Array Dynamic resize in heap
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$begingroup$
I have answered a Question in Stackoverflow link.
a) Create a function called resize that can be used to increase the
size of integer arrays dynamically. The function takes three
parameters. The first parameter is the original array, the second
parameter is the size of this array, and the third parameter is the
size of the larger array to be created by this function. Make sure
that you allocate memory from the heap inside this function. After
allocating memory for the second array the function must copy the
elements from the first array into the larger array. Finally, the
function must return a pointer to the new array.
b. In main, allocate an array on the heap that is just large enough to
store the integers 5, 7, 3, and 1.
c. Resize the array to store 10 integers by calling the resize
function created in step a. Remove the old (smaller) array from the
heap. Add the numbers 4, 2, and 8 to the end of the new array.
d. Write a sort function that sorts any integer array in increasing
order.
e. Use the sort function to sort the array of numbers in c above.
Display the sorted numbers.
Is there a Dangling pointer issue.
#include <array>
#include <iostream>
void swap(int *xp, int *yp)
{
int temp = *xp;
*xp = *yp;
*yp = temp;
}
//Bubble Sort
bool sort(int arr, int size)
{
for( int i = 0; i< size -1; i++)
{
for( int j = 0; j < size - i -1; j++)
{
//descending order
if(arr[j]<arr[j+1])
{
swap(&arr[j], &arr[j+1]);
}
}
}
return true;
}
void Print(int Array, int nSize)
{
for( int i = 0; i < nSize; i++)
{
std::cout<<" "<<Array[i];
}
std::cout<<"n";
}
void Resize( int *&Array, const int& nSizeOld, const int& nSize )
{
int * newArray = new int[nSize];
//Copy Elements of the Array
for(int i = 0; i< nSizeOld; i++)
{
newArray[i] = Array[i];
}
delete Array;
//Assign ptr of Prev to new Array
Array = newArray;
}
int _tmain(int argc, _TCHAR* argv)
{
const int kNewSize = 10, kSize = 5;
int *pMyArray = new int[kSize];
//Set Values
for( int i = 0; i< kSize; ++i )
{
pMyArray[i] = i * 5;
}
Resize( pMyArray, kSize, kNewSize );
//Set Values
for( int i = kSize; i< kNewSize; ++i )
{
pMyArray[i] = i * 10;
}
Print(pMyArray, kNewSize);
sort(pMyArray, kNewSize);
Print(pMyArray, kNewSize);
if( pMyArray!=NULL )
{
delete pMyArray;
}
return 0;
}
c++ c++11 pointers
New contributor
$endgroup$
add a comment |
$begingroup$
I have answered a Question in Stackoverflow link.
a) Create a function called resize that can be used to increase the
size of integer arrays dynamically. The function takes three
parameters. The first parameter is the original array, the second
parameter is the size of this array, and the third parameter is the
size of the larger array to be created by this function. Make sure
that you allocate memory from the heap inside this function. After
allocating memory for the second array the function must copy the
elements from the first array into the larger array. Finally, the
function must return a pointer to the new array.
b. In main, allocate an array on the heap that is just large enough to
store the integers 5, 7, 3, and 1.
c. Resize the array to store 10 integers by calling the resize
function created in step a. Remove the old (smaller) array from the
heap. Add the numbers 4, 2, and 8 to the end of the new array.
d. Write a sort function that sorts any integer array in increasing
order.
e. Use the sort function to sort the array of numbers in c above.
Display the sorted numbers.
Is there a Dangling pointer issue.
#include <array>
#include <iostream>
void swap(int *xp, int *yp)
{
int temp = *xp;
*xp = *yp;
*yp = temp;
}
//Bubble Sort
bool sort(int arr, int size)
{
for( int i = 0; i< size -1; i++)
{
for( int j = 0; j < size - i -1; j++)
{
//descending order
if(arr[j]<arr[j+1])
{
swap(&arr[j], &arr[j+1]);
}
}
}
return true;
}
void Print(int Array, int nSize)
{
for( int i = 0; i < nSize; i++)
{
std::cout<<" "<<Array[i];
}
std::cout<<"n";
}
void Resize( int *&Array, const int& nSizeOld, const int& nSize )
{
int * newArray = new int[nSize];
//Copy Elements of the Array
for(int i = 0; i< nSizeOld; i++)
{
newArray[i] = Array[i];
}
delete Array;
//Assign ptr of Prev to new Array
Array = newArray;
}
int _tmain(int argc, _TCHAR* argv)
{
const int kNewSize = 10, kSize = 5;
int *pMyArray = new int[kSize];
//Set Values
for( int i = 0; i< kSize; ++i )
{
pMyArray[i] = i * 5;
}
Resize( pMyArray, kSize, kNewSize );
//Set Values
for( int i = kSize; i< kNewSize; ++i )
{
pMyArray[i] = i * 10;
}
Print(pMyArray, kNewSize);
sort(pMyArray, kNewSize);
Print(pMyArray, kNewSize);
if( pMyArray!=NULL )
{
delete pMyArray;
}
return 0;
}
c++ c++11 pointers
New contributor
$endgroup$
add a comment |
$begingroup$
I have answered a Question in Stackoverflow link.
a) Create a function called resize that can be used to increase the
size of integer arrays dynamically. The function takes three
parameters. The first parameter is the original array, the second
parameter is the size of this array, and the third parameter is the
size of the larger array to be created by this function. Make sure
that you allocate memory from the heap inside this function. After
allocating memory for the second array the function must copy the
elements from the first array into the larger array. Finally, the
function must return a pointer to the new array.
b. In main, allocate an array on the heap that is just large enough to
store the integers 5, 7, 3, and 1.
c. Resize the array to store 10 integers by calling the resize
function created in step a. Remove the old (smaller) array from the
heap. Add the numbers 4, 2, and 8 to the end of the new array.
d. Write a sort function that sorts any integer array in increasing
order.
e. Use the sort function to sort the array of numbers in c above.
Display the sorted numbers.
Is there a Dangling pointer issue.
#include <array>
#include <iostream>
void swap(int *xp, int *yp)
{
int temp = *xp;
*xp = *yp;
*yp = temp;
}
//Bubble Sort
bool sort(int arr, int size)
{
for( int i = 0; i< size -1; i++)
{
for( int j = 0; j < size - i -1; j++)
{
//descending order
if(arr[j]<arr[j+1])
{
swap(&arr[j], &arr[j+1]);
}
}
}
return true;
}
void Print(int Array, int nSize)
{
for( int i = 0; i < nSize; i++)
{
std::cout<<" "<<Array[i];
}
std::cout<<"n";
}
void Resize( int *&Array, const int& nSizeOld, const int& nSize )
{
int * newArray = new int[nSize];
//Copy Elements of the Array
for(int i = 0; i< nSizeOld; i++)
{
newArray[i] = Array[i];
}
delete Array;
//Assign ptr of Prev to new Array
Array = newArray;
}
int _tmain(int argc, _TCHAR* argv)
{
const int kNewSize = 10, kSize = 5;
int *pMyArray = new int[kSize];
//Set Values
for( int i = 0; i< kSize; ++i )
{
pMyArray[i] = i * 5;
}
Resize( pMyArray, kSize, kNewSize );
//Set Values
for( int i = kSize; i< kNewSize; ++i )
{
pMyArray[i] = i * 10;
}
Print(pMyArray, kNewSize);
sort(pMyArray, kNewSize);
Print(pMyArray, kNewSize);
if( pMyArray!=NULL )
{
delete pMyArray;
}
return 0;
}
c++ c++11 pointers
New contributor
$endgroup$
I have answered a Question in Stackoverflow link.
a) Create a function called resize that can be used to increase the
size of integer arrays dynamically. The function takes three
parameters. The first parameter is the original array, the second
parameter is the size of this array, and the third parameter is the
size of the larger array to be created by this function. Make sure
that you allocate memory from the heap inside this function. After
allocating memory for the second array the function must copy the
elements from the first array into the larger array. Finally, the
function must return a pointer to the new array.
b. In main, allocate an array on the heap that is just large enough to
store the integers 5, 7, 3, and 1.
c. Resize the array to store 10 integers by calling the resize
function created in step a. Remove the old (smaller) array from the
heap. Add the numbers 4, 2, and 8 to the end of the new array.
d. Write a sort function that sorts any integer array in increasing
order.
e. Use the sort function to sort the array of numbers in c above.
Display the sorted numbers.
Is there a Dangling pointer issue.
#include <array>
#include <iostream>
void swap(int *xp, int *yp)
{
int temp = *xp;
*xp = *yp;
*yp = temp;
}
//Bubble Sort
bool sort(int arr, int size)
{
for( int i = 0; i< size -1; i++)
{
for( int j = 0; j < size - i -1; j++)
{
//descending order
if(arr[j]<arr[j+1])
{
swap(&arr[j], &arr[j+1]);
}
}
}
return true;
}
void Print(int Array, int nSize)
{
for( int i = 0; i < nSize; i++)
{
std::cout<<" "<<Array[i];
}
std::cout<<"n";
}
void Resize( int *&Array, const int& nSizeOld, const int& nSize )
{
int * newArray = new int[nSize];
//Copy Elements of the Array
for(int i = 0; i< nSizeOld; i++)
{
newArray[i] = Array[i];
}
delete Array;
//Assign ptr of Prev to new Array
Array = newArray;
}
int _tmain(int argc, _TCHAR* argv)
{
const int kNewSize = 10, kSize = 5;
int *pMyArray = new int[kSize];
//Set Values
for( int i = 0; i< kSize; ++i )
{
pMyArray[i] = i * 5;
}
Resize( pMyArray, kSize, kNewSize );
//Set Values
for( int i = kSize; i< kNewSize; ++i )
{
pMyArray[i] = i * 10;
}
Print(pMyArray, kNewSize);
sort(pMyArray, kNewSize);
Print(pMyArray, kNewSize);
if( pMyArray!=NULL )
{
delete pMyArray;
}
return 0;
}
c++ c++11 pointers
c++ c++11 pointers
New contributor
New contributor
edited 21 secs ago
f1r361rd
New contributor
asked 1 hour ago
f1r361rdf1r361rd
113
113
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2 Answers
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votes
$begingroup$
If you had tagged this code as C, it would have been acceptable. Since you tagged it as C++, it's horrible.
Instead of writing your own swap
function, there's already std::swap
in <algorithm>
.
Instead of writing bubble sort yourself, just use std::sort
, also from <algorithm>
.
Instead of using arrays and resizing them yourself, just use std::vector<int>
, from <vector>
.
After applying these transformations, you cannot have a dangling pointer anymore since your code is completely pointer-free.
As part of an exercise for learning the basic operations on memory management, it's ok to write code like this, but never ever use such code in production. In production the code should look like this:
#include <algorithm>
#include <iostream>
#include <vector>
void Print(const std::vector<int> &nums)
{
for(int num : nums)
{
std::cout << " " << num;
}
std::cout << "n";
}
int main()
{
std::vector<int> nums { 5, 7, 3, 1 };
// There's probably a more elegant way to add the elements to the vector.
nums.push_back(4);
nums.push_back(2);
nums.push_back(8);
std::sort(nums.begin(), nums.end());
Print(nums);
}
By the way, your original code doesn't have any dangling pointer as well. Well done.
You don't need the != NULL
check before the delete
since that pointer cannot be null. In modern C++ (since C++11 I think) you would also write nullptr
instead of NULL
. The reason is that historically NULL
had not been guaranteed to be of pointer type.
Have a look at https://www.cplusplus.com/reference/algorithm/ for more algorithms that you shouldn't implement yourself in C++.
$endgroup$
add a comment |
$begingroup$
The code is obviously wrong: your compiler should have warmed you that Resize()
never uses its nSizeOld
parameter.
$endgroup$
add a comment |
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2 Answers
2
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
If you had tagged this code as C, it would have been acceptable. Since you tagged it as C++, it's horrible.
Instead of writing your own swap
function, there's already std::swap
in <algorithm>
.
Instead of writing bubble sort yourself, just use std::sort
, also from <algorithm>
.
Instead of using arrays and resizing them yourself, just use std::vector<int>
, from <vector>
.
After applying these transformations, you cannot have a dangling pointer anymore since your code is completely pointer-free.
As part of an exercise for learning the basic operations on memory management, it's ok to write code like this, but never ever use such code in production. In production the code should look like this:
#include <algorithm>
#include <iostream>
#include <vector>
void Print(const std::vector<int> &nums)
{
for(int num : nums)
{
std::cout << " " << num;
}
std::cout << "n";
}
int main()
{
std::vector<int> nums { 5, 7, 3, 1 };
// There's probably a more elegant way to add the elements to the vector.
nums.push_back(4);
nums.push_back(2);
nums.push_back(8);
std::sort(nums.begin(), nums.end());
Print(nums);
}
By the way, your original code doesn't have any dangling pointer as well. Well done.
You don't need the != NULL
check before the delete
since that pointer cannot be null. In modern C++ (since C++11 I think) you would also write nullptr
instead of NULL
. The reason is that historically NULL
had not been guaranteed to be of pointer type.
Have a look at https://www.cplusplus.com/reference/algorithm/ for more algorithms that you shouldn't implement yourself in C++.
$endgroup$
add a comment |
$begingroup$
If you had tagged this code as C, it would have been acceptable. Since you tagged it as C++, it's horrible.
Instead of writing your own swap
function, there's already std::swap
in <algorithm>
.
Instead of writing bubble sort yourself, just use std::sort
, also from <algorithm>
.
Instead of using arrays and resizing them yourself, just use std::vector<int>
, from <vector>
.
After applying these transformations, you cannot have a dangling pointer anymore since your code is completely pointer-free.
As part of an exercise for learning the basic operations on memory management, it's ok to write code like this, but never ever use such code in production. In production the code should look like this:
#include <algorithm>
#include <iostream>
#include <vector>
void Print(const std::vector<int> &nums)
{
for(int num : nums)
{
std::cout << " " << num;
}
std::cout << "n";
}
int main()
{
std::vector<int> nums { 5, 7, 3, 1 };
// There's probably a more elegant way to add the elements to the vector.
nums.push_back(4);
nums.push_back(2);
nums.push_back(8);
std::sort(nums.begin(), nums.end());
Print(nums);
}
By the way, your original code doesn't have any dangling pointer as well. Well done.
You don't need the != NULL
check before the delete
since that pointer cannot be null. In modern C++ (since C++11 I think) you would also write nullptr
instead of NULL
. The reason is that historically NULL
had not been guaranteed to be of pointer type.
Have a look at https://www.cplusplus.com/reference/algorithm/ for more algorithms that you shouldn't implement yourself in C++.
$endgroup$
add a comment |
$begingroup$
If you had tagged this code as C, it would have been acceptable. Since you tagged it as C++, it's horrible.
Instead of writing your own swap
function, there's already std::swap
in <algorithm>
.
Instead of writing bubble sort yourself, just use std::sort
, also from <algorithm>
.
Instead of using arrays and resizing them yourself, just use std::vector<int>
, from <vector>
.
After applying these transformations, you cannot have a dangling pointer anymore since your code is completely pointer-free.
As part of an exercise for learning the basic operations on memory management, it's ok to write code like this, but never ever use such code in production. In production the code should look like this:
#include <algorithm>
#include <iostream>
#include <vector>
void Print(const std::vector<int> &nums)
{
for(int num : nums)
{
std::cout << " " << num;
}
std::cout << "n";
}
int main()
{
std::vector<int> nums { 5, 7, 3, 1 };
// There's probably a more elegant way to add the elements to the vector.
nums.push_back(4);
nums.push_back(2);
nums.push_back(8);
std::sort(nums.begin(), nums.end());
Print(nums);
}
By the way, your original code doesn't have any dangling pointer as well. Well done.
You don't need the != NULL
check before the delete
since that pointer cannot be null. In modern C++ (since C++11 I think) you would also write nullptr
instead of NULL
. The reason is that historically NULL
had not been guaranteed to be of pointer type.
Have a look at https://www.cplusplus.com/reference/algorithm/ for more algorithms that you shouldn't implement yourself in C++.
$endgroup$
If you had tagged this code as C, it would have been acceptable. Since you tagged it as C++, it's horrible.
Instead of writing your own swap
function, there's already std::swap
in <algorithm>
.
Instead of writing bubble sort yourself, just use std::sort
, also from <algorithm>
.
Instead of using arrays and resizing them yourself, just use std::vector<int>
, from <vector>
.
After applying these transformations, you cannot have a dangling pointer anymore since your code is completely pointer-free.
As part of an exercise for learning the basic operations on memory management, it's ok to write code like this, but never ever use such code in production. In production the code should look like this:
#include <algorithm>
#include <iostream>
#include <vector>
void Print(const std::vector<int> &nums)
{
for(int num : nums)
{
std::cout << " " << num;
}
std::cout << "n";
}
int main()
{
std::vector<int> nums { 5, 7, 3, 1 };
// There's probably a more elegant way to add the elements to the vector.
nums.push_back(4);
nums.push_back(2);
nums.push_back(8);
std::sort(nums.begin(), nums.end());
Print(nums);
}
By the way, your original code doesn't have any dangling pointer as well. Well done.
You don't need the != NULL
check before the delete
since that pointer cannot be null. In modern C++ (since C++11 I think) you would also write nullptr
instead of NULL
. The reason is that historically NULL
had not been guaranteed to be of pointer type.
Have a look at https://www.cplusplus.com/reference/algorithm/ for more algorithms that you shouldn't implement yourself in C++.
edited 19 mins ago
answered 24 mins ago
Roland IlligRoland Illig
11.9k11948
11.9k11948
add a comment |
add a comment |
$begingroup$
The code is obviously wrong: your compiler should have warmed you that Resize()
never uses its nSizeOld
parameter.
$endgroup$
add a comment |
$begingroup$
The code is obviously wrong: your compiler should have warmed you that Resize()
never uses its nSizeOld
parameter.
$endgroup$
add a comment |
$begingroup$
The code is obviously wrong: your compiler should have warmed you that Resize()
never uses its nSizeOld
parameter.
$endgroup$
The code is obviously wrong: your compiler should have warmed you that Resize()
never uses its nSizeOld
parameter.
answered 7 mins ago
200_success200_success
131k17157422
131k17157422
add a comment |
add a comment |
f1r361rd is a new contributor. Be nice, and check out our Code of Conduct.
f1r361rd is a new contributor. Be nice, and check out our Code of Conduct.
f1r361rd is a new contributor. Be nice, and check out our Code of Conduct.
f1r361rd is a new contributor. Be nice, and check out our Code of Conduct.
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