Images similarity using SIFT and Annoy












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Given an image, I need to get the most similar ones with "score" or percent of similarity



I'm using SIFT to get the descriptors from all the images and storing them in Annoy as individual vectors linked to the original image.



Then, given the image I want to get similar ones, I get the descriptors of the image, and I get the nearest neighbours (100 at the moment) from each of the descriptors. So for each of the descriptors of the image I want to measure I have the 100 nearest neighbours (with the original image of each)



Do you think this is a good approach?



How can I calculate the image with most similarity percent? Given an x number of descriptors where I get the most 100 nearest neighbours from each with the cosine or euclidean.










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    0












    $begingroup$


    Given an image, I need to get the most similar ones with "score" or percent of similarity



    I'm using SIFT to get the descriptors from all the images and storing them in Annoy as individual vectors linked to the original image.



    Then, given the image I want to get similar ones, I get the descriptors of the image, and I get the nearest neighbours (100 at the moment) from each of the descriptors. So for each of the descriptors of the image I want to measure I have the 100 nearest neighbours (with the original image of each)



    Do you think this is a good approach?



    How can I calculate the image with most similarity percent? Given an x number of descriptors where I get the most 100 nearest neighbours from each with the cosine or euclidean.










    share|improve this question







    New contributor




    Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      Given an image, I need to get the most similar ones with "score" or percent of similarity



      I'm using SIFT to get the descriptors from all the images and storing them in Annoy as individual vectors linked to the original image.



      Then, given the image I want to get similar ones, I get the descriptors of the image, and I get the nearest neighbours (100 at the moment) from each of the descriptors. So for each of the descriptors of the image I want to measure I have the 100 nearest neighbours (with the original image of each)



      Do you think this is a good approach?



      How can I calculate the image with most similarity percent? Given an x number of descriptors where I get the most 100 nearest neighbours from each with the cosine or euclidean.










      share|improve this question







      New contributor




      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Given an image, I need to get the most similar ones with "score" or percent of similarity



      I'm using SIFT to get the descriptors from all the images and storing them in Annoy as individual vectors linked to the original image.



      Then, given the image I want to get similar ones, I get the descriptors of the image, and I get the nearest neighbours (100 at the moment) from each of the descriptors. So for each of the descriptors of the image I want to measure I have the 100 nearest neighbours (with the original image of each)



      Do you think this is a good approach?



      How can I calculate the image with most similarity percent? Given an x number of descriptors where I get the most 100 nearest neighbours from each with the cosine or euclidean.







      python image-classification opencv image-preprocessing






      share|improve this question







      New contributor




      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 3 hours ago









      Santi BarbatSanti Barbat

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      New contributor




      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Santi Barbat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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