How do I make numbers 50-100 using only the numbers 2, 0, 1, 9?












5












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Rules

Use ALL the digits in the year $2019$ (you may not use any other numbers except $2, 0, 1, 9$) to write mathematical expressions that give results for the numbers 50 to 100.



You may use the arithmetic operations $+$, $-$, $times$, $sqrt{}$, and $!$ (see below).
Indices or exponents may only be made from the digits $2, 0, 1,$ and $9$; for example, $(9+1)^2 $is allowed, as it has used the $9$, $1$ and $2$. Multi-digit numbers and decimals points can be used such as $20$, $102$, and $.02$, but you CANNOT make 30 by combining $(2+1)0$.



Recurring decimals can be used using the overhead dots or bar e.g. $0.bar1=0.111 ...=frac19$



Factorials are allowed

Here's how you might use factorials:



$n!=ntimes(n-1)times(n-2)timesdotstimes2times1$



For example
$(10-9+2)!=3!=3times2times1=6$
$0!=1$










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$endgroup$












  • $begingroup$
    So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
    $endgroup$
    – Brandon_J
    Jan 9 at 20:23
















5












$begingroup$


Rules

Use ALL the digits in the year $2019$ (you may not use any other numbers except $2, 0, 1, 9$) to write mathematical expressions that give results for the numbers 50 to 100.



You may use the arithmetic operations $+$, $-$, $times$, $sqrt{}$, and $!$ (see below).
Indices or exponents may only be made from the digits $2, 0, 1,$ and $9$; for example, $(9+1)^2 $is allowed, as it has used the $9$, $1$ and $2$. Multi-digit numbers and decimals points can be used such as $20$, $102$, and $.02$, but you CANNOT make 30 by combining $(2+1)0$.



Recurring decimals can be used using the overhead dots or bar e.g. $0.bar1=0.111 ...=frac19$



Factorials are allowed

Here's how you might use factorials:



$n!=ntimes(n-1)times(n-2)timesdotstimes2times1$



For example
$(10-9+2)!=3!=3times2times1=6$
$0!=1$










share|improve this question











$endgroup$












  • $begingroup$
    So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
    $endgroup$
    – Brandon_J
    Jan 9 at 20:23














5












5








5





$begingroup$


Rules

Use ALL the digits in the year $2019$ (you may not use any other numbers except $2, 0, 1, 9$) to write mathematical expressions that give results for the numbers 50 to 100.



You may use the arithmetic operations $+$, $-$, $times$, $sqrt{}$, and $!$ (see below).
Indices or exponents may only be made from the digits $2, 0, 1,$ and $9$; for example, $(9+1)^2 $is allowed, as it has used the $9$, $1$ and $2$. Multi-digit numbers and decimals points can be used such as $20$, $102$, and $.02$, but you CANNOT make 30 by combining $(2+1)0$.



Recurring decimals can be used using the overhead dots or bar e.g. $0.bar1=0.111 ...=frac19$



Factorials are allowed

Here's how you might use factorials:



$n!=ntimes(n-1)times(n-2)timesdotstimes2times1$



For example
$(10-9+2)!=3!=3times2times1=6$
$0!=1$










share|improve this question











$endgroup$




Rules

Use ALL the digits in the year $2019$ (you may not use any other numbers except $2, 0, 1, 9$) to write mathematical expressions that give results for the numbers 50 to 100.



You may use the arithmetic operations $+$, $-$, $times$, $sqrt{}$, and $!$ (see below).
Indices or exponents may only be made from the digits $2, 0, 1,$ and $9$; for example, $(9+1)^2 $is allowed, as it has used the $9$, $1$ and $2$. Multi-digit numbers and decimals points can be used such as $20$, $102$, and $.02$, but you CANNOT make 30 by combining $(2+1)0$.



Recurring decimals can be used using the overhead dots or bar e.g. $0.bar1=0.111 ...=frac19$



Factorials are allowed

Here's how you might use factorials:



$n!=ntimes(n-1)times(n-2)timesdotstimes2times1$



For example
$(10-9+2)!=3!=3times2times1=6$
$0!=1$







calculation-puzzle






share|improve this question















share|improve this question













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share|improve this question








edited Jan 9 at 19:23









Sesquipedalian

357




357










asked Jan 9 at 14:10









jamalewisjamalewis

261




261












  • $begingroup$
    So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
    $endgroup$
    – Brandon_J
    Jan 9 at 20:23


















  • $begingroup$
    So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
    $endgroup$
    – Brandon_J
    Jan 9 at 20:23
















$begingroup$
So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
$endgroup$
– Brandon_J
Jan 9 at 20:23




$begingroup$
So...can we use the square root operator AND the cube root operator? I know that there is a three in the cube root, but there is also an implied two in square root.
$endgroup$
– Brandon_J
Jan 9 at 20:23










5 Answers
5






active

oldest

votes


















4












$begingroup$

Here are answers for all numbers. I'm going to try to find better answers for 76 and 86 because not only is it dumb trying to read multifactorials, but Wolfram Alpha can't even calculate anything past double factorials.




50: $10 * (sqrt9 + 2)$

51: $((sqrt9)!)!! + 2 + 1 + 0$

52: $((sqrt9)!)!! + 2 + 1 + 0!$

53: $9 * (2 + 1)! - 0!$

54: $9 * (2 + 1)! + 0$

55: $9 * (2 + 1)! + 0!$

56: $((sqrt9)!)!! + (2 + 1 + 0!)!!$

57: $19 * (2 + 0!)$

58: $10 * (sqrt9)! - 2$

59: $20 * sqrt9 - 1$

60: $20 * sqrt9 * 1$

61: $20 * sqrt9 + 1$

62: $10 * (sqrt9)! + 2$

63: $21 * sqrt9 + 0$

64: $(9 - 1)^2 + 0$

65: $2^{(sqrt9)!} + 1 + 0$

66: $2^{(sqrt9)!} + 1 + 0!$

67: $((sqrt9)!)!! + 20 - 1$

68: $((sqrt9)!)!! + 21 - 0!$

69: $90 - 21$

70: $10 * (9 - 2)$

71: $91 - 20$

72: $12 * (sqrt9)! + 0$

73: $12 * (sqrt9)! + 0!$

74: $((sqrt9)!)! * .1 + 2 + 0$

75: $((sqrt9)!)! * .1 + 2 + 0!$

76: $21!!!!!!!!!!!!!!!!! - 9 + 0!$

77: $((sqrt9)!)! * (.bar1) - 2 - 0!$

78: $90 - 12$

79: $9^2 - 1 - 0!$

80: $9^2 - 1 + 0$

81: $9^2 + (1 * 0)$

82: $9^2 + 1 + 0$

83: $9^2 + 1 + 0!$

84: $90 - (2 + 1)!$

85: $91 - (2 + 0!)!$

86: $(20 - 1)!!!!!!!!!!!!!! - 9$

87: $90 - 2 - 1$

88: $90 - (2 * 1)$

89: $90 - 2 + 1$

90: $92 - 1 - 0!$

91: $91 + (2 * 0)$

92: $92 + (1 * 0)$

93: $92 + 1 + 0$

94: $92 + 1 + 0!$

95: $((sqrt9)!)!! * 2 - 1 + 0$

96: $90 + (2 + 1)!$

97: $91 + (2 + 0!)!$

98: $((sqrt9)!)!! * 2 + 1 + 0!$

99: $(9 + 1)^2 - 0!$

100: $(9 + 1)^2 + 0$







share|improve this answer











$endgroup$













  • $begingroup$
    Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
    $endgroup$
    – Meerkat
    Jan 10 at 18:03










  • $begingroup$
    Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
    $endgroup$
    – Weather Vane
    Jan 10 at 18:08










  • $begingroup$
    Also solved 67 and 68, see my answer.
    $endgroup$
    – Weather Vane
    Jan 10 at 18:36



















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$begingroup$

Here are two more solutions:




67 = $((sqrt 9)!)!! + 20 - 1$

68 = $((sqrt 9)!)!! + 21 - 0!$







share|improve this answer









$endgroup$









  • 1




    $begingroup$
    This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
    $endgroup$
    – Meerkat
    Jan 10 at 18:46



















2












$begingroup$

some solutions without double factorials



51:




$ .02^{-1} + .bar9 $




52:




$ (sqrt9)! * (.bar1)^{-0!} - 2 $




56:




$ .02^{-1} + (sqrt9)! $




67:




$ ((sqrt9)!)! * .1 - .2^{-0!} $




76:




$ .bar1^{-2} - (sqrt9)! + 0! $




86:




$ 91 - .2^{-0!} $




95:




$ 19 * .2^{-0!} $




98:




$ .1^{-2} + 0! - sqrt9 $







share|improve this answer










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$endgroup$





















    0












    $begingroup$

    Hope few of my solutions (not mentioned before) will help you. It's not an easy task and I'm curious if it's even possible to come up with each of them.



    54:




    $54 = 9*1*(2+0!)!$




    64:




    $64 = (9-1)^2+0$




    71:




    $71 = 91 - 20$




    76:




    $76 = 19 * (2 + 1 + 0!)$




    81:




    $81 = sqrt{9}^{(2^{(0!+1)})}$




    82:




    $82 = 92 - 10$




    95:




    $95 = 190 / 2$




    99:




    $99 = (9+1)-0!$







    share|improve this answer











    $endgroup$













    • $begingroup$
      76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
      $endgroup$
      – Meerkat
      Jan 9 at 15:55










    • $begingroup$
      The last one is missing $2$ possibly just a typo.
      $endgroup$
      – Weather Vane
      Jan 9 at 18:25



















    0












    $begingroup$

    Partial, only a few numbers so far:




    50 =

    51 =

    52 =

    53 =

    54 =

    55 =

    56 =

    57 = $19 * (2+0!)$

    58 = $29 * (1+0!)$

    59 =

    60 =

    61 =

    62 =

    63 =

    64 =

    65 =

    66 =

    67 =

    68 =

    69 =

    70 = $(9-2) * 10$

    71 = $91 - 20$

    72 =

    73 =

    74 =

    75 =

    76 =

    77 =

    78 =

    79 = $91 - (0! + 2)$

    80 =

    81 =

    82 = $92 - 10$

    83 =

    84 = $90 - (1 + 2)!$

    85 =

    86 =

    87 = $90 - 1 - 2$

    88 = $91 - 2 - 0!$

    89 = $91 - 2 - 0$

    90 = $92 - (1+0!)$

    91 = $91 + 0 * 2$

    92 = $92 + 1 * 0$

    93 = $90 + 1 + 2$

    94 = $91 + 2 + 0!$

    95 =

    96 = $90 + (1 + 2)!$

    97 = $91 + (0! + 2)!$

    98 =

    99 =

    100 =







    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
      $endgroup$
      – Meerkat
      Jan 9 at 16:41






    • 1




      $begingroup$
      79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
      $endgroup$
      – Yout Ried
      Jan 11 at 2:09











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    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4












    $begingroup$

    Here are answers for all numbers. I'm going to try to find better answers for 76 and 86 because not only is it dumb trying to read multifactorials, but Wolfram Alpha can't even calculate anything past double factorials.




    50: $10 * (sqrt9 + 2)$

    51: $((sqrt9)!)!! + 2 + 1 + 0$

    52: $((sqrt9)!)!! + 2 + 1 + 0!$

    53: $9 * (2 + 1)! - 0!$

    54: $9 * (2 + 1)! + 0$

    55: $9 * (2 + 1)! + 0!$

    56: $((sqrt9)!)!! + (2 + 1 + 0!)!!$

    57: $19 * (2 + 0!)$

    58: $10 * (sqrt9)! - 2$

    59: $20 * sqrt9 - 1$

    60: $20 * sqrt9 * 1$

    61: $20 * sqrt9 + 1$

    62: $10 * (sqrt9)! + 2$

    63: $21 * sqrt9 + 0$

    64: $(9 - 1)^2 + 0$

    65: $2^{(sqrt9)!} + 1 + 0$

    66: $2^{(sqrt9)!} + 1 + 0!$

    67: $((sqrt9)!)!! + 20 - 1$

    68: $((sqrt9)!)!! + 21 - 0!$

    69: $90 - 21$

    70: $10 * (9 - 2)$

    71: $91 - 20$

    72: $12 * (sqrt9)! + 0$

    73: $12 * (sqrt9)! + 0!$

    74: $((sqrt9)!)! * .1 + 2 + 0$

    75: $((sqrt9)!)! * .1 + 2 + 0!$

    76: $21!!!!!!!!!!!!!!!!! - 9 + 0!$

    77: $((sqrt9)!)! * (.bar1) - 2 - 0!$

    78: $90 - 12$

    79: $9^2 - 1 - 0!$

    80: $9^2 - 1 + 0$

    81: $9^2 + (1 * 0)$

    82: $9^2 + 1 + 0$

    83: $9^2 + 1 + 0!$

    84: $90 - (2 + 1)!$

    85: $91 - (2 + 0!)!$

    86: $(20 - 1)!!!!!!!!!!!!!! - 9$

    87: $90 - 2 - 1$

    88: $90 - (2 * 1)$

    89: $90 - 2 + 1$

    90: $92 - 1 - 0!$

    91: $91 + (2 * 0)$

    92: $92 + (1 * 0)$

    93: $92 + 1 + 0$

    94: $92 + 1 + 0!$

    95: $((sqrt9)!)!! * 2 - 1 + 0$

    96: $90 + (2 + 1)!$

    97: $91 + (2 + 0!)!$

    98: $((sqrt9)!)!! * 2 + 1 + 0!$

    99: $(9 + 1)^2 - 0!$

    100: $(9 + 1)^2 + 0$







    share|improve this answer











    $endgroup$













    • $begingroup$
      Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
      $endgroup$
      – Meerkat
      Jan 10 at 18:03










    • $begingroup$
      Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
      $endgroup$
      – Weather Vane
      Jan 10 at 18:08










    • $begingroup$
      Also solved 67 and 68, see my answer.
      $endgroup$
      – Weather Vane
      Jan 10 at 18:36
















    4












    $begingroup$

    Here are answers for all numbers. I'm going to try to find better answers for 76 and 86 because not only is it dumb trying to read multifactorials, but Wolfram Alpha can't even calculate anything past double factorials.




    50: $10 * (sqrt9 + 2)$

    51: $((sqrt9)!)!! + 2 + 1 + 0$

    52: $((sqrt9)!)!! + 2 + 1 + 0!$

    53: $9 * (2 + 1)! - 0!$

    54: $9 * (2 + 1)! + 0$

    55: $9 * (2 + 1)! + 0!$

    56: $((sqrt9)!)!! + (2 + 1 + 0!)!!$

    57: $19 * (2 + 0!)$

    58: $10 * (sqrt9)! - 2$

    59: $20 * sqrt9 - 1$

    60: $20 * sqrt9 * 1$

    61: $20 * sqrt9 + 1$

    62: $10 * (sqrt9)! + 2$

    63: $21 * sqrt9 + 0$

    64: $(9 - 1)^2 + 0$

    65: $2^{(sqrt9)!} + 1 + 0$

    66: $2^{(sqrt9)!} + 1 + 0!$

    67: $((sqrt9)!)!! + 20 - 1$

    68: $((sqrt9)!)!! + 21 - 0!$

    69: $90 - 21$

    70: $10 * (9 - 2)$

    71: $91 - 20$

    72: $12 * (sqrt9)! + 0$

    73: $12 * (sqrt9)! + 0!$

    74: $((sqrt9)!)! * .1 + 2 + 0$

    75: $((sqrt9)!)! * .1 + 2 + 0!$

    76: $21!!!!!!!!!!!!!!!!! - 9 + 0!$

    77: $((sqrt9)!)! * (.bar1) - 2 - 0!$

    78: $90 - 12$

    79: $9^2 - 1 - 0!$

    80: $9^2 - 1 + 0$

    81: $9^2 + (1 * 0)$

    82: $9^2 + 1 + 0$

    83: $9^2 + 1 + 0!$

    84: $90 - (2 + 1)!$

    85: $91 - (2 + 0!)!$

    86: $(20 - 1)!!!!!!!!!!!!!! - 9$

    87: $90 - 2 - 1$

    88: $90 - (2 * 1)$

    89: $90 - 2 + 1$

    90: $92 - 1 - 0!$

    91: $91 + (2 * 0)$

    92: $92 + (1 * 0)$

    93: $92 + 1 + 0$

    94: $92 + 1 + 0!$

    95: $((sqrt9)!)!! * 2 - 1 + 0$

    96: $90 + (2 + 1)!$

    97: $91 + (2 + 0!)!$

    98: $((sqrt9)!)!! * 2 + 1 + 0!$

    99: $(9 + 1)^2 - 0!$

    100: $(9 + 1)^2 + 0$







    share|improve this answer











    $endgroup$













    • $begingroup$
      Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
      $endgroup$
      – Meerkat
      Jan 10 at 18:03










    • $begingroup$
      Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
      $endgroup$
      – Weather Vane
      Jan 10 at 18:08










    • $begingroup$
      Also solved 67 and 68, see my answer.
      $endgroup$
      – Weather Vane
      Jan 10 at 18:36














    4












    4








    4





    $begingroup$

    Here are answers for all numbers. I'm going to try to find better answers for 76 and 86 because not only is it dumb trying to read multifactorials, but Wolfram Alpha can't even calculate anything past double factorials.




    50: $10 * (sqrt9 + 2)$

    51: $((sqrt9)!)!! + 2 + 1 + 0$

    52: $((sqrt9)!)!! + 2 + 1 + 0!$

    53: $9 * (2 + 1)! - 0!$

    54: $9 * (2 + 1)! + 0$

    55: $9 * (2 + 1)! + 0!$

    56: $((sqrt9)!)!! + (2 + 1 + 0!)!!$

    57: $19 * (2 + 0!)$

    58: $10 * (sqrt9)! - 2$

    59: $20 * sqrt9 - 1$

    60: $20 * sqrt9 * 1$

    61: $20 * sqrt9 + 1$

    62: $10 * (sqrt9)! + 2$

    63: $21 * sqrt9 + 0$

    64: $(9 - 1)^2 + 0$

    65: $2^{(sqrt9)!} + 1 + 0$

    66: $2^{(sqrt9)!} + 1 + 0!$

    67: $((sqrt9)!)!! + 20 - 1$

    68: $((sqrt9)!)!! + 21 - 0!$

    69: $90 - 21$

    70: $10 * (9 - 2)$

    71: $91 - 20$

    72: $12 * (sqrt9)! + 0$

    73: $12 * (sqrt9)! + 0!$

    74: $((sqrt9)!)! * .1 + 2 + 0$

    75: $((sqrt9)!)! * .1 + 2 + 0!$

    76: $21!!!!!!!!!!!!!!!!! - 9 + 0!$

    77: $((sqrt9)!)! * (.bar1) - 2 - 0!$

    78: $90 - 12$

    79: $9^2 - 1 - 0!$

    80: $9^2 - 1 + 0$

    81: $9^2 + (1 * 0)$

    82: $9^2 + 1 + 0$

    83: $9^2 + 1 + 0!$

    84: $90 - (2 + 1)!$

    85: $91 - (2 + 0!)!$

    86: $(20 - 1)!!!!!!!!!!!!!! - 9$

    87: $90 - 2 - 1$

    88: $90 - (2 * 1)$

    89: $90 - 2 + 1$

    90: $92 - 1 - 0!$

    91: $91 + (2 * 0)$

    92: $92 + (1 * 0)$

    93: $92 + 1 + 0$

    94: $92 + 1 + 0!$

    95: $((sqrt9)!)!! * 2 - 1 + 0$

    96: $90 + (2 + 1)!$

    97: $91 + (2 + 0!)!$

    98: $((sqrt9)!)!! * 2 + 1 + 0!$

    99: $(9 + 1)^2 - 0!$

    100: $(9 + 1)^2 + 0$







    share|improve this answer











    $endgroup$



    Here are answers for all numbers. I'm going to try to find better answers for 76 and 86 because not only is it dumb trying to read multifactorials, but Wolfram Alpha can't even calculate anything past double factorials.




    50: $10 * (sqrt9 + 2)$

    51: $((sqrt9)!)!! + 2 + 1 + 0$

    52: $((sqrt9)!)!! + 2 + 1 + 0!$

    53: $9 * (2 + 1)! - 0!$

    54: $9 * (2 + 1)! + 0$

    55: $9 * (2 + 1)! + 0!$

    56: $((sqrt9)!)!! + (2 + 1 + 0!)!!$

    57: $19 * (2 + 0!)$

    58: $10 * (sqrt9)! - 2$

    59: $20 * sqrt9 - 1$

    60: $20 * sqrt9 * 1$

    61: $20 * sqrt9 + 1$

    62: $10 * (sqrt9)! + 2$

    63: $21 * sqrt9 + 0$

    64: $(9 - 1)^2 + 0$

    65: $2^{(sqrt9)!} + 1 + 0$

    66: $2^{(sqrt9)!} + 1 + 0!$

    67: $((sqrt9)!)!! + 20 - 1$

    68: $((sqrt9)!)!! + 21 - 0!$

    69: $90 - 21$

    70: $10 * (9 - 2)$

    71: $91 - 20$

    72: $12 * (sqrt9)! + 0$

    73: $12 * (sqrt9)! + 0!$

    74: $((sqrt9)!)! * .1 + 2 + 0$

    75: $((sqrt9)!)! * .1 + 2 + 0!$

    76: $21!!!!!!!!!!!!!!!!! - 9 + 0!$

    77: $((sqrt9)!)! * (.bar1) - 2 - 0!$

    78: $90 - 12$

    79: $9^2 - 1 - 0!$

    80: $9^2 - 1 + 0$

    81: $9^2 + (1 * 0)$

    82: $9^2 + 1 + 0$

    83: $9^2 + 1 + 0!$

    84: $90 - (2 + 1)!$

    85: $91 - (2 + 0!)!$

    86: $(20 - 1)!!!!!!!!!!!!!! - 9$

    87: $90 - 2 - 1$

    88: $90 - (2 * 1)$

    89: $90 - 2 + 1$

    90: $92 - 1 - 0!$

    91: $91 + (2 * 0)$

    92: $92 + (1 * 0)$

    93: $92 + 1 + 0$

    94: $92 + 1 + 0!$

    95: $((sqrt9)!)!! * 2 - 1 + 0$

    96: $90 + (2 + 1)!$

    97: $91 + (2 + 0!)!$

    98: $((sqrt9)!)!! * 2 + 1 + 0!$

    99: $(9 + 1)^2 - 0!$

    100: $(9 + 1)^2 + 0$








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 10 at 18:49

























    answered Jan 9 at 16:04









    MeerkatMeerkat

    35011




    35011












    • $begingroup$
      Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
      $endgroup$
      – Meerkat
      Jan 10 at 18:03










    • $begingroup$
      Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
      $endgroup$
      – Weather Vane
      Jan 10 at 18:08










    • $begingroup$
      Also solved 67 and 68, see my answer.
      $endgroup$
      – Weather Vane
      Jan 10 at 18:36


















    • $begingroup$
      Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
      $endgroup$
      – Meerkat
      Jan 10 at 18:03










    • $begingroup$
      Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
      $endgroup$
      – Weather Vane
      Jan 10 at 18:08










    • $begingroup$
      Also solved 67 and 68, see my answer.
      $endgroup$
      – Weather Vane
      Jan 10 at 18:36
















    $begingroup$
    Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
    $endgroup$
    – Meerkat
    Jan 10 at 18:03




    $begingroup$
    Yes, apologies. Though reminding me of double factorials opens up some new possibilities I hadn't thought of...
    $endgroup$
    – Meerkat
    Jan 10 at 18:03












    $begingroup$
    Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
    $endgroup$
    – Weather Vane
    Jan 10 at 18:08




    $begingroup$
    Yes, 51 = $((sqrt 9)!)!! + 2 + 1 + 0$
    $endgroup$
    – Weather Vane
    Jan 10 at 18:08












    $begingroup$
    Also solved 67 and 68, see my answer.
    $endgroup$
    – Weather Vane
    Jan 10 at 18:36




    $begingroup$
    Also solved 67 and 68, see my answer.
    $endgroup$
    – Weather Vane
    Jan 10 at 18:36











    2












    $begingroup$

    Here are two more solutions:




    67 = $((sqrt 9)!)!! + 20 - 1$

    68 = $((sqrt 9)!)!! + 21 - 0!$







    share|improve this answer









    $endgroup$









    • 1




      $begingroup$
      This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
      $endgroup$
      – Meerkat
      Jan 10 at 18:46
















    2












    $begingroup$

    Here are two more solutions:




    67 = $((sqrt 9)!)!! + 20 - 1$

    68 = $((sqrt 9)!)!! + 21 - 0!$







    share|improve this answer









    $endgroup$









    • 1




      $begingroup$
      This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
      $endgroup$
      – Meerkat
      Jan 10 at 18:46














    2












    2








    2





    $begingroup$

    Here are two more solutions:




    67 = $((sqrt 9)!)!! + 20 - 1$

    68 = $((sqrt 9)!)!! + 21 - 0!$







    share|improve this answer









    $endgroup$



    Here are two more solutions:




    67 = $((sqrt 9)!)!! + 20 - 1$

    68 = $((sqrt 9)!)!! + 21 - 0!$








    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 10 at 18:35









    Weather VaneWeather Vane

    1,17719




    1,17719








    • 1




      $begingroup$
      This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
      $endgroup$
      – Meerkat
      Jan 10 at 18:46














    • 1




      $begingroup$
      This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
      $endgroup$
      – Meerkat
      Jan 10 at 18:46








    1




    1




    $begingroup$
    This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
    $endgroup$
    – Meerkat
    Jan 10 at 18:46




    $begingroup$
    This is much more elegant than my answer for those two were going to be. I had $67 = 12!!!!!!! + (sqrt9)! + 0!$ and $68 = (12 + 0!)!!!!!!!! + sqrt9$, which are terribly unreadable.
    $endgroup$
    – Meerkat
    Jan 10 at 18:46











    2












    $begingroup$

    some solutions without double factorials



    51:




    $ .02^{-1} + .bar9 $




    52:




    $ (sqrt9)! * (.bar1)^{-0!} - 2 $




    56:




    $ .02^{-1} + (sqrt9)! $




    67:




    $ ((sqrt9)!)! * .1 - .2^{-0!} $




    76:




    $ .bar1^{-2} - (sqrt9)! + 0! $




    86:




    $ 91 - .2^{-0!} $




    95:




    $ 19 * .2^{-0!} $




    98:




    $ .1^{-2} + 0! - sqrt9 $







    share|improve this answer










    New contributor




    Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$


















      2












      $begingroup$

      some solutions without double factorials



      51:




      $ .02^{-1} + .bar9 $




      52:




      $ (sqrt9)! * (.bar1)^{-0!} - 2 $




      56:




      $ .02^{-1} + (sqrt9)! $




      67:




      $ ((sqrt9)!)! * .1 - .2^{-0!} $




      76:




      $ .bar1^{-2} - (sqrt9)! + 0! $




      86:




      $ 91 - .2^{-0!} $




      95:




      $ 19 * .2^{-0!} $




      98:




      $ .1^{-2} + 0! - sqrt9 $







      share|improve this answer










      New contributor




      Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$
















        2












        2








        2





        $begingroup$

        some solutions without double factorials



        51:




        $ .02^{-1} + .bar9 $




        52:




        $ (sqrt9)! * (.bar1)^{-0!} - 2 $




        56:




        $ .02^{-1} + (sqrt9)! $




        67:




        $ ((sqrt9)!)! * .1 - .2^{-0!} $




        76:




        $ .bar1^{-2} - (sqrt9)! + 0! $




        86:




        $ 91 - .2^{-0!} $




        95:




        $ 19 * .2^{-0!} $




        98:




        $ .1^{-2} + 0! - sqrt9 $







        share|improve this answer










        New contributor




        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        $endgroup$



        some solutions without double factorials



        51:




        $ .02^{-1} + .bar9 $




        52:




        $ (sqrt9)! * (.bar1)^{-0!} - 2 $




        56:




        $ .02^{-1} + (sqrt9)! $




        67:




        $ ((sqrt9)!)! * .1 - .2^{-0!} $




        76:




        $ .bar1^{-2} - (sqrt9)! + 0! $




        86:




        $ 91 - .2^{-0!} $




        95:




        $ 19 * .2^{-0!} $




        98:




        $ .1^{-2} + 0! - sqrt9 $








        share|improve this answer










        New contributor




        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer








        edited 8 hours ago





















        New contributor




        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered Jan 12 at 4:22









        Jonathan LangJonathan Lang

        213




        213




        New contributor




        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        Jonathan Lang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.























            0












            $begingroup$

            Hope few of my solutions (not mentioned before) will help you. It's not an easy task and I'm curious if it's even possible to come up with each of them.



            54:




            $54 = 9*1*(2+0!)!$




            64:




            $64 = (9-1)^2+0$




            71:




            $71 = 91 - 20$




            76:




            $76 = 19 * (2 + 1 + 0!)$




            81:




            $81 = sqrt{9}^{(2^{(0!+1)})}$




            82:




            $82 = 92 - 10$




            95:




            $95 = 190 / 2$




            99:




            $99 = (9+1)-0!$







            share|improve this answer











            $endgroup$













            • $begingroup$
              76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
              $endgroup$
              – Meerkat
              Jan 9 at 15:55










            • $begingroup$
              The last one is missing $2$ possibly just a typo.
              $endgroup$
              – Weather Vane
              Jan 9 at 18:25
















            0












            $begingroup$

            Hope few of my solutions (not mentioned before) will help you. It's not an easy task and I'm curious if it's even possible to come up with each of them.



            54:




            $54 = 9*1*(2+0!)!$




            64:




            $64 = (9-1)^2+0$




            71:




            $71 = 91 - 20$




            76:




            $76 = 19 * (2 + 1 + 0!)$




            81:




            $81 = sqrt{9}^{(2^{(0!+1)})}$




            82:




            $82 = 92 - 10$




            95:




            $95 = 190 / 2$




            99:




            $99 = (9+1)-0!$







            share|improve this answer











            $endgroup$













            • $begingroup$
              76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
              $endgroup$
              – Meerkat
              Jan 9 at 15:55










            • $begingroup$
              The last one is missing $2$ possibly just a typo.
              $endgroup$
              – Weather Vane
              Jan 9 at 18:25














            0












            0








            0





            $begingroup$

            Hope few of my solutions (not mentioned before) will help you. It's not an easy task and I'm curious if it's even possible to come up with each of them.



            54:




            $54 = 9*1*(2+0!)!$




            64:




            $64 = (9-1)^2+0$




            71:




            $71 = 91 - 20$




            76:




            $76 = 19 * (2 + 1 + 0!)$




            81:




            $81 = sqrt{9}^{(2^{(0!+1)})}$




            82:




            $82 = 92 - 10$




            95:




            $95 = 190 / 2$




            99:




            $99 = (9+1)-0!$







            share|improve this answer











            $endgroup$



            Hope few of my solutions (not mentioned before) will help you. It's not an easy task and I'm curious if it's even possible to come up with each of them.



            54:




            $54 = 9*1*(2+0!)!$




            64:




            $64 = (9-1)^2+0$




            71:




            $71 = 91 - 20$




            76:




            $76 = 19 * (2 + 1 + 0!)$




            81:




            $81 = sqrt{9}^{(2^{(0!+1)})}$




            82:




            $82 = 92 - 10$




            95:




            $95 = 190 / 2$




            99:




            $99 = (9+1)-0!$








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Jan 9 at 20:38









            a stone arachnid

            1707




            1707










            answered Jan 9 at 15:47









            Rafał KlatRafał Klat

            11




            11












            • $begingroup$
              76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
              $endgroup$
              – Meerkat
              Jan 9 at 15:55










            • $begingroup$
              The last one is missing $2$ possibly just a typo.
              $endgroup$
              – Weather Vane
              Jan 9 at 18:25


















            • $begingroup$
              76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
              $endgroup$
              – Meerkat
              Jan 9 at 15:55










            • $begingroup$
              The last one is missing $2$ possibly just a typo.
              $endgroup$
              – Weather Vane
              Jan 9 at 18:25
















            $begingroup$
            76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
            $endgroup$
            – Meerkat
            Jan 9 at 15:55




            $begingroup$
            76 uses 1 twice, and division isn't allowed, so 95 = 190 / 2 won't work either. The rest do work, however.
            $endgroup$
            – Meerkat
            Jan 9 at 15:55












            $begingroup$
            The last one is missing $2$ possibly just a typo.
            $endgroup$
            – Weather Vane
            Jan 9 at 18:25




            $begingroup$
            The last one is missing $2$ possibly just a typo.
            $endgroup$
            – Weather Vane
            Jan 9 at 18:25











            0












            $begingroup$

            Partial, only a few numbers so far:




            50 =

            51 =

            52 =

            53 =

            54 =

            55 =

            56 =

            57 = $19 * (2+0!)$

            58 = $29 * (1+0!)$

            59 =

            60 =

            61 =

            62 =

            63 =

            64 =

            65 =

            66 =

            67 =

            68 =

            69 =

            70 = $(9-2) * 10$

            71 = $91 - 20$

            72 =

            73 =

            74 =

            75 =

            76 =

            77 =

            78 =

            79 = $91 - (0! + 2)$

            80 =

            81 =

            82 = $92 - 10$

            83 =

            84 = $90 - (1 + 2)!$

            85 =

            86 =

            87 = $90 - 1 - 2$

            88 = $91 - 2 - 0!$

            89 = $91 - 2 - 0$

            90 = $92 - (1+0!)$

            91 = $91 + 0 * 2$

            92 = $92 + 1 * 0$

            93 = $90 + 1 + 2$

            94 = $91 + 2 + 0!$

            95 =

            96 = $90 + (1 + 2)!$

            97 = $91 + (0! + 2)!$

            98 =

            99 =

            100 =







            share|improve this answer











            $endgroup$









            • 1




              $begingroup$
              86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
              $endgroup$
              – Meerkat
              Jan 9 at 16:41






            • 1




              $begingroup$
              79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
              $endgroup$
              – Yout Ried
              Jan 11 at 2:09
















            0












            $begingroup$

            Partial, only a few numbers so far:




            50 =

            51 =

            52 =

            53 =

            54 =

            55 =

            56 =

            57 = $19 * (2+0!)$

            58 = $29 * (1+0!)$

            59 =

            60 =

            61 =

            62 =

            63 =

            64 =

            65 =

            66 =

            67 =

            68 =

            69 =

            70 = $(9-2) * 10$

            71 = $91 - 20$

            72 =

            73 =

            74 =

            75 =

            76 =

            77 =

            78 =

            79 = $91 - (0! + 2)$

            80 =

            81 =

            82 = $92 - 10$

            83 =

            84 = $90 - (1 + 2)!$

            85 =

            86 =

            87 = $90 - 1 - 2$

            88 = $91 - 2 - 0!$

            89 = $91 - 2 - 0$

            90 = $92 - (1+0!)$

            91 = $91 + 0 * 2$

            92 = $92 + 1 * 0$

            93 = $90 + 1 + 2$

            94 = $91 + 2 + 0!$

            95 =

            96 = $90 + (1 + 2)!$

            97 = $91 + (0! + 2)!$

            98 =

            99 =

            100 =







            share|improve this answer











            $endgroup$









            • 1




              $begingroup$
              86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
              $endgroup$
              – Meerkat
              Jan 9 at 16:41






            • 1




              $begingroup$
              79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
              $endgroup$
              – Yout Ried
              Jan 11 at 2:09














            0












            0








            0





            $begingroup$

            Partial, only a few numbers so far:




            50 =

            51 =

            52 =

            53 =

            54 =

            55 =

            56 =

            57 = $19 * (2+0!)$

            58 = $29 * (1+0!)$

            59 =

            60 =

            61 =

            62 =

            63 =

            64 =

            65 =

            66 =

            67 =

            68 =

            69 =

            70 = $(9-2) * 10$

            71 = $91 - 20$

            72 =

            73 =

            74 =

            75 =

            76 =

            77 =

            78 =

            79 = $91 - (0! + 2)$

            80 =

            81 =

            82 = $92 - 10$

            83 =

            84 = $90 - (1 + 2)!$

            85 =

            86 =

            87 = $90 - 1 - 2$

            88 = $91 - 2 - 0!$

            89 = $91 - 2 - 0$

            90 = $92 - (1+0!)$

            91 = $91 + 0 * 2$

            92 = $92 + 1 * 0$

            93 = $90 + 1 + 2$

            94 = $91 + 2 + 0!$

            95 =

            96 = $90 + (1 + 2)!$

            97 = $91 + (0! + 2)!$

            98 =

            99 =

            100 =







            share|improve this answer











            $endgroup$



            Partial, only a few numbers so far:




            50 =

            51 =

            52 =

            53 =

            54 =

            55 =

            56 =

            57 = $19 * (2+0!)$

            58 = $29 * (1+0!)$

            59 =

            60 =

            61 =

            62 =

            63 =

            64 =

            65 =

            66 =

            67 =

            68 =

            69 =

            70 = $(9-2) * 10$

            71 = $91 - 20$

            72 =

            73 =

            74 =

            75 =

            76 =

            77 =

            78 =

            79 = $91 - (0! + 2)$

            80 =

            81 =

            82 = $92 - 10$

            83 =

            84 = $90 - (1 + 2)!$

            85 =

            86 =

            87 = $90 - 1 - 2$

            88 = $91 - 2 - 0!$

            89 = $91 - 2 - 0$

            90 = $92 - (1+0!)$

            91 = $91 + 0 * 2$

            92 = $92 + 1 * 0$

            93 = $90 + 1 + 2$

            94 = $91 + 2 + 0!$

            95 =

            96 = $90 + (1 + 2)!$

            97 = $91 + (0! + 2)!$

            98 =

            99 =

            100 =








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Jan 11 at 2:32

























            answered Jan 9 at 15:29









            rhsquaredrhsquared

            8,14021849




            8,14021849








            • 1




              $begingroup$
              86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
              $endgroup$
              – Meerkat
              Jan 9 at 16:41






            • 1




              $begingroup$
              79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
              $endgroup$
              – Yout Ried
              Jan 11 at 2:09














            • 1




              $begingroup$
              86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
              $endgroup$
              – Meerkat
              Jan 9 at 16:41






            • 1




              $begingroup$
              79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
              $endgroup$
              – Yout Ried
              Jan 11 at 2:09








            1




            1




            $begingroup$
            86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
            $endgroup$
            – Meerkat
            Jan 9 at 16:41




            $begingroup$
            86 = 90 - 2 * (1+0!) doesn't work, as you use 0 twice in the formula.
            $endgroup$
            – Meerkat
            Jan 9 at 16:41




            1




            1




            $begingroup$
            79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
            $endgroup$
            – Yout Ried
            Jan 11 at 2:09




            $begingroup$
            79 doesn't work, you use 1 twice. 78 would though 90-12 instead of 91-12
            $endgroup$
            – Yout Ried
            Jan 11 at 2:09


















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