Shortcut for a polynomial of the from $a_nx^n+ldots+a_1x+a_0$
I currently taking a course in Algebra, and I find myself typing the polynomial
$a_nx^n+ldots+a_1x+a_0$
over and over again, and I was wondering if I could create a shortcut for such a polynomial form, such that I can control what coefficients and variables I want.
I would be very grateful!
I know the polynomial package exists, but I cannot seem to incorporate the "ldots" in the commands it offers.
math-mode macros shortcut
New contributor
add a comment |
I currently taking a course in Algebra, and I find myself typing the polynomial
$a_nx^n+ldots+a_1x+a_0$
over and over again, and I was wondering if I could create a shortcut for such a polynomial form, such that I can control what coefficients and variables I want.
I would be very grateful!
I know the polynomial package exists, but I cannot seem to incorporate the "ldots" in the commands it offers.
math-mode macros shortcut
New contributor
Welcome to TeX.SE!
– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order alwaysn
(w/n>1
, right?) and is the lowest order always0
, i.e., a constant?
– Mico
2 hours ago
1
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago
add a comment |
I currently taking a course in Algebra, and I find myself typing the polynomial
$a_nx^n+ldots+a_1x+a_0$
over and over again, and I was wondering if I could create a shortcut for such a polynomial form, such that I can control what coefficients and variables I want.
I would be very grateful!
I know the polynomial package exists, but I cannot seem to incorporate the "ldots" in the commands it offers.
math-mode macros shortcut
New contributor
I currently taking a course in Algebra, and I find myself typing the polynomial
$a_nx^n+ldots+a_1x+a_0$
over and over again, and I was wondering if I could create a shortcut for such a polynomial form, such that I can control what coefficients and variables I want.
I would be very grateful!
I know the polynomial package exists, but I cannot seem to incorporate the "ldots" in the commands it offers.
math-mode macros shortcut
math-mode macros shortcut
New contributor
New contributor
edited 2 hours ago
Mico
276k30374765
276k30374765
New contributor
asked 2 hours ago
KamKam
233
233
New contributor
New contributor
Welcome to TeX.SE!
– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order alwaysn
(w/n>1
, right?) and is the lowest order always0
, i.e., a constant?
– Mico
2 hours ago
1
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago
add a comment |
Welcome to TeX.SE!
– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order alwaysn
(w/n>1
, right?) and is the lowest order always0
, i.e., a constant?
– Mico
2 hours ago
1
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago
Welcome to TeX.SE!
– Mico
2 hours ago
Welcome to TeX.SE!
– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order always
n
(w/ n>1
, right?) and is the lowest order always 0
, i.e., a constant?– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order always
n
(w/ n>1
, right?) and is the lowest order always 0
, i.e., a constant?– Mico
2 hours ago
1
1
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
I think that what you need is a macro that takes two arguments: the "name" of the coefficients, and the "name" of the base of the power terms. The names will, in general, be single letters, right? (You've indicated, in a comment, that the highest and lowest order of the polynomial are always n
and 0
, respectively.) The macro called pn
in the following example satisfies these criteria.
Incidentally, the typographic ellipsis used between binary operators (such as +
) is usually of the form cdots
, not ldots
. (The letters "c" and "l" refer to either centered (on the math line) or low (on the typographic baseline).
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[2]{#1_n #2^n + cdots + #1_1 #2 + #1_0}
begin{document}
$pn{a}{x}$
$pn{lambda}{z}$
$pn{alpha}{xi}$
end{document}
Addendum to address the OP's follow-up request: Suppose that not all polynomials are of order n
, but that it's true that most polynomials are, in fact, order n
. In that case, it makes sense to modify the pn
macro that it takes 3 rather than 2 arguments, with additional argument taking on the value n
by default.
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[3][n]{#2_{#1} #3^{#1} + cdots + #2_1 #3 + #2_0}
begin{document}
$pn{a}{x}$ % use default order (n) of polynomial
$pn[4]{lambda}{z}$
$pn[q]{alpha}{xi}$
end{document}
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of thepn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value isn
.
– Mico
1 hour ago
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
add a comment |
With a fairly simple syntax:
documentclass{article}
usepackage{amsmath}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{poly}{O{}}
{
group_begin:
keys_set:nn { poly } { #1 }
kam_poly:
group_end:
}
keys_define:nn { poly }
{
degree .tl_set:N = l__poly_degree_tl,
var .tl_set:N = l__poly_var_tl,
coef .tl_set:N = l__poly_coef_tl,
reverse .bool_set:N = l__poly_reverse_bool,
degree .initial:n = n,
var .initial:n = x,
coef .initial:n = a,
reverse .default:n = true,
}
cs_new_protected:Nn kam_poly:
{
bool_if:NTF l__poly_reverse_bool
{
l__poly_coef_tl sb { 0 } +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
dots +
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl }
}
{
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl } +
dots +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
l__poly_coef_tl sb { 0 }
}
}
ExplSyntaxOff
begin{document}
$poly$
$poly[var=z]$
$poly[var=t,degree=m,coef=b]$
$poly[var=t,degree=m,coef=b,reverse]$
end{document}
The keys can be specified in any order, freeing you from the need to remember which parameter goes first; the default values are
var = x
degree = n
coef = a
You can also make shorthands with, say
newcommand{polybtn}{poly[var=t,coef=b,degree=n]}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think that what you need is a macro that takes two arguments: the "name" of the coefficients, and the "name" of the base of the power terms. The names will, in general, be single letters, right? (You've indicated, in a comment, that the highest and lowest order of the polynomial are always n
and 0
, respectively.) The macro called pn
in the following example satisfies these criteria.
Incidentally, the typographic ellipsis used between binary operators (such as +
) is usually of the form cdots
, not ldots
. (The letters "c" and "l" refer to either centered (on the math line) or low (on the typographic baseline).
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[2]{#1_n #2^n + cdots + #1_1 #2 + #1_0}
begin{document}
$pn{a}{x}$
$pn{lambda}{z}$
$pn{alpha}{xi}$
end{document}
Addendum to address the OP's follow-up request: Suppose that not all polynomials are of order n
, but that it's true that most polynomials are, in fact, order n
. In that case, it makes sense to modify the pn
macro that it takes 3 rather than 2 arguments, with additional argument taking on the value n
by default.
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[3][n]{#2_{#1} #3^{#1} + cdots + #2_1 #3 + #2_0}
begin{document}
$pn{a}{x}$ % use default order (n) of polynomial
$pn[4]{lambda}{z}$
$pn[q]{alpha}{xi}$
end{document}
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of thepn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value isn
.
– Mico
1 hour ago
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
add a comment |
I think that what you need is a macro that takes two arguments: the "name" of the coefficients, and the "name" of the base of the power terms. The names will, in general, be single letters, right? (You've indicated, in a comment, that the highest and lowest order of the polynomial are always n
and 0
, respectively.) The macro called pn
in the following example satisfies these criteria.
Incidentally, the typographic ellipsis used between binary operators (such as +
) is usually of the form cdots
, not ldots
. (The letters "c" and "l" refer to either centered (on the math line) or low (on the typographic baseline).
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[2]{#1_n #2^n + cdots + #1_1 #2 + #1_0}
begin{document}
$pn{a}{x}$
$pn{lambda}{z}$
$pn{alpha}{xi}$
end{document}
Addendum to address the OP's follow-up request: Suppose that not all polynomials are of order n
, but that it's true that most polynomials are, in fact, order n
. In that case, it makes sense to modify the pn
macro that it takes 3 rather than 2 arguments, with additional argument taking on the value n
by default.
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[3][n]{#2_{#1} #3^{#1} + cdots + #2_1 #3 + #2_0}
begin{document}
$pn{a}{x}$ % use default order (n) of polynomial
$pn[4]{lambda}{z}$
$pn[q]{alpha}{xi}$
end{document}
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of thepn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value isn
.
– Mico
1 hour ago
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
add a comment |
I think that what you need is a macro that takes two arguments: the "name" of the coefficients, and the "name" of the base of the power terms. The names will, in general, be single letters, right? (You've indicated, in a comment, that the highest and lowest order of the polynomial are always n
and 0
, respectively.) The macro called pn
in the following example satisfies these criteria.
Incidentally, the typographic ellipsis used between binary operators (such as +
) is usually of the form cdots
, not ldots
. (The letters "c" and "l" refer to either centered (on the math line) or low (on the typographic baseline).
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[2]{#1_n #2^n + cdots + #1_1 #2 + #1_0}
begin{document}
$pn{a}{x}$
$pn{lambda}{z}$
$pn{alpha}{xi}$
end{document}
Addendum to address the OP's follow-up request: Suppose that not all polynomials are of order n
, but that it's true that most polynomials are, in fact, order n
. In that case, it makes sense to modify the pn
macro that it takes 3 rather than 2 arguments, with additional argument taking on the value n
by default.
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[3][n]{#2_{#1} #3^{#1} + cdots + #2_1 #3 + #2_0}
begin{document}
$pn{a}{x}$ % use default order (n) of polynomial
$pn[4]{lambda}{z}$
$pn[q]{alpha}{xi}$
end{document}
I think that what you need is a macro that takes two arguments: the "name" of the coefficients, and the "name" of the base of the power terms. The names will, in general, be single letters, right? (You've indicated, in a comment, that the highest and lowest order of the polynomial are always n
and 0
, respectively.) The macro called pn
in the following example satisfies these criteria.
Incidentally, the typographic ellipsis used between binary operators (such as +
) is usually of the form cdots
, not ldots
. (The letters "c" and "l" refer to either centered (on the math line) or low (on the typographic baseline).
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[2]{#1_n #2^n + cdots + #1_1 #2 + #1_0}
begin{document}
$pn{a}{x}$
$pn{lambda}{z}$
$pn{alpha}{xi}$
end{document}
Addendum to address the OP's follow-up request: Suppose that not all polynomials are of order n
, but that it's true that most polynomials are, in fact, order n
. In that case, it makes sense to modify the pn
macro that it takes 3 rather than 2 arguments, with additional argument taking on the value n
by default.
documentclass{article}
%% The following macro must be used only in math mode:
newcommandpn[3][n]{#2_{#1} #3^{#1} + cdots + #2_1 #3 + #2_0}
begin{document}
$pn{a}{x}$ % use default order (n) of polynomial
$pn[4]{lambda}{z}$
$pn[q]{alpha}{xi}$
end{document}
edited 1 hour ago
answered 2 hours ago
MicoMico
276k30374765
276k30374765
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of thepn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value isn
.
– Mico
1 hour ago
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
add a comment |
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of thepn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value isn
.
– Mico
1 hour ago
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
1
1
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Thank you so much!!! This is great :) (I would upvote, but I need 15 rep pts haha, as soon as I get them I'll take care of it!
– Kam
2 hours ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
Question, if I want to change the variable "n", how should I proceed? I am sorry to bother you again
– Kam
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of the
pn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value is n
.– Mico
1 hour ago
@Kam - Please see the addendum I just posted. In this addendum, I changed the structure of the
pn
macro so that it takes, in addition to the usual two mandatory arguments, an optional argument (to denote the highest order of the polynomial) whose default value is n
.– Mico
1 hour ago
2
2
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
Eternally Grateful! Thanks again :)
– Kam
1 hour ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
+1 for generating enthusiasm :)
– jfbu
35 mins ago
add a comment |
With a fairly simple syntax:
documentclass{article}
usepackage{amsmath}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{poly}{O{}}
{
group_begin:
keys_set:nn { poly } { #1 }
kam_poly:
group_end:
}
keys_define:nn { poly }
{
degree .tl_set:N = l__poly_degree_tl,
var .tl_set:N = l__poly_var_tl,
coef .tl_set:N = l__poly_coef_tl,
reverse .bool_set:N = l__poly_reverse_bool,
degree .initial:n = n,
var .initial:n = x,
coef .initial:n = a,
reverse .default:n = true,
}
cs_new_protected:Nn kam_poly:
{
bool_if:NTF l__poly_reverse_bool
{
l__poly_coef_tl sb { 0 } +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
dots +
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl }
}
{
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl } +
dots +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
l__poly_coef_tl sb { 0 }
}
}
ExplSyntaxOff
begin{document}
$poly$
$poly[var=z]$
$poly[var=t,degree=m,coef=b]$
$poly[var=t,degree=m,coef=b,reverse]$
end{document}
The keys can be specified in any order, freeing you from the need to remember which parameter goes first; the default values are
var = x
degree = n
coef = a
You can also make shorthands with, say
newcommand{polybtn}{poly[var=t,coef=b,degree=n]}
add a comment |
With a fairly simple syntax:
documentclass{article}
usepackage{amsmath}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{poly}{O{}}
{
group_begin:
keys_set:nn { poly } { #1 }
kam_poly:
group_end:
}
keys_define:nn { poly }
{
degree .tl_set:N = l__poly_degree_tl,
var .tl_set:N = l__poly_var_tl,
coef .tl_set:N = l__poly_coef_tl,
reverse .bool_set:N = l__poly_reverse_bool,
degree .initial:n = n,
var .initial:n = x,
coef .initial:n = a,
reverse .default:n = true,
}
cs_new_protected:Nn kam_poly:
{
bool_if:NTF l__poly_reverse_bool
{
l__poly_coef_tl sb { 0 } +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
dots +
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl }
}
{
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl } +
dots +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
l__poly_coef_tl sb { 0 }
}
}
ExplSyntaxOff
begin{document}
$poly$
$poly[var=z]$
$poly[var=t,degree=m,coef=b]$
$poly[var=t,degree=m,coef=b,reverse]$
end{document}
The keys can be specified in any order, freeing you from the need to remember which parameter goes first; the default values are
var = x
degree = n
coef = a
You can also make shorthands with, say
newcommand{polybtn}{poly[var=t,coef=b,degree=n]}
add a comment |
With a fairly simple syntax:
documentclass{article}
usepackage{amsmath}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{poly}{O{}}
{
group_begin:
keys_set:nn { poly } { #1 }
kam_poly:
group_end:
}
keys_define:nn { poly }
{
degree .tl_set:N = l__poly_degree_tl,
var .tl_set:N = l__poly_var_tl,
coef .tl_set:N = l__poly_coef_tl,
reverse .bool_set:N = l__poly_reverse_bool,
degree .initial:n = n,
var .initial:n = x,
coef .initial:n = a,
reverse .default:n = true,
}
cs_new_protected:Nn kam_poly:
{
bool_if:NTF l__poly_reverse_bool
{
l__poly_coef_tl sb { 0 } +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
dots +
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl }
}
{
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl } +
dots +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
l__poly_coef_tl sb { 0 }
}
}
ExplSyntaxOff
begin{document}
$poly$
$poly[var=z]$
$poly[var=t,degree=m,coef=b]$
$poly[var=t,degree=m,coef=b,reverse]$
end{document}
The keys can be specified in any order, freeing you from the need to remember which parameter goes first; the default values are
var = x
degree = n
coef = a
You can also make shorthands with, say
newcommand{polybtn}{poly[var=t,coef=b,degree=n]}
With a fairly simple syntax:
documentclass{article}
usepackage{amsmath}
usepackage{xparse}
ExplSyntaxOn
NewDocumentCommand{poly}{O{}}
{
group_begin:
keys_set:nn { poly } { #1 }
kam_poly:
group_end:
}
keys_define:nn { poly }
{
degree .tl_set:N = l__poly_degree_tl,
var .tl_set:N = l__poly_var_tl,
coef .tl_set:N = l__poly_coef_tl,
reverse .bool_set:N = l__poly_reverse_bool,
degree .initial:n = n,
var .initial:n = x,
coef .initial:n = a,
reverse .default:n = true,
}
cs_new_protected:Nn kam_poly:
{
bool_if:NTF l__poly_reverse_bool
{
l__poly_coef_tl sb { 0 } +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
dots +
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl }
}
{
l__poly_coef_tl sb { l__poly_degree_tl }
l__poly_var_tl sp { l__poly_degree_tl } +
dots +
l__poly_coef_tl sb { 1 } l__poly_var_tl +
l__poly_coef_tl sb { 0 }
}
}
ExplSyntaxOff
begin{document}
$poly$
$poly[var=z]$
$poly[var=t,degree=m,coef=b]$
$poly[var=t,degree=m,coef=b,reverse]$
end{document}
The keys can be specified in any order, freeing you from the need to remember which parameter goes first; the default values are
var = x
degree = n
coef = a
You can also make shorthands with, say
newcommand{polybtn}{poly[var=t,coef=b,degree=n]}
answered 30 mins ago
egregegreg
715k8618983185
715k8618983185
add a comment |
add a comment |
Kam is a new contributor. Be nice, and check out our Code of Conduct.
Kam is a new contributor. Be nice, and check out our Code of Conduct.
Kam is a new contributor. Be nice, and check out our Code of Conduct.
Kam is a new contributor. Be nice, and check out our Code of Conduct.
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Welcome to TeX.SE!
– Mico
2 hours ago
Please tell us more about the "canonical form" of the polynomials you find yourself writing repeatedly. E.g., is the highest order always
n
(w/n>1
, right?) and is the lowest order always0
, i.e., a constant?– Mico
2 hours ago
1
Exactly as you say! and thank you for the warm welcome :) @Mico
– Kam
2 hours ago