SVM radial basis generate equation for hyperplane
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I would be very grateful if I could receive some help regarding generating hyperplane equation. I need to generate an equation for hyperplane, I have two independent variables and one binary dependent variable.
Regarding this following equation for svm , f(x)=sgn( sum_i alpha_i K(sv_i,x) + b )
I have two independent variables (say P and Q) with 130 point values for each variable. I used svm radial basis function for binary classification (0 and 1) and I calculated for radial basis kernelized case,and now I have one column of 51 y (i) alpha (i) or (dual coeffficients), two columns of 51 sv (support vectors)for P and Q, and one single value for b . I received these using scikit SVC.
https://scikit-learn.org/stable/modules/svm.html
So, how can I generate the equation now? Can I multiply those 51 y (i) alpha (i) or (dual coeffficients) with 51 sv (support vectors) for each variable P and Q so that I have two coefficients for P and Q so that finally my equation appears as : f(x)=sgn( mP + nQ +b) where m = sum of the (product of 51 sv of P with 51 dual coefficients) and n = sum of the (product of 51 sv of Q with 51 dual coefficients).
i would be grateful for any kind of suggestion. Many thanks in advance.
machine-learning python scikit-learn svm machine-learning-model
New contributor
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add a comment |
$begingroup$
I would be very grateful if I could receive some help regarding generating hyperplane equation. I need to generate an equation for hyperplane, I have two independent variables and one binary dependent variable.
Regarding this following equation for svm , f(x)=sgn( sum_i alpha_i K(sv_i,x) + b )
I have two independent variables (say P and Q) with 130 point values for each variable. I used svm radial basis function for binary classification (0 and 1) and I calculated for radial basis kernelized case,and now I have one column of 51 y (i) alpha (i) or (dual coeffficients), two columns of 51 sv (support vectors)for P and Q, and one single value for b . I received these using scikit SVC.
https://scikit-learn.org/stable/modules/svm.html
So, how can I generate the equation now? Can I multiply those 51 y (i) alpha (i) or (dual coeffficients) with 51 sv (support vectors) for each variable P and Q so that I have two coefficients for P and Q so that finally my equation appears as : f(x)=sgn( mP + nQ +b) where m = sum of the (product of 51 sv of P with 51 dual coefficients) and n = sum of the (product of 51 sv of Q with 51 dual coefficients).
i would be grateful for any kind of suggestion. Many thanks in advance.
machine-learning python scikit-learn svm machine-learning-model
New contributor
$endgroup$
add a comment |
$begingroup$
I would be very grateful if I could receive some help regarding generating hyperplane equation. I need to generate an equation for hyperplane, I have two independent variables and one binary dependent variable.
Regarding this following equation for svm , f(x)=sgn( sum_i alpha_i K(sv_i,x) + b )
I have two independent variables (say P and Q) with 130 point values for each variable. I used svm radial basis function for binary classification (0 and 1) and I calculated for radial basis kernelized case,and now I have one column of 51 y (i) alpha (i) or (dual coeffficients), two columns of 51 sv (support vectors)for P and Q, and one single value for b . I received these using scikit SVC.
https://scikit-learn.org/stable/modules/svm.html
So, how can I generate the equation now? Can I multiply those 51 y (i) alpha (i) or (dual coeffficients) with 51 sv (support vectors) for each variable P and Q so that I have two coefficients for P and Q so that finally my equation appears as : f(x)=sgn( mP + nQ +b) where m = sum of the (product of 51 sv of P with 51 dual coefficients) and n = sum of the (product of 51 sv of Q with 51 dual coefficients).
i would be grateful for any kind of suggestion. Many thanks in advance.
machine-learning python scikit-learn svm machine-learning-model
New contributor
$endgroup$
I would be very grateful if I could receive some help regarding generating hyperplane equation. I need to generate an equation for hyperplane, I have two independent variables and one binary dependent variable.
Regarding this following equation for svm , f(x)=sgn( sum_i alpha_i K(sv_i,x) + b )
I have two independent variables (say P and Q) with 130 point values for each variable. I used svm radial basis function for binary classification (0 and 1) and I calculated for radial basis kernelized case,and now I have one column of 51 y (i) alpha (i) or (dual coeffficients), two columns of 51 sv (support vectors)for P and Q, and one single value for b . I received these using scikit SVC.
https://scikit-learn.org/stable/modules/svm.html
So, how can I generate the equation now? Can I multiply those 51 y (i) alpha (i) or (dual coeffficients) with 51 sv (support vectors) for each variable P and Q so that I have two coefficients for P and Q so that finally my equation appears as : f(x)=sgn( mP + nQ +b) where m = sum of the (product of 51 sv of P with 51 dual coefficients) and n = sum of the (product of 51 sv of Q with 51 dual coefficients).
i would be grateful for any kind of suggestion. Many thanks in advance.
machine-learning python scikit-learn svm machine-learning-model
machine-learning python scikit-learn svm machine-learning-model
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Alejandro Alejandro
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I'm not sure if I've fully understood you. Radial basis kernel assumes that you transform your features into an infinite space and the dot product of your transformed vectors is exactly the radial basis kernel.
$k(x,y)=phi(x)cdot phi(y)$
$phi(x)$ - mapping
The main reason for using a kernel trick is the ability to transform features into higher dimensions without knowing the map function explicitly. Your hyperplane has infinite number of coefficients. You can always expend the radial basis kernel into Taylor series and get some of the initial coefficients.
New contributor
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Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
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– Alejandro
22 hours ago
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$begingroup$
I'm not sure if I've fully understood you. Radial basis kernel assumes that you transform your features into an infinite space and the dot product of your transformed vectors is exactly the radial basis kernel.
$k(x,y)=phi(x)cdot phi(y)$
$phi(x)$ - mapping
The main reason for using a kernel trick is the ability to transform features into higher dimensions without knowing the map function explicitly. Your hyperplane has infinite number of coefficients. You can always expend the radial basis kernel into Taylor series and get some of the initial coefficients.
New contributor
$endgroup$
$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
add a comment |
$begingroup$
I'm not sure if I've fully understood you. Radial basis kernel assumes that you transform your features into an infinite space and the dot product of your transformed vectors is exactly the radial basis kernel.
$k(x,y)=phi(x)cdot phi(y)$
$phi(x)$ - mapping
The main reason for using a kernel trick is the ability to transform features into higher dimensions without knowing the map function explicitly. Your hyperplane has infinite number of coefficients. You can always expend the radial basis kernel into Taylor series and get some of the initial coefficients.
New contributor
$endgroup$
$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
add a comment |
$begingroup$
I'm not sure if I've fully understood you. Radial basis kernel assumes that you transform your features into an infinite space and the dot product of your transformed vectors is exactly the radial basis kernel.
$k(x,y)=phi(x)cdot phi(y)$
$phi(x)$ - mapping
The main reason for using a kernel trick is the ability to transform features into higher dimensions without knowing the map function explicitly. Your hyperplane has infinite number of coefficients. You can always expend the radial basis kernel into Taylor series and get some of the initial coefficients.
New contributor
$endgroup$
I'm not sure if I've fully understood you. Radial basis kernel assumes that you transform your features into an infinite space and the dot product of your transformed vectors is exactly the radial basis kernel.
$k(x,y)=phi(x)cdot phi(y)$
$phi(x)$ - mapping
The main reason for using a kernel trick is the ability to transform features into higher dimensions without knowing the map function explicitly. Your hyperplane has infinite number of coefficients. You can always expend the radial basis kernel into Taylor series and get some of the initial coefficients.
New contributor
edited yesterday
New contributor
answered yesterday
Michał KardachMichał Kardach
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$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
add a comment |
$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
$begingroup$
Lets say i have two independent variables (P and Q) and a binary variable C. i use logistic regression to calculate individual coefficients of P and Q (m,n) plus a constant( b). The equation of generalized linear model will be (mP + nQ + b). I can now use this equation to calculate probabilities. Similarly, if I use support vector, how to get this kind of generalised linear model equation? I have used scikit in Python and also R, all i get is total number of support vectors and their values and value for (alpha (i) x X(i)).
$endgroup$
– Alejandro
22 hours ago
add a comment |
Alejandro is a new contributor. Be nice, and check out our Code of Conduct.
Alejandro is a new contributor. Be nice, and check out our Code of Conduct.
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