Complete the sequence
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As the title says it is a compete the sequence.
My thoughts:
From all the circle ones that aren't a circle, you can make a circle by rotating the pieces. From all the triangle ones that aren't a triangle, you can make a triangle by moving one line. But I can't figure out a rule for the square-ish things. (Of course the rules I came up with for the circle and triangle might be wrong.)
pattern visual
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add a comment |
$begingroup$
As the title says it is a compete the sequence.
My thoughts:
From all the circle ones that aren't a circle, you can make a circle by rotating the pieces. From all the triangle ones that aren't a triangle, you can make a triangle by moving one line. But I can't figure out a rule for the square-ish things. (Of course the rules I came up with for the circle and triangle might be wrong.)
pattern visual
$endgroup$
add a comment |
$begingroup$
As the title says it is a compete the sequence.
My thoughts:
From all the circle ones that aren't a circle, you can make a circle by rotating the pieces. From all the triangle ones that aren't a triangle, you can make a triangle by moving one line. But I can't figure out a rule for the square-ish things. (Of course the rules I came up with for the circle and triangle might be wrong.)
pattern visual
$endgroup$
As the title says it is a compete the sequence.
My thoughts:
From all the circle ones that aren't a circle, you can make a circle by rotating the pieces. From all the triangle ones that aren't a triangle, you can make a triangle by moving one line. But I can't figure out a rule for the square-ish things. (Of course the rules I came up with for the circle and triangle might be wrong.)
pattern visual
pattern visual
edited Nov 22 '18 at 19:42
gabbo1092
4,748738
4,748738
asked Sep 22 '15 at 13:39
user265554user265554
1966
1966
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
I'll go with:
Why?
There's a triangle, a circle and a 'U' shape. They each appear both 'normal', once with both halves mirrored along a vertical axis, and once with the left side intact and the right rotated 180 degrees.
Based on what's there already:
the three states for triangle and circle, and both the normal and mirrored state of the 'U' shape
what we need is:
left side of the U intact, right side rotated 180 degrees.
$endgroup$
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
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Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
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@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
add a comment |
$begingroup$
I think it is the,
Third one in the first row
There is a circle, a mirrored half of a triangle, and an upside down T in each each row
The first row is correct
The second row, you cut it vertically and switch the sides
The third row, you cut it down the middle vertically and flip the right side over the x axis and the left side over the y axis
The reason it isn't a circle, triangle, and U is because of the second row. There is no way to move the triangle and U to get the circle while preserving their shape, therefore, they need to move the same way the circle will which gives you the shapes in the first row. the rows do not have the same moves to get to the end result although they do build on each other in number of moves. The first row has 0 moves, the second has 1, and the third has 2.
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But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
$begingroup$
@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
$endgroup$
– SirParselot
Sep 22 '15 at 14:39
$begingroup$
But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
$endgroup$
– user265554
Sep 22 '15 at 14:47
$begingroup$
@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
$endgroup$
– SirParselot
Sep 22 '15 at 14:55
$begingroup$
If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
$endgroup$
– user265554
Sep 22 '15 at 15:03
|
show 1 more comment
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It is
the third one in the first row.
Let's look at the triangles:
Row 2, Column 2: First picture: the intact triangle
Row 3, Column 2: Second picture: right half of the triangle has been rotated horizontally and vertically
Row 1, Column 3: Third picture: other half of the triangle has been rotated horizontally and vertically, afterwards that whole picture is again rotated horizontally
And now for the circles
Row 1, Column 2: First picture: the intact circle
Row 3, Column 1: Second picture: half of the circle has been rotated horizontally and vertically
Row 2, Column 1: See: half of the circle has been rotated horizontally and vertically, and then again rotated horizontally
Aaaand finally the .. squarish things?
Row 2, Column 3: intact U
Row 1, Column 1: again, rotating the right half vertically and horizontacally
That is the one in the new Row 1, Column 3
Row 1, Column 1: final picture
You can also see a pattern in the rows and columns:
Triangles
Rows: 2, 3, 1
Columns: 2, 2, 3
Circles
Rows: 1, 3, 2
Columns: 2, 1, 1
Squares
Rows: 2, 1, 3
Columns: 3, 1, 3
So all in all it's this:
Rows are: 1,2,3 - 1,2,3 - 1,2,3
Columns are: 1,1,2 - 2,2,3 - 3,3,1
Cheers.
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add a comment |
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1.3
Divide image in half, flip half; and reconstruct the whole image.
New contributor
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Welcome to PSE. Please hide your answers in spoilers in the future.
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– rhsquared
13 hours ago
1
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Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
$endgroup$
– Brandon_J
13 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I'll go with:
Why?
There's a triangle, a circle and a 'U' shape. They each appear both 'normal', once with both halves mirrored along a vertical axis, and once with the left side intact and the right rotated 180 degrees.
Based on what's there already:
the three states for triangle and circle, and both the normal and mirrored state of the 'U' shape
what we need is:
left side of the U intact, right side rotated 180 degrees.
$endgroup$
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
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Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
add a comment |
$begingroup$
I'll go with:
Why?
There's a triangle, a circle and a 'U' shape. They each appear both 'normal', once with both halves mirrored along a vertical axis, and once with the left side intact and the right rotated 180 degrees.
Based on what's there already:
the three states for triangle and circle, and both the normal and mirrored state of the 'U' shape
what we need is:
left side of the U intact, right side rotated 180 degrees.
$endgroup$
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
$begingroup$
Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
add a comment |
$begingroup$
I'll go with:
Why?
There's a triangle, a circle and a 'U' shape. They each appear both 'normal', once with both halves mirrored along a vertical axis, and once with the left side intact and the right rotated 180 degrees.
Based on what's there already:
the three states for triangle and circle, and both the normal and mirrored state of the 'U' shape
what we need is:
left side of the U intact, right side rotated 180 degrees.
$endgroup$
I'll go with:
Why?
There's a triangle, a circle and a 'U' shape. They each appear both 'normal', once with both halves mirrored along a vertical axis, and once with the left side intact and the right rotated 180 degrees.
Based on what's there already:
the three states for triangle and circle, and both the normal and mirrored state of the 'U' shape
what we need is:
left side of the U intact, right side rotated 180 degrees.
answered Sep 22 '15 at 14:24
Tim CouwelierTim Couwelier
4,0661536
4,0661536
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
$begingroup$
Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
add a comment |
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
$begingroup$
Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
1
1
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
$begingroup$
But if we keep the left side intact, how does the left side of the circle flip when going from second row to third row?
$endgroup$
– user265554
Sep 22 '15 at 14:34
$begingroup$
Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
Because we started from the circle, not from the double-half-circle.
$endgroup$
– Hellion
Sep 22 '15 at 14:57
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
These rules apply to the circle objects but not to the triangle objects
$endgroup$
– user265554
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
What @Helion said: the transformations I described are all starting from the base form, not from an already transformed state.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:06
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
$begingroup$
@user265554 Yes they do. The original triangle is on row 2 column 2. The varation where both halves are mirrored is on row 1 colum 3. The variation where the left half stays untouched and the right half is rotated 180 degrees is row 3 column 2. If you're going to downvote for an error on my part, do make sure it's an actual error.
$endgroup$
– Tim Couwelier
Sep 22 '15 at 15:09
add a comment |
$begingroup$
I think it is the,
Third one in the first row
There is a circle, a mirrored half of a triangle, and an upside down T in each each row
The first row is correct
The second row, you cut it vertically and switch the sides
The third row, you cut it down the middle vertically and flip the right side over the x axis and the left side over the y axis
The reason it isn't a circle, triangle, and U is because of the second row. There is no way to move the triangle and U to get the circle while preserving their shape, therefore, they need to move the same way the circle will which gives you the shapes in the first row. the rows do not have the same moves to get to the end result although they do build on each other in number of moves. The first row has 0 moves, the second has 1, and the third has 2.
$endgroup$
$begingroup$
But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
$begingroup$
@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
$endgroup$
– SirParselot
Sep 22 '15 at 14:39
$begingroup$
But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
$endgroup$
– user265554
Sep 22 '15 at 14:47
$begingroup$
@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
$endgroup$
– SirParselot
Sep 22 '15 at 14:55
$begingroup$
If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
$endgroup$
– user265554
Sep 22 '15 at 15:03
|
show 1 more comment
$begingroup$
I think it is the,
Third one in the first row
There is a circle, a mirrored half of a triangle, and an upside down T in each each row
The first row is correct
The second row, you cut it vertically and switch the sides
The third row, you cut it down the middle vertically and flip the right side over the x axis and the left side over the y axis
The reason it isn't a circle, triangle, and U is because of the second row. There is no way to move the triangle and U to get the circle while preserving their shape, therefore, they need to move the same way the circle will which gives you the shapes in the first row. the rows do not have the same moves to get to the end result although they do build on each other in number of moves. The first row has 0 moves, the second has 1, and the third has 2.
$endgroup$
$begingroup$
But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
$begingroup$
@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
$endgroup$
– SirParselot
Sep 22 '15 at 14:39
$begingroup$
But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
$endgroup$
– user265554
Sep 22 '15 at 14:47
$begingroup$
@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
$endgroup$
– SirParselot
Sep 22 '15 at 14:55
$begingroup$
If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
$endgroup$
– user265554
Sep 22 '15 at 15:03
|
show 1 more comment
$begingroup$
I think it is the,
Third one in the first row
There is a circle, a mirrored half of a triangle, and an upside down T in each each row
The first row is correct
The second row, you cut it vertically and switch the sides
The third row, you cut it down the middle vertically and flip the right side over the x axis and the left side over the y axis
The reason it isn't a circle, triangle, and U is because of the second row. There is no way to move the triangle and U to get the circle while preserving their shape, therefore, they need to move the same way the circle will which gives you the shapes in the first row. the rows do not have the same moves to get to the end result although they do build on each other in number of moves. The first row has 0 moves, the second has 1, and the third has 2.
$endgroup$
I think it is the,
Third one in the first row
There is a circle, a mirrored half of a triangle, and an upside down T in each each row
The first row is correct
The second row, you cut it vertically and switch the sides
The third row, you cut it down the middle vertically and flip the right side over the x axis and the left side over the y axis
The reason it isn't a circle, triangle, and U is because of the second row. There is no way to move the triangle and U to get the circle while preserving their shape, therefore, they need to move the same way the circle will which gives you the shapes in the first row. the rows do not have the same moves to get to the end result although they do build on each other in number of moves. The first row has 0 moves, the second has 1, and the third has 2.
edited Sep 22 '15 at 15:04
answered Sep 22 '15 at 14:21
SirParselotSirParselot
60639
60639
$begingroup$
But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
$begingroup$
@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
$endgroup$
– SirParselot
Sep 22 '15 at 14:39
$begingroup$
But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
$endgroup$
– user265554
Sep 22 '15 at 14:47
$begingroup$
@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
$endgroup$
– SirParselot
Sep 22 '15 at 14:55
$begingroup$
If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
$endgroup$
– user265554
Sep 22 '15 at 15:03
|
show 1 more comment
$begingroup$
But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
$begingroup$
@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
$endgroup$
– SirParselot
Sep 22 '15 at 14:39
$begingroup$
But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
$endgroup$
– user265554
Sep 22 '15 at 14:47
$begingroup$
@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
$endgroup$
– SirParselot
Sep 22 '15 at 14:55
$begingroup$
If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
$endgroup$
– user265554
Sep 22 '15 at 15:03
$begingroup$
But how does the circle's left side change and not the right side when going from the second row to the third?
$endgroup$
– user265554
Sep 22 '15 at 14:36
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But how does the circle's left side change and not the right side when going from the second row to the third?
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– user265554
Sep 22 '15 at 14:36
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@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
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– SirParselot
Sep 22 '15 at 14:39
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@user265554 the rows are unrelated. You don't need to know how the second row was flipped to get to the third row. The first two rows are there to help you figure out the shapes. If it wasn't for the second row it could be a circle, triangle, and U shape rather than an circle, mirrored half of a triangle, and an upside down T
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– SirParselot
Sep 22 '15 at 14:39
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But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
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– user265554
Sep 22 '15 at 14:47
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But if you take the whole circle from the first row, and flip the right side over the x-axis and the left side over the y-axis, you get a shape that is the first shape from the third row but which has been rotated 180 degrees
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– user265554
Sep 22 '15 at 14:47
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@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
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– SirParselot
Sep 22 '15 at 14:55
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@user265554 That is valid but what's your point? If you follow that rule for each row you will get a different second row while the first and third rows match. My point is that there is no one set of moves that you can apply to each row and get the same shapes (Orientation matters) therefore each row will have a different set of moves or none at all
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– SirParselot
Sep 22 '15 at 14:55
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If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
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– user265554
Sep 22 '15 at 15:03
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If the rules for getting the third row from the first row are to flip the the right side over the x-axis and the left side over the y-axis, you can't get the first object of the third row from the second object of the first row with these rules.
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– user265554
Sep 22 '15 at 15:03
|
show 1 more comment
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It is
the third one in the first row.
Let's look at the triangles:
Row 2, Column 2: First picture: the intact triangle
Row 3, Column 2: Second picture: right half of the triangle has been rotated horizontally and vertically
Row 1, Column 3: Third picture: other half of the triangle has been rotated horizontally and vertically, afterwards that whole picture is again rotated horizontally
And now for the circles
Row 1, Column 2: First picture: the intact circle
Row 3, Column 1: Second picture: half of the circle has been rotated horizontally and vertically
Row 2, Column 1: See: half of the circle has been rotated horizontally and vertically, and then again rotated horizontally
Aaaand finally the .. squarish things?
Row 2, Column 3: intact U
Row 1, Column 1: again, rotating the right half vertically and horizontacally
That is the one in the new Row 1, Column 3
Row 1, Column 1: final picture
You can also see a pattern in the rows and columns:
Triangles
Rows: 2, 3, 1
Columns: 2, 2, 3
Circles
Rows: 1, 3, 2
Columns: 2, 1, 1
Squares
Rows: 2, 1, 3
Columns: 3, 1, 3
So all in all it's this:
Rows are: 1,2,3 - 1,2,3 - 1,2,3
Columns are: 1,1,2 - 2,2,3 - 3,3,1
Cheers.
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add a comment |
$begingroup$
It is
the third one in the first row.
Let's look at the triangles:
Row 2, Column 2: First picture: the intact triangle
Row 3, Column 2: Second picture: right half of the triangle has been rotated horizontally and vertically
Row 1, Column 3: Third picture: other half of the triangle has been rotated horizontally and vertically, afterwards that whole picture is again rotated horizontally
And now for the circles
Row 1, Column 2: First picture: the intact circle
Row 3, Column 1: Second picture: half of the circle has been rotated horizontally and vertically
Row 2, Column 1: See: half of the circle has been rotated horizontally and vertically, and then again rotated horizontally
Aaaand finally the .. squarish things?
Row 2, Column 3: intact U
Row 1, Column 1: again, rotating the right half vertically and horizontacally
That is the one in the new Row 1, Column 3
Row 1, Column 1: final picture
You can also see a pattern in the rows and columns:
Triangles
Rows: 2, 3, 1
Columns: 2, 2, 3
Circles
Rows: 1, 3, 2
Columns: 2, 1, 1
Squares
Rows: 2, 1, 3
Columns: 3, 1, 3
So all in all it's this:
Rows are: 1,2,3 - 1,2,3 - 1,2,3
Columns are: 1,1,2 - 2,2,3 - 3,3,1
Cheers.
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add a comment |
$begingroup$
It is
the third one in the first row.
Let's look at the triangles:
Row 2, Column 2: First picture: the intact triangle
Row 3, Column 2: Second picture: right half of the triangle has been rotated horizontally and vertically
Row 1, Column 3: Third picture: other half of the triangle has been rotated horizontally and vertically, afterwards that whole picture is again rotated horizontally
And now for the circles
Row 1, Column 2: First picture: the intact circle
Row 3, Column 1: Second picture: half of the circle has been rotated horizontally and vertically
Row 2, Column 1: See: half of the circle has been rotated horizontally and vertically, and then again rotated horizontally
Aaaand finally the .. squarish things?
Row 2, Column 3: intact U
Row 1, Column 1: again, rotating the right half vertically and horizontacally
That is the one in the new Row 1, Column 3
Row 1, Column 1: final picture
You can also see a pattern in the rows and columns:
Triangles
Rows: 2, 3, 1
Columns: 2, 2, 3
Circles
Rows: 1, 3, 2
Columns: 2, 1, 1
Squares
Rows: 2, 1, 3
Columns: 3, 1, 3
So all in all it's this:
Rows are: 1,2,3 - 1,2,3 - 1,2,3
Columns are: 1,1,2 - 2,2,3 - 3,3,1
Cheers.
$endgroup$
It is
the third one in the first row.
Let's look at the triangles:
Row 2, Column 2: First picture: the intact triangle
Row 3, Column 2: Second picture: right half of the triangle has been rotated horizontally and vertically
Row 1, Column 3: Third picture: other half of the triangle has been rotated horizontally and vertically, afterwards that whole picture is again rotated horizontally
And now for the circles
Row 1, Column 2: First picture: the intact circle
Row 3, Column 1: Second picture: half of the circle has been rotated horizontally and vertically
Row 2, Column 1: See: half of the circle has been rotated horizontally and vertically, and then again rotated horizontally
Aaaand finally the .. squarish things?
Row 2, Column 3: intact U
Row 1, Column 1: again, rotating the right half vertically and horizontacally
That is the one in the new Row 1, Column 3
Row 1, Column 1: final picture
You can also see a pattern in the rows and columns:
Triangles
Rows: 2, 3, 1
Columns: 2, 2, 3
Circles
Rows: 1, 3, 2
Columns: 2, 1, 1
Squares
Rows: 2, 1, 3
Columns: 3, 1, 3
So all in all it's this:
Rows are: 1,2,3 - 1,2,3 - 1,2,3
Columns are: 1,1,2 - 2,2,3 - 3,3,1
Cheers.
answered Sep 22 '15 at 15:06
Tom K.Tom K.
23429
23429
add a comment |
add a comment |
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1.3
Divide image in half, flip half; and reconstruct the whole image.
New contributor
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Welcome to PSE. Please hide your answers in spoilers in the future.
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– rhsquared
13 hours ago
1
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Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
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– Brandon_J
13 hours ago
add a comment |
$begingroup$
1.3
Divide image in half, flip half; and reconstruct the whole image.
New contributor
$endgroup$
$begingroup$
Welcome to PSE. Please hide your answers in spoilers in the future.
$endgroup$
– rhsquared
13 hours ago
1
$begingroup$
Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
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– Brandon_J
13 hours ago
add a comment |
$begingroup$
1.3
Divide image in half, flip half; and reconstruct the whole image.
New contributor
$endgroup$
1.3
Divide image in half, flip half; and reconstruct the whole image.
New contributor
edited 13 hours ago
rhsquared
8,14021849
8,14021849
New contributor
answered 14 hours ago
PatricioPatricio
11
11
New contributor
New contributor
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Welcome to PSE. Please hide your answers in spoilers in the future.
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– rhsquared
13 hours ago
1
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Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
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– Brandon_J
13 hours ago
add a comment |
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Welcome to PSE. Please hide your answers in spoilers in the future.
$endgroup$
– rhsquared
13 hours ago
1
$begingroup$
Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
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– Brandon_J
13 hours ago
$begingroup$
Welcome to PSE. Please hide your answers in spoilers in the future.
$endgroup$
– rhsquared
13 hours ago
$begingroup$
Welcome to PSE. Please hide your answers in spoilers in the future.
$endgroup$
– rhsquared
13 hours ago
1
1
$begingroup$
Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
$endgroup$
– Brandon_J
13 hours ago
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Welcome to Puzzling.SE! In the future, please use the ">!" spoiler notation for answers.
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– Brandon_J
13 hours ago
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