Constructions of PRF (Pseudo Random Function)












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I was taught only GGM based PRF construction in class. It's very inefficient. I am just curious about various PRF constructions from standard assumptions. Please provide a few PRF constructions from various assumptions.










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  • $begingroup$
    Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
    $endgroup$
    – Squeamish Ossifrage
    3 hours ago


















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$begingroup$


I was taught only GGM based PRF construction in class. It's very inefficient. I am just curious about various PRF constructions from standard assumptions. Please provide a few PRF constructions from various assumptions.










share|improve this question









$endgroup$












  • $begingroup$
    Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
    $endgroup$
    – Squeamish Ossifrage
    3 hours ago
















2












2








2





$begingroup$


I was taught only GGM based PRF construction in class. It's very inefficient. I am just curious about various PRF constructions from standard assumptions. Please provide a few PRF constructions from various assumptions.










share|improve this question









$endgroup$




I was taught only GGM based PRF construction in class. It's very inefficient. I am just curious about various PRF constructions from standard assumptions. Please provide a few PRF constructions from various assumptions.







pseudo-random-generator pseudo-random-function






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asked 4 hours ago









satyasatya

441317




441317












  • $begingroup$
    Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
    $endgroup$
    – Squeamish Ossifrage
    3 hours ago




















  • $begingroup$
    Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
    $endgroup$
    – Squeamish Ossifrage
    3 hours ago


















$begingroup$
Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
$endgroup$
– Squeamish Ossifrage
3 hours ago






$begingroup$
Well, one standard assumption is that the SHA-256 compression function is a PRF, from which we can conclude that HMAC-SHA256 is a PRF (and a reasonably efficient one at that), but maybe you meant to restrict the domain of ‘standard assumptions’?
$endgroup$
– Squeamish Ossifrage
3 hours ago












1 Answer
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$begingroup$

The most common efficient PRFs from specific assumptions are:



The Naor-Reingold PRF, which is based on the decision Diffie-Hellman assumption (DDH), and



The BPR PRF, which is based on the learning with error assumption (LWE).



Perhaps slightly less well-known is the NRR PRF, which is based on the hardness of factoring.






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    $begingroup$

    The most common efficient PRFs from specific assumptions are:



    The Naor-Reingold PRF, which is based on the decision Diffie-Hellman assumption (DDH), and



    The BPR PRF, which is based on the learning with error assumption (LWE).



    Perhaps slightly less well-known is the NRR PRF, which is based on the hardness of factoring.






    share|improve this answer









    $endgroup$


















      4












      $begingroup$

      The most common efficient PRFs from specific assumptions are:



      The Naor-Reingold PRF, which is based on the decision Diffie-Hellman assumption (DDH), and



      The BPR PRF, which is based on the learning with error assumption (LWE).



      Perhaps slightly less well-known is the NRR PRF, which is based on the hardness of factoring.






      share|improve this answer









      $endgroup$
















        4












        4








        4





        $begingroup$

        The most common efficient PRFs from specific assumptions are:



        The Naor-Reingold PRF, which is based on the decision Diffie-Hellman assumption (DDH), and



        The BPR PRF, which is based on the learning with error assumption (LWE).



        Perhaps slightly less well-known is the NRR PRF, which is based on the hardness of factoring.






        share|improve this answer









        $endgroup$



        The most common efficient PRFs from specific assumptions are:



        The Naor-Reingold PRF, which is based on the decision Diffie-Hellman assumption (DDH), and



        The BPR PRF, which is based on the learning with error assumption (LWE).



        Perhaps slightly less well-known is the NRR PRF, which is based on the hardness of factoring.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 3 hours ago









        Geoffroy CouteauGeoffroy Couteau

        9,29011834




        9,29011834






























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