten[Outer[List, ListX, ListY], 1], ListZ], 2]


                The Outer product gives all the pairs, but they are nested funny so you need to Flatten. Riffle does the interleaving of the Outer product with ListZ, and again it's not quite got your desired structure, but Partition fixes that.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 8 hours ago









                bill sbill s

                53.6k376152




                53.6k376152























                    7












                    $begingroup$

                    Transpose@{Tuples@{ListX, ListY}, ListZ}





                    share|improve this answer








                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$









                    • 1




                      $begingroup$
                      Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                      $endgroup$
                      – rmw
                      7 hours ago










                    • $begingroup$
                      Yes. Thanks for reminding me that.
                      $endgroup$
                      – ukar
                      4 hours ago
















                    7












                    $begingroup$

                    Transpose@{Tuples@{ListX, ListY}, ListZ}





                    share|improve this answer








                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$









                    • 1




                      $begingroup$
                      Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                      $endgroup$
                      – rmw
                      7 hours ago










                    • $begingroup$
                      Yes. Thanks for reminding me that.
                      $endgroup$
                      – ukar
                      4 hours ago














                    7












                    7








                    7





                    $begingroup$

                    Transpose@{Tuples@{ListX, ListY}, ListZ}





                    share|improve this answer








                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$



                    Transpose@{Tuples@{ListX, ListY}, ListZ}






                    share|improve this answer








                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    share|improve this answer



                    share|improve this answer






                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    answered 7 hours ago









                    ukarukar

                    691




                    691




                    New contributor




                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.





                    New contributor





                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    ukar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.








                    • 1




                      $begingroup$
                      Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                      $endgroup$
                      – rmw
                      7 hours ago










                    • $begingroup$
                      Yes. Thanks for reminding me that.
                      $endgroup$
                      – ukar
                      4 hours ago














                    • 1




                      $begingroup$
                      Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                      $endgroup$
                      – rmw
                      7 hours ago










                    • $begingroup$
                      Yes. Thanks for reminding me that.
                      $endgroup$
                      – ukar
                      4 hours ago








                    1




                    1




                    $begingroup$
                    Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                    $endgroup$
                    – rmw
                    7 hours ago




                    $begingroup$
                    Very nice solution! You can also use Thread instead of Transpose:Thread@{Tuples@{ListX, ListY}, ListZ}
                    $endgroup$
                    – rmw
                    7 hours ago












                    $begingroup$
                    Yes. Thanks for reminding me that.
                    $endgroup$
                    – ukar
                    4 hours ago




                    $begingroup$
                    Yes. Thanks for reminding me that.
                    $endgroup$
                    – ukar
                    4 hours ago


















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